copyright © 2009 pearson education, inc. slide 5 - 1 active learning lecture slides for use with...
TRANSCRIPT
![Page 1: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/1.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 1
Active Learning Lecture SlidesFor use with Classroom Response Systems
© 2009 Pearson Education, Inc.
Chapter 5Exponential
and Logarithmic Functions
![Page 2: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/2.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 2
CHAPTER 5: Exponential and
Logarithmic Functions5.1 Inverse Functions5.2 Exponential Functions and Graphs5.3 Logarithmic Functions and Graphs
5.4 Properties of Logarithmic Functions
5.5 Solving Exponential and Logarithmic Equations
5.6 Applications and Models: Growth and Decay; and
Compound Interest
![Page 3: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/3.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 3
Find the inverse of the relation
a.
c.
b.
d.
3,2 , 4,0 , 5,1 , 1, 6
3, 2 , 4,0 , 5, 1 , 1,6 .
2, 3 , 0, 4 , 1,5 , 6,1
2,3 , 0,4 , 1, 5 , 6, 1
1 1 1 1 1, , ,0 , , 1 , 1,
3 2 4 5 6
![Page 4: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/4.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 4
Find the inverse of the relation
a.
c.
b.
d.
3,2 , 4,0 , 5,1 , 1, 6
3, 2 , 4,0 , 5, 1 , 1,6 .
2, 3 , 0, 4 , 1,5 , 6,1
2,3 , 0,4 , 1, 5 , 6, 1
1 1 1 1 1, , ,0 , , 1 , 1,
3 2 4 5 6
![Page 5: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/5.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 5
Find the inverse of the relation
a.
c.
b.
d.
4,2 , 0, 5 , 5,3 , 1, 7
2,4 , 5,0 , 3, 5 , 7,1 .
4, 2 , 0,5 , 5, 3 , 1,7
2, 4 , 5,0 , 3,5 , 7, 1
1 1 1 1 1 1, , ,0 , , , ,1
2 4 5 3 5 6
![Page 6: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/6.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 6
Find the inverse of the relation
a.
c.
b.
d.
4,2 , 0, 5 , 5,3 , 1, 7
2,4 , 5,0 , 3, 5 , 7,1 .
4, 2 , 0,5 , 5, 3 , 1,7
2, 4 , 5,0 , 3,5 , 7, 1
1 1 1 1 1 1, , ,0 , , , ,1
2 4 5 3 5 6
![Page 7: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/7.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 7
Find a formula for the inverse of the function f(x) = 10 – 6x.
a.
c.
b.
d.
1 6 10f x x
1 6
10
xf x
1 10
6
xf x
1 5
3f x x
![Page 8: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/8.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 8
Find a formula for the inverse of the function f(x) = 10 – 6x.
a.
c.
b.
d.
1 6 10f x x
1 6
10
xf x
1 10
6
xf x
1 5
3f x x
![Page 9: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/9.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 9
Find a formula for the inverse of the function f(x) = 2x+5.
a.
c.
b.
d.
1 5
2
xf x
1 15
2f x x
1 5 2f x x
1 5
2
xf x
![Page 10: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/10.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 10
Find a formula for the inverse of the function f(x) = 2x+5.
a.
c.
b.
d.
1 5
2
xf x
1 15
2f x x
1 5 2f x x
1 5
2
xf x
![Page 11: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/11.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 11
Which of the following functions is one-to-one?
a. b.
c. d.
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
![Page 12: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/12.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 12
Which of the following functions is one-to-one?
a. b.
c. d.
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
![Page 13: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/13.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 13
Which of the following graphs illustrates the graph of f(x) = 4x.
a. b.
c. d.
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
![Page 14: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/14.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 14
Which of the following graphs illustrates the graph of f(x) = 4x.
a. b.
c. d.
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
![Page 15: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/15.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 15
Which of the following graphs illustrates the graph of f(x) = –2x – 1.
a. b.
c. d.
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
![Page 16: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/16.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 16
Which of the following graphs illustrates the graph of f(x) = –2x – 1.
a. b.
c. d.
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
X
Y
-5 -4 -3 -2 -1 1 2 3 4 5
-5
-4
-3
-2
-1
1
2
3
4
5
0
![Page 17: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/17.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 17
Find the approximate value of e0.16 to four decimal places.
a. –1.1735
c. 0.8521
b. –0.8521
d. 1.0161
![Page 18: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/18.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 18
Find the approximate value of e–0.16 to four decimal places.
a. –1.1735
c. 0.8521
b. –0.8521
d. 1.0161
![Page 19: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/19.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 19
Using the compound interest formula,
determine the approximate amount in the account after 5 years if the investment is $1500 at an
interest rate of 8.2% compounded quarterly.
a. $2195.64
c. $2260.23
b. $2250.88
d. $2271.56
1nt
rA P
n
![Page 20: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/20.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 20
Using the compound interest formula,
determine the approximate amount in the account after 5 years if the investment is $1500 at an
interest rate of 8.2% compounded quarterly.
a. $2195.64
c. $2260.23
b. $2250.88
d. $2271.56
1nt
rA P
n
![Page 21: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/21.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 21
Suppose a school deposited a $1000 scholarship in an account paying 7.9% interest compounded quarterly. Approximately how much will the scholarship be worth in two years?
a. $1169.36
c. $1268.77
b. $1250.98
d. $1316.42
![Page 22: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/22.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 22
Suppose a school deposited a $1000 scholarship in an account paying 7.9% interest compounded quarterly. Approximately how much will the scholarship be worth in two years?
a. $1169.36
c. $1268.77
b. $1250.98
d. $1316.42
![Page 23: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/23.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 23
Convert to a logarithmic equation: 2x = 20.
a. x = log220
c. 2 = logx20
b. x = log10
d. x = log202
![Page 24: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/24.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 24
Convert to a logarithmic equation: 2x = 20.
a. x = log220
c. 2 = logx20
b. x = log10
d. x = log202
![Page 25: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/25.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 25
Convert to an exponential equation: log3x = 5.
a. x = 53
c. x5 = 3
b. x = 35
d. x3 = 5
![Page 26: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/26.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 26
Convert to an exponential equation: log3x = 5.
a. x = 53
c. x5 = 3
b. x = 35
d. x3 = 5
![Page 27: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/27.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 27
Find ln 3 using a calculator. Round to four decimal places.
a. 0.4771
c. 20.0855
b. 1.0986
d. 1000
![Page 28: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/28.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 28
Find ln 3 using a calculator. Round to four decimal places.
a. 0.4771
c. 20.0855
b. 1.0986
d. 1000
![Page 29: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/29.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 29
Find log 0.001. Do not use a calculator.
a. –4
c. 3
b. –3
d. 1000
![Page 30: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/30.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 30
Find log 0.001. Do not use a calculator.
a. –4
c. 3
b. –3
d. 1000
![Page 31: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/31.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 31
Find log58 using the change-of-base formula.
a. 0.2041
c. 1.2920
b. 0.7740
d. 1.6
![Page 32: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/32.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 32
Find log58 using the change-of-base formula.
a. 0.2041
c. 1.2920
b. 0.7740
d. 1.6
![Page 33: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/33.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 33
Express in terms of sums and
differences of logarithms:
a.
c.
b.
d.
2
3log .x
y
1 1log log
9 3x y
6log 3logx y
2 1log log
3 3x y
2log log
3x y
![Page 34: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/34.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 34
Express in terms of sums and
differences of logarithms:
a.
c.
b.
d.
2
3log .x
y
1 1log log
9 3x y
6log 3logx y
2 1log log
3 3x y
2log log
3x y
![Page 35: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/35.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 35
Express in terms of sums and
differences of logarithms:
a.
c.
b.
d.
35log .y z
3log log
5y z
5log 5log
3y z
5log3 5logy z
3 1log log
5 5y z
![Page 36: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/36.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 36
Express in terms of sums and
differences of logarithms:
a.
c.
b.
d.
35log .y z
3log log
5y z
5log 5log
3y z
5log3 5logy z
3 1log log
5 5y z
![Page 37: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/37.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 37
Given that logc2 = 0.3333 and logc12 = 1.1950, find logc6.
a. 3.5854
c. 0.8617
b. 0.9999
d. 0.1951
![Page 38: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/38.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 38
Given that logc2 = 0.3333 and logc12 = 1.1950, find logc6.
a. 3.5854
c. 0.8617
b. 0.9999
d. 0.1951
![Page 39: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/39.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 39
Given that loga3 = 0.6826 and loga4 = 0.8614, find loga36.
a. 0.4014
c. 2.2266
b. 1.1760
d. 4.6320
![Page 40: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/40.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 40
Given that loga3 = 0.6826 and loga4 = 0.8614, find loga36.
a. 0.4014
c. 2.2266
b. 1.1760
d. 4.6320
![Page 41: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/41.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 41
Simplify: lne6t.
a. e-6t
c. 6t
b. te6
d. –6t
![Page 42: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/42.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 42
Simplify: lne6t.
a. e-6t
c. 6t
b. te6
d. –6t
![Page 43: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/43.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 43
Solve: log3(3x + 6) – log3(x – 6) = 2.
a. 14
c.
b. 10
d. Does not exist
3
2
![Page 44: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/44.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 44
Solve: log3(3x + 6) – log3(x – 6) = 2.
a. 14
c.
b. 10
d. Does not exist
3
2
![Page 45: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/45.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 45
Solve: log2(x + 5) + log2(x – 1) = 4.
a.
c. 5
b. 3
d. 6
1
3
![Page 46: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/46.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 46
Solve: log2(x + 5) + log2(x – 1) = 4.
a.
c. 5
b. 3
d. 6
1
3
![Page 47: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/47.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 47
Solve: log2(x – 3) + log2(2x – 10) = 4.
a. 4
c.
b. 7
d. No solution
29
3
![Page 48: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/48.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 48
Solve: log2(x – 3) + log2(2x – 10) = 4.
a. 4
c.
b. 7
d. No solution
29
3
![Page 49: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/49.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 49
Solve: 25+x = 32x-4.
a.
c.
b.
d. 25
4
69
15
9
4
15
4
![Page 50: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/50.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 50
Solve: 25+x = 32x-4.
a.
c.
b.
d. 25
4
69
15
9
4
15
4
![Page 51: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/51.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 51
Solve: 35+4x = 9x.
a.
c.
b. –5
d.
5
2
5
3
5
3
![Page 52: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/52.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 52
Solve: 35+4x = 9x.
a.
c.
b. –5
d.
5
2
5
3
5
3
![Page 53: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/53.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 53
The population of a city doubled in 12 years. What was the approximate exponential growth rate?
a. 16.7%
c. 5.8%
b. 6.0%
d. 2.48%
![Page 54: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/54.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 54
The population of a city doubled in 12 years. What was the approximate exponential growth rate?
a. 16.7%
c. 5.8%
b. 6.0%
d. 2.48%
![Page 55: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/55.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 55
The population of a city doubled in 10 years. What was the approximate exponential growth rate?
a. 3.0%
c. 6.9%
b. 5.0%
d. 14.4%
![Page 56: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/56.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 56
The population of a city doubled in 10 years. What was the approximate exponential growth rate?
a. 3.0%
c. 6.9%
b. 5.0%
d. 14.4%
![Page 57: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/57.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 57
Suppose $2000 is invested at interest rate, k, compounded continuously, and grows to $2,473.53 in 5 years. Find the approximate interest rate.
a. 3.83%
c. 4.75%
b. 4.25%
d. 7.89%
![Page 58: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/58.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 58
Suppose $2000 is invested at interest rate, k, compounded continuously, and grows to $2.473.53 in 5 years. Find the approximate interest rate.
a. 3.83%
c. 4.75%
b. 4.25%
d. 7.89%
![Page 59: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/59.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 59
Suppose $2000 is invested at interest rate, k, compounded continuously, and grows to $2.473.53 in 5 years. Find the approximate doubling time.
a. 7.1 years
c. 16.3 years
b. 14.6 years
d. 21.1 years
![Page 60: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/60.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 60
Suppose $2000 is invested at interest rate, k, compounded continuously, and grows to $2.473.53 in 5 years. Find the approximate doubling time.
a. 7.1 years
c. 16.3 years
b. 14.6 years
d. 21.1 years
![Page 61: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/61.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 61
Suppose $8000 is invested at interest rate, k, compounded continuously, and grows to $10,962.07 in 5 years. Approximate the amount in the account after 10 years.
a. $13,924.14
c. $15,020.87
b. $14,259.22
d. $15,664.41
![Page 62: Copyright © 2009 Pearson Education, Inc. Slide 5 - 1 Active Learning Lecture Slides For use with Classroom Response Systems © 2009 Pearson Education, Inc](https://reader034.vdocuments.us/reader034/viewer/2022051821/5697bf7d1a28abf838c846a8/html5/thumbnails/62.jpg)
Copyright © 2009 Pearson Education, Inc. Slide 5 - 62
Suppose $8000 is invested at interest rate, k, compounded continuously, and grows to $10,962.07 in 5 years. Approximate the amount in the account after 10 years.
a. $13,924.14
c. $15,020.87
b. $14,259.22
d. $15,664.41