8/8/2019 Correction de Devoirs Libre 01

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01

1 :

+H : .

.2 :

:Pf=27,5kPa :PV=nRT

:( ) ( )2 2 2( ) f f f P CO V CO n CO RT =( ) ( )2 2

2( )f f

f

f

P CO V COn CO

RT=

T=273+25=298K

:R=8,314m3.Pa.K mol-1:Pf(CO2)=27,5.103Pa

:Vf(CO2)=1,41l-0,06l=1,35L

: 3 3

2

27,5.10 1,35.10( ) 0,0149

8,31 298f

n CO mol

= =

3 :

:3. 5,0 60 10 0,3 A A An C V mol

= = =

: ( )

( )

3

3

1,250,015

84B

m NaHCOn mol

M NaHCO

= = =

4

nB

8/8/2019 Correction de Devoirs Libre 01

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)0( (1)(2)

(1) (2).

2: I :1 . .2 .II .1 " ."....

mer air B A

B A

A B

d dV V t t

t t

t t

> >