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Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc. Chapter 5 Exponentia l and Logarithmi c Functions

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Page 1: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 1

Active Learning Lecture SlidesFor use with Classroom Response Systems

© 2009 Pearson Education, Inc.

Chapter 5Exponential

and Logarithmic Functions

Page 2: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 2

CHAPTER 5: Exponential and

Logarithmic Functions5.1 Inverse Functions5.2 Exponential Functions and Graphs5.3 Logarithmic Functions and Graphs

5.4 Properties of Logarithmic Functions

5.5 Solving Exponential and Logarithmic Equations

5.6 Applications and Models: Growth and Decay; and

Compound Interest

Page 3: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 3

Find the inverse of the relation

a.

c.

b.

d.

3,2 , 4,0 , 5,1 , 1, 6

3, 2 , 4,0 , 5, 1 , 1,6 .

2, 3 , 0, 4 , 1,5 , 6,1

2,3 , 0,4 , 1, 5 , 6, 1

1 1 1 1 1, , ,0 , , 1 , 1,

3 2 4 5 6

Page 4: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 4

Find the inverse of the relation

a.

c.

b.

d.

3,2 , 4,0 , 5,1 , 1, 6

3, 2 , 4,0 , 5, 1 , 1,6 .

2, 3 , 0, 4 , 1,5 , 6,1

2,3 , 0,4 , 1, 5 , 6, 1

1 1 1 1 1, , ,0 , , 1 , 1,

3 2 4 5 6

Page 5: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 5

Find the inverse of the relation

a.

c.

b.

d.

4,2 , 0, 5 , 5,3 , 1, 7

2,4 , 5,0 , 3, 5 , 7,1 .

4, 2 , 0,5 , 5, 3 , 1,7

2, 4 , 5,0 , 3,5 , 7, 1

1 1 1 1 1 1, , ,0 , , , ,1

2 4 5 3 5 6

Page 6: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 6

Find the inverse of the relation

a.

c.

b.

d.

4,2 , 0, 5 , 5,3 , 1, 7

2,4 , 5,0 , 3, 5 , 7,1 .

4, 2 , 0,5 , 5, 3 , 1,7

2, 4 , 5,0 , 3,5 , 7, 1

1 1 1 1 1 1, , ,0 , , , ,1

2 4 5 3 5 6

Page 7: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 7

Find a formula for the inverse of the function f(x) = 10 – 6x.

a.

c.

b.

d.

1 6 10f x x

1 6

10

xf x

1 10

6

xf x

1 5

3f x x

Page 8: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 8

Find a formula for the inverse of the function f(x) = 10 – 6x.

a.

c.

b.

d.

1 6 10f x x

1 6

10

xf x

1 10

6

xf x

1 5

3f x x

Page 9: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 9

Find a formula for the inverse of the function f(x) = 2x+5.

a.

c.

b.

d.

1 5

2

xf x

1 15

2f x x

1 5 2f x x

1 5

2

xf x

Page 10: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 10

Find a formula for the inverse of the function f(x) = 2x+5.

a.

c.

b.

d.

1 5

2

xf x

1 15

2f x x

1 5 2f x x

1 5

2

xf x

Page 11: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 11

Which of the following functions is one-to-one?

a. b.

c. d.

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

Page 12: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 12

Which of the following functions is one-to-one?

a. b.

c. d.

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

Page 13: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 13

Which of the following graphs illustrates the graph of f(x) = 4x.

a. b.

c. d.

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

Page 14: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 14

Which of the following graphs illustrates the graph of f(x) = 4x.

a. b.

c. d.

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

Page 15: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 15

Which of the following graphs illustrates the graph of f(x) = –2x – 1.

a. b.

c. d.

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

Page 16: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 16

Which of the following graphs illustrates the graph of f(x) = –2x – 1.

a. b.

c. d.

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

X

Y

-5 -4 -3 -2 -1 1 2 3 4 5

-5

-4

-3

-2

-1

1

2

3

4

5

0

Page 17: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 17

Find the approximate value of e0.16 to four decimal places.

a. –1.1735

c. 0.8521

b. –0.8521

d. 1.0161

Page 18: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 18

Find the approximate value of e–0.16 to four decimal places.

a. –1.1735

c. 0.8521

b. –0.8521

d. 1.0161

Page 19: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 19

Using the compound interest formula,

determine the approximate amount in the account after 5 years if the investment is $1500 at an

interest rate of 8.2% compounded quarterly.

a. $2195.64

c. $2260.23

b. $2250.88

d. $2271.56

1nt

rA P

n

Page 20: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 20

Using the compound interest formula,

determine the approximate amount in the account after 5 years if the investment is $1500 at an

interest rate of 8.2% compounded quarterly.

a. $2195.64

c. $2260.23

b. $2250.88

d. $2271.56

1nt

rA P

n

Page 21: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 21

Suppose a school deposited a $1000 scholarship in an account paying 7.9% interest compounded quarterly. Approximately how much will the scholarship be worth in two years?

a. $1169.36

c. $1268.77

b. $1250.98

d. $1316.42

Page 22: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 22

Suppose a school deposited a $1000 scholarship in an account paying 7.9% interest compounded quarterly. Approximately how much will the scholarship be worth in two years?

a. $1169.36

c. $1268.77

b. $1250.98

d. $1316.42

Page 23: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 23

Convert to a logarithmic equation: 2x = 20.

a. x = log220

c. 2 = logx20

b. x = log10

d. x = log202

Page 24: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 24

Convert to a logarithmic equation: 2x = 20.

a. x = log220

c. 2 = logx20

b. x = log10

d. x = log202

Page 25: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 25

Convert to an exponential equation: log3x = 5.

a. x = 53

c. x5 = 3

b. x = 35

d. x3 = 5

Page 26: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 26

Convert to an exponential equation: log3x = 5.

a. x = 53

c. x5 = 3

b. x = 35

d. x3 = 5

Page 27: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 27

Find ln 3 using a calculator. Round to four decimal places.

a. 0.4771

c. 20.0855

b. 1.0986

d. 1000

Page 28: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 28

Find ln 3 using a calculator. Round to four decimal places.

a. 0.4771

c. 20.0855

b. 1.0986

d. 1000

Page 29: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 29

Find log 0.001. Do not use a calculator.

a. –4

c. 3

b. –3

d. 1000

Page 30: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 30

Find log 0.001. Do not use a calculator.

a. –4

c. 3

b. –3

d. 1000

Page 31: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 31

Find log58 using the change-of-base formula.

a. 0.2041

c. 1.2920

b. 0.7740

d. 1.6

Page 32: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 32

Find log58 using the change-of-base formula.

a. 0.2041

c. 1.2920

b. 0.7740

d. 1.6

Page 33: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 33

Express in terms of sums and

differences of logarithms:

a.

c.

b.

d.

2

3log .x

y

1 1log log

9 3x y

6log 3logx y

2 1log log

3 3x y

2log log

3x y

Page 34: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 34

Express in terms of sums and

differences of logarithms:

a.

c.

b.

d.

2

3log .x

y

1 1log log

9 3x y

6log 3logx y

2 1log log

3 3x y

2log log

3x y

Page 35: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 35

Express in terms of sums and

differences of logarithms:

a.

c.

b.

d.

35log .y z

3log log

5y z

5log 5log

3y z

5log3 5logy z

3 1log log

5 5y z

Page 36: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 36

Express in terms of sums and

differences of logarithms:

a.

c.

b.

d.

35log .y z

3log log

5y z

5log 5log

3y z

5log3 5logy z

3 1log log

5 5y z

Page 37: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 37

Given that logc2 = 0.3333 and logc12 = 1.1950, find logc6.

a. 3.5854

c. 0.8617

b. 0.9999

d. 0.1951

Page 38: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 38

Given that logc2 = 0.3333 and logc12 = 1.1950, find logc6.

a. 3.5854

c. 0.8617

b. 0.9999

d. 0.1951

Page 39: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 39

Given that loga3 = 0.6826 and loga4 = 0.8614, find loga36.

a. 0.4014

c. 2.2266

b. 1.1760

d. 4.6320

Page 40: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 40

Given that loga3 = 0.6826 and loga4 = 0.8614, find loga36.

a. 0.4014

c. 2.2266

b. 1.1760

d. 4.6320

Page 41: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 41

Simplify: lne6t.

a. e-6t

c. 6t

b. te6

d. –6t

Page 42: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 42

Simplify: lne6t.

a. e-6t

c. 6t

b. te6

d. –6t

Page 43: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 43

Solve: log3(3x + 6) – log3(x – 6) = 2.

a. 14

c.

b. 10

d. Does not exist

3

2

Page 44: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 44

Solve: log3(3x + 6) – log3(x – 6) = 2.

a. 14

c.

b. 10

d. Does not exist

3

2

Page 45: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 45

Solve: log2(x + 5) + log2(x – 1) = 4.

a.

c. 5

b. 3

d. 6

1

3

Page 46: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 46

Solve: log2(x + 5) + log2(x – 1) = 4.

a.

c. 5

b. 3

d. 6

1

3

Page 47: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 47

Solve: log2(x – 3) + log2(2x – 10) = 4.

a. 4

c.

b. 7

d. No solution

29

3

Page 48: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 48

Solve: log2(x – 3) + log2(2x – 10) = 4.

a. 4

c.

b. 7

d. No solution

29

3

Page 49: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 49

Solve: 25+x = 32x-4.

a.

c.

b.

d. 25

4

69

15

9

4

15

4

Page 50: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 50

Solve: 25+x = 32x-4.

a.

c.

b.

d. 25

4

69

15

9

4

15

4

Page 51: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 51

Solve: 35+4x = 9x.

a.

c.

b. –5

d.

5

2

5

3

5

3

Page 52: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 52

Solve: 35+4x = 9x.

a.

c.

b. –5

d.

5

2

5

3

5

3

Page 53: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 53

The population of a city doubled in 12 years. What was the approximate exponential growth rate?

a. 16.7%

c. 5.8%

b. 6.0%

d. 2.48%

Page 54: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 54

The population of a city doubled in 12 years. What was the approximate exponential growth rate?

a. 16.7%

c. 5.8%

b. 6.0%

d. 2.48%

Page 55: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 55

The population of a city doubled in 10 years. What was the approximate exponential growth rate?

a. 3.0%

c. 6.9%

b. 5.0%

d. 14.4%

Page 56: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 56

The population of a city doubled in 10 years. What was the approximate exponential growth rate?

a. 3.0%

c. 6.9%

b. 5.0%

d. 14.4%

Page 57: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 57

Suppose $2000 is invested at interest rate, k, compounded continuously, and grows to $2,473.53 in 5 years. Find the approximate interest rate.

a. 3.83%

c. 4.75%

b. 4.25%

d. 7.89%

Page 58: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 58

Suppose $2000 is invested at interest rate, k, compounded continuously, and grows to $2.473.53 in 5 years. Find the approximate interest rate.

a. 3.83%

c. 4.75%

b. 4.25%

d. 7.89%

Page 59: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 59

Suppose $2000 is invested at interest rate, k, compounded continuously, and grows to $2.473.53 in 5 years. Find the approximate doubling time.

a. 7.1 years

c. 16.3 years

b. 14.6 years

d. 21.1 years

Page 60: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 60

Suppose $2000 is invested at interest rate, k, compounded continuously, and grows to $2.473.53 in 5 years. Find the approximate doubling time.

a. 7.1 years

c. 16.3 years

b. 14.6 years

d. 21.1 years

Page 61: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc

Copyright © 2009 Pearson Education, Inc. Slide 5 - 61

Suppose $8000 is invested at interest rate, k, compounded continuously, and grows to $10,962.07 in 5 years. Approximate the amount in the account after 10 years.

a. $13,924.14

c. $15,020.87

b. $14,259.22

d. $15,664.41

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Copyright © 2009 Pearson Education, Inc. Slide 5 - 62

Suppose $8000 is invested at interest rate, k, compounded continuously, and grows to $10,962.07 in 5 years. Approximate the amount in the account after 10 years.

a. $13,924.14

c. $15,020.87

b. $14,259.22

d. $15,664.41