jee_2012_pt-1(paper 2)

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Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose.

Date : 04-07-2010 Duration : 3 Hours Max. Marks : 243

PAPER - 2

CODE

0COURSE : VIPUL (B)

PART TEST-1 (PT-1)TARGET : IIT-JEE 2012

INSTRUCTIONSA. General :

1. This Question Paper contains 63 questions.

2. The question paper CODE is printed on the right hand top corner on this sheet of this booklet.

3. No additional sheets will be provided for rough work.

4. Blank paper, clipboard, log tables, slide rules, calculators, cellular phones, pagers and electronic gadgetsin any form are not allowed.

5. The answer sheet, a machine-gradable Objective Response Sheet (ORS) , is provided separately.

6. Do not Tamper / mutilate the ORS or this booklet.

7. Do not break the seals of the question-paper booklet before instructed to do so by the invigilators.

8. Write your Name, Roll No. and Sign in the space provide on the back page of this booklet.

B. Filling the bottom-half of the ORS :

9. The ORS has CODE printed on its lower and upper Parts.

10. Make sure the CODE on the ORS is the same as that on this booklet. If the Codes do not match, ask for achange of the Booklet.

11. Write your Registration No., Name and Name of centre and sig with pen in appropriate boxes. Do not writethese anywhere else.

12. Darken the appropriate bubbles below your registration number with HB Pencil .

C. Question paper format and Marking scheme :

13. The question paper consists of 3 parts (Chemistry, Mathematics & Physics). Each part consists of four Sections.

14. For each question in Section I , you will be awarded 3 marks if you darken the bubble corresponding to the

correct answer and zero marks if no bubble is darkened. In case of bubbling of incorrect answer, minusone ( 1) mark will be awarded.

15. For each question in Section II , you will be awarded 4 marks if you darken the bubble(s) correspondingto the correct choice(s) for the answer and zero mark if no bubbled is darkened. Partial marks will beanswered for partially correct answers. No negative marks will be awarded in this Section.

MCQ Partial Marking Scheme :(a) If one choice is correct then for correct choice 4 marks, else zero.

(b) If two correct choices are answer then(i) for one correct choice 2 marks. (ii) for two correct choices 4 marks.(iii) If any wrong choice is bubbled then 0 mark.

e.g. : If correct answer is (A, C)(i) If you bubble only (A) then you get 2 marks. (ii) If you bubble only (C) then you get 2 marks(iii) If you bubble (A,C) then you get 4 marks. (iv) If you bubble (A,B) then you get 0 mark.

(c) If three choices are correct(i) for one correct choice 1 mark. (ii) for two correct choices 2 marks.(iii) for three correct choices 4 marks. (iv) If any wrong choice is bubbled then 0 mark.

(d) If four choices are correct(i) for one correct choice 1 mark. (ii) for two correct choices 2 marks.(iii) for three correct choices 3 marks. (iv) for four correct choices 4 marks.(v) If any wrong choice is bubbled then 0 mark.

16. For each question in Section III, you will be awarded 4 marks if you darken the bubble corresponding tothe correct answer, and zero mark if no bubble is darkened. In case of bubbling of incorrect answer, minusone ( 1) mark will be awarded.

17. For each question in Section IV, you will be awarded 2 marks for each row in which you have darkened thebubble(s) corresponding to the correct answer. Thus, each question in this section carries a maximum of

8 marks . There is no negative marking for incorrect answer(s) for this this section.

D O N O T B R E A K

T H E S E A L S W I T H O U T B E I N G

I N S T R U C T E D T O D O S O B Y T H E I N V I G I L A T O R

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(SPACE FOR ROUGH WORK)

PART-I

Atomic masses : [H = 1, D = 2, Li = 7, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24, Al = 27, Si = 28,P = 31, S = 32, Cl = 35.5, K = 39, Ca = 40, Cr = 52, Mn = 55, Fe = 56, Cu = 63.5, Zn = 65, As = 75,Br = 80, Ag = 108, I = 127, Ba = 137, Hg = 200, Pb = 207]

SECTION - IStraight Objective Type

This section contains 11 multiple choice questions. Each question has choices (A), (B), (C) and (D),out of which ONLY ONE is correct.

1. How many moles of each reactants were there if 8.75 moles of N 2(g) is produced according to given reactionand no reactants are left after reaction :4NH3(g) + 6NO(g) 5N2 (g) + 6H 2O(g)(A) 7 moles of NH 3 and 7 moles of NO (B) 4 moles of NH 3 and 6 moles of NO(C) 5.5 moles of NH 3 and 9.75 moles of NO (D) 7 moles of NH 3 and 10.5 moles of NO

2. Cl2O7 is a solid that decomposes on heating. 18.3 g of Cl 2O7 is subjected to prolonged heating according togiven reaction. If the compound x is found to weigh 8.7 g. A possible formula of compound x is :

Cl2O7(s) x + O 2(A) Cl2 (B) Cl 2O (C) Cl 2O3 (D) Cl 2O5

3. 2H2O 2H2(g) + O 2(g)If a given experiment results in 2500 cm 3 of H2(g) being produced, what volume of O 2(g) is liberated at thesame time under the same conditions of temperature and pressure :(A) 2500 cm 3 (B) 22400 cm 3 (C) 1250 m 3 (D) 1250 ml

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4. If 27 litres of reactants are consumed at STP for the given reaction. What volume of nitric oxide (NO) isproduced at STP :

4NH 3(g) + 5O 2(g) 4NO (g) + 6H 2O (g)(A) 27 L (B) 18 L (C) 12 L (D) 6 L

5. In presence of gases hydrogen sulphide (H 2S) and oxygen, metallic silver is converted to silver sulphide(Ag2S) according to balanced chemical equation4Ag (s) + 2H 2S (g) + O 2 (g) 2Ag2S + 2H 2O ( )If 27 g of Ag is allowed to react with 2240 ml of H 2S gas at STP and 6.023 10

22 molecules of oxygen, whichreactant will be the limiting reagent :(A) Ag (B) H 2S (C) O 2 (D) None of these

6. For the synthesis of an organic compound, a series of four sequential reactions is carried out. The percent-age yield for the individual reaction are listed below :Reaction No. Percentage yield1. 50%2. 20%3. 20%4. 10%The overall yield for the synthesis of organic compound is :(A) 100% (B) 0 % (C) 0.002 % (D) 0.2 %

7. If an air bag in a car needs 44.8L of gas when filled, how many grams of NaN 3 are needed to fill the bag withN2 gas at standard temperature and pressure.The balanced chemical reaction is

2NaN 3(s) 2Na(s) + 3N 2(g)(A) 48.75 g (B) 86.6 g (C) 130 g (D) 195 g

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8. 16 g of SO x occupies 5.6 litre volume at S.T.P. Assuming ideal gas nature, the value of x is :(A) 1 (B) 2 (C) 3 (D) None of these

9. A gaseous mixture contains CO 2(g) and N 2O(g) in 2 : 5 ratio by mass. The ratio of the number of moleculesof CO 2(g) and N 2O(g) is :(A) 5 :2 (B) 2 : 5 (C) 1 : 2 (D) 5 : 4

10. Density of ozone relative to methane under the same temperature & pressure conditions is :(A) 1/3 (B) 3 (C) 1.5 (D) 2.5

11. If the diameter of two different nuclei are in the ratio 1:3 then their atomic mass number are in the ratio :(A) 1:9 (B) 27:1 (C) 1:8 (D) 1:27

SECTION - IIMultiple Correct Answers Type

This section contains 5 multiple correct answer(s) type questions. Each question has 4 choices (A),(B), (C) and (D), out of which ONE OR MORE is/are correct.

12. If two sample of Ca 3 (PO 4)2 (s) and H 3PO 4 (s) contain same P atoms then choose the correct option(s) :(A) The ratio of oxygen atoms in the sample of Ca 3(PO 4)2 and H 3PO 4 is 1 : 1.(B) The ratio of moles of compounds Ca 3(PO 4)2 and H 3PO 4 is 1 : 2 in the sample.(C) The ratio of weight of compounds Ca 3(PO 4)2 and H 3PO 4 is 3 : 7 in the sample.(D) The ratio of atoms of Ca and H in respective compounds is 1 : 1 in the sample.

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13. Which of the following statement(s) is/are correct :(A) 1 mole CO 2 contains 3N A total atoms.(B) Both 16g of O 2 and 16g of O 3 have same number of atoms.(C) 1.7g sample of NH 3 contain 0.4N A total atoms.(D) 100g CaCO 3 contains 3N A total atoms.

14. A reaction is represented by equationxA + yB products

is started by mixing 1.00 mol of A with 2.00 mol of B in a 1.00L container at a certain temperature.These concentrations are measured at a certain time.

Substance Concentration[A] 0.875 M[B] 1.81M

choose the correct option(s):(A) x/y ratio in this reaction is 0.125/0.19(B) x/y ratio in this reaction is 1/2(C) Reactant A will be limitting reagent(D) Reactant B will be limitting reagent.

15. A + B A3B2 (unbalanced)A3B2 + C A3B2C2 (unbalanced)Above two reactions are carried out by taking 3 moles each of A and B and one mole of C. Then whichoption(s) is/are correct ?

(A) 1 mole of A 3B2C2 is formed (B) 21 mole of AA3B2C2 is formed

(C) 1/2 mole of A 3B2 is formed (D) 21 mole of AA3B2 is left finally

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16. Which of the following is/are iso-electronic with neon?(A) O 2 (B) F (C) Mg (D) Na +

SECTION - III

Reasoning TypeThis section contains 3 reasoning type questions. Each question has 4 choices (A), (B), (C) and(D), out of which ONLY ONE is correct.

17. Statement-1 : 1M solution has always lower concentration than 2M solution irrespective to theirvolumes.Statement-2 : 1M solution has lower number of solute particles than 2M solution irrespective to their volume.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True

18. Statement-1 : Vapour density of equimolar mixture of CH 4(g) and O 2 (g) is 24.

Statement-2 : Vapour density of a gaseous mixture is defined as half of average mass of the mixture.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True

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19. Statement-1 : Specific charge of -particles is twice to that of proton.Statement-2 : Specific charge is given by e/m.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True

SECTION - IVMatrix - Match Type

This section contains 2 questions. Each question contains statements given in twocolumns, which have to be matched. The statements in Column-I are labelledA, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Anygiven statement in Column-I can have correct matching with ONE OR MOREstatement(s) in Column-II . The appropriate bubbles corresponding to the answersto these questions have to be drakened as illustrated in the following example.If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening ofbubbles will look like the following :

20. Match the following :Column I Column II(A) 44 g of CO 2 (p) Number of mole of compound = 1(B) 30 g of HCHO (q) Number of molecules = 0.5 N A(C) 30 g of C 6H12 O 6 (r) Total number of atoms = 4 N A(D) 30 g of CH 3COOH (s) Number of C-atoms = N A

(t) Number of O-atoms = N A

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21. Column-I and Column-II contains four entries each. Entries of Column-I are to be matched with some

entries of Column-II . One or more than one entries of Column-I may have the matching with the same

entries of Column-II .

Column-I Column-II

(A) 0.5 mole of SO 2 (g) (p) Occupy 11.2 L at STP

(B) 9 g of H 2O (g) (q) Weighs 24 g

(C) 0.5 mole of O 3 (g) (r) Total no. of atoms = 1.5 N A(D) 1 g molecule of O 2 (g) (s) Weighs 32 g

(t) Number of oxygen atoms = N A

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PART- II

SECTION - I

Straight Objective Type This section contains 11 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for itsanswer, out of which ONLY ONE is correct.

22. Sum of series 631

+ 961

+ 1291

+ 15121

+......+ 3363331

is

(A)336333

(B)336111

(C)33637

(D)336113

23. Sum of the values of x satisfying |4x + 3| + |3x 4| = 12 is

(A)72

(B) 72

(C)7

24(D) 0

24. The value of i + i2

+ i3

+ i4

+........+ i243

is (where i = 1 )(A) i (B) 1 (C) i (D) 1


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25. If xi + 2y + 3i + 6 = 3x 2iy, then the value of |x| + |y| is (where i = 1 )

(A)1121

(B)821

(C)32

(D)83

26. Let N = 5 2 1 5 , then the value of [N] is (where [ . ] is greatest integer function)

(A) 1 (B) 2 (C) 3 (D) 1

27. Let | x + 2| = |x2

|, then sum of real values of x satisfying it, is(A) 1 (B) 3 (C) 1 (D) no real x exist

28. Graph of y = |2x 5| is

(A) (B)

(C) (D)

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29. Let roots of x 2 3x + 2 = 0 are and , then quadratic equation whose roots are + and is(A) x2 + 5x + 5 = 0 (B) x 2 5x 6 = 0 (C) x 2 5x + 6 = 0 (D) x 2 + 5x + 6 = 0

30. Number of real values of x satisfying the equation xlog2 33 2 x 3 = 0 is(A) zero (B) 1 (C) 2 (D) more than 2

31. In the given figure (circle) PT = 5, PD = 7 and PA = 2, then the value of PB + PC is

(A)14

125(B)

14225

(C)14

325(D)

1455

32. If x = 3 257 3 257

1, then the value of x 3 + 3x 4 is equal to

(A) 2 (B) 0 (C) 10 (D) 4

SECTION - II

Multiple Correct Answer Type This section contains 5 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its

answer, out of which ONE OR MORE is/are correct.

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37. A value of log 4 / 14 / 14 / 1 )256()81()1( is

(A)41

(log 1 + log 81 + log256) (B) log1 + 3log2

(C) log 8 (D)21

(log1 + log 81 + log 256)

SECTION - III

Reasoning Type This section contains 3 reasoning type questions. Each question has 4 choices (A), (B), (C) and (D),out of which ONLY ONE is correct.

38. STATEMENT -1 : Let a, b, c R, then a 2 + b 2 + c 2 ab bc ac = 0 a = b = c.STATEMENT -2 : (x y)2 + (y z)2 + (z x)2 = 0 x = y = z.(A) Statement -1 is True, Statement -2 is True ; Statement -2 is a correct explanation for Statement -1(B) Statement-1 is True, Statement-2 is True ; Statement-2 is NOT a correct explanation for Statement-1(C) Statement -1 is True, Statement -2 is False(D) Statement -1 is False, Statement -2 is True

39. STATEMENT -1 : ln1 + ln2 + ln3 = ln(1 + 2 + 3).STATEMENT -2 : l

n (a + b + c) =lna +

lnb +

lnc , where a, b, c are positive.(A) Statement -1 is True, Statement -2 is True ; Statement -2 is a correct explanation for Statement -1

(B) Statement-1 is True, Statement-2 is True ; Statement-2 is NOT a correct explanation for Statement-1(C) Statement -1 is True, Statement -2 is False(D) Statement -1 is False, Statement -2 is True

40. STATEMENT -1 : 11121 .STATEMENT -2 : x2 = 121 x = 11.(A) Statement -1 is True, Statement -2 is True ; Statement -2 is a correct explanation for Statement -1(B) Statement-1 is True, Statement-2 is True ; Statement-2 is NOT a correct explanation for Statement-1(C) Statement -1 is True, Statement -2 is False(D) Statement -1 is False, Statement -2 is True


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SECTION - IV

Matrix - Match Type This section contains 2 questions. Each question contains statements given in twocolumns, which have to be matched. The statements in Column-I are labelledA, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Anygiven statement in Column-I can have correct matching with ONE OR MORE

statement(s) in Column-II . The appropriate bubbles corresponding to the answers

to these questions have to be drakened as illustrated in the following example.If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening ofbubbles will look like the following :

41. Column - I Column - II

(A) The value of log 2 816 is (p) 27

(B) The value of log 5 625254

is (q) 629

(C) The value of log 11

3 133114641121 is (r)

211

(D) The value of log 2 84

42

3

is (s)25

(t) 3


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42. Column - I Column - II

(A) The value of 3612 + 36 12 is (p) 32

(B) Sum of roots of the equation x 2 7|x| + 12 = 0 is (q) 3

(C) If x = 2 + 3i , then the value of x 2 4x + 9 is (r) 6

(D) Let N = log 23. log 34. log 45. log 56. log 67. log 78 (s) 2then the value of [N] is(where [ .] denotes greatest integer function)

(t) 0


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PART IIISECTION - I

Straight Objective Type This section contains 11 multiple choice questions. Each question has choices (A), (B), (C) and (D),out of which ONLY ONE is correct.

43. Value of10

cos10

sin 22 is :

(A)21 (B) 2 (C) 1 (D) can't be calculated

44. If y = e x nx, thendxdy

will be :

(A) e x +x1

(B)x

e x(C) e xx + e x nx (D) e x nx +

xe x

45. The value of 2 /

0

2 dxxsin will be :

(A) 1 (B) 0 (C)4

(D)2

46. Component of j

4i

3 along j

i

will be :

(A)2

5(B) 7 (C)

2

7(D) 27

47. If two positive numbers x & y are such that x + 2y = 60 then maximum value of xy will be :

(A) 900 (B) 450 (C) 1000 (D) Infinite

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48. The resultant of two forces 3F and 2F is R, if first force is doubled, the resultant is also doubled. Thenthe angle between the forces is :(A) 30 (B) 60 (C) 120 (D) 150

49. If j

i

F1 and k

5 j

4i

3F2 then angle between 1F and 2F is :

(A) cos 1107

(B) cos 152

3(C) cos 1

55

3(D) cos 1

53

50. The resultant of two forces acting at an angle 150 is 100 N and is perpendicular to one of the forces.The other force is :

(A) 200 N (B) 3100 N (C) 3200 N (D) 3200

N

51. A particle is dropped from a tower. It is found that it travels 45m in the last second of its journey. Theheight of the tower is : (take g = 10 m/s 2)(A) 125 m (B) 250 m (C) 100 m (D) 62.5 m

52. If y = x 3 then (x+1)dy is :

(A)2

x2+ x + C (B)

4x3 4

+ x 3 + C (C)4x3 4

+ 3x 3 + C (D) x 2 + x + C

53.dxd

sin 3 x is :

(A) 3 sin 2 x (B) 3 sin 2x cos x

(C) 3x 2 sin x (D) 9x 2 sin 2x

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SECTION - III

Reasoning Type This section contains 3 reasoning type questions. Each question has 4 choices (A), (B), (C) and(D), out of which ONLY ONE is correct.

59. Statement-1 : A physical quantity that has both magnitude and direction, must be vector.Statement-2 : Electric current is a scalar quantity.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True

60. Statement-1 : If velocity and acceleration are in opposite direction, speed decreases.Statement-2 : A particle having negative acceleration will slow down.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True

61. Statement-1 : Average speed is never less than magnitude of average velocity.Statement-2 : Distance travelled is always greater than or equal to displacement.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True


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SECTION - IV

Matrix - Match Type This section contains 2 questions. Each question contains statements given in twocolumns, which have to be matched. The statements in Column-I are labelledA, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Anygiven statement in Column-I can have correct matching with ONE OR MOREstatement(s) in Column-II . The appropriate bubbles corresponding to the answersto these questions have to be darkened as illustrated in the following example.If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening ofbubbles will look like the following :

62. Match the integrals (given in column II) with the given functions (in column I)

Column I Column II

(A)

dxx1

x2sin (p) 2sin2x

x1

+ C

(B)

dxx1

2x

cos2 (q) Cx

12

x2cos2

(C) dx)x2eccosx(sec22

(r) Cnx2x2cos

(D)

dxxx1

(s) tanx C2

x2cot

(t) nx +3

x2 2 / 3+ C

63. If displacement of a particle is given by x = (t 3 + t 2 + t)m, then match the quantities in column I withapproximate answer in column II.

Column I Column II

(A) Average velocity in time interval (p) 14t = 0 to t = 2 sec. (in m/s)

(B) Instantaneous velocity at (q) 8t = 2 sec. (in m/s)

(C) Average acceleration in time (r) 5interval t = 0 to t = 2 sec. (in m/s 2)

(D) Instantaneous acceleration (s) 7at t = 2 sec. (in m/s 2)

(t) 17


jee_2012_pt-1(paper 2)

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