errata 5thed first printing
TRANSCRIPT
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8/4/2019 Errata 5thEd First Printing
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Chapra and CanaleNumerical Methods for Engineers, 5th Ed.
Errata for first printing(Last updated: 2/6/06)
p. 44; First line of function at bottom of page should be
function yy = euler(dt,ti,tf,yi,m,cd)
Last line should be
yy = y;
p. 45; Function at top of page should be
function dydt = dy(t, v, m, cd)
g = 9.8;
dydt = g (cd/m) * v;
p. 131; Figure P5.14, change dimensions as shown.
4 2
p. 132; Prob. 5.16; Equation should be (delete 2 at end)
[ ]3
32 hRhV
=
p. 159; Prob. 6.23;
Use an initial guess ofx0 = 3.2.
p. 181 Example 7.7; 4th
line of Problem Statement:
delete the minus sign.
p. 204; Prob. 8.11; Equation should be (first epsilon should be cubed)
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75.1)/(
1150
1
3
2+
=
op
p
oGDL
D
G
P
p. 207; Prob. 8.27; Equation should be (x 8 term should be cubed)
[ ] xxxxxxxuy 25.2386577758
61550
65)( 3
2344+++=
p. 209; Prob. 8.37;
compute the time at which v = 750 m/s.
p. 210; Prob. 8.42; Last equation should be (changeIItoIII)
yzxzxyxyzzxzyyyzxxzzyyxxIII 2222 +=
p. 240; 2nd
to last line from bottom of page. Delete bi and replace with sum.
p. 261; 3rd
line from top of page, delete multiply/divide
p. 261; delete denominators of 2 in Eq. (9.37)
p. 283; prob. 10.2;
Change in Sec. 10.2 to Sec. 10.1.2
p. 284; Prob. 10.19; Last equation should read (change first b to 6 and delete first c):
( ) ( ) kcjbiaCABAr
rrrrrr
)14()23()65( ++++=+
p. 346; 5th
equation should be modified to
765.110
528.1)528.1sin(2)528.1()(
2
2 === fxf
p. 357; first line of computer code should read
maxf = -1E9
p. 365; Equations (14.7) and (14.8) should read
22
2 ),(),(2),(
x
yxxfyxfyxxf
x
f
++=
(14.7)
22
2 ),(),(2),(
y
yyxfyxfyyxf
y
f
++=
(14.8)
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p. 384; Change next to last sentence to read:
Because 8 is the smallest possible intercept,
p. 399; Prob. 15.6; Change Minimize to Maximize
p. 421; Prob. 16.30
A manufacturing firm produces four types
p. 506; Prob. 18.9;
Note that the values in the table were generated with the functionf(x) = x2/(1 + x
2).
p. 506; Prob. 18.19; (delete 0 from the data to be evaluated)
Test your program for f(x) = lnx using data fromx = 1, 2, ... , 10.
p. 518; Second equation in right column of box:
=
=
+=10
00)(k
tik
k
k
tik
k ecectf
p. 542; Prob. 19.1; Add "Note that the period is 24 hrs."
p. 556; Prob. 20.21; In table at bottom of page change 0.02 in first column to 0.20.
p. 560; Prob. 20.47; The units of speed should be changed from m/h to km/h.
p. 620; Fig. 22.4; The equation for the approximate error should be (change term I1,itertoI2,iter)
ea = ABS((I1,iter+1 I2,iter) / I1,iter+1) * 100
p. 631; Prob 22.9 (c); Equation should be
dyyy
++
0 22
)2/(1)(1
1
Prob 22.9 (e); Equation should be
(e) dxex
0
2/
2
1
2
p. 650; First line; change Fto d.
p. 657; Prob. 24.9; Equation should be (changeA to a),
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)1( = ao ea
E
p. 658; Prob. 24.9; Equation should be (changex to ),
)1(1
=
a
a ee
p. 659; Prob. 24.10; Change last line in problem statement to with a step size of2 s.
p. 665; Prob. 24.47. Change beginning of second sentence to Use second-order accurate
derivative approximations
p. 665; Prob. 24.49; Change (b) to
(b) Use multiple-application Simpsons rule to integrate.
p. 665; Prob. 24.50; Change the parenthetical phrase before the equation to
(evaluate the integral from 0.1 atm to 50 atm)
p. 715; Main or "Driver" Program; Change first loop to:
DOFOR i = 1, n
ypi,m = yiiyi = yii
END DO
p. 725; Prob. 25.24; Change depth of liquid in tank from h toH.
p. 804; Prob. 28.24; Change equation to (add minus)
)(2)(4
2
ehghA
d
dt
dh+=
p. 806; Prob. 28.38; units should be changed to k= 6 N/m.
p. 807; Prob. 28.39; Change equation to (add minus)
02
2
2
=
+ pu
dx
du
xdx
ud
p. 854; Example 30.5; Change to
T1,1 = 3.01597
p. 854; Example 30.5; Change to (13.0639 12.0639)
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=
0619.82577.00639.12
167.20835.00835.0167.20835.0
0835.0167.2
1,3
1,2
1,1
T
T
T
p. 867; Eq. (31.24); Change to
( )( )21
122
12
21 12
1
TTxx
dxxx
TTx
x
=
p. 867; Eq. (31.25); Change to
( )( )21
122
12
21 12
1
TTxx
dxxx
TTx
x+
=
+
p. 886; Eq. (32.7); Change to
in10 2222 c
DxUc
xUDc
DxU
Uxk
xUD
+=
+++
p. 887; Eq. (32.10); Change to
022
1 =
+
+
nn cU
xk
xU
Dc
xU
D
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