graphical analysis of the relationship between circumference and diameter of a circle
TRANSCRIPT
Graphical Analysis of the Relationship between Circumference and Diameter of a
Circle
Graphical Analysis ExerciseDetermining the Relationship between
Circumference and Diameter
Procedure:
1. Measure the Circumference and diameter of five circular objects.
2. Analyze data using graphical analysis.
diameter, cm Circumference, cmDATA
53.1
2.14.88.811.517
7.515.428.336.2
DIAMETER, cm
CIRCUMFERENCE vs. DIAMETER
2468
10
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50
60
70
80
Plot a graph of Circumference versus diameter.
1. Is your graph a straight line?
CALCULATIONS AND OBSERVATIONS:
YES
2. Does the graph pass through the origin? YES…b = 0
3. Are circumference and diameter directly proportional? YES
4. Calculate the slope; Points Used:
(4.8cm,15.4cm) & (11.5cm,36.2cm)
slope =m=ΔYΔX =ΔC
Δd =36.2cm −15.4cm11.5cm−4.8cm =
20.8cm6.7cm =3.1
Slope has NO units
Y = m⋅X+b
What is the equation relating Circumference and diameter?
C d3.1⋅ 0+
C=3.1⋅dCompare slope = 3.1 to 314)
%error=experimental value-accepted value
accepted value×100%
% error =3.1 −3.14
3.14×100% = .04
3.14× 100% =1.3%
Non-Linear Graphs
What procedure do we follow if our graph is not a straight line?
Consider an experiment designed to investigate the motion of an object.
We want to determine the relationship between the object’s distance traveled and time.
We measure its distance each second for 10s.
Here is the resulting data.
time-t, s distance-d, m0 51 9.92 24.63 49.14 83.45 127.56 181.47 245.18 318.69 401.910 495
Data
We then plot a graph of distance versus time.
0
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500
0 1 2 3 4 5 6 7 8 9 10 11
time, s
Distance versus Time
Not a straight line but is a uniform curve
Compare graph to graphs of other functions of the
independent variable
0
1
2
3
4
5
6
7
Y
0 1 2 3 4 5 6 7
X
y=x
Y =mX+b
Y ∝ X
0
10
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30
40
Y
0 1 2 3 4 5 6 7
X
y=x2
Y ∝ X2
Y =mX2 +b
0
0.5
1
1.5
2
2.5
Y
0 2 4 6 8
X
y = x1/2
Y ∝ X
Y =m X +b
0
0.25
0.5
0.75
1
1.25
Y
0 1 2 3 4 5 6 7
X
y = 1/x
Y ∝ 1X
Y =m 1X +b
0
0.25
0.5
0.75
1
1.25
Y
0 1 2 3 4 5 6 7
X
y = 1/x 2
Y ∝ 1X2
Y =m 1X2 +b
0.4
0.5
0.6
0.7
0.8
0.9
1
1.1
Y
0 1 2 3 4 5 6 7
X
y = 1/x 1/2
Y ∝ 1X
Y =m 1X +b
0
1
2
3
4
5
6
7
Y
0 1 2 3 4 5 6 7
X
y=x
Y =mX+b
Y ∝ X
0
10
20
30
40
Y
0 1 2 3 4 5 6 7
X
y=x2
Y ∝ X2
Y =mX2 +b
0
0.5
1
1.5
2
2.5
Y
0 2 4 6 8
X
y = x1/2
Y ∝ X
Y =m X +b
0
0.25
0.5
0.75
1
1.25
Y
0 1 2 3 4 5 6 7
X
y = 1/x
Y ∝ 1X
Y =m 1X +b
0
0.25
0.5
0.75
1
1.25
Y
0 1 2 3 4 5 6 7
X
y = 1/x 2
Y ∝ 1X2
Y =m 1X2 +b
0.4
0.5
0.6
0.7
0.8
0.9
1
1.1
Y
0 1 2 3 4 5 6 7
X
y = 1/x 1/2
Y ∝ 1X
Y =m 1X +b
¸
0
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200
250
300
350
400
450
500
0 1 2 3 4 5 6 7 8 9 10 11
time, s
Distance versus Time
Plot a new graph where time squared is the independent variable:
Distance, d versus Time Squared, t2
time-t,s distance-d,m0 51 9.92 24.63 49.14 83.45 127.56 181.47 245.18 318.69 401.910 495
Revised Data Table
0149
162536496481
100
time2-t2, s2
Y=m⋅X +b
Analysis of Graph
distance timesquared
d t2
d=m⋅t2 +b
Slope Calculation :m = ΔY
ΔX = ΔdΔt2
Points Chosen :
(4s2 , 24.6m) and (64s2 ,318.6m)
m = 318.6m −24.6m64s2 −4s2 =294m
60s2
m =4.9 ms2
With units of m/s2 the slope represents the acceleration of the object.
d=4.9 ms2 ⋅t2 +b
intercept,bIt will be difficult to
determine the intercept from the graph!
Two Other Methods for Determining the Intercept
1. The intercept is the value of the dependent variable where the graph intersects the vertical axis. At this point the value of the independent variable is zero.
Look at the data table to determine the value of d where t2 equals zero. t2 =0⇒ b=5m2. Start with the partial equation:
Solve for “b”:
d =4.9 ms2 ⋅t2 +b
b =d−4.9 ms2 ⋅t2
Choose any data pair and substitute the values of “d” and “t2” into the equation for “b”: (25s2, 127.5m)
b =127.5m−4.9 ms2 ⋅25s2 b =5m
Final Equation
d=4.9ms2 ⋅t2 +5m
Graphical Analysis of “Free-Fall” Motion
Determining the Acceleration Due to Gravity
Purpose:In this lab, you will determine the correct description of free-fall motion and to measure the value of the
acceleration due to gravity, g.
Introduction: The Greek natural philosopher Aristotle was one of the first to attempt a “natural” description of an object undergoing free-fall motion. Aristotle believed that objects moved according to their composition of four elements, earth, water, air, and fire. Each of these elements had a natural position with earth at the bottom, then water, then air, and fire at the top. If a rock, composed primarily of earth, was held in the air and then released its composition would cause it to return to the earth. Accordingly, Aristotle thought that objects fell with a constant speed which was proportional to the object's weight, that is, a heavier object would fall faster than a lighter one.
Motion at a constant speed can be described by the equation:
Comparing the equation above with the slope-intercept equation of a straight line, Y = mX + b,
where d is the distance fallen, v is the speed, and t is the time the object has been falling.
we see that a graph of distance fallen versus time should be a straight line passing through the origin (d directly proportional to t), and the slope of the line would give the speed, v, at which the object was falling.
d =v⋅t
d =v⋅t
Y =m⋅X +b
dependent variableindependent variableslope 0||
where d is the distance fallen, a is the acceleration, and t is the time the object has been falling.
In the late 16th and early 17th centuries Galileo challenged much of the work of Aristotle. Working with objects rolling down inclined planes he demonstrated that objects fall with a constant acceleration that is independent of their weight. According to Galileo objects fell with a speed that changed uniformly and at the same rate for all objects.
Motion at a constant acceleration, starting from rest, can be described by the equation:
d = 12 a⋅t2
Comparing the equation above with the slope-intercept equation of a straight line, Y = mX + b,
we see that a graph of distance fallen versus time squared should be a straight line passing through the origin (d directly proportional to t2), and the slope of the line would equal one-half of the acceleration at which the object was falling.
d =12 a⋅t2
Y =m⋅ X +b
dependent variableindependent variableslope 0||
To find the true nature of Free-Fall:
Let a ball roll down an incline,
Measure the distance traveled after certain times,
Plot graphs of distance versus time and distance versus time-squared.
If distance versus time is a straight line then Free-Fall is at a constant velocity and the slope of the graph measures that velocity.
If distance versus time-squared is a straight line then Free-Fall is at a constant acceleration and the slope of the graph measures one-half of that acceleration.
v, velocity = m, slope
a, acceleration = 2m, 2 x slope
The Acceleration Due to Gravity
If distance versus time-squared is a straight line then Free-Fall is at a constant acceleration and the slope of the graph measures one-half of that acceleration.
The acceleration, a, found from the slope of the d vs t2 graph is related to but not equal to the acceleration due to gravity, g.
To find the actual value of g we must account for the effect of the incline.
g =a×Lh
L
h
CBR
CBL
Using Graphical Analysis to Investigate the Motion of a
Simple Pendulum
QuickTime™ and aAnimation decompressor
are needed to see this picture.
The composition and motion of a pendulum can be described in terms of four measurable quantities.
Independent Variables
MassLengthAmplitude
Dependent Variable
Period
On which of the independent variables is the period dependent?
Only two variables can be investigated at a time.
Period versus MassLength & Amplitude constant
Period versus AmplitudeLength & Mass constant
Period versus LengthMass & Amplitude constant
Investigating the dependence of the Period on the Mass of the pendulum.
Varying the mass while keeping the amplitude and length constant
Experimental Set-Up
As the pendulum swings the CBR emits sound waves which reflect off of the pendulum and return to the CBR.
The CBR calculates the distance to the pendulum and sends the data to the TI-83 which then plots the position of the pendulum versus time.
CBRTI-83
Sound Waves
CBR / TI-83 Set-UPConnect the CBR to the TI-83
Press: APPS
Press “4” CBL/CBR
Press “Enter”
Press “2” Data Logger
Data Logger Set-Up
Probe
# SAMPLES
INTRVL (SEC)
UNITS
PLOT
DIRECTNS
GO...
Sonic
Enter: 75
Enter: .02
Select: m
Select: REAL TIME
Select: ON
Press "Enter"
Press: Enter
CBR/CBL Set-Upcontinued
Press “2” CBR
After CBR-CBL link has been tested:Press: “Enter”
After “Status OK”:Press: “Enter”
When you are ready to begin taking data”Press: “Enter”
After data collection is complete the TI-83 will plot a graph of the pendulum’s position versus time.
Dependence of the Period on the Mass of the Pendulum
Length, cm (constant)
Amplitude, cm (constant) Mass,g Trial # Period,
s
Data TableDependence on Mass
0.200.21
0.230.21
Each group will use a different mass and determine the pendulum’s period. Then the period related to each mass will be recorded in a composite data table.
From this composite data table each group will determine whether or not the period of a pendulum depends on its mass.
120202020
23
Average
Dependence of the Period on the Amplitude and Length of the Pendulum
We will now use Interactive Physics to simulate the motion of a simple pendulum and determine the dependence of the Period on Amplitude and Length.
Mass = 6.0kg Length = 10.0mAmplitude, cm Period, s
0.51.01.52.02.53.03.54.04.55.05.5
6.336.336.336.336.336.336.336.336.336.336.33
Does the Period of a Pendulum depend on its Amplitude?We will first exam the dependence on the Amplitude by choosing a mass (6kg) and a length (10m) and holding them constant while varying the amplitude.
Does the Period depend on the Length?Choose any mass (6kg) and amplitude (3m) and hold them constant while varying the length.
Mass = 6.0kg Amplitude = 3.0mLength, cm Period, s
4567891011
4.024.504.925.315.676.036.336.66
Does the Period of a Pendulum depend on its Length?
What is the mathematical relationship between Period and Length?
We will begin by plotting a graph of Period, T versus Length, L.
If this graph is a straight line we then determine its slope and y-intercept and use the general slope-intercept equation to determine the relationship between T and L. T =mL+b
Length, m
Period versus Length
If the graph of period versus length is not a straight line we must determine what function of L to graph next.
Study the various graph shapes to determine which one most resembles the graph of Period versus Length.
0
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y
0 5 10 15 20x
x2
x
x0
0.25
0.5
0.75
1
1.25
y
0 5 10 15 20x
1x
1x2
1x
Once a new function of L has been chosen, create a new column in the data table for that function.
Revised Data Table
Next, plot a new graph of Period versus New Function of L.
Length, mNew Function
of Length, units
Period, s
4 4.02
5 4.50
6 4.92
7 5.31
8 5.67
9 6.03
10 6.33
11 6.66
Convert lengths based on new function.
New Function of Length
Period versus New Function of Length
If this graph is a straight line, use the general slope-intercept equation to determine the relationship.
T =m( )new function of L+bIf this graph is not a straight line, continue the process with a different function of L until a straight line graph is achieved.