dm qm background mathematics lecture 10

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  • 8/10/2019 Dm Qm Background Mathematics Lecture 10

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    Quantum Mechanics for

    Scientists and Engineers

    David Miller

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    Background mathematics 10

    Linear equations and matrices

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    Linear equations and matrices

    Suppose we have equations for two

    straight linesNote, if you are used to the form

    we can rewrite this as

    so these are equivalentWe can rewrite these equations as

    the one matrix equation

    or, with b1 instead of x and b2instead of y

    in summation form

    11 12 1

    12 22 2

    A x A y c

    A x A y c

    y mx c

    11 12 1 12( / ) ( / )y A A x c A

    11 12 1

    21 22 2

    A cx xAA A cy y

    2

    1

    mn n m

    n

    A b c

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    Linear equation solutions

    With the linear equations in matrix

    formwe can formally solve them if weknow the inverse

    multiplying by

    Sincewe have the solution

    the intersection point of

    the linesSolving linear equations and invertinga matrix are the same operation

    11 12 1

    21 22 2

    A A cx x

    A A A cy y

    1A

    1A 11 1

    2

    cxA A Acy

    1 A I

    11

    2

    cx Acy

    ( , )x y

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    Determinant

    If the determinant of a matrix is

    not zerothen the matrix has an inverse

    and if a matrix has an inverse,

    the determinant of the matrixis not zero

    A nonzero determinant is a

    necessary and sufficient

    condition for a matrix to beinvertible

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    Determinant of a matrix

    The determinant of a matrix is

    written in one of two notations

    There are two complete formulasfor calculating it

    Leibnizs formulaLaplaces formula

    and many numerical techniquesto calculate it

    we will not give these generalformulas or methods here

    11 12 1

    21 22 2

    1 2

    det

    N

    N

    N N NN

    A A

    A A AA

    A A A

    A

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    Determinant of a 2x2 matrix

    For a 2x2 matrix

    we add the product on the leadingdiagonal

    and subtract the product on the otherdiagonal

    11 12 11 22 12 2121 22

    detA A

    A A A A AA A

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    Determinant of a 3x3 matrix

    For a 3x3 matrix, we have

    11 22 33 23 3211 12 13

    21 22 23 12 21 33 23 31

    31 32 3313 21 32 22 31

    det

    A A A A AA A A

    A A A A A A A A A

    A A A A A A A A

    + +-11

    2

    12 13

    21 2 23

    32 3331

    A

    A

    A

    A

    A A

    A

    A

    11 13

    2

    12

    21 22

    331 332

    3

    A

    A A

    A

    A

    A A

    A

    A

    13

    21 2

    11 12

    22

    31 32

    3

    33

    A

    A A

    A A

    A A

    A

    A

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    General form of determinant

    If we multiply out the 3x3 determinant expression

    we see that each term, e.g., contains adifferent element from each row

    and the elements in each term are never fromthe same column

    but we always have one element from eachrow and each column in each term

    11 22 33 23 32 12 21 33 23 31 13 21 32 22 3111 22 33 11 23 32 12 21 33 12 23 31 13 21 32 13 22 31

    det A A A A A A A A A A A A A A A A

    A A A A A A A A A A A A A A A A A A

    12 23 31A A A

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    General form of the determinant

    We see that this form

    contains every possible term with one

    element from each rowall from different columns

    this is a general property ofdeterminants

    11 22 33 11 23 32 12 21 33 12 23 31 13 21 32 13 22 31det A A A A A A A A A A A A A A A A A A A

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    General form of the determinant

    To understand how to construct a

    determinantit only remains to find the sign of the terms

    To do so

    count the number of adjacent row (orcolumn) swaps required

    to get all the elements in the term ontothe leading diagonal

    if that number is even, the sign is +if that number is odd, the sign is -

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    Sign of determinant terms

    For the term

    we have to perform 1 row swap

    1 is an odd number

    so the sign of this term in the

    determinant is negative

    11 23 32A A A

    12 13

    21 2

    11

    232

    31 3 332

    A

    A A

    A

    A A

    A

    A

    11

    32

    23

    12 13

    31 33

    21 22

    A A

    A

    A A

    A

    A

    A

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    Sign of determinant terms

    For the term

    we have to perform 2 row swaps

    2 is an even number

    so the sign of this term in the

    determinant is positive

    This is actually Leibnizs determinant formula

    12 23 31A A A

    11 13

    21 2

    12

    23

    31

    2

    32 33

    A

    A

    A

    A

    A

    A

    A 31

    12

    23

    32 33

    11 13

    21 22

    A

    A

    A A

    A

    A

    A

    11 13

    32 33

    1

    21 2

    2

    1

    22

    3

    3

    A A

    A A

    A A

    A

    A

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    Background mathematics 10

    Eigenvalues and eigenvectors

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    Matrix eigenequation

    An equation of the form

    where d is a vector, is a number, and isa square matrix

    is called aneigenequation

    with eigenvalue

    and eigenvector d

    If there are solutions

    they may only exist for specific values of

    Ad dA

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    Solving an eigenequation

    We can rewrite as

    where we have introduced the identitymatrix

    which we can always do becauseSo

    (strictly, the 0 here is a vector with elements 0)

    so, writing we have

    d d

    Ad Id

    I

    Id d

    0A I d

    B A I 0Bd

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    Solving an eigenequation

    Now, for to have any solutions for any

    non-zero vector dthe matrix cannot have an inverse

    if it did have an inverse

    but any (finite) matrix multiplying azero vector must give a zero vector

    so there is no non-zero solution d

    Hence, by reductio ad absurdum,has no inverse

    0Bd

    B1B

    1 1 0B Bd Id d B

    B

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    Solving an eigenequation

    The fact that has no inverse means

    from the properties of the determinant

    This equation will allow us to constructa secular equation

    whose solutions will give theeigenvalues

    From those we will deduce thecorresponding eigenvectors d

    B A I

    det 0A I

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    Solving an eigenequation

    Suppose we want to find the eigenvalues and

    eigenvectorsif they exist

    of the matrix

    So we write the determinant condition forfinding eigenvalues

    1.5 0.5 1 0

    det det 00.5 1.5 0 1

    i

    A I i

    1.5 0.50.5 1.5

    iA

    i

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    Solving an eigenequation

    Now

    So our secular equation becomes, from

    i.e.,

    1.5 0.5 1 0 1.5 0.5 0det det

    0.5 1.5 0 1 0.5 1.5 0

    1.5 0.5

    det 0.5 1.5

    i i

    i i

    i

    i

    2 2

    1.5 (0.5 ) 0.5 1.5 0.25 0i i

    2 3 2 0

    det 0A I

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    Solving an eigenequation

    Solving this quadratic equation

    gives rootsand

    Now that we know the eigenvalues

    we substitute them back into theeigenequation

    and deduce the correspondingeigenvectors

    2 3 2 0

    1 1 2 2

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    Solving an eigenequation

    Our eigenequation is, explicitly

    where now, for a given eigenvalue

    we are trying to find d1 and d2so we know the corresponding eigenvector

    Rewriting gives

    Ad d

    1 1

    2 2

    1.5 0.5

    0.5 1.5

    d di

    d di

    1

    2

    1.5 0.5 00.5 1.5 0

    didi

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    Solving an eigenequation

    Now evaluating

    for a specific eigenvalue

    say, the first one,

    gives

    or, as linear equations

    1

    2

    1.5 0.5 0

    0.5 1.5 0

    di

    di

    1 1

    1

    2

    0.5 0.5 0

    0.5 0.5 0

    di

    di

    1 2

    1 2

    0.5 0.5 00.5 0.5 0

    d id

    id d

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    Solving eigenequations

    For larger matrices with eigensolutions

    e.g.,we have correspondingly higher order

    polynomial secular equations

    which can have Neigenvalues andeigenvectors

    e.g., a matrix can have 3 eigenvalues andeigenvectors

    Note eigenvectors can be multiplied by anyconstant and still be eigenvectors

    N N

    3 3

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