ecom 4314 data communications fall september, 2010

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ECOM 4314 Data Communications Fall September, 2010

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ECOM 4314 Data Communications Fall September, 2010. Lecture #5 Outline. Aspects of Digital-to-Analog Conversion Amplitude Shift Keying Frequency Shift Keying Phase Shift Keying Quadrature Amplitude Modulation. - PowerPoint PPT Presentation

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Page 1: ECOM 4314 Data Communications Fall September, 2010

ECOM 4314

Data CommunicationsFall September, 2010

Page 2: ECOM 4314 Data Communications Fall September, 2010

Data Communication 2

Lecture #5 OutlineLecture #5 Outline

Aspects of Digital-to-Analog Conversion Amplitude Shift Keying Frequency Shift Keying Phase Shift Keying Quadrature Amplitude Modulation

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Digital-to-analog conversion is the process of changing one of the

characteristics of an analog signal based on the information in digital data.

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Digital to Analog ConversionDigital to Analog Conversion

Digital data needs to be carried on an analog signal.

A carrier signal (frequency fc) performs the function of transporting the digital data in an analog waveform.

The analog carrier signal is manipulated to uniquely identify the digital data being carried.

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Digital-to-analog conversion

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Types of digital-to-analog conversion

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Bit rate, N, is the number of bits per second (bps).

Baud rate is the number of signal elements per second (bauds).

In the analog transmission of digital data, the signal or baud rate is less than or equal to the bit rate. S=Nx1/r bauds Where r is the number of data bits per signal element.

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Amplitude Shift Keying (ASK)Amplitude Shift Keying (ASK)

ASK is implemented by changing the amplitude of a carrier signal to reflect amplitude levels in the digital signal.

For example: a digital “1” could not affect the signal, whereas a digital “0” would, by making it zero.

The line encoding will determine the values of the analog waveform to reflect the digital data being carried.

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Bandwidth of ASKBandwidth of ASK

The bandwidth B of ASK is proportional to the signal rate S.

B = (1+d)S “d” is due to modulation and filtering, lies

between 0 and 1.

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Amplitude Shift Keying (ASK)Amplitude Shift Keying (ASK)

Binary amplitude shift keying

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Implementation of binary ASK

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Frequency Shift KeyingFrequency Shift Keying

• The digital data stream changes the frequency of the carrier signal, fc.

• For example, a “1” could be represented by f1=fc +f, and a “0” could be represented by f2=fc-f.

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Frequency Shift KeyingFrequency Shift Keying

Binary frequency shift keying

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Bandwidth of FSKBandwidth of FSK

• If the difference between the two frequencies (f1 and f2) is 2f, then the required BW B will be:

B = (1+d)xS +2f

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ExampleExample

We have an available bandwidth of 100 kHz which spans from 200 to 300 kHz. What should be the carrier frequency and the bit rate if we modulated our data by using FSK with d = 1?

SolutionThis problem is similar to Example 5.3, but we are modulating by using FSK. The midpoint of the band is at 250 kHz. We choose 2Δf to be 50 kHz; this means

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Coherent and Non CoherentCoherent and Non Coherent

In coherent FSK, the switch from one frequency signal to the other only occurs at the same phase in the signal.

In a non-coherent FSK scheme, when we change from one frequency to the other, we do not adhere to the current phase of the signal.

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Multi level FSKMulti level FSK

• Similarly to ASK, FSK can use multiple bits per signal element.

• That means we need to provision for multiple frequencies, each one to represent a group of data bits.

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Multi level FSKMulti level FSK

Figure 5.7 Bandwidth of MFSK used in Example 5.6

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ExampleExample

We need to send data 3 bits at a time at a bit rate of 3 Mbps. The carrier frequency is 10 MHz. Calculate the number of levels (different frequencies), the baud rate, and the bandwidth.

SolutionWe can have L = 23 = 8. The baud rate is S = 3 Mbps/3 = 1 Mbaud. This means that the carrier frequencies must be 1 MHz apart (2Δf = 1 MHz). The bandwidth is B = 8 × 1M = 8M. Figure 5.8 shows the allocation of frequencies and bandwidth.

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ExampleExample

Bandwidth of MFSK used in Example 5.6

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Phase Shift KeyeingPhase Shift Keyeing

We vary the phase shift of the carrier signal to represent digital data.

The bandwidth requirement, B is:B = (1+d)xS

PSK is much more robust than ASK as it is not that vulnerable to noise, which changes amplitude of the signal.

PSK is less susceptible to noise than ASK. PSK is superior to FSK because we do not need two carrier signals

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Phase Shift KeyeingPhase Shift Keyeing

Binary phase shift keying

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Phase Shift KeyeingPhase Shift Keyeing

Implementation of BASK

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Quadrature PSKQuadrature PSK

To increase the bit rate, we can code 2 or more bits onto one signal element.

In QPSK, we parallelize the bit stream so that every two incoming bits are split up and PSK a carrier frequency.

One carrier frequency is phase shifted 90 from the other - in quadrature.

The two PSK signals are then added to produce one of 4 signal elements. L = 4 here.

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Quadrature PSKQuadrature PSK

QPSK and its implementation

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Quadrature PSKQuadrature PSK

To increase the bit rate, we can code 2 or more bits onto one signal element.

In QPSK, we parallelize the bit stream so that every two incoming bits are split up and PSK a carrier frequency. One carrier frequency is phase shifted 90o from the other - in quadrature.

The two PSKed signals are then added to produce one of 4 signal elements. L = 4 here.

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QPSK and its implementation

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Analog-to-analog conversionAnalog-to-analog conversion

Analog-to-analog conversion is the representation of analog information by an analog signal.

One may ask why we need to modulate an analog signal; it is already analog.

Modulation is needed if the medium is bandpass in nature or if only a bandpass channel is available to us.

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Analog-to-analog conversionAnalog-to-analog conversion

Types of analog-to-analog modulation

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Amplitude ModulationAmplitude Modulation

A carrier signal is modulated only in amplitude value

The modulating signal is the envelope of the carrier

The required bandwidth is 2B, where B is the bandwidth of the modulating signal

Since on both sides of the carrier freq. fc, the spectrum is identical, we can discard one half, thus requiring a smaller bandwidth for transmission.

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Amplitude ModulationAmplitude Modulation

Amplitude modulation

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Amplitude ModulationAmplitude Modulation

The total bandwidth required for AM can be determined from the bandwidth

of the audio signal: BAM = 2B.

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Frequency ModulationFrequency Modulation

The modulating signal changes the freq. fc of the carrier signal

The bandwidth for FM is high It is approx. 10x the signal frequency

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Frequency ModulationFrequency Modulation

The total bandwidth required for FM can be determined from the bandwidth of the audio signal: BFM = 2(1 + β)B.

Where is usually 4.

Page 35: ECOM 4314 Data Communications Fall September, 2010

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Frequency ModulationFrequency Modulation

Frequency modulation

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Phase Modulation (PM)Phase Modulation (PM)

The modulating signal only changes the phase of the carrier signal.

The phase change manifests itself as a frequency change but the instantaneous frequency change is proportional to the derivative of the amplitude.

The bandwidth is higher than for AM.

Page 37: ECOM 4314 Data Communications Fall September, 2010

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Phase Modulation (PM)Phase Modulation (PM)

Phase modulation

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Phase Modulation (PM)Phase Modulation (PM)

The total bandwidth required for PM can be determined from the bandwidth

and maximum amplitude of the modulating signal:

BPM = 2(1 + β)B.Where = 2 most often.

Page 39: ECOM 4314 Data Communications Fall September, 2010

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ReferencesReferences

Ayman, Maliha, “Data Communication Lectures”, IUG.

BehrouzA. Forouzan , “Data Communications and Networking”, 4rdEdition, Chapter4, 2007

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