cones pyrimids and jim smith jchs. parts of a pyrimid ( square base ) base edge height ( h ) slant...
TRANSCRIPT
CONESCONES
PYRIMIDSPYRIMIDS
ANDAND
Jim Smith JCHSJim Smith JCHS
PARTS OF A PYRIMIDPARTS OF A PYRIMID( SQUARE BASE )( SQUARE BASE )
BASE EDGEBASE EDGE
BASE EDGEBASE EDGE
HEIGHTHEIGHT ( h ) ( h )
SLANT HEIGHT ( SLANT HEIGHT ( ll ) )
PARTS OF CONESPARTS OF CONES
HEIGHT ( h )HEIGHT ( h )
rr
SLANT HEIGHT ( SLANT HEIGHT ( ll ) )
LA = LA = ½½ p p ll
SA = LA + BSA = LA + B
VOL= VOL= ⅓⅓ B h B h
FIND THE PERIMETERFIND THE PERIMETER AND AREA FIRSTAND AREA FIRST
1212
Base edge Base edge hh sl sl 12 12 88 1010
P = 12 + 12 + 12 + 12 = 48P = 12 + 12 + 12 + 12 = 48B = 12 x 12 = 144B = 12 x 12 = 144
LA = ½ p l = ½ x 48 x 10 = LA = ½ p l = ½ x 48 x 10 = 240 sq un240 sq unSA = LA + B = 240 + 144 = SA = LA + B = 240 + 144 = 384 sq un384 sq unVOL = ⅓VOL = ⅓ B x h = B x h = ⅓⅓ 144 x 8 = 144 x 8 = 384 cu un384 cu un
33
r r hh slsl3 3 44 55
p = 2 p = 2 ππ r = r = 2 2 ππ 3 = 6 3 = 6 ππB = B = ππ r r² = ² = ππ 3² = 9 3² = 9 ππ
LA = ½ p l = ½ x 6 LA = ½ p l = ½ x 6 ππ x 5 = 15 x 5 = 15 ππ sq unsq un
SA = LA + B = 15 SA = LA + B = 15 ππ + 9 + 9 ππ = 24 = 24 ππ sq unsq un
VOL = ⅓ B h = ⅓ x 9 VOL = ⅓ B h = ⅓ x 9 ππ x 4 = 12 x 4 = 12 ππ cu uncu un