lecture 6_treatment structure 1 factorial and nested new

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  • 7/26/2019 LECTURE 6_Treatment Structure 1 Factorial and Nested New

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    Treatment structures

    How the treatments arearranged or combined in the

    design structure

    Presentation 5

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    Recapitulation

    So far our discussion on CRD, RCBD and LT!"S#$R% ha&e been limited to '"% treatmentfactor (but with a few le&els) onl*+

    e+g+ ariet*- ., /, 0

    1rom now on we will consider more than onetreatment factor (use T2'), each with a few

    le&els+

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    2hat to do if there are more than onefactor3

    How are we going to arrange the factors (and 4tinto the CRD and RCBD designs)3

    Treatmentstructures

    Designstructures

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    !+ 1actorial arrangement

    factorial eperiment6 treatments consist ofall possiblecombinations of the

    le&els of se&eralfactors

    $seful in eplorator*wor7 when little is7nown about theoptimum le&els of thefactors

    1actor

    . /

    1actorB

    B.A1B1

    A2B1

    B/A1B2

    A2B2

    %ample of a/8/

    factorial

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    %amples

    The e9ect of temperature (/5 and 55 C) and altitude (.:; ft,0: ;) on the current

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    d&antages of multifactor studieso&er one factor at a time approach

    %>cienc*

    ar* the temp (/5 ? 55C), 7eep altitude constant (.:;)+@et results, repeat eperiment to estimate error&ariabilit*+

    Do the same at 0:; n alternati&e, use factorial arrangement combining

    temp+ and altitude+

    The amount of eperimentation is less when use factorial+

    mount of !nformation Readil* in&estigate the Aoint e9ects or interaction+

    2hen the factors interact, factorial eperiments can

    estimate the interaction+ 'neatattime eperiments cannot estimate interaction+

    $se of oneatatime eperiments in the presence ofinteraction can lead to serious misunderstanding of howthe response &aries as a function of the factors+

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    alidit* of 1inding

    part from being more e>cient and readil* pro&idinginformation on interaction e9ects, multifactor studiesalso strengthen the &alidit* of results+

    e+g+The e9ects of selling price (R= .:, /:, 0:) and t*peof ad&ertising campaign ("ewspaper, Radio) on sales ofa product+

    primar* interest is e9ect of price on sales+!f onl* used newspaper ad&ertising, doubts might eistwhether or not the price e9ect di9ers for otherad&ertising campaigns+ B* using other t*pe ofad&ertising, management can get info on thepersistence of price e9ect with di9erent promotionalcampaign+

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    Caution

    The ad&antages of multifactor eperiment Austdescribed should not be mista7en that the morefactors are included in a stud*, the better+

    %periments in&ol&ing man* factors with each atnumerous le&els become more comple tointerpret, costl* and timeconsuming+

    The better strateg* is to begin with onl* a fewfactors (the important ones), then etend thestud* in accordance with the results obtainedthereof+

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    1actorial rrangement in CRD

    To stud* the in

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    To stud* the in

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    Data

    .B. .B/ /B. /B/ Total

    E+50 .F+50 0G+. 0/+:

    /:+50 /.+:F /I+/ /0+E

    ./+50 /:+E: 0.+00 /E+EF

    .+:: .F+00 5+E /5+:I

    .:+E: /:+:F :+/ /G+00

    J II+0G GI+E .E/+IF .0G+:I E+G/

    J/ GI0+EE .EEF+:/ IG.0+I0 0G./+.F .0IFI+F

    .0+/E .G+0I 0I+50 /F+E. /+/5Y

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    Statistical linear model

    Recall basic CRD with one treatment factor

    Yij= + ti + eij

    1or factorial with / factors in CRD, treatment nowconsists of two factors

    Yij= + ti + eij

    Yijk= + i+ j+ ij+ eijk

    i = the e9ect of ithfactor

    j = the r9ect ofjthfactor B

    ij = the interaction of ithfactor andjthfactor B

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    Statistical =odel

    Yijk= + i+ j +ij+ ijk

    where i= 1,,a; j=1,..,b; k=1,...,r

    Computation (Basic CRD)

    C1 Y2/ rab E/K/:SST' Y2ijk CF .0IFI+F ..F5F+0 .G.G+0

    SSTR Y2ij. /r CF (II+0/ ++.0G+:/)K5 6 ..F5F+0 .50G+SS% b* di9erence .G.G+0 6 .50G+ 0FG+G

    Decomposition of SSTR in factorial into its components

    SSTR is made up of two components, SSTR SS SSB SSB

    SS Y2i../rb CF (.I0+./ 0/.+F0/) K.: 6 C1 ./5I+FSSB Y2.j./ra CF (/G+:/ /05+E/) K.: 6 C1 E+FSSB SSTR 6 SS 6 SSB .50G+ ./5I+F E+F /F0+G

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    "'

    basic no&a table for CRD

    Source df SSTreatment ab. 0 .50G+%rror (r.)ab.I 0FG+G

    Total rab..G .G.G+0

    no&a Table =odi4ed for 1actorial rrangement in CRDBrea7down of treatment e9ectsSource df SS =S 1

    Time a.. ./5I+F ./5I+F 50MHormone b.. E+F E+F N.

    Time Horm+ (a.)(b.). /F0+G /F0+G ..+5M%rror (r.)ab.I 0FG+G /0+F

    Total rab. .G.G+0

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    More on Interaction

    =odelJiA7 u i BA (MB)iA eiA7

    Test h*pothesis

    Ho- Test whether or not main e9ects arepresentHo- Test whether or not main e9ects B arepresent

    Ho- Test whether or not the two factors interact

    To illustrate the meaning of the model elements,consider a simple twofactor stud* on the e9ectsof S%8 and @% on L%R"!"@ of a tas7+

    S%8- male (.) and female (/)

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    Interaction plot : To chec7 whether the factorsare or are are not independent+

    "o interaction

    AGE and SEX effects, with no

    interactions

    Graphical presentation

    The curves of mean responses for

    the different levels of a factor are

    parallel.

    AGE effect but no SEX effect, with nointeractions

    Graphic presentation

    The zero slope of each curve indicates that

    SEX has no effect.

    The differences in heihts of the curves

    show the AGE effects.

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    !nteraction present

    AGE and SEX effects, with important

    interactions

    Graphical presentation

    The treatment mean curves for the two

    SEXES are not parallel

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    !actorial with one observation per cell

    Yij= + i+ j+ eij

    !actorial with more than one observations per

    cell "have replicates#

    Yijk= + i+ j+ ij+ eijk

    . / 0

    B. J.. J/. J0.

    B/ J./ J// J0/

    . / 0

    B. J...J../

    J/..J/./

    J0..J0./

    B/ J./.J.//

    J//.J///

    J0/.J0//

    "ote- =odel summar*

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    1actorial arrangement in RCBD

    Oust as factorial eperiment can be done inCRD when eperimental units or setting arehomogeneous, it can also be carried out

    using RCBD when the units of eperimentare not homogeneous (the bloc7ing criteriaha&e been discussed pre&iousl*)+

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    simple eample of // factorial inRCBD

    Consider an eperiment to stud* the e9ects oftwoconcentration le&els of a substrate (factor )and tworeaction temperatures (factor B) on the*ield of a chemical product+

    %ach of these four combinations is to be run inrandom order on each of three da*s+

    The primar* interest is to loo7 at the e9ects ofconcentrations and reaction temperatures+

    Howe&er since onl* four reactions (eperiments)can be done in a gi&en da*, the etraneous e9ectof da*s will be bloc7ed+

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    La*out and Data

    DJ.

    .

    B.

    /

    B.

    /

    B/

    .

    B/

    DJ/

    /

    B.

    .

    B.

    /

    B/

    .

    B/

    DJ0

    .

    B/

    /

    B/

    .

    B.

    /

    B.

    .B. .B/ /B. /B/

    DJ. .. .F .. /. 60

    DJ/ I .0 .: /I 55

    DJ0 I I .: ./ 34

    23 36 31 59 149

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    Basi !CB"

    Yi#= + i+ #+ i#

    where i= ith b$%k e&et

    #re'rese(ts treat#e(ts a() i* the treat#e(ts are*%r#e) b tw% *at%r *at%ria$ the(

    # =j+ k+ jk

    s% the %#'$ete #%)e$ *%r 2*at%r F-C!0- i(!CB"

    Yijk= + i+ j+ k+ jk+ ijk

    Statistical linear model

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    Construction of "'

    Proceed as usual Compute

    C1

    SSBloc7

    SSTR

    SST'

    SS% b* di9erence

    SST' SSBloc7 SSTR SS%

    Basic Anova for RCBD

    Source df SS

    Bloc7 r. SSBloc7

    Trtt. SSTR

    %rror (r.)(t.) SS%Total rt. SST'

    Anova for factorial in RCBD

    Bloc7 bloc7. SSBloc7

    a.B b. SSTR SS SSB

    B (a.)(b.) SSB

    %rror (r.)(ab.) SS%

    Total rab. SSTR

    tab

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    Computations for our eample

    C1 .G/K./ .E5:+:E

    SST' ../ .F/ + .//6 C1 .E+G/ SSBloc7 (I:/ 55/ 0/)K 6 C1 G5+.F

    SS Q(.)/ (/)/KI 6 C1 (5G/ G:/)KI 6 C1 E:+:E

    SSB Q(B.)/ (B/)/KI 6 C1 (5/ G5/)KI 6 C1 .:+:E

    SSB Q(.B.)/ (.B/)/ (/B.)/(/B/)/K0 6 C1 6 SS 6SSB

    SSTR 6 SSSSB (/0/ 0I/0./5G/)K0 C1 6SS 6 SSB .E+F5

    SS% SST' 6 SSBloc7 6 SS 6 SSB 6 SSB E+E0

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    "' Table

    Source D1 SS =S 1 PM

    Bloc7 / G5+.F F+5E 0+0F:+.:5

    . E:+:E E:+:E 5+II :+:55

    B . .:+:E .:+:E G+G. :+:/:

    MB . .E+F5 .E+F5 .+00:+/G0

    %rror I E+E0 .+.

    Total .. .E+G/M P &alues are generated b*computer

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    !!+ "ested Structure

    Distinction beteenneste! an! factorial

    1actorial or crossed factors

    %&er* le&el of one factorappears with each le&el of

    e&er* other factor

    B. B/ B0 B

    . U U

    / U U

    B. B/ B0 B

    . U U U U

    / U U U U

    Certain le&els of a factoroccurs onl* with one le&el

    of the other factor i+e+, B.and B/ occurs onl* with .+B0 and B occurs onl* with/+

    B is said to be nested within

    factor

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    %ample ? "ested model

    !nstructor (B) withinschool ()

    . /0

    B. B/ B0 B B5BI

    @eneral model for twofactors nested

    Let JiA7denote kthobser&ation for ith le&el andjth le&el of B

    Yijk= + i+ 3 j2i3+ k2ij3

    Pots within Species

    Sp. Sp/Sp0

    Plants within pots

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    2or7ed eample

    School i !nstructor A

    Class 7 !ns Total SchTotal

    Sch. !ns . /5 /G 5 FG

    !ns / . .. /5

    Sch / !ns 0 .. I .F 5F!ns // .E :

    Sch 0 !ns 5 .F /: 0F

    !ns I 5 / F

    Three regional schools for mechanics+ The school ha&etwo instructors each who teaches classes of .:mechanics in a 0wee7 sessions+ Classes are randoml*assigned to instructors in the school+ This was done for /sessions+ J was a suitable measure of learning+

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    computation

    Compute SST'

    /5/ /G/ +//6 .E:/K./ FII

    Compute SS for factor , SS

    (FG/ 5F/ /)K .E:/K./ .5I+5

    To determine SSB(), consider each school separatel*+Compute

    Sch .- (5/ /5/)K/ FG/K /.:+/5

    Sch /- (.F/ :/)K/ 5F/K .0/+/5

    Sch 0 - (0F/ F/)K/ /K //5+:Total SSB() 5IF+5

    SS% b* subtraction

    SS% SST' 6 SS 6 SSB() /

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    "' Table

    Source D1 SS =S 1

    School / (school 0.) .5I+5 FE+/5FE+/5K.EG+.F :+.

    !ns(sch) 0 (/.)(.0) 5IF+5 .EG+.F.EG+.FKF /F+:/

    %rror /0I /+: F+::

    Total (/I)... FII+:

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    Relation between 1actorial or crossedwith nested SS

    Suppose for some reason (computer pac7age una&ailabilit*) orpurel* a mista7e, *ou anal*sed the nested eperiment as afactorial eperiment+

    Source D1 SS =S

    sch / .5I+5 FE+/5inst . .:E+: .:E+:

    schMinst / 5G+5 //G+F5

    %rror I /+: F+::

    Total .. FII+: =SSSKD1

    But nested anal*ses do not ha&e interaction SS, so use therelationship

    SSB() SSB SSB to get the correct nested "'

    SSB() .:E+: 5G+5 5IF+5+ Similarl* for D1/,0,I,..+