electronic and band structure slater blochl
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Chapter 7: The Electronic Band Structure of Solids
Bloch & Slater
April 2, 2001
Contents
1 Symmetry of (r) 3
2 The nearly free Electron Approximation. 6
2.1 The Origin of Band Gaps . . . . . . . . . . . . . . . . . . . . . . . . 9
3 Tight Binding Approximation 15
4 Photo-Emission Spectroscopy 24
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Free electrons -FLT Band Structure
E
Ef
D(E)
V(r)
Ef
Ef
metal
"heavy" metal
insulator
E
D(E)
V(r) = V0
Ef
Figure 1: The additional effects of the lattice potential can have a profound effect on
the electronic density of states (RIGHT) compared to the free-electron result (LEFT).
In the last chapter, we ignored the lattice potential and con-
sidered the effects of a small electronic potential U. In this
chapter we will set U = 0, and consider the effects of the ion po-
tential V(r). As shown in Fig. 1, additional effects of the lattice
potential can have a profound effect on the electronic density of
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states compared to the free-electron result, and depending on
the location of the Fermi energy, the resulting system can be
a metal, semimetal, an insulator, or a metal with an enhanced
electronic mass.
1 Symmetry of (r)
From the symmetry of the electronic potential V(r) one may
infer some of the properties of the electronic wave functions
(r).
Due to the translational symmetry of the lattice V(r) is pe-
riodic
V(r) = V(r + rn), rn = n1a1 + n2a2 + n3a3 (1)
and may then be expanded in a Fourier expansion
V(r) =G
VGeiGr, G = hg1 + kg2 + lg3 , (2)
which, since G rn = 2m (m Z) guarantees V(r) =
V(r + rn). Given this, and letting (r) =
k Ckeikr the
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Schroedinger equation becomes
H(r) = h
2
2m2 + V(r)
= E (3)
k
h2k2
2mCke
ikr+
kG
CkVGei(k+G)r = E
k
Ckeikr, k kG
(4)
ork
eikrh
2
k2
2m E
Ck + G
VGCkG = 0r (5)
Since this is true for any r, it must be thath
2k2
2m E
Ck +
G
VGCkG = 0, k (6)
Thus the potential acts to couple each Ck only with its recip-
rocal space translations Ck+G and the problem decouples in to
N independent problems for each k in the first BZ. Ie., each of
the N problems has a solution which is a sum over plane waves
whos wave vectors differ only by Gs. Thus the eigenvalues
may be indexed by k.
Ek = E(k), I.e. k is still a good q.n.! (7)
We may now sum over G to get k with the eigenvector sum
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X
X
X
X
X
X
First B.Z.
Figure 2: The potential acts to couple each Ck with its reciprocal space translations
Ck+G (i.e. x x, , and) and the problem decouples into N indepen-dent problems for each k in the first BZ.
restricted to reciprocal lattice sites k, k + G, . . .
k(r) = G
Ck
Gei(kG)r =
G
Ck
GeiGr eikr (8)
k(r) = Uk(r)eikr, where Uk(r) = Uk(r + rn) (9)
Note that ifV(r) = 0, U(r) = 1V
. This result is called Blochs
Theorem; ie., that may be resolved into a plane wave and a
periodic function. Its consequences as follows:
k+G(r) =G
Ck+GGei(GkG)r =
GCkGeiG
r eikr
= k(r), where G G G (10)
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Ie., k+G(r) = k(r) and as a result
Hk = E(k)k Hk+G = E(k + G)k+G (11)
= Hk = E(k + G)k+G (12)
Thus E(k + G) = E(k) : E(k) is periodic then since both
k(r) and E(k) are periodic in reciprocal space, one only needs
knowledge of them in the first BZ to know them everywhere.
2 The nearly free Electron Approximation.
If the potential is weak, VG 0 G, then we may solve the
VG = 0 problem, subject to our constraints of periodicity, and
treat VG as a perturbation.
When VG = 0, then
E(k) =h2k2
2mfree electron (13)
However, we must also have that (if VG = 0)
E(k) = E(k + G) h
2
2m|k + G|2 (14)
Ie., the possible electron states are not restricted to a single
parabola, but can be found equally well on paraboli shifted by
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First BZ 2/a
E
Figure 3: For small VG, we may approximate the band structure as composed of N
parabolic bands. Of course, it is sufficient to consider this in the first Brillouin zone,
where the parabola centered at finite G cross at high energies. To understand the
effects of the perturbation VG consider this special k at the edge of the BZ. where the
paraboli cross.
any G vector. In 1-d Since E(k) = E(k + G), it is sufficient
to represent this in the first zone only. For example in a 3-D
cubic lattice the energy band structure along kx(ky = kz = 0)
is already rather complicated within the first zone. (See Fig.4.)
The effect ofVG can now be discussed. Lets return to the 1-d
problem and consider the edges of the zone where the [paraboli
intersect. (See Fig. 3.) An electron state with k = a will
involve at least the two G values G = 0, 2a . Of course, the
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a a k
x
First B.Z.
a-a
Figure 4: The situation becomes more complicated in three dimensions since there are
many more bands and so they can cross the first zone at lower energies. For example
in a 3-D cubic lattice the energy band structure along kx(ky = kz = 0) is already
rather complicated within the first zone.
exact solution must involve all G since
h2k22m
Ek
Ck + G
VGCkG = 0 (15)
We can generally take V0 = 0 since this just sets a zero for the
potential. Then, those G for which Ek = EkG h2k2
2mare
going to give the largest contribution since
Ck =G
VG CkGh2k22m
EkG(16)
Ck VG1CkG1
h2k2
2m EkG1
(17)
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CkG1 = G
VGCkG1G
h2k2
2m EkGG1(18)
CkG1 VG1Ck
h2k2
2m Ek
(19)
Thus to a first approximation, we may neglect the other CkG,
and since VG = VG (so that V(r) is real) |Ck| |CkG1|
other GkG
k(r) =G
CkGei(kG)r
(eiGx/2 + eiGx/2) cos xa
(eiGx/2 eiGx/2) sin xa
(20)
The corresponding electron densities are sketched in Fig. 5.
Clearly + has higher density near the ionic cores, and will
be more tightly bound, thus E+ < E. Thus a gap opens in
Ek near k =G2 .
2.1 The Origin of Band Gaps
Now lets reexamine this gap at k = G1/2 in a quantitative
manner. Start with the eigen value equation shifted by G.
CkG
Ek h
2
2m|k G|2
=
GVGCkGG =
G
VGGCkG
(21)
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V(x)
(x)
(x)+
E
k
Gap!
E
D(E)
Figure 5: + cos2(x/a) has higher density near the ionic cores, and will be moretightly bound, thus E+ < E. Thus a gap opens in Ek near k =
G2
.
CkG =
G VGGCkGEk
h2
2m|k G|2 (22)
To a first approximation (VG 0) lets set E =h2k2
2m(a free-
electron energy) and ignore all but the largest CkG; ie., those
for which the denominator vanishes.
k2 = |k G|2 , (23)
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-/a /a0 k
2 VG
Ek
k
e
Figure 7:
And the band structure looks something like Fig. 7. Within this
approximation, the gap, or forbidden regions in which there are
no electronic states arise when the Bragg condition (kf k0 =G) is satisfied.
| k| |k + G| (33)
The interpretation is clear: the high degree of back scattering
for these k-values destroys the electronic states.
Thus, by treating the lattice potential as a perturbation to
the free electron problem, we see that gaps arise due to enhanced
electron-lattice back scattering for k near the zone edge. How-
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Ai
BiB
i
Bi
Bi
Figure 11: A simple cubic tight binding lattice composed of s-orbitals, with overlap
integral Bi.
Bi =
i (r rm)v(r rn)i(r rn)d3r (46)
Bi describes the hybridization of adjacent orbitals.
Ai; Bi > 0, since v(r rn) < 0 (47)
Thus
E(k) Ei Ai Bim
eik(rnrm) sum over m n.n. to n
(48)Now, if we have a cubic lattice, then
(rn rm) = (a, 0, 0)(0, a, 0)(0, 0, a) (49)
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so
E(k) = Ei Ai 2Bi{cos kxa + cos kya + cos kza} (50)
Thus a band centered about Ei Ai of width 12Bi is formed.
Near the band center, for k-vectors near the center of the zone
we can expand the cosines cos ka 1 12 (ka)2 + and let
k2
= k2
x + k2
y + k2
z, so that
E(k) Ei Ai + Bia2k2 (51)
The electrons near the zone center act as if they were free with
a renormalized mass.
h2k2
2m = Bia2
k2
, i.e.1
m curvature of band (52)
For this reason, the hybridization term Bi is often associated
with kinetic energy. This makes sense, from its origins of wave
function overlap and thus electronic transfer.
The width of the band, 12 Bi, will increase as the electronic
overlap increases and the interatomic orbitals (core orbitals or
valance f and d orbitals) will tend to form narrow bands with
high effective masses (small Bi).
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First B.Z.
Fermi surface
Figure 12: Electronic states for a cubic lattice near the center of the B.Z. act like free
electrons with a renormalized mass. Hence, if the band is partially filled, the Fermi
surface will be spherical.
The bands are filled then by placing two electrons in each
band state ( with spins up and down). A metal then forms
when the valence band is partially full. I.e., for Na with a1s22s22p63s1 atomic configuration the 1s, 2s and 2p orbitals
evolve into (narrow) filled bands, but the 3s1 band will only
be half full, and thus it evolves into a metal. Mg 1s22s22p63s2
also metal since the p and s band overlaps the unfilled d-band.
There are exceptions to this rule. Consider C with atomic con-figuration of 1s22s22p2. Its valance s and p states form a strong
sp3 hybrid band which is further split into a bonding and anti-
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a
E
E1
E1
E2
2E
1A
2A
212 B
112 B
k = 0
- /a /a
k
k
k
k
111
111
111
Atomic Potential Tight Binding Bands
Figure 13: In the tight-binding approximation, band form from overlapping orbitals
states (states of the atomic potential). The bandwidth is proportional to the hy-
bridization B (12B for a SC lattice). More localized, compact, atomic states tend to
form narrower bands.
bonding band. (See Fig.14). Here, the gap is not tied to the
periodicity of the lattice, and so an amorphous material of C
may also display a gap.
The tight-binding picture can also explain the variety of fea-
tures seen in the DOS of real materials. For example, in Cu
(Ar)3d
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4s the d-orbitals are rather small whereas the valences-orbitals have a large extent . As a result the s-s hybridization
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a
P
sp antibonding3
sp bonding3
S
a
E
r
Figure 14: C (diamond) with atomic configuration of 1s22s22p2. Its valance s and p
states form a strong sp3 hybrid band which is split into a bonding and anti-bonding
band.
Bssi : is strong and the Bddi is weak.
Bddi Bssi (53)
In addition the s-d hybridization is inhibited by the opposing
symmetry of the s-d orbitals.
Bsdi =
si (r r1)v(r r2)di (r r2)d
3r Bssi (54)
where si is essentially even and di is essentially odd. So B
sdi
Bssi . Thus, to a first approximation the s-orbitals will form a
very wide band of mostly s-character and the d-orbitals will
form a very narrow band of mostly d-character. Since both the
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+ +
+1 2
+ +
+ +
d
s
D(E)
Figure 15: Schematic DOS of Cu 3d104s1. The narrow d-band feature is split due to
crystal fields.
s and d bands are valance, they will overlap leading to a DOS
with both d and s features superimposed.
4 Photo-Emission Spectroscopy
The electronic density of electronic states (especially for oc-
cupied states), and to a less extent band structure, are very
important for illuminating the interesting physics of materials.
As we saw in Chap. 6, an enhanced DOS at the Fermi sur-
face indicates an enhanced electronic mass, and if D(EF) = 0,
we have an insulator (semiconductor). The effective electronic
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hd
detector
synchrotron
r
materialsample
V
e
Figure 16: XPS Experiment: By varying the voltage one may select the kinetic
energy of the electrons reaching the counting detector.
mass also varies inversely with the curvature of the bands. The
density of states away from the Fermi surface can allow us to
predict the properties of the material upon doping, or it can
yield information about core-level states. Thus it is important
to be able to measure D(E). This may be done by x-ray pho-
toemission (XPS), UPS or PS in general. The band dispersion
E(k) may also be measured using angle-resolved photoemission
(ARPES) where angle between the incident radiation and the
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detector is also measured.
The basic idea is that a photon (usually an x-ray) is used
to knock an electron out of the system (See figure 17.) Of
Eh - E
b
h - E -b
D(E)
Intensity(E)
Kinetic Energy of electrons h -
X-ray
Eb
Figure 17: Let the binding energy be defined so that Eb > 0, = work function, then
the detected electron intensity I(Ekin h ) D(Eb)f(Eb)
course, in order for an electron at an energy of Eb below the
Fermi surface to escape the material, the incident photon must
have an energy which exceeds Eb and the work function ofthe material. If h > , then the emitted electrons will have
a distribution of kinetic energies Ekin, extending from zero to
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h . From Fermis golden rule, we know that the probability
per unit time of an electron being ejected is proportional to
the density of occupied electronic states times the probability
(Fermi function) that the electronic state is occupied
I(Ekin) =1
(Ekin) D(Eb)f(Eb)
D(Ekin + h)f(Ekin + h) (55)
Thus if we measure the energy and number of ejected particles,
then we know D(Eb).
phonon Coulombicinteration
Secondary electrons
e
e
Figure 18: Left: Origin of the background in I(Ekin. Right: Electrons excited deep
within the bulk scatter so often that they rarely escape. Thus, most of the signal I
originates at the surface, which must be clean and representative of the bulk.
There are several problems with this procedure. First some
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of the photon excited particles will scatter off phonons and elec-
tronic excitations within the material. Since these processes can
occur over a very wide range of energies, they will produce a
broad featureless background in N(Ek). Second, due to these
0 1 2 3 4
Ekin
0
2
4
6
I(E
kin
)
background subtracted
background
raw data
h-
Figure 19: In Photoemission, we measure the rate of ejected electrons as a function
of their kinetic energy. The raw data contains a background. Once this is subtracted
off, the subtracted data is proportional to the electronic density of states convolved
with a Fermi function I(Ekin) D(Ekin + h)f(Ekin + h).
secondary scattering processes, it is very unlikely that an elec-
tron which is excited deep within the bulk, will ever escape from
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measure
h
Ekin
e
Figure 20: BIS Ekin = h Eb , Eb = h Ekin
the material. Thus, we only learn about D(E) near the surface
of the material. Therefore it is important for this surface to be
clean so that it is representative of the bulk. For this reasonthese experiments are often carried out in ultra-high vacuum
conditions.
We can also learn about the electronic states D(E) above the
Fermi surface, E > FF, using Inverse Photoemmision. Here,
an electron beam is focussed on the surface and the outgoingflus of photons are measured.
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