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![Page 1: ExamView - Semester 1 Final Review - Weeblygiordanom.weebly.com/.../9/9/17992643/algebra_semester_1_final_revie… · Semester 1 Final Review Find the value of x that completes the](https://reader034.vdocuments.us/reader034/viewer/2022051918/600a14709fb99234c144af4c/html5/thumbnails/1.jpg)
Name: ________________________ Class: ___________________ Date: __________ ID: A
1
Semester 1 Final Review
Find the value of x that completes the statement.
1. x
36
106
a.53
b. 60 c. 10
What is an algebraic expression for the word phrase?
2. the difference of r and 3
a. 3r
b.r3
c. r – 3
3. 3 times the sum of b and f
a. 3(b + f )
b. 3 + b + f
c. 3b + f
What word phrase can you use to represent the algebraic expression?
4. 5x + 2
a. five times the sum of a number x and two
b. the sum of five times a number x and two
c. a number x times the sum of five and two
What is the simplified form of each expression?
5. 4(20 12) (4 3)
a. 92
b. 29
c. 128
6. 3 3 32 12 4
a. 867
b. 437
c. 291
7. Evaluate uz xy2
, for u = 20, x = 4, y = 7, and z = 10.
a. 294
b. 198
c. 786
8. Evaluate (ab) 2 for a = 4 and b = 3.
a. 36
b. 24
c. 144
Simplify each expression.
9. (8 + 7a) + 4
a. 12 + 7a
b. 12 + 11a
c. 8 + 11a
What is each sum?
10. –6 + (–3)
a. 3
b. –3
c. –9
What is the simplified form of each expression?
11. (4 – c)(–1)
a. 4 – c
b. –4 + c
c. 4 + c
What is the simplified form of each expression?
12. 8d 3w( )
a. 8d 3w
b. 8d 3w
c. 8d 3w
Is the equation true, false, or open? Explain.
13. 9p 8 10p 7
a. Open; there is a variable.
b. True; the expressions are the same for all values of the variables.
c. False; the expressions are never the same.
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Name: ________________________ ID: A
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14. Is x = 1 a solution of the equation 2 – 8x = –6?
a. yes
b. no
15. Is (3, 13) a solution of the equation y = 4x?
a. yes
b. no
What is the solution of the equation?
16. w 2 3
a. –5
b. –1
c. 32
17. 7 h5
a. 35
b. –35
c. 7
5
18. –9 = 5
17n
a. 1745
b. 4517
c. 153
5
What is the solution of the equation?
19. 16 = –d + 6
a. –15
b. –9
c. –10
20. Hannah wants to buy a $570 camera. She can save $50 each week from her paycheck. However, before Hannah can buy the camera, she must give her brother $80 that she owes him. For how many weeks will Hannah need to save before she can pay back her brother and buy the camera?
a. 11 weeks
b. 13 weeks
c. 15 weeks
What is the solution of the equation?
21. 16 5 z
4
a. –1
b. 69
c. 59
22. b 6
5 10
a. 56
b. –4
c. 44
What is the solution of the equation?
23. 2 6p 8 5p
a. 10
b. –6
c. 2
24. 6y 14 4y 32
a. 18
b. –9
c. 9
25. John and 2 friends are going out for pizza for lunch. They split one pizza and 3 large drinks. The pizza cost $12.00. They spend a total of $16.95. Find the cost of one large drink.
a. $1.65
b. $1.70
c. $2.48
What is the solution of the equation?
26. 4(y + 2) = 32
a. 10
b. 6
c. 4
27. 70 = –7(–2 – 2z)
a. 4
b. 784
c. –112
28. 3p
5
85 1
a. –1
b. 2
c. 15
What is the solution of the equation?
29. 6x – 3 = 5x – 5
a. –2
b. –1
c. –4
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Name: ________________________ ID: A
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What is the solution of the equation?
30. 3p 1 5(p 1) 2(7 2p)
a. 0
b. –9
c. 3
31. Which equation is an identity?
a. 8y 9 8y 3
b. 11 (2v 3) 2v 8
c. 5w 8 w 6w 2(w 4)
32. Which equation has no solution?
a. 7y 9 7y 6
b. 3w 4 w 5w 2(w 2)
c. 8 (5v 3) 5v 5
What is the solution of each equation?
33. 2(h 8) h h 16
a. 8
b. infinitely many solutions
c. no solution
34. 2 3z 5 3z
a. infinitely many solutions
b. 213
c. no solution
35. What equation do you get when you solve zm z bx for x?
a. x mb
b. x 2zm
b
c. x bm
36. Car A travels 180 miles in 7 hours. Car B travels 350 miles in 4 hours. Car C travels 584 miles in 15 hours. Which car has the fastest average speed?
a. They all have the same average speed
b. Car B
c. Car A
37. You are shopping for jeans. City Express sells 3 pairs of jeans for $61. Denim Planet sells 2 pairs of jeans for $73. New Threads sells 4 pairs of jeans for $110. Which store has the best deal?
a. New Threads
b. City Express
c. Denim Planet
What is the solution of the proportion?
38. h8
192
a. 16
b. 76
c. –38
What is the solution of the proportion?
39. x 8
5
24
a.52
b. 18
c.212
40. w 14
4w 6
3
4
a.8
19
b.19
4
c.2
7
41. A van travels 220 miles on 10 gallons of gas. Find how many gallons the van needs to travel 550 miles.
a. 25 gallons of gas
b. 31 gallons of gas
c. 115 gallons of gas
42. School guidelines require that there must be at least 2 chaperones for every 25 students going on a school trip. How many chaperones must there be for 80 students?
a. 6 chaperones
b. 3 chaperones
c. 7 chaperones
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Name: ________________________ ID: A
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What are the variables in each graph? Describe how the variables are related at various points on the graph.
43. The graph shows the height of a hiker above sea level. The hiker walks at a constant speed for the entire trip. What are the variables? Describe how the variables are related at various points on the graph.
a. The variables are height and time. For the first part of the graph, the height is increasing slowly, which means the hiker is climbing a steep incline. Flat parts of the graph show where the elevation does not change, which means the hiker stopped to rest. The steep part at the end of the graph shows that the hiker is descending a gentle slope.
b. The variables are height and time. For the first part of the graph, the height is increasing slowly, which means the hiker is walking up a gentle slope. Flat parts of the graph show where the elevation does not change, which means the trail is flat here. The steep part at the end of the graph shows that the hiker is descending a steep incline.
c. The variables are height and time. For the first part of the graph, the height is increasing slowly, which means the hiker is climbing a steep incline. Flat parts of the graph show where the elevation does not change, which means the trail is flat here. The steep part at the end of the graph shows that the hiker is descending a steep incline.
d. All of the above.
44. A new comedian is building a fan base. The table shows the number of people who attended his shows in the first, second, third and fourth month of his career. Which graph could represent the data shown in the table?
MonthTotal Number of
People1 1192 2143 385
4 693
a.
b.
c.
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Name: ________________________ ID: A
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The table shows the relationship between the number of sports teams a person belongs to and the amount of free time the person has per week.
Number of Sports Teams Free Time (hours)0 461 39
2 323 25
45. What is the graph for the above relationship?
a.
b.
c.
46. Is the above relationship a linear function?
a. yesb. no
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Name: ________________________ ID: A
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What is the graph of the function rule?
47. y 3x 2
a.
b.
c.
48. Identify the mapping diagram that represents the relation and determine whether the relation is a function.
(3, 6), (1, 6), (5, 6), (8, 6)ÏÌÓÔÔÔÔ
¸˝̨ÔÔÔÔ
a.
The relation is a function.
b.
The relation is not a function.
c.
The relation is a function.
49. Identify the domain and range of the relation.
(9, 2), (4, 2), (3, 2), (9, 2)ÏÌÓÔÔÔÔ
¸˝̨ÔÔÔÔ
50. Identify the domain and range of the relation.
(4, 2), (9, 5), (4, 12), (8, 8)ÏÌÓÔÔÔÔ
¸˝̨ÔÔÔÔ
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Name: ________________________ ID: A
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Use the vertical line test to determine whether the relation is a function.
51.
The rate of change is constant in each table. Find the rate of change. Explain what the rate of change means for the situation.
52. The table shows the number of miles driven over time.
Time (hours) Distance (miles)
4 204
6 306
8 408
10 510
a. 10; Your car travels for 10 hours.
b.51
1; Your car travels 51 miles every 1 hour.
c.1
51; Your car travels 51 miles every 1 hour.
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Name: ________________________ ID: A
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Find the slope of the line.
53.
a. 2
b. 12
c. 2
54.
a. 43
b. – 34
c.34
What is the slope of the line that passes through the pair of points?
55. (1, 7), (10, 1)
a. 23
b. 32
c.23
What is the slope of the line?
56.
a. undefined
b. 0
57.
a. 0
b. undefined
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Name: ________________________ ID: A
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What are the slope and y-intercept of the graph of the given equation?
58. y = –4x + 2
a. The slope is 4 and the y-intercept is –2.
b. The slope is –4 and the y-intercept is 2.
c. The slope is 2 and the y-intercept is –4.
59. y = 89
x 103
a. The slope is 89
and the y-intercept is 103
.
b. The slope is 98
and the y-intercept is 103
.
c. The slope is 103
and the y-intercept is 89
.
Write an equation of a line with the given slope and y-intercept.
60. m = –5, b = –3
a. y = 5x – 3
b. y = –5x – 3
c. y = –3x – 5
61. m = 35
, b = 13
a. y = 13
x + 35
b. y = 35
x + 13
c. y = 35
x – 13
Which number is a solution of the inequality?
62. 10.6 < b
a. 14 b. –18 c. –9
What is the graph of the inequality?
63. x 5
a.
b.
c.
What inequality describes the situation?
64. Let t = the amount Thomas earned. Thomas earned $49 or more.
a. t 49 b. t < 49 c. t 49
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Name: ________________________ ID: A
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What are the solutions of the inequality? Graph the solutions.
65. x 3 12
a. x 12
3
b. x 9
c. x 15
66. Suppose you had d dollars in your bank account. You spent $12 but have at least $51 left. How much money did you have initially? Write and solve an inequality that represents this situation.
a. d 12 51; d 75
b. d 12 51; d 63
c. d 12 51; d 75
What are the solutions of the inequality? Graph the solutions.
67. x
9 9
a. x > 1
b. x > 81
c. x > 0
What are the solutions of the inequality? Graph and check the solutions.
68. x
4 2
a. x 8
b. x 8
c. x 8
What are the solutions of the inequality? Graph the solutions.
69. 5x 10
a. x 2
b. x 2
c. x 5
Which is a solution of the inequality?
70. p + 4 – 2(p – 10) > 0
a. 26
b. 24
c. 22
What are the solutions of the inequality?
71. 2 3x 2( ) 6x 4
a. x 0
b. x 6
c. all real numbers
d. no solution
72. 10x 10 7x 3x 2
a. x 8
b. x 8
c. all real numbers
d. no solution
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What are the solutions of the compound inequality? Graph the solutions.
73. –2 < 4x – 10 < 6
a. 3 < x < 1
b. –16 < x < –8
c. 2 < x < 4
What are the solutions of the compound inequality? Graph the solutions.
74. 2x – 2 < –12 or 2x + 3 > 7
a. x < 7 or x > 5
b. x < –5 or x > 2
c. x < –12 or x > 2
75. What is the graph of (–8, 2]?
a.
b.
c.
76. How do you write x 6 and x 3 in interval notation?
a. [–6, –3)
b. [–6, –3]
c. (–6, –3]
77. What is the graph of (,8) or (6,)?
a.
b.
c.
78. How do you write (, 8) or (10,) as an inequality?
a. x 10 or x 8
b. x 8 or x 10
c. x 8 and x 10
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79. The function j(x) 39x represents the number of jumping jacks j(x) you can do in x minutes. How many jumping jacks can you do in 5 minutes?a. 195 jumping jacksb. 7 jumping jacksc. 144 jumping jacksd. 234 jumping jacks
Write the slope-intercept form of the equation for the line.
80.
a. y = 34
x 1 c. y = 34
x 1
b. y = 43
x 1 d. y = 43
x 1
Write an equation in point-slope form for the line through the given point with the given slope.
81. (8, 3); m = 6a. y 3 6(x 8)b. y 3 6(x 8) c. y 3 6(x 8)d. y 3 6x 8
82. (3, –10); m = –0.83a. y – 10 = –0.83(x + 3)b. y – 10 = –0.83(x – 3)c. y – 3 = –0.83(x + 10)d. y + 10 = –0.83(x – 3)
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83. The table shows the height of a plant as it grows. What equation in point-slope form gives the plant’s height at any time? Let y stand for the height of the plant in cm and let x stand for the time in months.
Time (months) Plant Height (cm)
3 15
5 25
7 35
9 45
a. y – 15 = 52
(x – 3)
b. y – 15 = 5(x – 3)
c. y – 3 = 52
(x – 15)
d. The relationship cannot be modeled.
84. The table shows the height above the ground of a helicopter taking off from the top of a building. What equation in point-slope form gives the helicopter’s height at any time? Let y stand for the height of the helicopter in m and let x stand for the time in seconds.
Time (s) Height (m)
3 24
5 40
7 56
9 72
a. y – 24 = 8(x –3)b. y – 3 = 4(x –24)c. y – 24 = 4(x –3)d. The relationship cannot be modeled.
Find the x- and y-intercept of the line.
85. 75
x 4y = 7
a. x-intercept is 74
; y-intercept is 5 c. x-intercept is 5; y-intercept is 74
b. x-intercept is 5; y-intercept is 74
d. x-intercept is 5; y-intercept is 74
Graph the equation.
86. y = 4x – 3a.
b.
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c.
d.
87. y = –3x – 1a.
b.
c.
d.
88. Giselle pays $210 in advance on her account at the athletic club. Each time she uses the club, $15 is deducted from the account. Model the situation with a linear function and a graph.
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Name: ________________________ ID: A
15
a.
b = 210 – 15xb.
b = 210 + 15x
c.
b = 195 + 15xd.
b = 195 – 15x
Match the equation with its graph.
89. –8x – 5y = 40
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a.
b.
c.
d.
What is the graph of the equation?
90. y = –3a.
b.
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c.
d.
91. x = –4a.
b.
c.
d.
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92. A paint store sells exterior paint for $28.25 a gallon and paint rollers for $6.25 each. Write an equation in standard form for the number of gallons p of paint and rollers r that a customer could buy with $145.a. 28.25 + 6.25 = pb. 28.25p = 6.25r + 145c. 28.25r + 6.25p = 145d. 28.25p + 6.25r = 145
93. The grocery store sells dates for $4.00 a pound and pomegranates for $2.75 a pound. Write an equation in standard form for the weights of dates d and pomegranates p that a customer could buy with $12.a. 4p + 2.75d = 12b. 4d = 2.75p + 12c. 4d + 2.75p = 12d. 4 + 2.75 = d
94. Find the slope of the line passing through (-12,-1) and (-3, -4)a. 1/3b. -3c. -1/3d. 3
95. Find the slope of the line passing through (-11, 7) and (-11, -2)a. undefined slopeb. 0c. 11d. 9
96.
Write the equation of the following line.
a. x = -1b. y = -xc. y = -1d. y = x-1
97. A local gas station is offering a deal to their customers. If they purchase an $8.00 car wash, the cost per gallon of gas is $2.60. Write and solve a linear equaiton to find how many gallons you can afford if you have $40.a. y = 2.60x + 8.00; 12.31 gallonsb. y = 8x + 2.60; 4.675 gallonsc. y = 2.60x + 8.00; 112 gallonsd. y = 2.60x + 8.00; 18.46 gallons
98. Amy deposited dimes and quarters into the Coinstar machine at her local gorcery store. The total money she deposited was $11.35. If Amy had 26 dimes, write and solve a linear equation to find the number of quarters she had.a. .10x + 26y = 11.35; 35 quartersb. .10x + .25y = 26; 19 quartersc. .10x + .25y = 11.35; 48 quartersd. .10x + .25y = 11.35; 35 quarters
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99. To sign-up for Tivo, you must purchase the DVR recorder upfront, then pay $19,95 per month for service. Eight months after signing up, Martha had paid a total of 288.60 for the recorder and service. Write and solve a linear equation to find the total amount she will have paid for the 2-year agreement she signed.a. y=19.95x + 129; $607.80b. y=19.95x + 129; $168.90c. y=19.95x + 288.60; $767.40d. y=19.95x + 288; $327.90
100. The cost of a classified ad is based on a daily rate plus a flat service fee. One day costs $3.50 and four days costs $8.00. Write and solve a linear equation to find the flat service fee.a. y=1.50x + 2.00; $8.00b. y=1.50x + 3.50; $3.50c. y=1.50x + 2.00; $2.00d. y=1.50x + 3.50; $8.00
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Semester 1 Final ReviewAnswer Section
1. ANS: B PTS: 1 DIF: L2 REF: 0-4 Simplifying FractionsOBJ: Simplifying Fractions TOP: Skills Handbook: Simplifying FractionsKEY: proportion
2. ANS: C PTS: 1 DIF: L2 REF: 1-1 Variables and ExpressionsOBJ: 1-1.1 To write algebraic expressions NAT: CC A.SSE.1.a| A.1.a| A.3.b STA: A1.9.1 TOP: 1-1 Problem 1 Writing Expressions With Addition and SubtractionKEY: algebraic expression | variable
3. ANS: A PTS: 1 DIF: L3 REF: 1-1 Variables and ExpressionsOBJ: 1-1.1 To write algebraic expressions NAT: CC A.SSE.1.a| A.1.a| A.3.b STA: A1.9.1 TOP: 1-1 Problem 3 Writing Expressions With Two Operations KEY: algebraic expression | variable
4. ANS: B PTS: 1 DIF: L3 REF: 1-1 Variables and ExpressionsOBJ: 1-1.1 To write algebraic expressions NAT: CC A.SSE.1.a| A.1.a| A.3.b STA: A1.9.1 TOP: 1-1 Problem 4 Using Words for an Expression KEY: algebraic expression | variable | quantity
5. ANS: C PTS: 1 DIF: L3 REF: 1-2 Order of Operations and Evaluating ExpressionsOBJ: 1-2.2 To use the order of operations to evaluate expressions NAT: CC A.SSE.1.a| N.3.a| N.5.eSTA: A1.1.4 TOP: 1-2 Problem 2 Simplifying a Numerical Expression KEY: power | exponent | base | simplify | evaluate
6. ANS: A PTS: 1 DIF: L3 REF: 1-2 Order of Operations and Evaluating ExpressionsOBJ: 1-2.2 To use the order of operations to evaluate expressions NAT: CC A.SSE.1.a| N.3.a| N.5.eSTA: A1.1.4 TOP: 1-2 Problem 2 Simplifying a Numerical Expression KEY: power | exponent | base | simplify | evaluate
7. ANS: B PTS: 1 DIF: L4 REF: 1-2 Order of Operations and Evaluating ExpressionsOBJ: 1-2.2 To use the order of operations to evaluate expressions NAT: CC A.SSE.1.a| N.3.a| N.5.eSTA: A1.1.4 TOP: 1-2 Problem 3 Evaluating Algebraic Expressions KEY: power | exponent | base | simplify | evaluate
8. ANS: C PTS: 1 DIF: L3 REF: 1-2 Order of Operations and Evaluating ExpressionsOBJ: 1-2.2 To use the order of operations to evaluate expressions NAT: CC A.SSE.1.a| N.3.a| N.5.eSTA: A1.1.4 TOP: 1-2 Problem 3 Evaluating Algebraic Expressions KEY: power | exponent | base | simplify | evaluate
9. ANS: A PTS: 1 DIF: L3 REF: 1-4 Properties of Real NumbersOBJ: 1-4.1 To identify and use properties of real numbers NAT: CC N.RN.3| N.1.d| N.3.d| N.5.f| N.6.a| A.3.dSTA: A1.1.3| A1.9.8 TOP: 1-4 Problem 3 Writing Equivalent Expressions KEY: equivalent expressions
10. ANS: C PTS: 1 DIF: L2 REF: 1-5 Adding and Subtracting Real NumbersOBJ: 1-5.1 To find sums and differences of real numbers NAT: CC N.RN.3| N.1.d| N.3.b| N.3.c| N.3.d| A.3.cSTA: A1.9.1 TOP: 1-5 Problem 2 Adding Real Numbers KEY: opposites | additive inverses
11. ANS: B PTS: 1 DIF: L3 REF: 1-7 The Distributive PropertyOBJ: 1-7.1 To use the Distributive Property to simplify expressions NAT: CC A.SSE.1.a| N.1.d| N.3.b| N.3.c| N.3.d| A.3.cSTA: A1.1.3 TOP: 1-7 Problem 1 Simplifying Expressions KEY: Distributive Property | coefficient | term | like terms
12. ANS: C PTS: 1 DIF: L2 REF: 1-7 The Distributive PropertyOBJ: 1-7.1 To use the Distributive Property to simplify expressions NAT: CC A.SSE.1.a| N.1.d| N.3.b| N.3.c| N.3.d| A.3.cSTA: A1.1.3 TOP: 1-7 Problem 3 Using the Multiplication Property of -1 KEY: Distributive Property | coefficient | term | like terms
13. ANS: A PTS: 1 DIF: L4 REF: 1-8 An Introduction to EquationsOBJ: 1-8.1 To solve equations using tables and mental math NAT: CC A.CED.1| N.2.b| A.3.bSTA: A1.2.1| A1.9.1 TOP: 1-8 Problem 1 Classifying Equations KEY: equation | open sentence
14. ANS: A PTS: 1 DIF: L3 REF: 1-8 An Introduction to EquationsOBJ: 1-8.1 To solve equations using tables and mental math NAT: CC A.CED.1| N.2.b| A.3.bSTA: A1.2.1| A1.9.1 TOP: 1-8 Problem 2 Identifying Solutions of an Equation KEY: solution of an equation
15. ANS: B PTS: 1 DIF: L3 REF: 1-9 Patterns, Equations, and GraphsOBJ: 1-9.1 To use tables, equations, and graphs to describe relationships NAT: CC A.CED.2| CC A.REI.10| A.1.aSTA: A1.3.1| A1.9.1 TOP: 1-9 Problem 1 Identifying Solutions of a Two-Variable EquationKEY: solution of an equation
16. ANS: B PTS: 1 DIF: L2 REF: 2-1 Solving One-Step EquationsOBJ: 2-1.1 To solve one-step equations in one variable NAT: CC A.CED.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.9.3| A1.9.4 TOP: 2-1 Problem 2 Solving an Equation Using AdditionKEY: Addition Property of Equality | equivalent equations | isolate | inverse operations
17. ANS: B PTS: 1 DIF: L2 REF: 2-1 Solving One-Step EquationsOBJ: 2-1.1 To solve one-step equations in one variable NAT: CC A.CED.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.9.3| A1.9.4 TOP: 2-1 Problem 4 Solving an Equation Using MultiplicationKEY: Multiplication Property of Equality | equivalent equations | isolate | inverse operations
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ID: A
2
18. ANS: C PTS: 1 DIF: L2 REF: 2-1 Solving One-Step EquationsOBJ: 2-1.1 To solve one-step equations in one variable NAT: CC A.CED.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.9.3| A1.9.4 TOP: 2-1 Problem 5 Solving an Equation Using ReciprocalsKEY: Multiplication Property of Equality | equivalent equations | isolate | inverse operations
19. ANS: C PTS: 1 DIF: L2 REF: 2-2 Solving Two-Step EquationsOBJ: 2-2.1 To solve two-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.2.6| A1.9.3 TOP: 2-2 Problem 1 Solving a Two-Step EquationKEY: equation in one variable | isolate | inverse operations
20. ANS: B PTS: 1 DIF: L4 REF: 2-2 Solving Two-Step EquationsOBJ: 2-2.1 To solve two-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.2.6| A1.9.3 TOP: 2-2 Problem 2 Using an Equation as a ModelKEY: create an equation | isolate | equation in one variable
21. ANS: B PTS: 1 DIF: L3 REF: 2-2 Solving Two-Step EquationsOBJ: 2-2.1 To solve two-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.2.6| A1.9.3 TOP: 2-2 Problem 3 Solving With Two Terms in the NumeratorKEY: equation in one variable | isolate | inverse operations
22. ANS: C PTS: 1 DIF: L3 REF: 2-2 Solving Two-Step EquationsOBJ: 2-2.1 To solve two-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.2.6| A1.9.3 TOP: 2-2 Problem 3 Solving With Two Terms in the NumeratorKEY: equation in one variable | isolate | inverse operations
23. ANS: A PTS: 1 DIF: L3 REF: 2-3 Solving Multi-Step EquationsOBJ: 2-3.1 To solve multi-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-3 Problem 1 Combining Like TermsKEY: like terms | equation in one variable | inverse operations
24. ANS: B PTS: 1 DIF: L3 REF: 2-3 Solving Multi-Step EquationsOBJ: 2-3.1 To solve multi-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-3 Problem 1 Combining Like TermsKEY: like terms | equation in one variable | inverse operations
25. ANS: A PTS: 1 DIF: L3 REF: 2-3 Solving Multi-Step EquationsOBJ: 2-3.1 To solve multi-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-3 Problem 2 Solving a Multi-Step EquationKEY: create an equation | equation in one variable | problem solving
26. ANS: B PTS: 1 DIF: L2 REF: 2-3 Solving Multi-Step EquationsOBJ: 2-3.1 To solve multi-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-3 Problem 3 Solving an Equation Using the Distributive PropertyKEY: Distributive Property | equation in one variable | inverse operations
27. ANS: A PTS: 1 DIF: L3 REF: 2-3 Solving Multi-Step EquationsOBJ: 2-3.1 To solve multi-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-3 Problem 3 Solving an Equation Using the Distributive PropertyKEY: Distributive Property | equation in one variable | inverse operations
28. ANS: A PTS: 1 DIF: L3 REF: 2-3 Solving Multi-Step EquationsOBJ: 2-3.1 To solve multi-step equations in one variable NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-3 Problem 4 Solving an Equation that Contains FractionsKEY: equation in one variable | inverse operations
29. ANS: A PTS: 1 DIF: L3 REF: 2-4 Solving Equations With Variables on Both SidesOBJ: 2-4.1 To solve equations with variables on both sides NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-4 Problem 1 Solving an Equation With Variables on Both SidesKEY: equation in one variable | inverse operations | like terms
30. ANS: C PTS: 1 DIF: L3 REF: 2-4 Solving Equations With Variables on Both SidesOBJ: 2-4.1 To solve equations with variables on both sides NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-4 Problem 3 Solving an Equation With Grouping SymbolsKEY: Distributive Property | like terms
31. ANS: C PTS: 1 DIF: L3 REF: 2-4 Solving Equations With Variables on Both SidesOBJ: 2-4.2 To identify equations that are identities or have no solution NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-4 Problem 4 Identities and Equations With No SolutionKEY: identity | no solution
32. ANS: A PTS: 1 DIF: L3 REF: 2-4 Solving Equations With Variables on Both SidesOBJ: 2-4.2 To identify equations that are identities or have no solution NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-4 Problem 4 Identities and Equations With No SolutionKEY: identity | no solution
33. ANS: B PTS: 1 DIF: L3 REF: 2-4 Solving Equations With Variables on Both SidesOBJ: 2-4.2 To identify equations that are identities or have no solution NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-4 Problem 4 Identities and Equations With No SolutionKEY: identity | no solution
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ID: A
3
34. ANS: C PTS: 1 DIF: L3 REF: 2-4 Solving Equations With Variables on Both SidesOBJ: 2-4.2 To identify equations that are identities or have no solution NAT: CC A.CED.1| CC A.REI.1| CC A.REI.3| A.4.a| A.4.cSTA: A1.2.1| A1.1.3| A1.2.6| A1.9.3 TOP: 2-4 Problem 4 Identities and Equations With No SolutionKEY: identity | no solution
35. ANS: A PTS: 1 DIF: L3 REF: 2-5 Literal Equations and FormulasOBJ: 2-5.1 To rewrite and use literal equations and formulas NAT: CC N.Q.1| CC A.CED.1| CC A.CED.4| CC A.REI.1| CC A.REI.3| A.4.a| A.4.c| A.4.e| A.4.f STA: A1.2.2| A1.2.6| A1.9.3 TOP: 2-5 Problem 2 Rewriting a Literal Equation With Only VariablesKEY: literal equation
36. ANS: B PTS: 1 DIF: L3 REF: 2-6.1 To find ratios and ratesOBJ: 2-6.1 To find ratios and rates NAT: CC N.Q.1| CC N.Q.2| N.3.b| N.3.f| M.1.i| M.2.bSTA: A1.1.5| A1.9.2 TOP: 2-6 Problem 1 Comparing Unit Rates KEY: ratio | unit rate | rate
37. ANS: B PTS: 1 DIF: L3 REF: 2-6 Ratios, Rates, and ConversionsOBJ: 2-6.1 To find ratios and rates NAT: CC N.Q.1| CC N.Q.2| N.3.b| N.3.f| M.1.i| M.2.bSTA: A1.1.5| A1.9.2 TOP: 2-6 Problem 1 Comparing Unit Rates KEY: ratio | rate | unit rate
38. ANS: B PTS: 1 DIF: L3 REF: 2-7 Solving ProportionsOBJ: 2-7.1 To solve and apply proportions NAT: CC N.Q.1| CC A.CED.1| CC A.REI.3| N.3.b| N.3.f| N.4.cSTA: A1.1.3| A1.2.1| A1.7.2 TOP: 2-7 Problem 1 Solving a Proportion Using the Multiplication PropertyKEY: proportion
39. ANS: C PTS: 1 DIF: L2 REF: 2-7 Solving ProportionsOBJ: 2-7.1 To solve and apply proportions NAT: CC N.Q.1| CC A.CED.1| CC A.REI.3| N.3.b| N.3.f| N.4.cSTA: A1.1.3| A1.2.1| A1.7.2 TOP: 2-7 Problem 3 Solving a Multi-Step ProportionKEY: proportion | cross products | Cross Products Property
40. ANS: B PTS: 1 DIF: L3 REF: 2-7 Solving ProportionsOBJ: 2-7.1 To solve and apply proportions NAT: CC N.Q.1| CC A.CED.1| CC A.REI.3| N.3.b| N.3.f| N.4.cSTA: A1.1.3| A1.2.1| A1.7.2 TOP: 2-7 Problem 3 Solving a Multi-Step ProportionKEY: proportion | cross products | Cross Products Property
41. ANS: A PTS: 1 DIF: L2 REF: 2-7 Solving ProportionsOBJ: 2-7.1 To solve and apply proportions NAT: CC N.Q.1| CC A.CED.1| CC A.REI.3| N.3.b| N.3.f| N.4.cSTA: A1.1.3| A1.2.1| A1.7.2 TOP: 2-7 Problem 4 Using a Proportion to Solve a ProblemKEY: create an equation | cross products | Cross Products Property
42. ANS: C PTS: 1 DIF: L3 REF: 2-7 Solving ProportionsOBJ: 2-7.1 To solve and apply proportions NAT: CC N.Q.1| CC A.CED.1| CC A.REI.3| N.3.b| N.3.f| N.4.cSTA: A1.1.3| A1.2.1| A1.7.2 TOP: 2-7 Problem 4 Using a Proportion to Solve a ProblemKEY: create an equation | cross products | Cross Products Property
43. ANS: B PTS: 1 DIF: L3 REF: 4-1 Using Graphs to Relate Two QuantitiesOBJ: 4-1.1 To represent mathematical relationships using graphs NAT: CC F.IF.4STA: A1.3.1| A1.3.2 TOP: 4-1 Problem 1 Analyzing a Graph KEY: interpreting a graph
44. ANS: C PTS: 1 DIF: L3 REF: 4-1 Using Graphs to Relate Two QuantitiesOBJ: 4-1.1 To represent mathematical relationships using graphs NAT: CC F.IF.4STA: A1.3.1| A1.3.2 TOP: 4-1 Problem 2 Matching a Table and a Graph KEY: sketching a graph | modeling a relationship
45. ANS: A PTS: 1 DIF: L3 REF: 4-2 Patterns and Linear FunctionsOBJ: 4-2.1 To identify and represent patterns that describe linear functions NAT: CC A.REI.10| CC F.IF.4| A.1.a| A.1.b| A.1.e| A.1.hSTA: A1.3.1| A1.3.3 TOP: 4-2 Problem 2 Representing a Linear Function KEY: dependent variable | independent variable | function | linear function | sketching a graph | modeling a relationship
46. ANS: A PTS: 1 DIF: L3 REF: 4-2 Patterns and Linear FunctionsOBJ: 4-2.1 To identify and represent patterns that describe linear functions NAT: CC A.REI.10| CC F.IF.4| A.1.a| A.1.b| A.1.e| A.1.hSTA: A1.3.1| A1.3.3 TOP: 4-2 Problem 2 Representing a Linear Function KEY: dependent variable | independent variable | function | linear function | create equations in two variables
47. ANS: B PTS: 1 DIF: L2 REF: 4-4 Graphing a Function RuleOBJ: 4-4.1 To graph equations that represent functions NAT: CC N.Q.1| CC A.REI.10| CC F.IF.5| A.1.bSTA: A1.3.1| A1.4.1| A1.8.1| A1.9.2 TOP: 4-4 Problem 1 Graphing a Function RuleKEY: continuous graph
48. ANS: C PTS: 1 DIF: L3 REF: 4-6 Formalizing Relations and FunctionsOBJ: 4-6.1 To determine whether a relation is a function NAT: CC F.IF.1| CC F.IF.2| N.2.c| A.1.b| A.1.g| A.1.i| A.3.fSTA: A1.3.3| A1.3.4| A1.9.2 TOP: 4-6 Problem 1 Identifying Functions Using Mapping DiagramsKEY: relation | domain | range
49. ANS: The domain is {–9, –4, 3, 9}.The range is {2}.
PTS: 1 DIF: L3 REF: 4-6 Formalizing Relations and FunctionsOBJ: 4-6.2 To find domain and range and use function notation NAT: CC F.IF.1| CC F.IF.2| N.2.c| A.1.b| A.1.g| A.1.i| A.3.fSTA: A1.3.3| A1.3.4| A1.9.2 TOP: 4-6 Problem 1 Identifying Functions Using Mapping DiagramsKEY: relation | domain | range
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ID: A
4
50. ANS: The domain is {–9, –4, 8}.The range is {–8, –5, 2, 12}.
PTS: 1 DIF: L3 REF: 4-6 Formalizing Relations and FunctionsOBJ: 4-6.2 To find domain and range and use function notation NAT: CC F.IF.1| CC F.IF.2| N.2.c| A.1.b| A.1.g| A.1.i| A.3.fSTA: A1.3.3| A1.3.4| A1.9.2 TOP: 4-6 Problem 1 Identifying Functions Using Mapping DiagramsKEY: relation | domain | range
51. ANS: The relation is a function.
PTS: 1 DIF: L2 REF: 4-6 Formalizing Relations and FunctionsOBJ: 4-6.1 To determine whether a relation is a function NAT: CC F.IF.1| CC F.IF.2| N.2.c| A.1.b| A.1.g| A.1.i| A.3.fSTA: A1.3.3| A1.3.4| A1.9.2 TOP: 4-6 Problem 2 Identifying Functions Using the Vertical Line TestKEY: relation | function | vertical line test
52. ANS: B PTS: 1 DIF: L3 REF: 5-1 Rate of Change and SlopeOBJ: 5-1.1 To find rates of change from tables NAT: CC F.IF.6| CC F.LE.1.b| A.2.a| A.2.bSTA: A1.4.2 TOP: 5-1 Problem 1 Finding Rate of Change Using a Table KEY: find rate of change | interpret rate of change
53. ANS: B PTS: 1 DIF: L3 REF: 5-1 Rate of Change and SlopeOBJ: 5-1.2 To find slope NAT: CC F.IF.6| CC F.LE.1.b| A.2.a| A.2.bSTA: A1.4.2 TOP: 5-1 Problem 2 Finding Slope Using a Graph KEY: slope
54. ANS: C PTS: 1 DIF: L3 REF: 5-1 Rate of Change and SlopeOBJ: 5-1.2 To find slope NAT: CC F.IF.6| CC F.LE.1.b| A.2.a| A.2.bSTA: A1.4.2 TOP: 5-1 Problem 2 Finding Slope Using a Graph KEY: slope
55. ANS: A PTS: 1 DIF: L2 REF: 5-1 Rate of Change and SlopeOBJ: 5-1.2 To find slope NAT: CC F.IF.6| CC F.LE.1.b| A.2.a| A.2.bSTA: A1.4.2 TOP: 5-1 Problem 3 Finding Slope Using Points KEY: slope
56. ANS: B PTS: 1 DIF: L3 REF: 5-1 Rate of Change and SlopeOBJ: 5-1.2 To find slope NAT: CC F.IF.6| CC F.LE.1.b| A.2.a| A.2.bSTA: A1.4.2 TOP: 5-1 Problem 4 Finding Slopes of Horizontal and Vertical LinesKEY: slope
57. ANS: B PTS: 1 DIF: L3 REF: 5-1 Rate of Change and SlopeOBJ: 5-1.2 To find slope NAT: CC F.IF.6| CC F.LE.1.b| A.2.a| A.2.bSTA: A1.4.2 TOP: 5-1 Problem 4 Finding Slopes of Horizontal and Vertical LinesKEY: slope
58. ANS: B PTS: 1 DIF: L2 REF: 5-3 Slope-Intercept FormOBJ: 5-3.1 To write linear equations using slope-intercept form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.2| A1.4.3| A1.4.4 TOP: 5-3 Problem 1 Identifying Slope and y-interceptKEY: linear equation | y-intercept | slope-intercept form
59. ANS: A PTS: 1 DIF: L3 REF: 5-3 Slope-Intercept FormOBJ: 5-3.1 To write linear equations using slope-intercept form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.2| A1.4.3| A1.4.4 TOP: 5-3 Problem 1 Identifying Slope and y-interceptKEY: linear equation | y-intercept | slope-intercept form
60. ANS: B PTS: 1 DIF: L2 REF: 5-3 Slope-Intercept FormOBJ: 5-3.1 To write linear equations using slope-intercept form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.2| A1.4.3| A1.4.4 TOP: 5-3 Problem 2 Writing an Equation in Slope-Intercept FormKEY: linear equation | slope-intercept form | y-intercept
61. ANS: B PTS: 1 DIF: L3 REF: 5-3 Slope-Intercept FormOBJ: 5-3.1 To write linear equations using slope-intercept form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.2| A1.4.3| A1.4.4 TOP: 5-3 Problem 2 Writing an Equation in Slope-Intercept FormKEY: linear equation | slope-intercept form | y-intercept
62. ANS: A PTS: 1 DIF: L3 REF: 3-1 Inequalities and Their GraphsOBJ: 3-1.1 To write, graph, and identify solutions of inequalities NAT: CC A.REI.3STA: A1.2.3 TOP: 3-1 Problem 2 Identifying Solutions by Evaluating KEY: solution of an inequality
63. ANS: B PTS: 1 DIF: L2 REF: 3-1 Inequalities and Their GraphsOBJ: 3-1.1 To write, graph, and identify solutions of inequalities NAT: CC A.REI.3STA: A1.2.3 TOP: 3-1 Problem 3 Graphing an Inequality KEY: solution of an inequality
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ID: A
5
64. ANS: A PTS: 1 DIF: L3 REF: 3-1 Inequalities and Their GraphsOBJ: 3-1.1 To write, graph, and identify solutions of inequalities NAT: CC A.REI.3STA: A1.2.3 TOP: 3-1 Problem 5 Writing Real-World Inequalities KEY: create inequalities in one variable | solution of an inequality
65. ANS: B PTS: 1 DIF: L3 REF: 3-2 Solving Inequalities Using Addition or SubtractionOBJ: 3-2.1 To use addition or subtraction to solve inequalities NAT: CC A.CED.1| CC A.REI.3STA: A1.2.4| A1.2.6 TOP: 3-2 Problem 1 Using the Addition Property of Inequality KEY: equivalent inequalities
66. ANS: B PTS: 1 DIF: L3 REF: 3-2 Solving Inequalities Using Addition or SubtractionOBJ: 3-2.1 To use addition or subtraction to solve inequalities NAT: CC A.CED.1| CC A.REI.3STA: A1.2.4| A1.2.6 TOP: 3-2 Problem 4 Writing and Solving an Inequality KEY: create inequalities in one variable | problem solving
67. ANS: B PTS: 1 DIF: L3 REF: 3-3 Solving Inequalities Using Multiplication or Division OBJ: 3-3.1 To use multiplication or division to solve inequalities NAT: CC N.Q.2| CC A.CED.1| CC A.REI.3STA: A1.2.4| A1.2.6 TOP: 3-3 Problem 1 Multiplying by a Positive Number
68. ANS: A PTS: 1 DIF: L3 REF: 3-3 Solving Inequalities Using Multiplication or Division OBJ: 3-3.1 To use multiplication or division to solve inequalities NAT: CC N.Q.2| CC A.CED.1| CC A.REI.3STA: A1.2.4| A1.2.6 TOP: 3-3 Problem 2 Multiplying by a Negative Number
69. ANS: B PTS: 1 DIF: L3 REF: 3-3 Solving Inequalities Using Multiplication or Division OBJ: 3-3.1 To use multiplication or division to solve inequalities NAT: CC N.Q.2| CC A.CED.1| CC A.REI.3STA: A1.2.4| A1.2.6 TOP: 3-3 Problem 4 Dividing by a Negative Number
70. ANS: C PTS: 1 DIF: L3 REF: 3-4 Solving Multi-Step InequalitiesOBJ: 3-4.1 To solve multi-step inequalities NAT: CC A.CED.1| CC A.REI.3 STA: A1.1.3| A1.2.4| A1.2.6 TOP: 3-4 Problem 3 Using the Distributive Property
71. ANS: C PTS: 1 DIF: L3 REF: 3-4 Solving Multi-Step InequalitiesOBJ: 3-4.1 To solve multi-step inequalities NAT: CC A.CED.1| CC A.REI.3 STA: A1.1.3| A1.2.4| A1.2.6 TOP: 3-4 Problem 5 Inequalities With Special Solutions
72. ANS: D PTS: 1 DIF: L3 REF: 3-4 Solving Multi-Step InequalitiesOBJ: 3-4.1 To solve multi-step inequalities NAT: CC A.CED.1| CC A.REI.3 STA: A1.1.3| A1.2.4| A1.2.6 TOP: 3-4 Problem 5 Inequalities With Special Solutions
73. ANS: C PTS: 1 DIF: L3 REF: 3-6 Compound InequalitiesOBJ: 3-6.1 To solve and graph inequalities containing the word and NAT: CC A.CED.1| CC A.REI.3STA: A1.2.5| A1.2.6 TOP: 3-6 Problem 2 Solving a Compound Inequality Involving AndKEY: compound inequality
74. ANS: B PTS: 1 DIF: L3 REF: 3-6 Compound InequalitiesOBJ: 3-6.2 To solve and graph inequalities containing the word or NAT: CC A.CED.1| CC A.REI.3STA: A1.2.5| A1.2.6 TOP: 3-6 Problem 4 Solving a Compound Inequality Involving Or KEY: compound inequality
75. ANS: A PTS: 1 DIF: L3 REF: 3-6 Compound InequalitiesOBJ: 3-6.1 To solve and graph inequalities containing the word and NAT: CC A.CED.1| CC A.REI.3STA: A1.2.5| A1.2.6 TOP: 3-6 Problem 5 Using Interval Notation KEY: compound inequality | interval notation
76. ANS: A PTS: 1 DIF: L3 REF: 3-6 Compound InequalitiesOBJ: 3-6.1 To solve and graph inequalities containing the word and NAT: CC A.CED.1| CC A.REI.3STA: A1.2.5| A1.2.6 TOP: 3-6 Problem 5 Using Interval Notation KEY: compound inequality | interval notation
77. ANS: A PTS: 1 DIF: L3 REF: 3-6 Compound InequalitiesOBJ: 3-6.2 To solve and graph inequalities containing the word or NAT: CC A.CED.1| CC A.REI.3STA: A1.2.5| A1.2.6 TOP: 3-6 Problem 5 Using Interval Notation KEY: compound inequality | interval notation
78. ANS: B PTS: 1 DIF: L3 REF: 3-6 Compound InequalitiesOBJ: 3-6.2 To solve and graph inequalities containing the word or NAT: CC A.CED.1| CC A.REI.3STA: A1.2.5| A1.2.6 TOP: 3-6 Problem 5 Using Interval Notation KEY: compound inequality | interval notation
79. ANS: A PTS: 1 DIF: L2 REF: 4-6 Formalizing Relations and FunctionsOBJ: 4-6.2 To find domain and range and use function notation NAT: CC F.IF.1| CC F.IF.2| N.2.c| A.1.b| A.1.g| A.1.i| A.3.fSTA: A1.3.3| A1.3.4| A1.9.2 TOP: 4-6 Problem 3 Evaluating a FunctionKEY: function notation
80. ANS: B PTS: 1 DIF: L3 REF: 5-3 Slope-Intercept FormOBJ: 5-3.2 To graph linear equations in slope-intercept form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.2| A1.4.3| A1.4.4 TOP: 5-3 Problem 3 Writing an Equation From a GraphKEY: slope-intercept form | linear equation | y-intercept
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ID: A
6
81. ANS: B PTS: 1 DIF: L2 REF: 5-4 Point-Slope FormOBJ: 5-4.1 To write and graph linear equations using point-slope form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.4 TOP: 5-4 Problem 1 Writing an Equation in Point-Slope Form KEY: point-slope form
82. ANS: D PTS: 1 DIF: L3 REF: 5-4 Point-Slope FormOBJ: 5-4.1 To write and graph linear equations using point-slope form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.4 TOP: 5-4 Problem 1 Writing an Equation in Point-Slope Form KEY: point-slope form
83. ANS: B PTS: 1 DIF: L3 REF: 5-4 Point-Slope FormOBJ: 5-4.1 To write and graph linear equations using point-slope form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.4 TOP: 5-4 Problem 4 Using a Table to Write an Equation KEY: point-slope form
84. ANS: A PTS: 1 DIF: L4 REF: 5-4 Point-Slope FormOBJ: 5-4.1 To write and graph linear equations using point-slope form NAT: CC A.SSE.1.a| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.BF.1.a| CC F.BF.3| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.4 TOP: 5-4 Problem 4 Using a Table to Write an Equation KEY: point-slope form
85. ANS: D PTS: 1 DIF: L3 REF: 5-5 Standard FormOBJ: 5-5.1 To graph linear equations using intercepts NAT: CC N.Q.2| CC A.SSE.2| CC A.CED.2| CC F.IF.4| CC F.IF.7.a| CC F.IF.9| CC F.BF.1.a| CC F.LE.2| CC F.LE.5| A.2.a| A.2.bSTA: A1.4.1| A1.4.2| A1.4.4| A1.9.2 TOP: 5-5 Problem 1 Finding x- and y-interceptsKEY: x-intercept | standard form of a linear equation
86. ANS: D PTS: 1 DIF: L3 REF: 5-3 Slope-Intercept FormOBJ: 5-3.2 To graph linear equations in slope-intercept form NAT: A.2.a| A.2.bSTA: A1.2.1| A1.2.2| A1.2.3| A1.2.4| C.2 TOP: 5-3 Problem 5 Graphing a Linear FunctionKEY: linear equation | y-intercept | slope-intercept form DOK: DOK 1
87. ANS: B PTS: 1 DIF: L3 REF: 5-3 Slope-Intercept FormOBJ: 5-3.2 To graph linear equations in slope-intercept form NAT: A.2.a| A.2.bSTA: A1.2.1| A1.2.2| A1.2.3| A1.2.4| C.2 TOP: 5-3 Problem 5 Graphing a Linear FunctionKEY: linear equation | y-intercept | slope-intercept form DOK: DOK 1
88. ANS: A PTS: 1 DIF: L3 REF: 5-3 Slope-Intercept FormOBJ: 5-3.2 To graph linear equations in slope-intercept form NAT: A.2.a| A.2.bSTA: A1.2.1| A1.2.2| A1.2.3| A1.2.4| C.2 TOP: 5-3 Problem 6 Modeling a FunctionKEY: linear equation | y-intercept | slope-intercept form DOK: DOK 2
89. ANS: C PTS: 1 DIF: L3 REF: 5-5 Standard FormOBJ: 5-5.1 To graph linear equations using intercepts NAT: A.2.a| A.2.b STA: A1.2.1| A1.2.2| A1.2.3| A1.2.4| C.2TOP: 5-5 Problem 2 Graphing a Line Using Intercepts KEY: standard form of a linear equationDOK: DOK 1
90. ANS: A PTS: 1 DIF: L3 REF: 5-5 Standard FormOBJ: 5-5.1 To graph linear equations using intercepts NAT: A.2.a| A.2.b STA: A1.2.1| A1.2.2| A1.2.3| A1.2.4| C.2TOP: 5-5 Problem 3 Graphing Horizontal and Vertical Lines KEY: standard form of a linear equationDOK: DOK 2
91. ANS: B PTS: 1 DIF: L3 REF: 5-5 Standard FormOBJ: 5-5.1 To graph linear equations using intercepts NAT: A.2.a| A.2.b STA: A1.2.1| A1.2.2| A1.2.3| A1.2.4| C.2TOP: 5-5 Problem 3 Graphing Horizontal and Vertical Lines KEY: standard form of a linear equationDOK: DOK 2
92. ANS: D PTS: 1 DIF: L3 REF: 5-5 Standard FormOBJ: 5-5.2 To write linear equations in standard form NAT: A.2.a| A.2.b STA: A1.2.1| A1.2.2| A1.2.3| A1.2.4| C.2TOP: 5-5 Problem 5 Using Standard Form as a Model KEY: standard form of a linear equationDOK: DOK 2
93. ANS: C PTS: 1 DIF: L3 REF: 5-5 Standard FormOBJ: 5-5.2 To write linear equations in standard form NAT: A.2.a| A.2.b STA: A1.2.1| A1.2.2| A1.2.3| A1.2.4| C.2TOP: 5-5 Problem 5 Using Standard Form as a Model KEY: standard form of a linear equationDOK: DOK 2
94. ANS: C PTS: 1 95. ANS: A PTS: 1 96. ANS: C PTS: 1 97. ANS: A PTS: 1 98. ANS: D PTS: 1 99. ANS: A PTS: 1 100. ANS: C PTS: 1