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George Kaptay Professor, corresponding member of the Hungarian Academy of Sciences
Application of the nano-Calphad method to select stable binary
nano-crystalline alloys
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Outlines
Calphad
Nano-Calphad
Stabilization of nano-grains in polycrystals
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Part 1. The essence of Calphad
happy customer unhappy customer
The subject of this talk
State parameters Equilibrium state
The subject of another talks
The subject of another talks
CALPHAD = CAlculation of PHAse Diagrams / equilibrium
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What we define and what Nature (God) defines
Number and nature of components, their
average concentration + temperature + pressure (+ size, if below 100 nm)
Number of phases Nature of phases
Phase fraction of phases Composition of phases
(shape, if below 100 nm)
Empirical way
Number of experiments needed for 84 stable elements: 10085 = 10170
Years needed if each hs performes 1 experiment per day: 10158 Mission Impossible
Gibbs energy
Calphad step 1 Databank collection
and modelling
Calphad step 2 Calculation of equilibrium
(phase diagrams)
The Calphad way
Calphad
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Materials balance System: your selection of a 3-D part of a Universe, including some matter n (mole), containing C (= 1, 2, β¦) components, each denoted as i = A, B, etcβ¦ (component = element)
ππ = πππ΄π΄ + πππ΅π΅ π₯π₯π΅π΅ β‘πππ΅π΅ππ
π₯π₯π΄π΄ = 1 β π₯π₯π΅π΅
Phase: a homogenous 3-D part of the system, formed spontaneously (not by us): Ξ¦ = Ξ±, Ξ²β¦ (their number: P = 1, 2, β¦)
ππ = οΏ½ππΦΦ
π¦π¦Ξ¦ β‘ππΞ¦ππ
π¦π¦πΌπΌ = 1 β π¦π¦π½π½
Each phase is composed of the same components as the system:
ππΞ¦ = πππ΄π΄(Ξ¦) + πππ΅π΅(Ξ¦) π₯π₯π΅π΅(Ξ¦) β‘πππ΅π΅(Ξ¦)
ππΞ¦ π₯π₯π΄π΄(Ξ¦) = 1 β π₯π₯π΅π΅(Ξ¦)
Materials balance equation: π₯π₯π΅π΅ = οΏ½π¦π¦Ξ¦ β π₯π₯π΅π΅(Ξ¦)Ξ¦
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g
l
s(Ξ±)
s(Ξ²)
An example of a 4-phase system
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Calphad
C, i, T, p
π₯π₯ππ P, Ξ¦
π¦π¦Ξ¦
π₯π₯ππ(Ξ¦)
πΊπΊππ(Ξ¦)
πΊπΊ = οΏ½π¦π¦Ξ¦ β πΊπΊΞ¦Ξ¦
πΊπΊΞ¦ = οΏ½π₯π₯i(Ξ¦) β πΊπΊi(Ξ¦)i
πΊπΊππ(Ξ¦) = ππ(πΆπΆ, ππ,ππ,ππ, π₯π₯i Ξ¦ ) πΊπΊ β ππππππ
πΊπΊππ(Ξ±) = πΊπΊππ(Ξ²)
ππππππππ = πΆπΆ + 2
π₯π₯ππ = οΏ½π¦π¦Ξ¦ β π₯π₯ππ(Ξ¦)Ξ¦
1.Calculation 2. Selection
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Does the solution exist?
Un-knowns for equilibrium state: π¦π¦Ξ¦ and π₯π₯ππ(Ξ¦)
Their number: (P-1) + P(C-1) = PC -1
Equations: πΊπΊππ(Ξ±) = πΊπΊππ(Ξ²) and π₯π₯ππ = οΏ½π¦π¦Ξ¦ β π₯π₯ππ(Ξ¦)Ξ¦
Their number: C(P-1) + C-1 = PC -1
As the number of un-knowns equals the number of equations,
the solution always exists
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Why?? πΊπΊ β ππππππ
The upper layer of the Earth
Towards equilibrium
Towards higher energy
There are at least two explanationsβ¦.
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Why?
A-B phase Ξ²A-B phase Ξ±
πΊπΊππ(Ξ±) = πΊπΊππ(Ξ²)
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Algorithm for 2-phase, 2-component macro-equilibria
1. Fix values for p, T, xA
Ξ²Ξ± ,, AA GG = Ξ²Ξ± ,, BB GG =
2. Solve the system of equations for xA,Ξ± and xA,Ξ²
In the two-phase Ξ±-Ξ² region the solution is not xA-dependent
3. Find the phase ratio yΞ±:
Ξ²Ξ±
Ξ²Ξ±
,,
,
AA
AA
xxxx
yβ
β=
This is a true tie-line
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Calphad needs supercomputers
0
10
20
30
0 21 42 63 84
LG(c
ombi
natio
ns)
Components
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Part 2. The essence of nano-Calphad
Nano-Calphad β‘ Calphad applied to nano-materials
Nano-materials β‘ materials with at least 1 phase with at least one of its dimensions below 100 nm
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Nano came last
kmfm nm Β΅m mm mpm
logLTΒ΅-Tn-Tp-Tf-T
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Why nano-materials are so special?
0
20
40
60
80
100
0 10 20 30 40 50
% o
f ato
ms a
long
surf
ace
r, nm
π₯π₯π π = π΄π΄π π π π βππππππ
π΄π΄π π π π β‘π΄π΄ππ
More than 1 % of atoms are along the surface, and so all
properties are size-dependent
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Size dependence of properties
80
100
120
140
160
180
200
220
0 20 40 60 80 100
Any
prop
erty
% of surface atoms
ππ = ππππ + π₯π₯π π β πππ π β ππππ
80
100
120
140
160
180
200
220
0 10 20 30 40 50
Any
prop
errt
y
r, nm
ππ = ππππ + π΄π΄π π π π βππππππβ πππ π β ππππ
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Size dependence of molar Gibbs energy 1
ππ = ππππ + π΄π΄π π π π βππππππβ πππ π β ππππ
ππ β‘ πΊπΊππ πΊπΊππ = πΊπΊππ,ππ + π΄π΄π π π π βππππππβ πΊπΊππ,π π β πΊπΊππ,ππ
πΊπΊππ = πΊπΊππ,ππ + π΄π΄π π π π β ππππ β ππ
ππ =πΊπΊππ,π π β πΊπΊππ,ππ
ππ
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Size dependence of molar Gibbs energy 2
Gibbs, 1878: πΊπΊ = πΊπΊππ + π΄π΄ β ππ
Divide by n:
ππ =ππππππ
π΄π΄π π π π β‘π΄π΄ππ
πΊπΊππ = πΊπΊππ,ππ + π΄π΄π π π π β ππππ β ππ
πΊπΊππ β‘πΊπΊππ
πΊπΊππ,ππ β‘πΊπΊππππ
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Size dependence of chemical potential
ππππ = ππππ,ππ + π΄π΄π π π π β ππππ,ππ β ππππ
πΊπΊππ = πΊπΊππ,ππ + π΄π΄π π π π β ππππ β ππ
πΊπΊππ = οΏ½ π₯π₯ππ β ππππππ
πΊπΊππ,ππ = οΏ½ π₯π₯ππ β ππππ,ππππ
ππππ = οΏ½ π₯π₯ππ β ππππ,ππππ
πΊπΊππ = οΏ½ π₯π₯ππ β ππππππ
= οΏ½ π₯π₯ππ β ππππ,ππ + π΄π΄π π π π β ππππ,ππ β ππππ
ππ = ππππ
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Chemical potential in multi-phase situations
ππππ = ππππ,ππ + π΄π΄π π π π β ππππ,ππ β ππ + ππππ,ππ βπΊπΊππππππ β πΊπΊπππ π
ππ
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Case 1: sessile drop
ππππ(π π π π π π π π πππ π π π ) = ππππ,ππ +3ππβ ππππ,ππ β πππ π ππ β
2 β 3 β ππππππΞ + ππππππ3Ξ4
1/3
ππππ = ππππ,ππ + π΄π΄π π π π β ππππ,ππ β ππππ
0
0,2
0,4
0,6
0,8
1
0 30 60 90 120 150 180
, degrees
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Case 2: Liquid confined in capillaries
ππππ(πππππ π ) = ππππ,ππ β2πππππππ π
β ππππ,ππ β πππ π ππ β ππππππΞ
ππππ(πππππ π ) = ππππ,ππ +2πππππππ π
β ππππ,ππ β πππ π ππ
-1
-0,5
0
0,5
1
0 30 60 90 120 150 180
, degrees
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Josiah Willard Gibbs 1839 - 1903
William Thomson (Lord Kelvin) 1824 - 1907
(1869) (1878)
The historical accident: nano-Calphad came before Calphad
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The Kelvin equation and the reasons of its incorrectness
πΊπΊππ = ππππ + ππ β ππππ β ππ β ππππ ππππππ = ππππππππ + ππ β1ππ1
+1ππ2
πΊπΊππ = πΊπΊππ,ππ + π΄π΄π π π π β ππππ β ππ
πΊπΊππ = πΊπΊππ,ππ +1ππ1
+1ππ2
β ππππ β ππ
Reasons of incorrectness: - p is a state parameter, not an inside pressure p(in) - No nano-effect for not-curved phases ? (cubic nano-L) - The surface term of Gibbs is forgotten, - The Laplace pressure is obtained from Gβ¦. - Contradiction with nucleation theory
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The nucleation contradiction
[J Nanosci Nanotechnol 12 (2012) 2625-2633]
Gibbs: critical size
Gibbs: equilibrium size
Kelvin (Gibbs-Thomson): equilibrium size
nucleus size, nm
Gibbs
energy
change,
J
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Kelvin (Gibbs-Thomson) or Gibbs?
Gibbs (specific surface area)
msSb VAGG ,, ΦΦΦΦΦ β β =β Ο
Kelvin (curvature)
+β β =β ΦΦΦΦ
21,
11rr
VGG mgb Ο
2r
rVmβ β Ο2
rVmβ β Ο3
0Ξ΄
Ξ΄ΟΟ moutin Vβ + )(
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CALORIMETRIC INVESTIGATION OF THE LIQUID Sn-3.8Ag-0.7Cu ALLOY WITH MINOR Co ADDITIONS
Andriy Yakymovych University of Vienna, Austria
George Kaptay University of Miskolc, Hungary
Ali Roshanghias, Hans Flandorfer, Herbert Ipser University of Vienna, Austria
. J. Phys. Chem. C,120 (2016) 1881-1890
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High-Temperature Calorimeter
β’SETARAM Β© β’High temperature calorimeter (twin calorimeter) β’ambient to 1000Β°C Equipped with an
automatic dropping device
H. Flandorfer, F. Gehringer, E. Hayer, Thermochim. Acta 382 (2002), 77-87
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Materials Sn-3.8Ag-0.7Cu foil High purity metals in bulk form
Alfa Aesar (99.99%)
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Results
βπ»π»ππππππππ= β7.5 Β± 1.5 ππππ/ππππππ
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Theoretical Consideration
π΄π΄π π π π β ππππ = π΄π΄π΅π΅π΅π΅π΅π΅ β ππ
( ) -2, , 2.80 0.15 J m
Dsg H TΟ β Β± β
( ) 3 2 150 10 10 m kgBETA β= Β± β β 3 158.933 10 kg molM β β= β β
βπ»π»ππ,ππβ= β8.2 Β± 2.1 ππππ/ππππππ
βπ»π»ππ,π π πππ π = β7.5 Β± 1.5 ππππ/ππππππ
πΊπΊππ = πΊπΊππ,ππ + π΄π΄π π π π β ππππ β ππ
bulk-liquid nano-liquid nano-bulk
π»π»ππππππ,ππππππππ = π»π»ππππππβπππππ π ππ + βπ»π»ππππππππ
βπ»π»ππππππππ = (0 β π΄π΄π π π π ) β ππππ β πππ π π π ,π»π»
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A new state parameter
ππππ(πΌπΌ) = ππππ(π½π½) ππππ = ππππ,ππ + π΄π΄π π π π β ππππ,ππ β ππππ
80
100
120
140
160
180
200
220
0 10 20 30 40 50
, J/m
ol
r, nm
A new state parameter: Asp, r, or N
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The extended phase rule of Gibbs
Gibbs, 1875:
Due to a new, independent variable:
CP += 3max PCF β+= 3
P = number of phases, C = number of components, F = freedom
[J. Nanosci. Nanotechnol., 2010, vol.10, pp.8164β8170]
CP += 2max PCF β+= 2
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Macro-thallium
-100
-50
0
50
100
480 500 520 540 560 580 600
T, K
Go a
- G
o HC
P, J
/mol
a = LIQΞ± = VAP2.5E-13 bar
a = HCP
a = BCC
Ξ± = VAP4.2E-11 bar
T1
T2
-15
-12
-9
-6
-3
0
3
6
480 500 520 540 560 580 600
T, K
logp
(bar
)
VAP
BCCHCP
HCP
LIQ
T2
T1
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Nano-thallium (with a quaternary point)
-15
-12
-9
-6
-3
0
3
6
480 500 520 540 560 580 600
T, K
logp
(bar
)
HCP
HCP
BCC LIQ
T1 VAPT2
N>1E12
T3
-15
-12
-9
-6
-3
0
3
6
480 500 520 540 560 580 600
T, K
logp
(bar
)
VAPVAP
LIQ
LIQ
HCP
HCPHCP
T1 T2
T3
N=2E5
BCC
-15
-12
-9
-6
-3
0
3
6
480 500 520 540 560 580 600
T, K
logp
(bar
)
HCPLIQ
HCP
BCC
VAPVAP
Q
HCP
N=1.2E5
-15
-12
-9
-6
-3
0
3
6
480 500 520 540 560 580 600
T, K
logp
(bar
)
HCP
HCP
LIQ
VAP
N=1E4
T4
[G.Kaptay: J. Nanosci. Nanotechnol., 2010, vol.10, pp.8164β8170]
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The size dependence of interfacial energies
Tolman, 1949:
Buff, 1951:
R
phase Ξ±phase Ξ²
r
o
Ξ΄ΟΟ
β +
= 21 VL ΟΟΞ΄
βΞ
β‘
+
β ββ = ....21
ro Ξ΄ΟΟ
0
0,2
0,4
0,6
0,8
1
0 1 2 3 4 5r, nm
Ο, J
/m2
,
Tolman
Buff
Ξ΄
Rcr
Samsonov
ΟΞΏ
( ) SrVTT
m
sslomm ββ β +
β β β=
Ξ΄Ο
23
![Page 37: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/37.jpg)
The separation dependence of interfacial energies
Ξ± = s
Ξ² = g
Ξ³ = l z
( ) )z(f5.0)z( //// β ΟβΟβ +Ο=Ο Ξ³Ξ±Ξ²Ξ±Ξ³Ξ±Ξ³Ξ±
[ ] )z(f5.0)z( //// β ΟβΟβ +Ο=Ο Ξ³Ξ²Ξ²Ξ±Ξ³Ξ²Ξ³Ξ²
2
)(
+
=z
zfΞΎ
ΞΎ
β=
ΞΎzzf exp)(metals:
non-metals:
ββ β++=
ΞΎΟΟΟΟ zz glls exp)( // gllsgs /// ΟΟΟΟ βββ‘β
![Page 38: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/38.jpg)
Surface melting
Ξ± = s
Ξ² = g
Ξ³ = l z
Ξ± = s
Ξ² = g
surface melting
( )
βββ ββββ ββ =
βΞΎ
Ο zSTTVz
AzG o
mo
mos
m exp1)(
-80
-60
-40
-20
0
20
40
60
0 3 6 9 12 15z, nm
βm
G/A
, mJ/
m2 equilibrium thickness of the
surface melted layer, zeq
( )
ββ ββ
β ββ =
TTSVz o
mm
os
eq ΞΎΟΞΎ ln
0
2
4
6
8
10
900 920 940 960 980 1000 1020T, K
z eq, n
m
omT
ΞΎ
( ) )/( SeVTT mo
so
m ββ β β ββ€β ΞΎΟ
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Ξ± Ξ² Ξ± Ξ²
The role of the relative arrangement of phases
Same results for N > 1012
Different results for N < 1012
Ξ± Ξ²
Equilibrium arrangement corresponds to minimum Gibbs energy
β ΦΦΦΦ Οβ β =βs
s/spec,s/surf AVG
![Page 40: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/40.jpg)
6. Dependence on the substrate material
Ξ³
Ξ²Ξ±
Ξ±Ξ²
Ξ³
Ξ±Ξ²
Ξ³
Wettable substrates stabilize nano-droplets
β ΦΦΦΦ Οβ β =βs
s/spec,s/surf AVG
![Page 41: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/41.jpg)
Dependence on segregation (Butler)
)s/(i)s/(B)s/(As/ ... ΦΦΦΦ Ο==Ο=Ο=Ο
3/13/2)(
)()/(
)(
)/(3/13/2
)()/()/( ln
Avi
Ei
Esi
bi
si
Avi
osisi NVf
GGx
xNVf
TRβ β
ββββ +
β
β β β
+=Ξ¦
ΦΦ
Ξ¦
Ξ¦
ΦΦΦ
Ξ²ΟΟ
1xi
)s/(i =β Ξ¦1)( =β Ξ¦
i
bix
0
0,2
0,4
0,6
0,8
1
1,2
0 0,2 0,4 0,6 0,8 1xB*
ΟA, Ο
B, J/
m2
A
B
solution
![Page 42: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/42.jpg)
Size limits of thermodynamics
Thermodynamics is a statistical science
G has an average value for a large number of atoms in the given environment during a long
enough time
At small N the fluctuations will increase.
What is the critical N below which thermodynamic is not valid is a βreligiousβ question (at N = 13: Tm β 0 K, what is OK):
only the fluctuation increases with smaller N
0
200
400
600
800
1000
0 3 6 9 12logNa
T m,i,
K
13 atoms
oimT ,
![Page 43: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/43.jpg)
Algorithm for 2-phase, 2-component nano-phase-equilibria (1)
1. Fix values for p, T, xA, N 2. Suppose a certain phase-arrangement, e.g.
3. Suppose a value for yΞ± (0 < yΞ± < 1), then:
Ξ±Ξ²
NyN β = Ξ±Ξ± NyN β β= )1( Ξ±Ξ²
![Page 44: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/44.jpg)
Algorithm for nano phase equilibria (2)
Ξ²Ξ± ,, AA GG =
4. Suppose a value for xA,Ξ± (0 < xA,Ξ± < 1), then:
Ξ±
Ξ±Ξ±Ξ² y
xyxx AA
A β
β β=
1,
,
Ξ±Ξ± ,, 1 AB xx β=
Ξ²Ξ² ,, 1 AB xx β=
5. Find ΟΞ± and ΟΞ² from the Butler equation (modify xAΞ±).
6. Check, if the equations for G-s with Ο-s are satisfied
7. If not, select new values for (xA,Ξ±, yΞ±) and go back to Step 3
8. If yes, check solution for other phase arrangements / shapes and select equilibrium arrangement / shape configuration for the phases by minimizing Gibbs energy
Ξ²Ξ± ,, BB GG =
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Algorithm for nano phase equilibria (3)
The final result xA,Ξ± and xA,Ξ² will be dependent on xA. Thus, tie line has not the same sense as before.
This is not a true tie-line
![Page 46: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/46.jpg)
T
A BxA
Ξ± Ξ²Ξ± + Ξ²
xA,Ξ²xA,Ξ±
p, N, T = const
A BxA
Ξ±
Ξ²
Ξ± + Ξ²
xA,Ξ²
xA,Ξ±
p, N = const
xA,Ξ²
xA,Ξ±
not a tie line
tie line
![Page 47: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/47.jpg)
Part 3. Thermodynamic stabilization of nano-alloys vs grain coarsening and precipitation
![Page 48: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/48.jpg)
The case of pure metals
πΊπΊππ,π΄π΄ππ = πΊπΊππ,π΄π΄,ππ
ππ + π΄π΄π π π π β ππππ,π΄π΄ππ β πππ΄π΄,π π ππ
ππ
π΄π΄π π π π β‘π΄π΄ππ
=ππππ
πΊπΊππ,π΄π΄ππ = πΊπΊππ,π΄π΄,ππ
ππ +ππππβ ππππ,π΄π΄
ππ β πππ΄π΄,π π ππππ
G.Kaptay: Nano-Calphad: extension of the Calphad method to systems with nano-phases and complexions. J Mater Sci, 47
(2012) 8320-8335
k = 3 (sphere); k = 3.72 (cube); k = 3.36 Β± 0.36 for a grain
0
2000
4000
6000
8000
10000
0 20 40 60 80 100
, J/m
ol
r, nm
coarsening, no stability
![Page 49: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/49.jpg)
2-component alloys (GB = grain boundayr)
49
A = bulk component, B = segregated component, = average mole fraction π₯π₯π΅π΅
y = GB-ratio, = atomic radius, = bulk and GB filling ratios, x = B mole fraction in bulk, ππππππππ = minimum possible grain size, πππ΅π΅
ππ ,πππ΅π΅ππ = molar surface area and GB energy of component B, Ξ© = bulk interaction energy, ππππ = molar volume, πΊπΊππ molar Gibbs energy.
π¦π¦ =ππβ
ππ + 3 β ππππ ππβ β‘
43β ππ β
πππ π ππππππ
β ππππ
ππππ ππππ, πππ π ππ
π₯π₯ =π₯π₯π΅π΅ β π¦π¦1 β π¦π¦ ππππππππ β
ππβ
π₯π₯π΅π΅β 3 β ππππ
ππππ =3 β ππππ β ππππ4 β ππ β πππ΄π΄ππ
1/3
πππ΅π΅ππ = ππ β ππππ2 β
πππ΄π΄πππππ π ππ
πΊπΊππ = π π β ππ β π₯π₯ β πππππ₯π₯ + 1 β π₯π₯ β ππππ 1 β π₯π₯ + Ξ© β π₯π₯ β 1 β π₯π₯ +
+ππ
ππ + 3 β ππππβπππππππ΅π΅ππ
β πππ΅π΅ππ β πππ΅π΅ππ β 1 +3 β ππππππ β π π β ππ β πππππ₯π₯ β Ξ© β 1 β π₯π₯ 2
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W-βAgβ alloys, 500 K, 15 mol% Ag
50 6M meeting, 29 March 2017, Miskolc, Hungary
-1000
0
1000
2000
3000
4000
0 4 8 12 16 20
Gm
, J/m
ol
r, nm
OMEGA = 20 kJ/mol
-1000
0
1000
2000
3000
4000
0 4 8 12 16 20
Gm
, J/m
ol
r, nm
OMEGA = 35 kJ/mol
-1000
0
1000
2000
3000
4000
0 4 8 12 16 20
Gm
, J/m
ol
r, nm
OMEGA = 50 kJ/mol
![Page 51: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/51.jpg)
Stability diagram for W-based alloys
51 6M meeting, 29 March 2017, Miskolc, Hungary
-40
-20
0
20
40
60
80
100
120
140
160
0 5 10 15 20 25 30 35
, kJ/
mol
, kJ/molunstable
kinetically stable
thermodynamically stable
Ti
Cr Sc
YAg, Mn
Ce
Cu
Ta
Mo, Nb99%
75%
ZrFe - Co - Ni Al
???
![Page 52: Application of the nano-Calphad method to select stable ...Β Β· The Kelvin equation and the reasons of its incorrectness πΊπΊππ= ππππ+ ππβππππβππβππππ](https://reader033.vdocuments.us/reader033/viewer/2022060604/6058f629288f2e6076269ce8/html5/thumbnails/52.jpg)
W-Ag phase diagram
52 6M meeting, 29 March 2017, Miskolc, Hungary
0
500
1000
1500
2000
2500
0 0,2 0,4 0,6 0,8 1
T, K
xAg
bulk bcc-W + bulk liq-Ag
bulk bcc-W + bulk fcc-Ag
bulk bcc-W + bulk vap-Ag (1 bar)
W Ag
0
500
1000
1500
2000
2500
0 0,2 0,4 0,6 0,8 1
T, K
xAgW Ag
bulk bcc-W + bulk fcc-Ag
bulk bcc-W + bulk liq-Ag
bulk bcc-W + bulk vap-Ag (1 bar)
100
3010 3 1
bcc-W-nano-grains with
segregated Ag atoms
Maximum Hall-Petch
Maximum stabity
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Theoretically selected stable nc alloys
W-based alloys: Ag, Au, Ba, Bi, Cd, Ce, Cr, Cs, Cu, Eu, Gd, Hg, Ho, In, K, La, Li, Mg, Na, Nd, Pb, Pu, Rb, Sb, Sc, Sm, Sn, Tb, Th, Tl, Tm, U, Y, Yb, Zn.
Mo-based alloys: Ag, Ba, Bi, Ca, Cd, Ce, Cs, Cu, Er, Eu, Hg, Ho, In, K, La, Li,
Mg, Na, Nd, Pb, Rb, Sm, Sr, Tl, Yb.
Nb-based alloys: Ag, Ba, Bi, Ca, Cd, Ce, Cs, Cu, Er, Eu, Gd, Hg, K, La, Li, Mg, Na, Rb, Sc, Sm, Tl, Y, Yb.
Ti-based alloys: Ba, Ca, Ce, Cs, Eu, Gd, K, La, Li, Mg, Na, Nd, Rb, Sr, Yb.
Al-based alloys: Bi, Cd, Cs, In, K, Na, Pb, Rb, Tl.
Mg-based alloys: Cs, K, Na, Rb.
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Key papers
Calphad, 56 (2017) 169-184.
J. Phys. Chem. C, 120 (2016) 1881-1890.
J. Mater. Sci., 51 (2016) 1738-1755.
Langmuir 31 (2015) 5796-5804.
Acta Mater, 60 (2012) 6804-6813.
J Mater Sci, 47 (2012) 8320-8335.
Int. J. Pharmaceutics, 430 (2012) 253-257.
J Nanosci Nanotechnol, 12 (2012) 2625-2633
J. Nanosci. Nanotechnol., 10 (2010) 8164β8170