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    M2-2

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    M3-3

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    Node Reaction Node Reaction

    217 41,766.18 210 27,163.46 209 41,586.81 218 27,146.53 225 40,263.37 202 25,320.31 206 35,698.83 226 25,302.79 214 35,650.39 230 25,224.03 213 35,001.17 119 25,217.02 221 34,960.71 117 23,783.03 205 34,916.33 237 23,752.88 229 34,873.88 105 20,255.75 222 34,573.70 235 20,208.06 231 34,157.76 101 18,390.39 198 34,156.91 234 18,381.21 233 33,402.97 106 17,489.95 201 33,392.18223 32,799.43

    207 32,690.30215 32,653.64227 32,057.60203 32,048.85219 32,048.15211 32,039.66212 31,801.56220 31,797.12204 31,592.09228 31,588.31200 30,383.72232 30,382.24208 29,224.84

    224 29,208.30216 29,208.20

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    Purlin

    DATA

    Length ,L 4 m.Spacing, @ 1 m.

    Slope of Roof 7 degree

    Load data

    Live Load 30 kg/m. 2

    Dead LoadRoof Material 15 kg/m. 2

    Purlin 6 kg/m. 2

    Other 15 kg/m. 3

    Total Dead Load 36 kg/m. 2

    Wind Load 50 kg/m. 2

    Wind Load to perpendicular roof= (2Psinθ/1+sin^2θ) 12.01 kg/m. 2

    Load Case

    Case 1 DL= Purlin spacing x DL= 36 kg/m.

    Case 2 DL+LL = spacing x(DL+LL )= 66 kg/m.

    Case 3 0.75(DL+LL+WL) x spacing = 58.51 kg/m.

    Load to purlin W = 60 kg/m.Wx = Wsin q = 7.31 kg/m.Wy = Wcos q = 59.55 kg/m.

    Member force from structural analysis programMoment max. = 95.28 kg.m.

    Section of modulus S x = 6.62 cm.

    Use C 100x 50x3.2 mm. @ 1.00 m.

    S x = 21.3 cm. Ix = 107 cm.

    Max. deflection 0.50 cm Allowable deflection L/240 = 1.67 cm O.K.

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    Rafter

    DATA

    Length ,L 4 m.Lateral Support 1 m.

    Rafter Spacing 4 m.Slope of Roof 7 degree

    LOAD

    Live Load 30 kg/m. 2

    Dead LoadSelf Weight 6 kg/m. 2

    (Roof Materia) 15 kg/m. 2

    Purlin 6 kg/m. 2

    Other 15 kg/m. 3

    Total Dead Load 42 kg/m. 2

    Horizontal Wind Load 50 kg/m. 2

    Wind Load on Purlin 12.01 kg/m. 2

    Use W = 252 kg/m.w = W/cosθ = 253.89 kg/m.

    Moment max. = 360.00 kg.m.

    Section of ModulusS x = 25.00 cm.

    Use 2 C 100 x 50 x 20 x 3.2

    S x = 42.6 cm. Ix = 214 cm.

    Max. deflection 0.54 cm.

    Allowable deflection 1.11 cm. O.K.

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    Slab S-1

    Short span(S) 1.30 m. m = S/L = 0.59Long span (L) 2.20 m. Two way slabMinimum thickness D= (2S+2L)/180 3.89 cm.Use thickness 10.00 cm.

    Concrete covering 3 cm.Effective thickness(d) 7.00 cm.

    Load

    Dead Load 240 kg/m 2

    Live Load 150 kg/m 2

    Finishing Load 50 kg/m 2

    Total Load (w) 440 kg/m 2

    Cmax = 0.098 M max = 72.87 kg.m

    Main reinforcement Rebar (As) = = 0.99 cm2

    Use Rebar RB 9 mm.@ 0.20 m. As = 3.18 cm2

    (Both side)

    Rb

    M

    d j fs M

    ..

    Determine Effective thickness(d)= = 2.38 cm. < 7.00 cm. O.K.

    Rb

    M

    d j fs M

    ..

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    Slab S-2

    Short span (S) 1.40 m. m = S/L = 0.35Length span(L) 4.00 m. One-way slabMinimum thickness D= S/20 7.00 cm.Use thickness 10.00 cm.

    Covering 3 cm.Effective thickness(d) 7.00 cm.

    LoadDead Load 240 kg/m 2

    Live Load 150 kg/m 2

    Finishing Load 50 kg/m 2

    Total (w) 440 kg/m 2

    Mmax =( ws 2) /8 = 107.80 kg.m < M = R.b.d 2= 630.81 kg.m. O.K.

    Main reinforcement Rebar (As) = = 1.47 cm 2

    Use rebar RB 9 mm. @ 0.20 m. As = 3.18 cm 2

    Rb M

    d j fs M

    ..

    Temperature steel(As t)= 0.0025 x b x h= 2.5 cm 2

    use rebar RB 9 mm. @ 0.20 m. As= 3.18 cm 2 O.K.

    Determine Effective thickness(d)= = 2.89 cm. < 7.00 cm. O.K. Rb M

    d j fs M

    ..

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    Slab SC-1

    Length 1.40 m.Minimum thickness D= s/10 0.14 m.Use thickness 10.00 cm.Concrete covering 2.5 cm.

    Effective thickness(d) 7.50 cm.

    Load

    Dead Load 240 kg/mLive Load 100 kg/mFinishing Load 50 kg/mTotal 390 kg/mPoint Load 30 kgM max. 424.2 kg.m

    Effective thickness (d)= = 6.12 cm. < 7.50 cm O.K.

    Reinforcing Bar(As)= = 4.22 cm 2

    Use Rebar RB 9 mm. @ 0.15 m. = 2

    Rb

    M

    d j fs M

    ..

    . . .

    temperature and shrinkage steel (As t)= 0.0025 x b x d= 2.5 cm2

    Use Rebar RB 9 mm. @ 0.20 m.

    As= 3.18 cm2

    O.K.

    Rb

    M

    d j fs M

    ..

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    ST-1

    (L) 4.00 m.

    ! " #$ L%&' .00 *m. &0.00 *m.

    + , - / 1 &.' *m.2 335 (6) 7.'0 *m.

    + 8 ! (9) ,#:;6 L?%mL@A: L?%mB@C@DE@C? L

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    Beam B1Section Width 0.15 m.

    Depth 0.30 m.Covering 0.03 m.d = 0.264 m.

    d' = 0.042 m.

    Dead Load B1 108 kg/m.

    M+ 440 kg-m.M- 650 kg-m.V 1,000 kg

    Determine Flexural ReinforcementMc =Rbd 2= 1,456.81 kg-m. > M + & M-

    At the middle (M+)

    0.15 Top Bars(Compression)2 DB 12 mm As = 2.26 cm 2

    0.30Bottom Bars(Tension)

    2 DB 12 mm As = 2.26 cm 2

    0 DB 0 mm As = 0.00 cm

    Total 2.26 cm

    As = M+/fs.jd= 1.26 cm 2

    At the end (M-)

    As = M+/fs.jd= 1.86 cm 2

    0.15 Top Bars(Tension)2 DB 12 mm As = 2.26 cm 2

    0 DB 0 mm As = 0.00 cm 2

    Total 2.26 cm 2

    0.30

    Bottom Bars(Compression)2 DB 12 mm As = 2.26 cm 2

    Design of Shear ReinforcementShear, V 1000 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 1779.09 kgV' = V -Vc= -779.09 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = -22.98 cm.spacing not exceed 0.15 m. OR 0.13 m.Use Stirrup RB 6 mm @ 0.15 m.

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    Beam B1ASection Width 0.15 m.

    Depth 0.30 m.Covering 0.025 m.d = 0.263 m.

    d' = 0.037 m.

    Dead Load B1A 108 kg/m.

    M+ 1,000 kg-m.V 1,400 kg

    Determine Flexural ReinforcementMc =Rbd 2= 1,445.79 kg-m. > M +Max.

    As 1 = M+/fs.jd= 2.87 cm

    Bottom Bars(Tension) 3 DB 12 mm As = 3.39 cm 2

    0 DB 0 mm As = 0.00 cm 2

    Total 3.39 cm

    Top Bars(Compression) 2 DB 12 mm As = 2.26 cm 2

    Design of Shear ReinforcementShear, V 1400 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 1772.35 kgV' = V -Vc= -372.35 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = -47.91 cm.spacing not exceed 0.15 m. OR 0.13 m.Use Stirrup RB 6 mm @ 0.15 m.

    0.15

    2 DB 12 mm.

    0.30 stirrup RB 6 mm. @ 0.15 mm.

    3 DB 12 mm.

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    Beam B2Section Width 0.20 m.

    Depth 0.40 m.Covering 0.03 m.d = 0.364 m.

    d' = 0.042 m.

    Dead Load B2 192 kg/m.

    M+ 1,100 kg-m.M- 1,500 kg-m.V 2,200 kg

    Determine Flexural ReinforcementMc =Rbd 2= 3,692.64 kg-m. > M + & M-

    At the middle (M+)

    0.20 Top Bars(Compression)2 DB 12 mm As = 2.26 cm 2

    0.40Bottom Bars(Tension)

    3 DB 12 mm As = 3.39 cm 2

    0 DB 0 mm As = 0.00 cm

    Total 3.39 cm

    As = M+/fs.jd= 2.28 cm 2

    At the end (M-)

    As = M+/fs.jd= 3.11 cm 2

    0.20 Top Bars(Tension)3 DB 12 mm As = 3.39 cm 2

    0 DB 0 mm As = 0.00 cm 2

    Total 3.39 cm 2

    0.40

    Bottom Bars(Compression)2 DB 12 mm As = 2.26 cm 2

    Design of Shear ReinforcementShear, V 2200 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 3270.66 kgV' = V -Vc= -1070.66 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = -23.06 cm.spacing not exceed 0.20 m. OR 0.18 m.Use Stirrup RB 6 mm @ 0.15 m.

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    Beam B3Section Width 0.20 m.

    Depth 0.40 m.Covering 0.03 m.d = 0.364 m.

    d' = 0.044 m.

    Dead Load B3 192 kg/m.

    M+ 800 kg-m.M- 3,600 kg-m.V 6,100 kg

    Determine Flexural ReinforcementMc =Rbd 2= 3,692.64 kg-m. > M + & M-

    At the middle (M+)

    0.20 Top Bars(Compression)2 DB 16 mm As = 4.02 cm 2

    0.40Bottom Bars(Tension)

    2 DB 16 mm As = 4.02 cm 2

    0 DB 0 mm As = 0.00 cm

    Total 4.02 cm

    As = M+/fs.jd= 1.66 cm 2

    At the end (M-)

    As = M+/fs.jd= 7.47 cm 2

    0.20 Top Bars(Tension)2 DB 16 mm As = 4.02 cm 2

    2 DB 16 mm As = 4.02 cm 2

    Total 8.04 cm 2

    0.40

    Bottom Bars(Compression)2 DB 16 mm As = 4.02 cm 2

    Design of Shear ReinforcementShear, V 6100 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 3270.66 kgV' = V -Vc= 2829.34 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = 8.73 cm.spacing not exceed 0.20 m. OR 0.18 m.Use Stirrup RB 6 mm @ 0.15 m.

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    Beam B3ASection Width 0.20 m.

    Depth 0.40 m.Covering 0.025 m.d = 0.361 m.

    d' = 0.039 m.

    Dead Load B3A 192 kg/m.

    M+ 2,000 kg-m.V 2,300 kg

    Determine Flexural ReinforcementMc =Rbd 2= 3,632.02 kg-m. > M +Max.

    As 1 = M+/fs.jd= 4.18 cm

    Bottom Bars(Tension) 3 DB 16 mm As = 6.03 cm 2

    0 DB 0 mm As = 0.00 cm 2

    Total 6.03 cm

    Top Bars(Compression) 2 DB 16 mm As = 4.02 cm 2

    Design of Shear ReinforcementShear, V 2300 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 3243.70 kgV' = V -Vc= -943.70 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = -25.95 cm.spacing not exceed 0.20 m. OR 0.18 m.Use Stirrup RB 6 mm @ 0.15 m.

    0.20

    2 DB 16 mm.

    0.40 stirrup RB 6 mm. @ 0.15 mm.

    3 DB 16 mm.

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    Beam B3BSection Width 0.20 m.

    Depth 0.40 m.Covering 0.03 m.d = 0.364 m.

    d' = 0.042 m.

    Dead Load B3B 192 kg/m.

    M+ 850 kg-m.M- 1,400 kg-m.V 2,100 kg

    Determine Flexural ReinforcementMc =Rbd 2= 3,692.64 kg-m. > M + & M-

    At the middle (M+)

    0.20 Top Bars(Compression)2 DB 12 mm As = 2.26 cm 2

    0.40Bottom Bars(Tension)

    3 DB 12 mm As = 3.39 cm 2

    0 DB 0 mm As = 0.00 cm

    Total 3.39 cm

    As = M+/fs.jd= 1.76 cm 2

    At the end (M-)

    As = M+/fs.jd= 2.90 cm 2

    0.20 Top Bars(Tension)3 DB 12 mm As = 3.39 cm 2

    0 DB 0 mm As = 0.00 cm 2

    Total 3.39 cm 2

    0.40

    Bottom Bars(Compression)2 DB 12 mm As = 2.26 cm 2

    Design of Shear ReinforcementShear, V 2100 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 3270.66 kgV' = V -Vc= -1170.66 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = -21.09 cm.spacing not exceed 0.20 m. OR 0.18 m.Use Stirrup RB 6 mm @ 0.15 m.

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    Beam B3CSection Width 0.20 m.

    Depth 0.40 m.Covering 0.03 m.d = 0.364 m.

    d' = 0.044 m.

    Dead Load B3C 192 kg/m.

    M+ 2,400 kg-m.M- 2,700 kg-m.V 4,500 kg

    Determine Flexural ReinforcementMc =Rbd 2= 3,692.64 kg-m. > M + & M-

    At the middle (M+)

    0.20 Top Bars(Compression)2 DB 16 mm As = 4.02 cm 2

    0.40Bottom Bars(Tension)

    3 DB 16 mm As = 6.03 cm 2

    0 DB 0 mm As = 0.00 cm

    Total 6.03 cm

    As = M+/fs.jd= 4.98 cm 2

    At the end (M-)

    As = M+/fs.jd= 5.60 cm 2

    0.20 Top Bars(Tension)2 DB 16 mm As = 4.02 cm 2

    2 DB 16 mm As = 4.02 cm 2

    Total 8.04 cm 2

    0.40

    Bottom Bars(Compression)2 DB 16 mm As = 4.02 cm 2

    Design of Shear ReinforcementShear, V 4500 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 3270.66 kgV' = V -Vc= 1229.34 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = 20.08 cm.spacing not exceed 0.20 m. OR 0.18 m.Use Stirrup RB 6 mm @ 0.15 m.

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    Beam B4Section Width 0.20 m.

    Depth 0.40 m.Covering 0.025 m.d = 0.361 m.

    d' = 0.039 m.

    Dead Load B4 192 kg/m.

    M+ 3,600 kg-m.V 2,900 kg

    Determine Flexural ReinforcementMc =Rbd 2= 3,632.02 kg-m. > M +Max.

    As 1 = M+/fs.jd= 7.53 cm

    Bottom Bars(Tension) 2 DB 16 mm As = 4.02 cm 2

    2 DB 16 mm As = 4.02 cm 2

    Total 8.04 cm

    Top Bars(Compression) 2 DB 16 mm As = 4.02 cm 2

    Design of Shear ReinforcementShear, V 2900 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 3243.70 kgV' = V -Vc= -343.70 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = -71.24 cm.spacing not exceed 0.20 m. OR 0.18 m.Use Stirrup RB 6 mm @ 0.15 m.

    0.20

    2 DB 16 mm.

    0.40 stirrup RB 6 mm. @ 0.15 mm.

    4 DB 16 mm.

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    Beam B5Section Width 0.20 m.

    Depth 0.50 m.Covering 0.03 m.d = 0.456 m.d' = 0.044 m.

    Dead Load 240 kg/m.

    M- 4200 kg-m. M + 4200 kg-m. Vmax 5500 kgDetermine Flexural ReinforcementAt the end (M-)Mc =Rbd 2= 3674.40 kg-m. < M -

    M' =M --Mc 525.60 kg-m. As1 = Mc/fs.jd= 5.97 cm 2

    As2 = M'/fs(d-d')= 0.85 cm 2

    As = As1+As2 = 6.82 cm 2

    0.20 Top Bars(Tension)2 DB 16 mm As = 4.02 cm 2

    2 DB 16 mm As = 4.02 cm 2

    0.50 Total 8.04 cm 2

    As' = 0.5As2((1-k)/k-(d'/d)) = 1.44 cm 2

    2 DB 16 mm As = 4.02 cm 2

    At the middle

    M+ = 4200 kg-m.Mc =Rbd 2= 3674.40 kg-m. > M + max.

    0.20 Top Bars(Compression)2 DB 16 mm As = 4.02 cm 2

    0.50 Bottom Bars(Tension) As ,required = M+/fs.jd = 6.83 cm 2

    2 DB 16 mm As = 4.02 cm 2

    2 DB 16 mm As = 4.02 cm 2

    Total 8.04 cm 2

    Design of Shear ReinforcementShear, V 5500 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 3478.69 kgV' = V -Vc= 2021.31 kgUse stirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = 15.30 cmspacing not exceed 0.2 m. 0.228 m.Use stirrup RB 6 mm. @ 0.15 m.

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    Beam B6Section Width 0.20 m.

    Depth 0.50 m.Covering 0.03 m.d = 0.456 m.d' = 0.044 m.

    Dead Load 240 kg/m.

    M- 5100 kg-m. M + 3500 kg-m. Vmax 5500 kgDetermine Flexural ReinforcementAt the end (M-)Mc =Rbd 2= 3674.40 kg-m. < M -

    M' =M --Mc 1425.60 kg-m. As1 = Mc/fs.jd= 5.97 cm 2

    As2 = M'/fs(d-d')= 2.31 cm 2

    As = As1+As2 = 8.28 cm 2

    0.20 Top Bars(Tension)3 DB 16 mm As = 6.03 cm 2

    2 DB 16 mm As = 4.02 cm 2

    0.50 Total 10.05 cm 2

    As' = 0.5As2((1-k)/k-(d'/d)) = 3.91 cm 2

    3 DB 16 mm As = 6.03 cm 2

    At the middle

    M+ = 3500 kg-m.Mc =Rbd 2= 3674.40 kg-m. > M + max.

    0.20 Top Bars(Compression)3 DB 16 mm As = 6.03 cm 2

    0.50 Bottom Bars(Tension) As ,required = M+/fs.jd = 5.69 cm 2

    0 DB 0 mm As = 0.00 cm 2

    3 DB 16 mm As = 6.03 cm 2

    Total 6.03 cm 2

    Design of Shear ReinforcementShear, V 5500 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 3478.69 kgV' = V -Vc= 2021.31 kgUse stirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = 15.30 cmspacing not exceed 0.2 m. 0.228 m.Use stirrup RB 6 mm. @ 0.15 m.

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    Beam B7Section Width 0.20 m.

    Depth 0.50 m.Covering 0.025 m.d = 0.461 m.

    d' = 0.039 m.

    Dead Load B7 240 kg/m.

    M+ 4,700 kg-m.V 4,300 kg

    Determine Flexural ReinforcementMc =Rbd 2= 5,922.92 kg-m. > M +Max.

    As 1 = M+/fs.jd= 7.70 cm

    Bottom Bars(Tension) 2 DB 16 mm As = 4.02 cm 2

    2 DB 16 mm As = 4.02 cm 2

    Total 8.04 cm

    Top Bars(Compression) 2 DB 16 mm As = 4.02 cm 2

    Design of Shear ReinforcementShear, V 4300 kgShear Capacity Vc = 0.29fc'^0.5(b.d) = 4142.23 kgV' = V -Vc= 157.77 kgStirrup RB 6 mm. Av = 0.57 cm 2

    Spacing s = Av.fv.d/(V') = 198.18 cm.spacing not exceed 0.20 m. OR 0.23 m.Use Stirrup RB 6 mm @ 0.15 m.

    0.20

    2 DB 16 mm.

    0.50 stirrup RB 6 mm. @ 0.15 mm.

    4 DB 16 mm.

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    Column C-1

    Axial load,P 42,000 kg.Moment,M 100 kg.m

    Dimensionb = 30 cmh = 30 cm

    Use rebar 8 DB 16 mm Ast = 16.08 cm 2

    Total area of steel 16.08 cm 2

    p g = 0.01786311 1.79 % OK

    m=fy/(0.85f 'c) = 13.45 kscconcrete covering 3 cmUse Stirrup RB 6 mm

    t = h = 30 cm

    d' = 4.4 cm

    e = M/P = 0.24 cm.

    P a =0.85A gf'c(0.25 + 0.34mp g) = 53,281.17 kgI = bh 3/12 + (2n-1)A s(hl

    2/4) 98,208.62 cm F a =0.34(1+p gm)f' c = 88.55 kscFb =0.45f' c = 94.5fb=MxC x/Ix = 1.5 kscfa=P b/Ag = 0.001111111 P bP o= F a Ag= 79,693.73 kg

    S =Ix/Cx= 6,547.24 cm 3

    Ms = Fb.S 618,714.29 kg-cm

    e a =M s((1/P a )-(1/P o)) = 3.85 cm. e P It's safety

    30

    30

    Use 8 DB 16 mm. rebar RB 6 m. @ 0.20 m. Stirrup

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    Column C-2

    Axial load,P 23,000 kg.Moment,M 810 kg.m

    Dimensionb = 25 cmh = 25 cm

    Use rebar 8 DB 12 mm Ast = 9.04 cm 2

    Total area of steel 9.04 cm 2

    p g = 0.01446912 1.45 % OK

    m=fy/(0.85f 'c) = 19.61 kscconcrete covering 3 cmUse Stirrup RB 6 mm

    t = h = 25 cm

    d' = 4.2 cm

    e = M/P = 3.52 cm.

    P a =0.85A gf'c(0.25 + 0.34mp g) = 26,504.25 I = bh 3/12 + (2n-1)A s(hl

    2/4) 45,634.79 cm F a =0.34(1+p gm)f' c = 62.85 kscFb =0.45f' c = 64.8fb=MxC x/Ix = 22.2 kscfa=P b/Ag = 0.0016 P bP o= F a Ag= 39,281.47 kg

    S =Ix/Cx= 3,650.78 cm 3

    Ms = Fb.S 236,570.75 kg-cm

    e a =M s((1/P a )-(1/P o)) = 2.90 cm. e>ea Type II

    e b = (0.67p gm+0.17)(t-d') = 7.49 > e

    (f a /F a ) +(f b/F b)

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    Column C-3

    Axial load,P 6,000 kg.Moment,M 350 kg.m

    Dimensionb = 20 cmh = 20 cm

    Use rebar 4 DB 12 mm Ast = 4.52 cm 2

    Total area of steel 4.52 cm 2

    p g = 0.011304 1.13 % OK

    m=fy/(0.85f 'c) = 16.81 kscconcrete covering 3 cmUse Stirrup RB 6 mm

    t = h = 20 cm

    d' = 4.2 cm

    e b = (0.67p gm+0.17)(t-d') = 4.70

    e = M/P = 5.83 cm. Tension zone

    I = bh 3/12 + (2n-1)A s(hl2/4) 15919.1459 cm

    F a =0.34(1+p m)f' c = 84.96 ksc .Fb =0.45f' c = 94.5fb=MxC x/Ix = 22.0 kscfa=P b/Ag = 0.0025 P b

    (fa/Fa) +(fb/Fb) =1

    P b = 26,078.85 kg

    Mb = P b x (e b/100 )= 1,224.97 kg.mM = 350 kg.mMo=0.4A sf y jd = 680.49 kg.m As = 4.02 cm

    P= Pb(M-Mo)/(Mb-Mo)= 15,829.66- kg < 6,000 kg. OK

    Use 4 DB 12 mm. rebar

    RB 6 m. @ 0.15 m. Stirrup

    20

    20

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    23,500 kg y 0.3 m. x 0.3 m.

    0.5 m.

    0.26 x 0.26 m.Safe load 25 ton/pile

    (> ) = 0.3 m.

    (> ) = 0.4 m.0.7 .

    0.7 .0.7 .

    108 kg.

    823.2 kg. 338.0 kg.

    24,769.20 kg. < 25,000 kg. OK

    fc' 210 ksc fy= 3000 kscfc= 94.5 ksc fs= 1500 kscEc= 218820 ksc 233928n= 9.32274 9k= 0.3618 j= 0.8794

    10 cm. b= 24.2 cm < 45 cm. OK 8 DB 16 mm.

    As = 16.08 cm 2

    Asmin= 9.8 cm 2 2 RB 9 mm @ 0.1 m (As= 0.64 cm 2)

    1

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    Project : Engineering By :

    Location : Date :

    . . . ; F2

    = . .

    : ( x - direction : a ) =

    : ( y - direction : b) =

    : x .

    . . = . ./

    =

    : Cx =

    : Cy =

    ( 3D ) =

    : ( Cx => 3D : x - direction )

    = >

    25000

    0.26

    0.30

    . . . 2 . .

    $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    SQDriven Pile 0.26

    > 1D : OK0.30

    45000

    0.30

    0.30

    0.78

    $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

    REINFORCED CONCRETE DESIGN

    22/3/2015 16:46

    ; ( L : x - direction ) =

    ; ( B : y - direction ) =

    ( t ) =

    : ( d ) =

    : (Total Load ) = . .

    : ( Load per pile ) = . ./ < : OK

    Mmax = WL = . .

    d req. = sqrt ( M / Rb) = . < Effective depth :OK

    ; Beam Shear

    vb = 0.29 x sqrt ( fc' ) = ./ . . .

    P ' = P/30 ( x+15 ) =

    Vb = V / ( B x d ) = ./ . . . < vb : OK

    ; Punching Shear

    vp = 0.53 x sqrt ( fc' ) = ./ . . .

    P ' = P/30 ( x+15 ) = .

    Vp = V / ( b x d ) = ./ . . . < vp : OK

    3.81

    0.00

    0.33

    0.55

    23105

    46210

    0.60

    .

    0.60

    2.92

    5,776.3

    0.00

    1.40

    6.97

    9627

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    As = M / f s / j / d As = . . .

    Use 5 DB 16 mm. m. A s = . . . > As req. : OK

    S 0 = . .

    Ast = 0.0020 x b x D As = . . .

    Use 8 DB 16 mm. m. A s = . . . > As req. : OK

    S 0 = . .

    u all = 3.23 x sqrt(fc') / D = . ./ . . . . (Bonding Pass : OK)

    S 0 = V / Uall x j x d = . . OK

    @ 0.13

    0.30

    14.40

    7.80

    10.05

    25.13

    @ 0.19 16.08

    0.30

    26.55

    0.801.40

    40.21

    17.62

    Ground level

    DB 12 mm.

    8 - DB16 mm.@ 0.19 m.

    5 - DB16 mm.@ 0.13 m.

    SQ - 0.26 x . 25 ./

    PLAN VIEW

    1.00

    0.05

    0 . 6

    0

    0 . 3

    0

    0 . 3

    0

    0.10

    0.60 0.55

    .

    0 . 3

    0