interpreting triangle diagram
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Interpreting a Ternary Liquid-
Liquid Triangle DiagramMike Hansen
ChEn 3603, Spring 2013
University of Utah
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Where are we?
•In the textbook, this is Section 5 of
Chapter 4
• In the notes, this is the set on Single Stage
Equilibrium
• Just finished flash drums
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Example Problem
• We’ll do an example problem involving
water, ethylene glycol, and furfural
• Furfural completely dissolves ethylene
glycol, but only partially dissolves water
We’re using furfural to separate
ethylene glycol from water
Solvent
Solute Carrier
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Triangle Diagram: Basics
Ethylene Glycol Water
Furfural
0
10
01
1PURE
PUREPURE
Binary mixture with
no water
Binary mixture with
no furfural
Binary mixture with
no ethylene glycol
Ternary
mixture
Be careful in reading back to the composition!
If you forget how toread the compositions,
use the zero lines
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Triangle Diagram:
Miscibility Boundary
Ethylene Glycol
Miscibility Boundary
Two Phase Region
Single
PhaseRegion
Water
Furfural
made by adding water to
ethylene glycol & furfuralmixture until there
is cloudiness (2nd phase)
0
1001
1
We need to be in the two-phase
region (extract & raffinate)
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Triangle Diagram:
Tie Lines & Plait Point
Ethylene Glycol Water
Furfural
0
1001
1Plait Point
Tie lines converge to the Plait Point,
where both liquid phases (extract and raffinate) have the same
composition
Tie Lines
Tie lines connect equilibrium points on
the miscibility boundary
Extract
Composition
(Phase 1)
Raffinate
Composition(Phase 2)
Mix(Feed + Solvent)
Feed + Solvent --> Mix composition --> Tie Line --> Extract and Raffinate composition at two-phase equilibrium
At 2-phase equilibrium,these are our extract and
raffinate compositions!
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Triangle Diagram:
Getting the Input Point
Ethylene Glycol
Water
Furfural
0
1001
1
Mix
Solvent composition
Feed
comp.
S
F
Points S and F define the line
M
the mix point M is found with the inverse-lever-arm rule
F
S =
SM
MF
flow rates
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Triangle Diagram:
Getting the Outflows
Ethylene Glycol
Water
Furfural
0
1001
1
Mix
Find the tie line that point M lies on
M
Use the inverse-lever-arm rule again...
unknown
flow rates
E
R
Total mass/mole balance to complete
E +R = F + S
EM +RM = ER
geometrically:
Extend to the extract and raffinate compositions
E
R =
RM
EM