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    PHYSICS CHAPTER 24

    1

    CHAPTER 24:

    Quantization of light(3 Hours)

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    PHYSICS CHAPTER 24

    Learning Outcome:

    At the end of this chapter, students should be able to:

    a. Distinguish between Planks quantum theory and

    classical theory of energy

    b. Use Einsteins formulae for photon energy,

    2

    24.1 Plancks quantum theory (1/2 hour)

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    PHYSICS CHAPTER 24

    24.1 Plancks quantum theory

    24.1.1 Classical theory of black body radiation

    Black body is defined as an ideal system that absorbs all the

    radiation incident on it. The electromagnetic (EM) radiation

    emitted by the black body is called black body radiation.

    From the black body experiment, the distribution of energy inblack body, Edepends only on the temperature, T.

    If the temperature increases thus the energy of the black body

    increases and vice versa.

    3

    (24.1)

    constantsBoltzmann':Bkwhere

    kelvininetemperatur:T

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    PHYSICS CHAPTER 24

    The spectrum of EM radiation emitted by the black body

    (experimental result) is shown in Figure 24.1.

    From the curve, Wiens theory was accurate at short

    wavelengths but deviated at longer wavelengths whereas the

    reverse was true for the Rayleigh-Jeans theory. 4

    Figure 24.1

    Experimental

    result

    Rayleigh -Jeans

    theoryWiens theory

    Classical

    physics

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    PHYSICS CHAPTER 24

    The Rayleigh-Jeans and Wiens theories failed to fit the

    experimental curve because this two theories based on classical

    ideas which are Energy of the EM radiation is not depend on its frequency

    or wavelength.

    Energy of the EM radiation is continuously.

    24.1.2 Plancks quantum theory In 1900, Max Planck proposed his theory that is fit with the

    experimental curve in Figure 24.1 at all wavelengths known as

    Plancks quantum theory.

    The assumptions made by Planck in his theory are :

    The EM radiation emitted by the black body is in discrete

    (separate) packets of energy. Each packet is called a

    quantum of energy. This means the energy of EM radiation

    is quantised.

    The energy size of the radiation depends on its frequency.

    5

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    PHYSICS CHAPTER 24

    According to this assumptions, the quantum of the energy E

    for radiation of frequency fis given by

    Since the speed of EM radiation in a vacuum is

    then eq. (24.2) can be written as

    From eq. (24.3), the quantum of the energy Efor radiation is

    inversely proportional to its wavelength.

    6

    where

    (24.2)

    (24.3)

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    PHYSICS CHAPTER 24

    It is convenient to express many quantum energies in electron-

    volts.

    The electron-volt (eV) is a unit of energy that can be definedas the kinetic energy gained by an electron in being

    accelerated by a potential difference (voltage) of 1 volt.

    Unit conversion:

    In 1905, Albert Einstein extended Plancks idea by proposing

    that electromagnetic radiation is also quantised. It consists of

    particle like packets (bundles) of energy called photons of

    electromagnetic radiation.

    7

    J101.60eV119

    Note:

    For EM radiation of n packets, the energyEn is given by

    (24.4)

    1,2,3,...numberreal: nwhere

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    PHYSICS CHAPTER 24

    24.1.3 Photon

    Photon is defined as a particle with zero mass consisting of aquantum of electromagnetic radiation where its energy is

    concentrated.

    A photon may also be regarded as a unit of energy equal to

    hf.

    Photons travel at the speed of light in a vacuum. They arerequired to explain the photoelectric effect and other

    phenomena that require light to have particle property.

    Table 9.1 shows the differences between the photon andelectromagnetic wave.

    8

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    PHYSICS CHAPTER 24

    EM Wave Photon

    9

    Energy of the EM wavedepends on the intensityof the wave. Intensity of

    the waveIis proportionalto the squared of its

    amplitudeA2 where

    Energy of a photon isproportional to thefrequency of the EMwave where

    Its energy is continuouslyand spread out throughthe medium as shown inFigure 24.2a.

    Its energy is discrete asshown in Figure 24.2b.

    Table 24.1

    2AI

    fE

    Photon

    Figure 24.2a Figure 24.2b

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    PHYSICS CHAPTER 24

    10

    A photon of the green light has a wavelength of 740 nm. Calculate

    a. the photons frequency,b. the photons energy in joule and electron-volt.

    (Given the speed of light in the vacuum, c =3.00108 m s1 and

    Plancks constant, h =6.631034 J s)

    Solution :a. The frequency of the photon is given by

    b. By applying the Plancks quantum theory, thus the photons

    energy in joule is

    and its energy in electron-volt is

    Example 24.1 :

    m107409

    fc f98 107401000.3

    hfE 1434 1005.41063.6 E

    101.60

    1069.2

    19

    19

    E

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    PHYSICS CHAPTER 24

    11

    For a gamma radiation of wavelength 4.621012 m propagates in

    the air, calculate the energy of a photon for gamma radiation inelectron-volt.

    (Given the speed of light in the vacuum, c =3.00108 m s1 and

    Plancks constant, h =6.631034 J s)

    Solution :

    By applying the Plancks quantum theory, thus the energy of a

    photon in electron-volt is

    Example 24.2 :

    m1062.4

    12

    hcE

    12

    834

    1062.4

    1000.31063.6

    E

    J1031.4 14E

    101.60

    1031.419

    14

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    PHYSICS CHAPTER 24

    Learning Outcome:

    At the end of this chapter, students should be able to:

    a) Explain the phenomenon of photoelectric effect.

    b) Define threshold frequency, work function and stopping

    potential.

    c) Describe and sketch diagram of the photoelectric effect

    experimental set-up.

    d) Explain the failure of wave theory to justify the

    photoelectric effect.

    12

    24.2 The photoelectric effect (3 hours)

    www.kms

    .matrik.e

    du

    .my/physic

    s

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    PHYSICS CHAPTER 24

    Learning Outcome ( Cont..):

    At the end of this chapter, students should be able to:

    c) Explain by using graph and equations the

    observation of photoelectric effect experiment in

    terms of the dependence of :

    i. Kinetic energy of photoelectron on the frequency of

    light

    ii. Photoelectric current on the intensity of incident

    light

    iii. Work function and threshold frequency on the types

    of metal surface

    13

    24.2 The photoelectric effect (3 hours)

    0s

    2

    max2

    1hfhfeVmv

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    PHYSICS CHAPTER 24

    Learning Outcome ( Cont..):

    At the end of this chapter, students should be able to:

    f. Use Einsteins photoelectric equation

    14

    24.2 The photoelectric effect (3 hours)

    WhfeVK s max

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    PHYSICS CHAPTER 24

    24.2 The photoelectric effect

    is defined as the emission of electron from the surfaceof a metal when the EM radiation (light) of higher frequency

    strikes its surface.

    Figure 24.3 shows the emission of the electron from the surface

    of the metal after shining by the light.

    Photoelectron is defined as an electron emitted from the

    surface of the metal when the EM radiation (light) strikes itssurface. 15

    Figure 24.3

    EM

    radiation- photoelectron

    - - - - - - - - - -

    Metal

    Free electrons

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    PHYSICS CHAPTER 24

    24.2.1 Photoelectric experiment

    The photoelectric effect can be studied through the experiment

    made by Franck Hertz in 1887.

    Figure 24.4a shows a schematic diagram of an experimental

    arrangement for studying the photoelectric effect.

    16

    --

    -

    EM radiation (light)

    anodecathode

    glass

    rheostatpower supply

    vacuumphotoelectron

    Figure 24.4a

    G

    V

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    PHYSICS CHAPTER 24

    The set-up apparatus as follows:

    Two conducting electrodes, the anode (positive electric

    potential) and the cathode (negative electric potential) areencased in an evacuated tube (vacuum).

    The monochromatic light of known frequency and intensity is

    incident on the cathode.

    Explanation of the experiment

    When a monochromatic light of suitable frequency (or

    wavelength) shines on the cathode, photoelectrons are emitted.

    These photoelectrons are attracted to the anode and give rise to

    the photoelectric current or photocurrentIwhich is measured bythe galvanometer.

    When the positive voltage (potential difference) across the

    cathode and anode is increased, more photoelectrons reach the

    anode , thus the photoelectric current increases.

    17

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    PHYSICS CHAPTER 24

    As positive voltage becomes sufficiently large, the photoelectric

    current reaches a maximum constant valueIm

    , called

    saturation current. Saturation current is defined as the maximum constant

    value of photocurrent when all the photoelectrons havereached the anode.

    If the positive voltage is gradually decreased, the photoelectric

    currentIalso decreases slowly. Even at zero voltage there arestill some photoelectrons with sufficient energy reach the anode

    and the photoelectric current flows isI0.

    Finally, when the voltage is made negative by reversing thepower supply terminal as shown in Figure 24.4b, the

    photoelectric current decreases even further to very low valuessince most photoelectrons are repelled by anode which isnow negative electric potential.

    18

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    PHYSICS CHAPTER 24

    As the potential of the anode becomes more negative, less

    photoelectrons reach the anode thus the photoelectric currentdrops until its value equals zero which the electric potential at

    this moment is called stopping potential (voltage)Vs.

    Stopping potential is defined as the minimum value of

    negative voltage when there are no photoelectrons

    reaching the anode. 19

    Figure 24.4b: reversing power supply terminal

    --

    -

    EM radiation (light)

    anodecathode

    glass

    rheostatpower supply

    vacuumphotoelectron

    G

    V

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    PHYSICS CHAPTER 24

    The potential energy Udue to this retarding voltage Vs

    now

    equals the maximum kinetic energyKmax

    of the photoelectron.

    The variation of photoelectric currentIas a function of the

    voltage Vcan be shown through the graph in Figure 9.4c.

    20

    maxKU(24.5)

    electrontheofmass:mwhere

    mI

    0I

    sV

    I,currentricPhotoelect

    V,Voltage0

    Before reversing the terminalAfterFigure 24.4c

    Simulation 9.1

    http://localhost/var/www/apps/conversion/tmp/scratch_7/AF_4009.swfhttp://localhost/var/www/apps/conversion/tmp/scratch_7/AF_4009.swf
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    PHYSICS CHAPTER 24

    24.2.2 Einsteins theory of photoelectric effect

    A photon is a packet of electromagnetic radiation with

    particle-like characteristic and carries the energyEgiven by

    and this energy is not spread out through the medium.

    Work function W0

    of a metal

    Is defined as the minimum energy of EM radiation requiredto emit an electron from the surface of the metal.

    It depends on the metal used.

    Its formulae is

    wheref0

    is called threshold frequency and is defined as the

    minimum frequency of EM radiation required to emit an

    electron from the surface of the metal. 21

    hfE

    min0 EW and 0min hfE

    (24.6)

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    PHYSICS CHAPTER 24

    Since c=f then the eq. (24.6) can be written as

    where 0

    is called threshold wavelength and is defined as the

    maximum wavelength of EM radiation required to emit anelectron from the surface of the metal.

    Table 24.2 shows the work functions of several elements.

    22

    (24.7)

    Element Work function (eV)

    Aluminum 4.3

    Sodium 2.3Copper 4.7

    Gold 5.1

    Silver 4.3

    Table 24.2

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    PHYSICS CHAPTER 24Einsteins photoelectric equation

    In the photoelectric effect, Einstein summarizes that some of the

    energy Eimparted by a photon is actually used to release anelectron from the surface of a metal (i.e. to overcome the

    binding force) and that the rest appears as the maximum

    kinetic energy of the emitted electron (photoelectron). It is

    given by

    where eq. (24.8) is known as Einsteins photoelectric equation.

    SinceKmax

    =eVsthen the eq. (24.8) can be written as

    23

    where and0max WKE hfE

    (24.8)

    (24.9)

    voltagestopping:sVwhere

    electronofchargeformagnitude:e

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    PHYSICS CHAPTER 24

    1st case:

    24

    Note:

    OR0Whf 0ff

    Electron is emitted with maximum

    kinetic energy.-Metal

    hf

    0W

    -maxv maxK

    2nd case: OR0Whf 0ff

    Electron is emitted but maximum

    kinetic energy is zero.

    - 0v 0max K

    3rd case: OR0Whf 0ff

    No electron is emitted.

    -Metal

    hf

    0W

    -Metal 0

    W

    hf

    Figure 24.5a

    Figure 24.5b

    Figure 24.5c

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    PHYSICS CHAPTER 24

    25

    Cadmium has a work function of 4.22 eV. Calculate

    a. its threshold frequency,b. the maximum speed of the photoelectrons when the cadmium is

    shined by UV radiation of wavelength 275 nm,

    c. the stopping potential.

    (Given c =3.00

    108

    m s1

    , h =6.63

    1034

    J s, me=9.11

    1031

    kg ande=1.601019 C)

    Solution :

    a. By using the equation of the work function, thus

    Example 24.3 :

    J1075.61060.122.4 19190 W

    00 hfW

    03419 1063.61075.6 f

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    PHYSICS CHAPTER 24

    26

    Solution :

    b. Given

    By applying the Einsteins photoelectric equation, thus

    c. The stopping potential is given by

    m10275 9

    0

    2

    max2

    1Wmv

    hc

    0max WKE

    J1075.61060.122.4 19190 W

    192max319834

    1075.61011.92

    1

    10275

    1000.31063.6

    v

    2

    maxs2

    1mveV

    2

    maxmax2

    1mvK

    2531s19 1026.31011.92

    11060.1 V

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    PHYSICS CHAPTER 24

    27

    A beam of white light containing frequencies between 4.00

    10

    14

    Hzand 7.90 1014 Hz is incident on a sodium surface, which has a

    work function of 2.28 eV.

    a. Calculate the threshold frequency of the sodium surface.

    b. What is the range of frequencies in this beam of light for which

    electrons are ejected from the sodium surface?c. Determine the highest maximum kinetic energy of the

    photoelectrons that are ejected from this surface.

    (Given c =3.00108 m s1, h =6.631034 J s, me=9.111031 kg and

    e=1.601019

    C)

    Example 24.4 :

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    PHYSICS CHAPTER 24

    28

    Solution :

    a. The threshold frequency is

    b. The range of the frequencies that eject electrons is

    c. For the highestKmax

    , take

    By applying the Einsteins photoelectric equation, thus

    03419 1063.61065.3 f 00 hfW

    J1065.31060.128.2 19190 W

    Hz1090.7 14f

    0

    2

    max2

    1 Wmvhf

    0max WKE

    19max1434 1065.31090.71063.6 K

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    PHYSICS CHAPTER 24

    29

    Exercise 24.1 :Given c =3.00108 m s1, h =6.631034 J s, m

    e=9.111031 kg and

    e=1.601019 C1. The energy of a photon from an electromagnetic wave is

    2.25 eV

    a. Calculate its wavelength.

    b. If this electromagnetic wave shines on a metal, electrons

    are emitted with a maximum kinetic energy of 1.10 eV.Calculate the work function of this metal in joules.

    ANS. : 553 nm; 1.841019 J

    2. In a photoelectric effect experiment it is observed that nocurrent flows when the wavelength of EM radiation is greaterthan 570 nm. Calculate

    a. the work function of this material in electron-volts.

    b. the stopping voltage required if light of wavelength 400 nmis used.

    (Physics for scientists & engineers, 3rd edition, Giancoli, Q15,p.974)

    ANS. : 2.18 eV; 0.92 V

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    PHYSICS CHAPTER 24

    30

    Exercise 24.1 :

    3. In an experiment on the photoelectric effect, the following data

    were collected.

    a. Calculate the maximum velocity of the photoelectrons

    when the wavelength of the incident radiation is 350 nm.

    b. Determine the value of the Planck constant from the above

    data.ANS. : 7.73105 m s1; 6.721034 J s

    Wavelength of EM

    radiation, (nm)

    Stopping potential,

    Vs(V)

    350 1.70

    450 0.900

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    PHYSICS CHAPTER 24

    24.2.3 Graph of photoelectric experiment

    Variation of photoelectric currentI

    with voltageV

    for the radiation of different intensities but its frequency is

    fixed.

    Reason:

    From the experiment, the photoelectric current is directly

    proportional to the intensity of the radiation as shown in

    Figure 24.6b. 31

    Intensity 2x

    mI

    I

    V0sV

    Intensity 1x

    m2I

    Figure 24.6a

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    PHYSICS CHAPTER 24

    for the radiation of different frequencies but its intensity is

    fixed.

    32

    Figure 24.6b

    I

    intensityLight0 1

    mIm2I

    2

    mI

    Figure 24.7a

    I

    V

    0s1V

    f1

    f2

    s2V

    f2> f

    1

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    PHYSICS CHAPTER 24

    Reason:

    From the Einsteins photoelectric equation,

    33

    Figure 24.7b

    0s WeVhf e

    Wf

    e

    hV 0s

    y xm c

    e

    W0

    f,frequency

    s,voltageStopping V

    02

    f

    s2V

    1f

    s1V

    IfVs=0, 0)0( Wehf

    hfW 0 0f

    0f

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    PHYSICS CHAPTER 24

    For the different metals of cathode but the intensity and

    frequency of the radiation are fixed.

    Reason: From the Einsteins photoelectric equation,

    34

    Figure 24.8a

    mI

    s1V

    01W

    s2V

    02W

    W02> W

    01

    0s WeVhf

    e

    hfW

    eV

    0s

    1

    e

    hf

    0W

    sV

    0 Ehf 01W

    1sV

    02W

    s2VEnergy of a photon

    in EM radiation

    I

    V0

    y xm c

    Figure 24.8b

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    PHYSICS CHAPTER 24

    Variation of stopping voltage Vs

    with frequency fof the radiation

    for different metals of cathode but the intensity is fixed.

    Reason: Since W0=hf0 then

    35

    Figure 24.9W03 >W02 > W01

    01f

    W01

    02f

    W02

    03f

    W03

    f

    sV

    0

    00 fW

    0s WeVhf e

    Wf

    e

    hV 0s

    y xm c

    IfVs=0, 0)0( Wehf

    hfW 0 0f

    Threshold (cut-off)frequency

    PHYSICS CHAPTER 24

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    PHYSICS CHAPTER 24

    24.2.4 Failure of wave theory of light

    Table 24.3 shows the classical predictions (wave theory),

    photoelectric experimental observation and modern theoryexplanation about photoelectric experiment.

    36

    Classical predictions Experimental

    observation

    Modern theory

    Emission of

    photoelectrons occurfor all frequencies of

    light. Energy of light is

    independent of

    frequency.

    Emission of

    photoelectrons occuronly when frequency

    of the light exceeds

    the certain frequency

    which value is

    characteristic of thematerial being

    illuminated.

    When the light frequency is

    greater than thresholdfrequency, a higher rate of

    photons striking the metal

    surface results in a higher

    rate of photoelectrons

    emitted. If it is less thanthreshold frequency no

    photoelectrons are emitted.

    Hence the emission of

    photoelectrons depend on

    the light frequency

    PHYSICS CHAPTER 24

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    PHYSICS CHAPTER 24

    37

    Classical predictions Experimental

    observation

    Modern theory

    The higher theintensity, the greater

    the energy imparted to

    the metal surface for

    emission of

    photoelectrons. Whenthe intensity is low, the

    energy of the radiation

    is too small for

    emission of electrons.

    Very low intensity buthigh frequency

    radiation could emit

    photoelectrons. The

    maximum kinetic

    energy ofphotoelectrons is

    independent of light

    intensity.

    The intensity of light is thenumber of photonsradiated per unit time on aunit surface area.

    Based on the Einsteins

    photoelectric equation:

    The maximum kineticenergy of photoelectrondepends only on the lightfrequency and the workfunction. If the lightintensity is doubled, thenumber of electrons emittedalso doubled but themaximum kinetic energy

    remains unchanged.

    0WhfK max

    PHYSICS CHAPTER 24

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    PHYSICS CHAPTER 24

    38

    Classical predictions Experimental

    observation

    Modern theory

    Light energy is spreadover the wavefront, the

    amount of energy

    incident on any one

    electron is small. An

    electron must gathersufficient energy

    before emission, hence

    there is time interval

    between absorption of

    light energy and

    emission. Time interval

    increases if the light

    intensity is low.

    Photoelectrons areemitted from the

    surface of the metal

    almost

    instantaneously

    after the surface isilluminated, even at

    very low light

    intensities.

    The transfer of photonsenergy to an electron is

    instantaneous as its energy

    is absorbed in its entirely,

    much like a particle to

    particle collision. Theemission of photoelectron

    is immediate and no time

    interval between

    absorption of light energy

    and emission.

    PHYSICS CHAPTER 24

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    PHYSICS CHAPTER 24

    39

    Classical predictions Experimental

    observation

    Modern theory

    Energy of lightdepends only on

    amplitude ( or

    intensity) and not on

    frequency.

    Energy of lightdepends on

    frequency.

    According to Plancksquantum theory which is

    E=hf

    Energy of light depends on

    its frequency.

    Table 24.3Note:

    Experimental observations deviate from classical predictions based onwave theory of light. Hence the classical physics cannot explain thephenomenon of photoelectric effect.

    The modern theory based on Einsteins photon theory of light canexplain the phenomenon of photoelectric effect.

    It is because Einstein postulated that light is quantized and light isemitted, transmitted and reabsorbed as photons.

    PHYSICS CHAPTER 24

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    PHYSICS CHAPTER 24

    40

    a. Why does the existence of a threshold frequency in the

    photoelectric effect favor a particle theory for light over a wavetheory?

    b. In the photoelectric effect, explains why the stopping potential

    depends on the frequency of light but not on the intensity.

    Solution :

    a. Wave theory predicts that the photoelectric effect should occur atany frequency, provided the light intensity is high enough.

    However, as seen in the photoelectric experiments, the light must

    have a sufficiently high frequency (greater than the threshold

    frequency) for the effect to occur.

    b. The stopping voltage measures the kinetic energy of the most

    energetic photoelectrons. Each of them has gotten its energy

    from a single photon. According to Plancks quantum theory , the

    photon energy depends on the frequency of the light. The

    intensity controls only the number of photons reaching a unit area

    in a unit time.

    Example 24.5 :

    PHYSICS CHAPTER 24

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    PHYSICS CHAPTER 24

    41

    In a photoelectric experiments, a graph of the light frequencyfisplotted against the maximum kinetic energyK

    maxof the

    photoelectron as shown in Figure 24.10.

    Based on the graph, for the light of frequency 7.14

    1014

    Hz,calculate

    a. the threshold wavelength,

    b. the maximum speed of the photoelectron.

    (Given c =3.00108 m s1, h =6.631034 J s, me=9.111031 kg and

    e=1.601019 C)

    Example 24.6 :

    Hz1014f

    83.4

    )eV(maxK0Figure 24.10

    PHYSICS CHAPTER 24

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    PHYSICS CHAPTER 24

    42

    Solution :

    a. By rearranging Einsteins photoelectric equation,

    From the graph,

    Therefore the threshold wavelength is given by

    Hz1014.7 14f

    Hz1014f

    83.4

    )eV(maxK0

    0max WKhf hWK

    hf 0max

    1

    y xm c

    0max

    1fK

    hf

    Hz1083.4 140 f

    0

    0f

    c

    14

    8

    1083.4

    1000.3

    PHYSICS CHAPTER 24

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    PHYSICS CHAPTER 24

    43

    Solution :

    b. By using the Einsteins photoelectric equation, thus

    Hz1014.7 14f

    02

    max21 Wmvhf

    0

    2

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    Exercise 24.2 :

    Given c =3.00108 m s1, h =6.631034 J s, me=9.111031 kg and

    e=1.601019 C

    1. A photocell with cathode and anode made of the same metalconnected in a circuit as shown in the Figure 24.11a.Monochromatic light of wavelength 365 nm shines on the

    cathode and the photocurrentIis measured for various values

    of voltage Vacross the cathode and anode. The result isshown in Figure 24.11b

    365 nm

    V

    G 5

    1

    )nA(I

    )V(V0

    Figure 24.11a Figure 24.11b

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    Exercise 24.2 :

    1. a. Calculate the maximum kinetic energy of photoelectron.

    b. Deduce the work function of the cathode.

    c. If the experiment is repeated with monochromatic light of

    wavelength 313 nm, determine the new intercept with the

    V-axis for the new graph.

    ANS. : 1.60

    10

    19

    J, 3.85

    10

    19

    J; 1.57 V2. When EM radiation falls on a metal surface, electrons may be

    emitted. This is photoelectric effect.

    a. Write Einsteins photoelectric equation, explaining the

    meaning of each term.

    b. Explain why for a particular metal, electrons are emittedonly when the frequency of the incident radiation is greater

    than a certain value?

    c. Explain why the maximum speed of the emitted electrons

    is independent of the intensity of the incident radiation?

    (Advanced Level Physics, 7th edition, Nelkon&Parker, Q6, p.835)

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    PHYSICS CHAPTER 24

    Next ChapterCHAPTER 25 :

    Wave properties of particle

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