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    ELECTRIC CIRCUITS

    The different types of wire used in blasting circuits can bedivided into three general categories classified by function:

    i. Leading or leg wires. These insulated wires (usuallymade of copper, but sometimes iron) are integral

    parts of an electric detonator unit. The insulation

    has been removed from the free end of each lead

    wire so that they can be connected to other wires to

    make a circuit.

    ii. Extension lead, connecting wire or buswire. Thiswire (the thickness varying between 21 and 25

    SWG) is used to connect two detonators when their

    lead wires are not long enough to meet. It is also

    used to connect a circuit to the firing cable.

    iii. Firing cable. This is used to connect the detonatorcircuit to the power source, which is generally a

    portable exploder or mains electricity, and is of

    heavy duty construction.

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    Lead wires topower source

    Lead wires topower source

    Lead wires topower source

    Lead wires to

    power source

    Various configurations of a series circuit

    All electric blasting is done by using one of the three basic

    circuits.

    i. Series circuit

    All detonators in a series circuit are connected together to

    provide a single path for the current, and the same amount

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    of current flows through each detonator. The figure above

    shows various configuration of a series circuit.

    This type of circuit is simple to connect and a convenient

    way to fire a small number of detonators (say, a maximum

    of 50). The series circuit has the unique advantage that

    the entire circuit can be tested for continuity and

    resistance.

    It is stipulated that the minimum firing current is 1.5

    amperes by direct current (DC) or 2.5 amperes by

    alternating current (AC).

    Worked example

    Find the voltage required to fire 30 electric detonators

    joined to 200 metres of firing cable with 50 metres of

    connecting wire. The resistances are as follows: an

    average of 2 ohms per detonator, 0.1 ohm per metre of

    connecting wire, and 0.05 ohm per metre for two-core

    firing cable. Suppose a DC power supply is available:

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    Resistance of detonators: 30 X 2.0 = 60

    Resistance of connecting wire: 50 x 0.1 = 5

    Resistance of firing cable: 200 x 0.05 = 10 Total resistance of the circuit = 75

    Hence the minimum voltage required is 1.5 x 75

    = 112.5 volts DC

    ii. Parallel circuitsIn this circuit, one lead wire from each detonator is

    connected to one conductor, while the other lead wire is

    joined to the second conductor.

    A. Straight parallel B. Reverse parallel

    C. Closed-loop straight parallel D. Closed loop reverse parallel

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    Type A causes poor current distribution, whereas type D

    produces the most even current.

    Arcing in the detonator may occur in parallel circuit due to

    heavy current being fed. This causes misfire.

    Arcing can be prevented in a number of ways, one of which

    is to select a firing cable and extension lead with high

    resistance, so that the principal voltage drop will occur

    within the firing line. Thus the voltage over the last

    detonator to fire may be limited to between 50 to 60 volts.

    The average current required is stipulated as 0.7 amps per

    detonator in the circuit.

    Parallel circuit is being used in shaft sinking operation.

    Worked example

    Find the power requirement and the energy input to a

    detonator of a parallel circuit with 30 detonators (each with

    a resistance of 1.5 ohms) with 300 m of twin core firing

    cable (resistance of 0.0033 ohms m-1)

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    Solution:

    Total resistance of detonators = 1.5/30 = 0.05 ohms

    Resistance of firing cable = 600 X 0.0033 = 2 ohmsHence total resistance of the circuit = 2.05 ohms

    Now total current required is 0.7 X 30 = 21 amps

    Voltage required = 21 X 2.05 = 43 volts

    Power requirement = 43 X 21 = 904 watts

    Total energy input (usually initiation time is 4 ms)

    = 904 X 0.004 = 3.6 J

    Energy input per detonator = 3.6/30 = 0.12 J = 120 mJ

    iii. Parallel-series circuits

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