fire hydraulic calculation (process bldgs)

Hydraulic Calculation Cover Sheet(For Process Buildings)

Project title : Doha North Sewerage Treatment Plant and Associated WorksCalculation title : Hydraulic calculation and analysis for Fire Fighting System

(Process Buildings)Ref : DNSTW_FIRE_CAL_002Fire Protection Systems Hydraulic AnalysisThe plant is provided with a dedicated hydrant system served by fire pumps located in the process area. This is shown on dwg no. K654_402_02_0011 & 0013 and schematically in Figure 3, 4 & 5.

The fire pumps provided have the flow characteristics 5568.64 L/min @ 641.07 kPa1471.24 gpm @ 92.96 psi

The hydrant network provides fire fighting water for the Workers Accommodation sprinkler system. The hydraulic calculation was done in DNSTW_FIRE_CAL_001 (which is submitted on previous

submission Permit ID 16421)

Hydrant NetworkThe most remote point of the hydrant network is the Workers Accommodation.The building requires 3 hydrants.The flow rate for these are as follows.

500 gpm 1893 Lpm250 gpm 946 Lpm250 gpm 946 Lpm

1000 gpm 3785 LpmThe minimum pressure available at the most remote hydrant is 350 kPa (50 psi) as required by the codes The flow characteristics required from the fire pumps considering the friction losses in the hydrant network piping are calculated in DNSTW_FIRE_CAL_001 as 3785 L/min @ 551 kPa

Sprinkler Network @ Workers AccommodationBy observation the most remote 139m2 area of operation is located under the atrium ceiling (the highest point). See drawing no: K654_406_02_4029The actual area of operation is 145 m2. The number of sprinklers in the area of operation is 16.The minimum flow rate from each sprinkler, q

is (4.1Lpm/m2 x 145m2)/16 spks = 37.16Lpm )Using quick response sprinklers with K-factor of 8.06 Lpm/kPa, the minimum pressure required at the most remote sprinkler = (37.16/8.0)2 = 21.24kPa

Based on this minimum pressure requirement at the most remote sprinkler and their elevation at 9.26m, the pipe friction losses are calculated in DNSTW_FIRE_CAL_001 up to the connection point on the hydrant network.The minimum required at connection to hydrant network for the sprinkler system is 897L/min @ 288kPa.The flow and pressure available at the connection is 1,893L/min @ 386kPa.

Most remote Hydrant2nd Hydrant3rd HydrantTotal flow

Sprinkler Network @ Dried Sludge Storage Building no. 14 (see Table 3)Storage classified as Class IV Commodities.By observation the most remote 186m2 area of operation is located far end of the building.(NFPA13, Table 16.2.1.3.2 & FIGURE 16.2.1.3.2(g))See drawing no: K654_406_02_2306The actual area of operation is 186.9 m2. The number of ceiling sprinklers in the area of operation is 20.According to NFPA13, Curve A of FIGURE 16.2.1.3.2(g), High temperature ceiling sprinklers and Ordinarytemperature in-rack sprinklers will be used.The design density is 15.9 mm/min (as per NFPA13, Table 16.2.1.3.2 & FIGURE 16.2.1.3.2(g))40% reduced design density is 9.54 mm/min (as per NFPA13, Table 16.2.1.3.4.3)The minimum flow rate from each ceiling sprinkler, q

is (9.54mm/min x 186.9m2)/20 spks = 59.96L/min )Using high temperature sprinklers with K-factor of 11.52 Lpm/kPa, the minimum pressure required at themost remote ceiling sprinkler = (89.2/11.52)2 = 59.96kPa

The number of in-rack sprinklers in the area of operation is 14 (most remote seven on each two top levels)Minimum discharge pressure for in-rack spk is 15 psi (103.5 kPa). (as per NFPA13, 16.2.4.4 )Using ordinary temperature sprinklers with K-factor of 8.06 Lpm/kPa, the minimum flow required at themost remote in-rack sprinkler = (8.06 x 103.51/2 )= 82.04 L/min

Based on this minimum pressure requirement at the most remote sprinkler and their elevation at 7.5m, The pipe friction losses are calculated in TABLE 3 up to the fire pumpThe total requirement up to the fire pump is 5568.64 L/min @ 641.07 kPa

Sprinkler Network @ Thermal Drying Plant (see Table 4)Hazard Classification = Ordinary Hazard Group 2By observation the most remote 139m2 area of operation is located far end of the building.See drawing no: K654_406_02_2509The actual area of operation is 147.5 m2. The number of sprinklers in the area of operation is 16.The minimum flow rate from each sprinkler, q

is (8.1mm/min x 147.5m2)/16 spks = 74.68L/min )Using quick response sprinklers with K-factor of 8.06 Lpm/kPa, the minimum pressure required at the most remote sprinkler = (74.68/8.06)2 = 85.77kPa

Based on this minimum pressure requirement at the most remote sprinkler and their elevation at 20m, The pipe friction losses are calculated in TABLE 4 up to the fire pumpThe total requirement up to the fire pump is 2438.84 L/min @ 590.38 kPa

Sprinkler Network @ Silo (see Table 5)Hazard Classification = Ordinary Hazard Group 2By observation the most remote 139m2 area of operation is located far end of the building.See drawing no: K654_406_02_2509The actual area of operation is 140.3 m2. The number of sprinklers in the area of operation is 16.The minimum flow rate from each sprinkler, q

is (8.1mm/min x 140.3m2)/16 spks = 71.02L/min )Using quick response sprinklers with K-factor of 8.06 Lpm/kPa, the minimum pressure required at the most remote sprinkler = (71.02/8.06)2 = 77.57kPa

Based on this minimum pressure requirement at the most remote sprinkler and their elevation at 27m, The pipe friction losses are calculated in TABLE 5 up to the fire pumpThe total requirement up to the fire pump is 2295.71 L/min @ 564.26 kPa

ConclusionAfter series of hydraulic calculation, it is observed that high demand and high pressure loss required at Dried Sludge Storage Building no. 14,Therefore, the fire pump flow characteristics should be 5568.64 L/min @ 641.07 kPa

0 TT HK GEKREV PREPARED CHECKED APPROVEDDATE DESCRIPTION CLIENT'S APPROVED

05-Feb-11 Hydraulic Calculation

Hydraulic Calculation for Sprinkler System at Dried Sludge Storage Building No. 14Storage Commodities Class = IV

Minimum Area of Sprinkler Operation = 186 m2 (NFPA13, Table 16.2.1.3.2 & FIGURE 16.2.1.3.2(g))Actual Area of Sprinkler Operation (Ceiling Sprinklers) = 186.9 m2 >186 m2 (See dwg: K654_406_02_2306 )

Coverage per sprinkler, a = 9.35 m2No. of sprinkler calculated = 20 nos.

Design density = 15.9 mm/min (NFPA13, Table 16.2.1.3.2 & FIGURE 16.2.1.3.2(g))40% reduced Design density, D = 9.54 mm/min (as per NFPA13, Table 16.2.1.3.4.3)

Sprinkler discharge characteristics, K = 8 gpm/(psi)1/2 = 11.52 L/min/(kPa)1/2K = Q / p (NFPA 13 , clause 14.4.2.4.3)p = (Q/K)2Q = K p

Pipe Fittings & Devices Qty Notes

(L/min) (m) (kPa)1 #1 q DN32 90 Std Elbow 1 L C = 120 Pt 59.96 Q = 9.35 x 15.9 = 89.2

F 1.01 Pe p = ( 89.2 / 11.52 ) = 59.96Q 89.2 T 1.01 2.9227 Pf 2.96

#2 q 91.38 DN32 L 3 C = 120 Pt 62.92 q =11.52 x 62.92 = 91.38

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Nozzle Ident. & Location

Flow Pipe Size

TABLE 3

Pressure Summary

(kPa/m)

Hydraulic Calculation

Eqv. Pipe Length

Friction loss / m

2

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#2 q 91.38 DN32 L 3 C = 120 Pt 62.92 q =11.52 x 62.92 = 91.38F Pe

Q 180.58 T 3 10.7758 Pf 32.33#3 q 112.44 DN32 L 3 C = 120 Pt 95.25 q =11.52 x 95.25 = 112.44

F PeQ 293.02 T 3 26.3858 Pf 79.16

2 q DN40 90 Std Elbow 1 L 3 C = 120 Pt 174.41 Kc = 293.02 / 174.41R/ Tee 1 F 1.22 Pe 15 Kc = 23

Q 293.02 T 4.22 9.8071 Pf 41.393 q 349.42 DN100 L 3 C = 120 Pt 230.8 q =23 x 230.8 = 349.42

F PeQ 642.44 T 3 0.2789 Pf 0.84

4 6 in-rack q 350.06 DN100 L 3 C = 120 Pt 231.64 q =23 x 231.64 = 350.06sprinkler qir 521.65 F Pe

Q 1514.15 T 3 1.3624 Pf 4.09 Kir = 34.35 q 353.14 DN100 L 3 C = 120 Pt 235.73 q =23 x 235.73 = 353.14

F PeQ 1867.29 T 3 2.0078 Pf 6.03

2

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6 6 in-rack q 357.62 DN100 L 3 C = 120 Pt 241.76 q =23 x 241.76 = 357.62sprinkler qir 533.32 F Pe qir = 34.3 x 241.76 = 533.32

Q 2758.23 T 3 4.1319 Pf 12.47 q 366.68 DN150 L 3 C = 120 Pt 254.16 q =23 x 254.16 = 366.68

F PeQ 3124.91 T 3 0.7013 Pf 2.11

8 2 in-rack q 368.2 DN150 L 3 C = 120 Pt 256.27 q =23 x 256.27 = 368.2sprinkler qir 183.03 F Pe

Q 3676.14 T 3 0.9471 Pf 2.859 hose q 1892.5 DN150 L 68 C = 120 Pt 259.12 +500gpm for inside+ outside hose stream

stream F Pe (As per NFPA13, Table 16.2.1.3.5 )demand Q 5568.64 T 68 2.0421 Pf 138.87 500 gpm = 1892.5 L/min

10 q DN200 90 Std Elbow 4 L 62 C = 120 Pt 397.99Gate Valve 1 F 51.54 Pe 70

Q 5568.64 Alarm Check Valve 1 T 113.5 0.5328 Pf 60.511 Under q DN200 90 Std Elbow 1 L 12.5 C = 140 Pt 528.49

-ground F 6.1 Pe 15pipe Q 5568.64 T 18.6 0.4006 Pf 7.46

12 Under q DN200 L 155.5 C = 140 Pt 550.95-ground F Pepipe Q 5568.64 T 155.5 0.4006 Pf 62.3

13 Under q DN250 90 Std Elbow 1 L 234.5 C = 140 Pt 613.25

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13 Under q DN250 90 Std Elbow 1 L 234.5 C = 140 Pt 613.25-ground Equal Tee (Flow thru branch) 1 F 22.86 Pe -15pipe Q 5568.64 T 257.4 0.1210 Pf 31.13

14 q DN250 90 Std Elbow 3 L 17 C = 120 Pt 629.38F 22.86 Pe -25

Q 5568.64 T 39.86 0.1609 Pf 6.4215 Pump q DN200 R/ Tee 1 L 1.5 C = 120 Pt 610.8

Alarm Check Valve 1 F 27.14 Pe 15Q 5568.64 Gate Valve 1 T 28.64 0.5328 Pf 15.27

641.07Total Calculated Flow = 5568.64 L/min Total required head = 641.07 kPa

= 1471.24 gpm = 64.11 mH2O= 92.96 psi

Total required flow = 1471.24 gpm @ 92.96 psi= 92.82 L/s @ 64.11 mH2O

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In-rack Sprinkler Calculation

No. of In-rack sprinkler calculated = 14 nos.(seven on each two top levels) by NFPA13, 16.2.4.3.1Min discharge pressure for in-rack spk = 15 psi (NFPA13, 16.2.4.4 )

= 103.5 kPaSprinkler discharge characteristics for in-rack spk, K = 5.6 gpm/(psi)1/2 = 8.064 L/min/(kPa)1/2

K = Q / p (NFPA 13 , clause 14.4.2.4.3)p = (Q/K)2Q = K p


(L/min) (m) (kPa)a #a q DN32 90 Std Elbow 1 L C = 120 Pt 103.5 Q =8.064x 103.5 = 82.04

F 1.01 PeQ 82.04 T 1.01 2.5036 Pf 2.53

b #b q 83.04 DN32 L 2.4 C = 120 Pt 106.03 q =8.064 x 106.03 = 83.04F Pe

Q 165.08 T 2.4 9.1273 Pf 21.91c #c q 91.22 DN32 L 2.4 C = 120 Pt 127.94 q =8.064 x 127.94 = 91.22

F PeQ 256.3 T 2.4 20.5966 Pf 49.44

Friction loss / m

Pressure Summary

(kPa/m)R ef

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Flow Pipe Size

Eqv. Pipe Length

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Q 256.3 T 2.4 20.5966 Pf 49.44d q DN40 90 Std Elbow 1 L 0.3 C = 120 Pt 177.38 Kir = 256.3 / 177.38

F 1.22 Pe Kir = 19.3Q 256.3 T 1.52 7.6553 Pf 11.64

e q 265.35 DN50 L 1.6 C = 120 Pt 189.02 q =19.3 x 189.02 = 265.35F Pe -16

Q 521.65 T 1.6 6.2650 Pf 10.03f q DN50 L 8.8 C = 120 Pt 183.05

F Pe -25Q 521.65 T 8.8 6.2650 Pf 55.14

g DN65 L 1.5 C = 120 Pt 213.19F Pe

Q 521.65 T 1.5 1.9760 Pf 2.97Pt 216.16

The minimum required pressure at 'g' for in-rack sprinkler is 216.16kPaThe pressure available at 'g' is 230.8 kPa

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ISOMETRIC SKETCH_ FORM DRIED SLUDGE STORAGE BLDG (NO. 14)TO FIRE PUMPS

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FIGURE 3

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Hydraulic Calculation for Sprinkler System at Thermal Drying PlantClassification of Occupancies = Ordinary Hazard Group 2

Area of Sprinkler Operation = 139 m2

Actual Area of Sprinkler Operation = 147.5 m2 >139 m2 (See dwg: K654_406_02_2509 )Coverage per sprinkler, a = 9.22 m2

No. of sprinkler calculated = 16 nos.Design density, D = 8.1 mm/min

Sprinkler discharge characteristics, K = 5.6 gpm/(psi)1/2 = 8.064 L/min/(kPa)1/2



(L/min) (m) (kPa)1 #a q DN32 90 Std Elbow 1 L C = 120 Pt 85.77 Q = 9.22 x 8.1 = 74.68

F 1.01 Pe p = ( 74.68 / 8.064 ) = 85.77

TABLE 4

Pressure Summary

(kPa/m)

Hydraulic CalculationR

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Flow Pipe Size

Eqv. Pipe Length

Friction loss / m

2

Page 8 of 15

F 1.01 Pe p = ( 74.68 / 8.064 ) = 85.77Q 74.68 T 1.01 2.1040 Pf 2.13

#b q 75.61 DN32 L 3 C = 120 Pt 87.9 q =8.064 x 87.9 = 75.61F Pe

Q 150.29 T 3 7.6724 Pf 23.02#c q 84.93 DN40 L 3 C = 120 Pt 110.92 q =8.064 x 110.92 = 84.93

F PeQ 235.22 T 3 6.5314 Pf 19.6

#d q 92.13 DN40 L 3 C = 120 Pt 130.52 q =8.064 x 130.52 = 92.13F Pe

Q 327.35 T 3 12.0379 Pf 36.12#e q 104.1 DN40 L 3 C = 120 Pt 166.64 q =8.064 x 166.64 = 104.1

F PeQ 431.45 T 3 20.0632 Pf 60.19

2 q DN50 R/ Tee 1 L 4.5 C = 120 Pt 226.83 K = 431.45 / 226.83F Pe 10 K = 29

Q 431.45 T 4.5 4.4095 Pf 19.85

2

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3 q 464.62 DN100 L 3 C = 120 Pt 256.68 q =29 x 256.68 = 464.62F Pe

Q 896.07 T 3 0.5162 Pf 1.554 q 466.02 DN100 L 3 C = 120 Pt 258.23 q =29 x 258.23 = 466.02

F PeQ 1362.09 T 3 1.1201 Pf 3.37

5 q DN100 L 3 C = 120 Pt 261.6q1 130.5 F Pe q1 = 8.064 x 261.6 = 130.5Q 1492.59 T 3 1.3267 Pf 3.99

6 q DN100 L 12 C = 120 Pt 265.59F Pe

Q 1492.59 T 12 1.3267 Pf 15.937 q 946.25 DN150 90 Std Elbow 9 L 134 C = 120 Pt 281.52 +250gpm for inside hose stream demand

Gate Valve 1 F 64.35 Pe 200 (As per NFPA13, Table 11.2.3.1.2 )Q 2438.84 Alarm Check Valve 1 T 198.4 0.4433 Pf 87.94 250 gpm = 946.25 L/min

8 Under q DN150 90 Std Elbow 2 L 5.5 C = 140 Pt 569.46-ground F 9.76 Pe 15pipe Q 2438.84 T 15.26 0.3333 Pf 5.09

9 Under q DN200 R/ Tee 1 L 90 C = 140 Pt 589.55-ground F Pe

Page 9 of 15

-groundpipe Q 2438.84 T 90 0.0870 Pf 7.83






= 644.35 gpm = 59.04 mH2O= 85.61 psi


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ISOMETRIC SKETCH_ FORM THERMAL DRYING PLANT TO FIRE PUMPS

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FIGURE 4

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Hydraulic Calculation for Sprinkler System at Thermal Drying Plant (Silo Area)Classification of Occupancies = Ordinary Hazard Group 2

Area of Sprinkler Operation = 139 m2

Actual Area of Sprinkler Operation = 140.3 m2 >139 m2 (See dwg: K654_406_02_2509 )Coverage per sprinkler, a = 8.77 m2

No. of sprinkler calculated = 16 nos.Design density, D = 8.1 mm/min

Sprinkler discharge characteristics, K = 5.6 gpm/(psi)1/2 = 8.064 L/min/(kPa)1/2



(L/min) (m) (kPa)1 #a q DN32 90 Std Elbow 1 L C = 120 Pt 77.57 Q = 8.77 x 8.1 = 71.02

F 1.01 Pe p = ( 71.02 / 8.064 ) = 77.57

TABLE 5Hydraulic CalculationR

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Flow Pipe Size

Eqv. Pipe Length

Friction loss / m

Pressure Summary

(kPa/m)

2

Page 11 of 15

F 1.01 Pe p = ( 71.02 / 8.064 ) = 77.57Q 71.02 T 1.01 1.9172 Pf 1.94

#b q 71.91 DN32 L 3 C = 120 Pt 79.51 q =8.064 x 79.51 = 71.91F Pe

Q 142.93 T 3 6.9918 Pf 20.98#c q 80.84 DN32 L 3 C = 120 Pt 100.49 q =8.064 x 100.49 = 80.84

F PeQ 223.77 T 3 16.0230 Pf 48.07

#d q 98.29 DN40 L 3 C = 120 Pt 148.56 q =8.064 x 148.56 = 98.29F Pe

Q 322.06 T 3 11.6805 Pf 35.052 q DN40 R/ Tee 1 L 0.75 C = 120 Pt 183.61 K = 322.06 / 183.61

F Pe 10 K = 24Q 322.06 T 0.75 11.6805 Pf 8.77

2

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3 q 341.43 DN100 L 3 C = 120 Pt 202.38 q =24 x 202.38 = 341.43F Pe

Q 663.49 T 3 0.2961 Pf 0.894 q 342.18 DN100 L 3 C = 120 Pt 203.27 q =24 x 203.27 = 342.18

F PeQ 1005.67 T 3 0.6390 Pf 1.92

5 q 343.79 DN100 L 3 C = 120 Pt 205.19 q =24 x 205.19 = 343.79F Pe

Q 1349.46 T 3 1.1010 Pf 3.316 q DN100 L 17 C = 120 Pt 208.5

F PeQ 1349.46 T 17 1.1010 Pf 18.72

7 q 946.25 DN150 90 Std Elbow 8 L 52.5 C = 120 Pt 227.22 +250gpm for inside hose stream demandGate Valve 1 F 59.47 Pe 275 (As per NFPA13, Table 11.2.3.1.2 )

Q 2295.71 Alarm Check Valve 1 T 112 0.3964 Pf 44.39 250 gpm = 946.25 L/min8 Under q DN150 90 Std Elbow 2 L 5.5 C = 140 Pt 546.61

-ground F 9.76 Pe 15pipe Q 2295.71 T 15.26 0.2980 Pf 4.55

9 Under q DN200 R/ Tee 1 L 90 C = 140 Pt 566.16-ground F Pe

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-groundpipe Q 2295.71 T 90 0.0778 Pf 7






= 606.53 gpm = 56.43 mH2O= 81.82 psi


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ISOMETRIC SKETCH_ FORM THERMAL DRYING PLANT (Silo Area) TO FIRE PUMPS

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FIGURE 5

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Overall requirement100% of rated capacity = 1471.2 gpm

100% of rated head = 92.96 psi150% of rated capacity = 2206.86 gpm

65% of rated head = 60.4 psi140% of rated head = 130.1 psi

Hydraulic CalculationFor Non-Process Buildings

Fire Pump CurveAs per NFPA 20, the pump's shutoff head will range from a minimum of 101 percent to a maximum of 140 percent of rated head. At 150 percent of rated capacity, head will range from a minimum of 65 percent to maximum of just below rated head.

Remarks:The fire sprinkler pumps shall be UL listed and FM aprroved.

Fire Water Tank Sizing

Required flow rate = 1471.24 gpm (as per calculation sheet)Required pressure = 79.96 psi (as per calculation sheet)

Type of Fire Fighting Pump = Horizontal CentrifugalType of Driven = Electric Motor Driven & Diesel Engine Driven

the duration of the water supply = 60~90 minsBut if the area shall be provided by the fire alarm system as well, the lower duration value shall be permitted. Therefore the duration of the water supply = 60 minsFire water tank is monitored by fire alarm system at all time and the main source of fire water is coming from TSE watertanks which total volume is 30,000 m3.The water capacity for the fire fighting system

= 1471.24 x 60= 88,274.40 gal= 334.15 m3

Hydraulic Calculation for Non-Process Buildings

fire hydraulic calculation (process bldgs)

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