dee-m.c-1 teasting of motor
TRANSCRIPT
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Parul Institute of Engineering
& Technology
Subject Code :330903
Name Of Subject : Machine -1
Name of Unit :D.C. MOTOR
Topic :Testing of d.c. motor
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Name of Faculty :Harshad
Mayavanshi
Name of Students:
(i) Parmar Kinjal(116380309009)(ii) Thite Vishruta
(116380309020)
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In this presentation, 2 most commonlyUsed methods are described briefly.
These two methods are:1) Direct Method &2) Indirect Method
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This method is suitable for small
d.c. machines.
In this method the d.c. machine is
subjected to rated load and theentire power output is wasted.
For a d.c. generator, the outputpower is wasted in resistor.
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D.C. MOTOR
Brake Test Swinburns Test
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BRAKE TEST
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Figure shows the arrangement for
this load test. It consists of a brakedrum keyed to the shaft of the
motor.
The brake drum is filled with water
to cool it. It is made of cast iron oraluminium.
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A belt is wrapped around the
drumad each end of the belt is
attached to a spring balance.
The spring balances are
suspended from a frame which isfixed rigidly.
Hand wheels are provided on thetop of the frame.
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The net torque in Kg-m is
calculated using the expression.
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ADVANTAGES
1) The test is simple.
2) Machine is actually loaded, so
true efficiency is obtained
3) As the machine is loaded, the
actual working condition is
produced, So the conditions likearmature reaction, heating,
commutation etc. are produced
when the machine will be used.
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DISADVANTAGES
1) Test is expensive as the outputpower is wasted.
2) Large amount of heat isproduced in machine of high
rating so there is difficulty of
cooling it. Due to these tworeasons, the test is limited for the
machine of the small rating.
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SWINBURNS TEST
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Losses are measured separately in
this method, and efficiency at any
desired load is predetermined.
The iron and friction lossescan be determined by
measuring the input to the
machine at no-load.
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The machine is run as a motor at
normal voltage and speed.
The copper losses are calculated
from measured values of the
various resistances. This method
is only applicable to levelcompounded and shunt motors.
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No load input current = ILoA
Supply voltage = V volt
So, the no load input power = V*ILo
No load armature current Iao = (ILo
Ish)
No load armature copper loss = Iao^2
Ra
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Input power = Output power + Total
lossLosses = No load armature copper
loss + Constant Losses Wc
V ILo = Iao^2 Ra + Wc
So, constant losses Wc = V ILo
Iao^2Ra
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ADVANTAGES
1) This test is economical as the
machine is run only at no load sopower equal to the losses is drawn
from the mains.
2) Efficiency of the machine can be
found either as motor or generator.
3) Machine is not loaded so no
arrangement is to be done for
loading of the machine.
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DISADVANTAGES
1)It is assumed that the iron losses of
the machine remain constant but in
practice when the machine is
loaded, there is change in flux dueto the armature reaction so the iron
losses change.
2) This test is used for the machine
whose speed remains almost
constant.
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3) Machine is tested at the no load
so it does not give any idea aboutcommutation, armature reaction,
heating etc. when the machine will
be actually loaded.
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Sub: M/c- 1
Topic: Testing of motor
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