heat transfer - prado

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    Evaluation of the Overall

    Heat Transfer Coefficient for aPilot Scale Heat Exchanger

    Josie Prado

    Erin Hadi

    Trevor Binney

    February 3rd, 2005

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    Project Objectives

    Project Planning and Execution

    Background and Experimental Procedure Results and Discussion

    Conclusions

    Recommendations for Future Work

    Presentation Overview

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    Project Objectives1) Experimentally determine the overall heat transfer

    coefficient (Uo)

    Laminar and turbulent flow regimes

    Co-current and counter current operation2) Correlate Uo to the liquid flow rate in the inner pipe inthe form Uo = aV

    b

    3) Compare experimental results with predicted and

    reported values4) Investigate the effect of the steam trap

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    Project Planning

    1) Design of Experiment

    Review equipment operation

    Determine what parameter(s) will be varied

    Determine what measurements to take2) Rotameter Calibration

    Cold water rotameter

    Range ~ 5 -100

    Quench water rotameter Range ~ 1.5-10

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    Project Planning

    3) Data Collection

    Co-current flow

    Without steam trap

    With steam trap Counter-current flow

    Without steam trap

    With steam trap

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    Project Planning

    4) Data Analysis

    Empirical Analysis

    Determination of Uo from experimental data

    Correlation of Uo to cold water flow rate by fitting thedata to a power curve

    Theoretical Analysis

    Performed from fundamental principles of heattransfer

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    Project Planning

    Roles and Responsibilities

    Josie Prado (Team Leader)

    Temperature, pressure, and flow rate measurements

    Trevor Binney (Safety Coordinator)

    Scale operator and timer

    Erin Hadi (Operations Manager)

    Data Entry

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    Project Planning

    Safety Issues

    Steam burns

    Mitt was used for all steam valve adjustments

    Steam trap configuration was checked before makingadjustments

    Tripping Hazards

    Hoses were kept away from major traffic areas

    Slipping Hazards

    Rubber sole shoes were worn at all times

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    Equipment Dimensions &Specifications

    Double pipe exchanger Inner Pipe: 1ID/1.125OD

    Outer Pipe: 2ID/2.125OD

    Length: 60 Cold water supply

    Tap water 9 to 10 C

    Steam Supply 26 to 29 psig

    ~128 C

    ri

    ro

    Steam

    Water

    Inner pipe(Cu)

    Outer pipe(Cu)

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    Background

    Resistance to Heat Transfer

    Convective: between surface and adjacent

    fluid Water/pipe interface

    Steam/pipe interface

    Conductive:

    Through the inner pipe

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    Heat Exchanger SetupCounter-Current Operation

    Water in

    Steam in

    Water Out

    Steam Out

    Thermocouples

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    Experimental Procedure Rotameter Calibration

    Set rotameter flow rate to a specific value

    Measure mass of water entering the drumover time

    10 lbs of water per interval of time Calculate flow rate in lb/s

    Generate calibration curve

    Physical Constraint

    Flow rate required for laminar flow isoutside the rotameters measuring range

    Max laminar flow rate = 0.08 lb/s

    Quench rotameter reading of 1.35

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    Experimental Procedure

    Collecting Data Set equipment configuration

    Co-current/Counter-current

    Steam trap ON/OFF

    Set flow rate & wait for steady state to be reached

    Record stream temperatures, pressure, and flow rates

    Take several readings at each set of conditions

    Weigh and time the collection of steam and quench water

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    Experimental Data Analysis

    Empirical Uo was calculated from data

    For co-current:

    For counter-current:

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    Results

    Quencher Calibration Data

    y = 0.0528x + 0.0087

    R2 = 0.9985

    0.0

    0.1

    0.1

    0.2

    0.2

    0.3

    0.3

    0.4

    0.4

    0.5

    0 2 4 6 8

    Rotameter Reading

    Massflowrate(lb/s)

    Quencher Linear (Quencher)

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    Results Cold Water Calibration Data

    y = 0.0129x + 0.0256

    R2 = 0.9983

    0.0

    0.1

    0.2

    0.3

    0.4

    0.5

    0.6

    0.7

    0.8

    0 10 20 30 40 50 60

    Rotameter reading

    Massflowrate(lb/s)

    Cold Water Linear (Cold Water)

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    Results

    Configuration # Data pts. Correlation R2

    Co-current w/o steam trap 18 Uo = 2931.9*V0.1857 0.95

    Counter-current w/o steam trap 22 Uo = 2540.8*V0.2154 0.89

    Co-current w/ steam trap 9 Uo = 2950.9*V0.1846 0.99

    Counter-current w/ steam trap 9 Uo = 2582.8*V0.3114 0.99

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    Results

    Overall Heat Transfer Coefficient vs. Water

    Velocity

    2000

    2100

    2200

    2300

    2400

    2500

    26002700

    2800

    2900

    3000

    0.00 0.20 0.40 0.60 0.80 1.00 1.20

    water velocity (m/s)

    Uo(W/m2K

    )

    Co-current without steam trapCounter-current without steam trapPower (Co-current without steam trap)Power (Counter-current without steam trap)

    Published data: Exchanger Uo values between 2280 3400 W/m2K

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    Results Co-current & Counter-current Uo vs. water flow rate with and

    without steam trap in operation:

    2000

    2100

    2200

    2300

    2400

    2500

    2600

    2700

    2800

    2900

    0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2

    water velocity (m/s)

    Uo(W/m2K

    )

    counter-current steam trap off counter-current steam trap on

    co-current steam trap on co-current steam trap off

    Power (counter-current steam trap on) Power (counter-current steam trap off)

    Power (co-current steam trap off) Power (co-current steam trap on)

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    Results & Discussion

    Why is Uo higher for co-current flow than for countercurrent flow?

    Why is the change in enthalpy of steam much lower than

    the change in enthalpy of water? Hwater ~ 42 kJ/lb

    Hsteam ~ -11 kJ/lb

    Is it possible that some of the steam is condensing?

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    Results and Discussion

    Effect of condensation on co-current vs.counter current operation:

    More drastic temperature difference in

    co-current mode leads to immediateformation of a condensate film

    In counter-current flow, condensate filmformation is likely to begin further down the

    pipe

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    Results & Discussion

    Comparison with theoretical values

    Assuming no steam condenses:

    Uo = 185 - 205 W/m2K

    Taking condensation into account

    Uo = 900 - 1740 W/m2K

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    Conclusions

    1) Empirical Uo values are verified by publishedvalues

    2) Theoretical analysis does not invalidate

    experimental values if steam condensation istaken into account

    3) The steam trap did not have a significant effect onthe heat exchanger performance

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    Recommendations for Future Work

    1) Investigate the effect of water velocity on Uo inlaminar region

    A more sensitive rotameter would be required

    2) Investigate heat exchanger performance whilevarying both water and steam flow rate

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    References

    Incropera, Frank P. and David P. Dewitt. (2002) Fundamentals ofHeat and Mass Transfer. John Wiley and Sons. New York, pp. 470,486, 492, 647, 723.

    Perrys Chemical Engineers Handbook, 7th Edition (1997). R.H.Perry, D.W. Green, and J.O. Maloney, Eds. McGraw Hill: New York,pp. 5-20, 10-5, 11-4

    Welty, James R, Charles E. Wicks, Robert E. Wilson, and Gregory

    Rorrer (2001). Fundamentals of Momentum, Heat, and MassTransfer. Fourth Edition. John Wiley and Sons: New York, pp.201-209, 374, 723, 727, 733.

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    Questions?