cs b 553: a lgorithms for o ptimization and l earning bayesian networks
TRANSCRIPT
CS B553: ALGORITHMS FOR OPTIMIZATION AND LEARNINGBayesian Networks
AGENDA
Bayesian networks Chain rule for Bayes nets Naïve Bayes models
Independence declarations D-separation
Probabilistic inference queries
PURPOSES OF BAYESIAN NETWORKS
Efficient and intuitive modeling of complex causal interactions
Compact representation of joint distributions O(n) rather than O(2n)
Algorithms for efficient inference with given evidence (more on this next time)
INDEPENDENCE OF RANDOM VARIABLES
Two random variables a and b are independent if
P(A,B) = P(A) P(B)
hence P(A|B) = P(A) Knowing b doesn’t give you any information
about a
[This equality has to hold for all combinations of values that A and B can take on, i.e., all events A=a and B=b are independent]
SIGNIFICANCE OF INDEPENDENCE
If A and B are independent, then P(A,B) = P(A) P(B)
=> The joint distribution over A and B can be defined as a product over the distribution of A and the distribution of B
=> Store two much smaller probability tables rather than a large probability table over all combinations of A and B
CONDITIONAL INDEPENDENCE
Two random variables a and b are conditionally independent given C, if
P(A, B|C) = P(A|C) P(B|C)
hence P(A|B,C) = P(A|C) Once you know C, learning B doesn’t give
you any information about A
[again, this has to hold for all combinations of values that A,B,C can take on]
SIGNIFICANCE OF CONDITIONAL INDEPENDENCE
Consider Grade(CS101), Intelligence, and SAT Ostensibly, the grade in a course doesn’t
have a direct relationship with SAT scores but good students are more likely to get good
SAT scores, so they are not independent… It is reasonable to believe that Grade(CS101)
and SAT are conditionally independent given Intelligence
BAYESIAN NETWORK Explicitly represent independence among
propositions Notice that Intelligence is the “cause” of both Grade
and SAT, and the causality is represented explicitly
Intel.
Grade
P(I=x)
high 0.3
low 0.7
SAT
6 probabilities, instead of 11
P(I,G,S) = P(G,S|I) P(I) = P(G|I) P(S|I) P(I)
P(G=x|I) I=low I=high
‘a’ 0.2 0.74
‘b’ 0.34 0.17
‘C’ 0.46 0.09
P(S=x|I) I=low I=high
low 0.95 0.05
high 0.2 0.8
DEFINITION: BAYESIAN NETWORK
Set of random variables X={X1,…,Xn} with domains Val(X1),…,Val(Xn)
Each node has a set of parents PaX
Graph must be a DAG Each node also maintains a conditional
probability distribution (often, a table) P(X|PaX) 2k-1 entries for binary valued variables
Overall: O(n2k) storage for binary variables
Encodes the joint probability over X1,…,Xn
CALCULATION OF JOINT PROBABILITY
B E P(a|…)
TTFF
TFTF
0.950.940.290.001
Burglary Earthquake
Alarm
MaryCallsJohnCalls
P(b)
0.001
P(e)
0.002
A P(j|…)
TF
0.900.05
A P(m|…)
TF
0.700.01
P(jmabe) = ??
P(jmabe)= P(jm|a,b,e) P(abe)= P(j|a,b,e) P(m|a,b,e) P(abe)(J and M are independent given A)
P(j|a,b,e) = P(j|a)(J and B and J and E are independent given A)
P(m|a,b,e) = P(m|a) P(abe) = P(a|b,e) P(b|e) P(e)
= P(a|b,e) P(b) P(e)(B and E are independent)
P(jmabe) = P(j|a)P(m|a)P(a|b,e)P(b)P(e)
Burglary Earthquake
Alarm
MaryCallsJohnCalls
CALCULATION OF JOINT PROBABILITY
B E P(a|…)
TTFF
TFTF
0.950.940.290.001
Burglary Earthquake
alarm
MaryCallsJohnCalls
P(b)
0.001
P(e)
0.002
A P(j|…)
TF
0.900.05
A P(m|…)
TF
0.700.01
P(jmabe)= P(j|a)P(m|a)P(a|b,e)P(b)P(e)= 0.9 x 0.7 x 0.001 x 0.999 x 0.998= 0.00062
CALCULATION OF JOINT PROBABILITY
b e P(a|…)
TTFF
TFTF
0.950.940.290.001
Burglary Earthquake
alarm
maryCallsjohnCalls
P(b)
0.001
P(e)
0.002
a P(j|…)
TF
0.900.05
a P(m|…)
TF
0.700.01
P(jmabe)= P(j|a)P(m|a)P(a|b,e)P(b)P(e)= 0.9 x 0.7 x 0.001 x 0.999 x 0.998= 0.00062
P(x1x2…xn) = Pi=1,…,nP(xi|paXi)
full joint distribution
CHAIN RULE FOR BAYES NETS
Joint distribution is a product of all CPTs
P(X1,X2,…,Xn) = Pi=1,…,nP(Xi|PaXi)
EXAMPLE: NAÏVE BAYES MODELS
P(Cause,Effect1,…,Effectn)
= P(Cause) Pi P(Effecti | Cause)
Cause
Effect1 Effect2 Effectn
ADVANTAGES OF BAYES NETS (AND OTHER GRAPHICAL MODELS)
More manageable # of parameters to set and store
Incremental modeling Explicit encoding of independence
assumptions Efficient inference techniques
ARCS DO NOT NECESSARILY ENCODE CAUSALITY
A
B
C
C
B
A
2 BN’s with the same expressive power, and a 3rd with greater power (exercise)
C
B
A
READING OFF INDEPENDENCE RELATIONSHIPS
Given B, does the value of A affect the probability of C? P(C|B,A) = P(C|B)?
No! C parent’s (B) are
given, and so it is independent of its non-descendents (A)
Independence is symmetric:C A | B => A C | B
A
B
C
BASIC RULE
A node is independent of its non-descendants given its parents (and given nothing else)
WHAT DOES THE BN ENCODE?
Burglary EarthquakeJohnCalls MaryCalls | AlarmJohnCalls Burglary | AlarmJohnCalls Earthquake | AlarmMaryCalls Burglary | AlarmMaryCalls Earthquake | Alarm
Burglary Earthquake
Alarm
MaryCallsJohnCalls
A node is independent of its non-descendents, given its parents
READING OFF INDEPENDENCE RELATIONSHIPS
How about Burglary Earthquake | Alarm ? No! Why?
Burglary Earthquake
Alarm
MaryCallsJohnCalls
READING OFF INDEPENDENCE RELATIONSHIPS
How about Burglary Earthquake | Alarm ? No! Why? P(BE|A) = P(A|B,E)P(BE)/P(A) = 0.00075 P(B|A)P(E|A) = 0.086
Burglary Earthquake
Alarm
MaryCallsJohnCalls
READING OFF INDEPENDENCE RELATIONSHIPS
How about Burglary Earthquake | JohnCalls? No! Why? Knowing JohnCalls affects the probability of
Alarm, which makes Burglary and Earthquake dependent
Burglary Earthquake
Alarm
MaryCallsJohnCalls
INDEPENDENCE RELATIONSHIPS
For polytrees, there exists a unique undirected path between A and B. For each node on the path: Evidence on the directed road XEY or XEY
makes X and Y independent Evidence on an XEY makes descendants
independent Evidence on a “V” node, or below the V:
XEY, or XWY with W… Emakes the X and Y dependent (otherwise they are independent)
GENERAL CASE
Formal property in general case: D-separation : the above properties hold for all
(acyclic) paths between A and B D-separation independence
That is, we can’t read off any more independence relationships from the graph than those that are encoded in D-separation The CPTs may indeed encode additional
independences
PROBABILITY QUERIES
Given: some probabilistic model over variables X
Find: distribution over YX given evidence E=e for some subset E X / Y P(Y|E=e)
Inference problem
ANSWERING INFERENCE PROBLEMS WITH THE JOINT DISTRIBUTION Easiest case: Y=X/E
P(Y|E=e) = P(Y,e)/P(e) Denominator makes the probabilities sum to 1
Determine P(e) by marginalizing: P(e) = Sy P(Y=y,e)
Otherwise, let Z=X/(EY) P(Y|E=e) = Sz P(Y,Z=z,e) /P(e)
P(e) = Sy Sz P(Y=y,Z=z,e)
Inference with joint distribution: O(2|X/E|) for binary variables
NAÏVE BAYES CLASSIFIER
P(Class,Feature1,…,Featuren)
= P(Class) Pi P(Featurei | Class)
Class
Feature1 Feature2 Featuren
P(C|F1,….,Fn) = P(C,F1,….,Fn)/P(F1,….,Fn)
= 1/Z P(C) Pi P(Fi|C)
Given features, what class?
Spam / Not Spam
English / French / Latin
…
Word occurrences
NAÏVE BAYES CLASSIFIER
P(Class,Feature1,…,Featuren)
= P(Class) Pi P(Featurei | Class)
P(C|F1,….,Fk) = 1/Z P(C,F1,….,Fk)
= 1/Z Sfk+1…fn P(C,F1,….,Fk,fk+1,…fn)
= 1/Z P(C) Sfk+1…fn Pi=1…k P(Fi|C) Pj=k+1…n P(fj|C)
= 1/Z P(C) Pi=1…k P(Fi|C) Pj=k+1…n Sfj P(fj|C)
= 1/Z P(C) Pi=1…k P(Fi|C)
Given some features, what is the distribution over class?
FOR GENERAL QUERIES
For BNs and queries in general, it’s not that simple… more in later lectures.
Next class: skim 5.1-3, begin reading 9.1-4