cm4106 review of lesson 3 (part 2)
TRANSCRIPT
CM4106 Chemical Equilibria & Thermodynamics
Lesson 3 (Part 2)Additional Aspects of Acid-Base Equilibria(Topic 3.6 – 3.9)
A Chemistry Education Blog by Mr Tanhttp://chemistry-mr-tan-yong-yao.blogspot.sg/
Indicators
Indicator pH = pKln pH range and colour change
Phenolphthalein
9.10Pink
8.30Colourless
↔ 10.0Pink
Litmus 6.50Purple
5.00Red
↔ 8.00Blue
Methyl Orange 3.70Orange
2.90Red
↔ 4.60Yellow
Bromothymol Blue
7.00Green
6.00Yellow
↔ 7.50Blue
Acid-Base Titration
Choose indicator where the pH range at which colour change occurs is close to the pH at equivalence point.
Choice of Indicator
Suitable
Suitable
Not Suitable
Choose indicator where the pH range at which colour change occurs is close to the pH at equivalence point.
A suitable indicator has a colour change range that lies within the change of pH equivalence point.
Acid-Base TitrationStrong Acid – Strong Base Strong Acid – Weak Base
1. sigmoidal shape2. large pH Δ around eq. pt.3. pH at eq. pt. = 7.04. Indicator: most indicators
1. “buffer region”2. smaller pH Δ around eq. pt.3. pH at eq. pt. < 7.04. Indicator: Methyl Orange
xBuffer Region
pH < 7Salt hydrolysis
pOH = pKb
Acid-Base TitrationWeak Acid – Strong Base Weak Acid – Weak Base
1. “buffer region”2. No steep pH Δ around eq. pt.3. No suitable indicator
1. “buffer region”2. smaller pH Δ around eq. pt.3. pH at eq. pt. > 7.04. Indicator: phenolphthalein
x
At Equivalence PtKa = Kb pH = 7Ka > Kb pH < 7Ka < Kb pH > 7
Buffer Region
pH > 7Salt hydrolysispH = pKa
1. Initial Pt Initial pOH [OH-] due to dissociation of base ICE Table
2. Buffering Region
3. Equivalence pt Volume of acid Concentration of base used At equivalence pt, all acid and base are
completely neutralized to give salt and H2O; determine [salt] =[conj. acid]pH [H+] due to hydrolysis of salt
4. Half equivalence pt pOH pKb
Acid-Base Titration Strong Acid – Weak Base
x
Buffer RegionpH < 7Salt hydrolysis
pOH = pKb1.
[base]
[salt]logKOH b pp
[base]
[salt]logKOH b pp
5. After Equivalence PtLow pH due to excess strong acid added
1. Initial Pt Initial pH [H+] due to dissociation of acid ICE Table
2. Buffering Region
3. Equivalence pt Volume of base Concentration of acid used At equivalence pt, all acid and base are completely neutralized to give salt and H2O; determine [salt] =[conj. base]pOH [OH-] due to hydrolysis of salt
4. Half equivalence pt pH pKa
Acid-Base Titration Weak Acid – Strong Base
x
Buffer Region
pH > 7Salt hydrolysispH = pKa
1.
[acid]
[salt]logKH a pp
[acid]
[salt]logKH a pp
5. After Equivalence PtHigh pH due to excess strong base added
pH of an acidic buffer pH of an alkaline buffer
pH at the point of maximum buffering capacity of an acidic
buffer
pH at the point of maximum buffering capacity of an
alkaline buffer
pH = pKa pOH = pKb
[base]
[salt]logKOH b pp
[acid]
[salt]logKH a pp
Choice of Indicators
Strong acid – strong alkali
Any
Strong acid – weak alkali
Methyl Orange
Weak acid – strong alkali
Phenolphthalein
Weak acid – Weak alkali
None
pH at equivalence point (Give equation of hydrolysis reaction, if any)
eg. NaCl
HCl (aq) + NaOH (aq) → NaCl (aq) +
H2O (l)
7.0No hydrolysis
e.g. NH4Cl
NH3 + HCl (aq) NH4
+Cl- (aq)
Acidic pH (pH < 7)
NH4+ (aq) + H2O (l)
⇌ NH3 (aq) + H3O+ (aq)
e.g. CH3COONa
CH3COOH(aq) + NaOH(aq) →
CH3COONa(aq) + H2O (l)
Basic pH (pH > 7)
CH3COO- (aq) + H2O (l) ⇌ CH3COOH (aq) + OH- (aq)
Depends on Ka and Kb values of conjugate acid and
conjugate base in salt
Ka = Kb pH = 7Ka > Kb pH < 7Ka < Kb pH > 7