diluting solutions. equation m 1 v 1 = m 2 v 2 m = molarity v = volume
DESCRIPTION
Example 1 What volume in milliliters of a 2.00M CaCl 2 stock solution would you use to make 0.50L of 0.300M calcium chloride solution? V 1 = ? mL M 1 =2.00M V 2 =0.50L=500m L M 2 =0.300M M 1 V 1 = M 2 V (V 1 ) = 0.300(500) V 1 =75mL **Variables must have the same units!! Look to the word problem for correct number of sig. figs.TRANSCRIPT
Diluting Solutions
Equation
M1 V1 = M2 V2
M = MolarityV = Volume
Example 1
What volume in milliliters of a 2.00M CaCl2 stock solution would you use to make
0.50L of 0.300M calcium chloride solution? V1= ? mLM1=2.00MV2=0.50L=500mLM2=0.300M
M1 V1 = M2 V2
2.00(V1) = 0.300(500)V1=75mL
**Variables must have the same units!! Look to the word problem for correct number of sig. figs.
Example 2
What volume in milliliters of a 12.0M HCl solution would you use to make 2.50L of
a 2.00M HCl solution? V1= ? mLM1=12.0MV2=2.50L=2500mLM2=2.00M
M1 V1 = M2 V2
12.00(V1) = 2.00(2500)V1=417mL
Colligative Properties
The physical properties of solutions that are different than the physical properties of a pure solvent
These depend only upon the number of particles in a solution Vapor pressure lowering Boiling point increasing Freezing point lowering