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    3-1

    Chapter 3: Alkanes and their Stereochemistry

    Coverage:

    1. Survey of Functional Groups

    2. Alkane Isomers3. Alkyl Groups

    4. Nomenclature of Alkanes

    5. Properties of Alkanes

    6. Conformations of Ethane, Propane, Butane

    7. Special Topic: Refining of Petroleum

    Goals:

    1. Be able to recognize and identify the functional group(s) in a molecule.

    2. Be able to predict the hybridization of an atom in a functional group.

    3. Know the definition of constitutional and stereoisomers and be able to apply definitions

    to alkanes.

    4. Know the structures of alkyl groups up to 4 carbons.5. Know the IUPAC system of nomenclature for naming alkanes.

    6. Know trends in boiling points and melting points of alkanes, both branched and straight

    chain.

    7. Know the meaning of gauche, anti, eclipsed, staggered in conformations.

    8. Be able to draw Newman projections of ethane, propane, butane and others.

    9. Know the sources of hydrocarbons, particularly petroleum refining.

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    3-2

    Classification of Organic Molecules

    Functional Groups

    1. Hydrocarbons - molecules that possess only hydrogen and carbon

    a1. Alkanesnoncyclic hydrocarbons with only C-C single bonds.

    Formula CnH2n+2 where n is an integer.

    a2. Cycloalkanescyclic hydrocarbons with only C-C single bonds.

    Formula CnH2n where n is an integer.

    Example: Butane CH3CH2CH2CH3 C4H10

    Example: Cyclobutane C4H8

    b1. Alkenesnoncyclic hydrocarbons with C=C double bonds.

    Formula CnH2n where n is an integer.

    Example: 2-Butene CH3CH=CHCH3 C4H8

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    c. Alkynesnoncyclic hydrocarbons with C=C triple bonds.

    Formula CnH2n-2 where n is an integer.

    Example: Butyne CH3C=CCH3 C4H6

    b2. Cycloalkenescyclic hydrocarbons with C=C double bonds.

    Formula CnH2n-2 where n is an integer.

    Example: Cyclobutene C4H6

    d. Aromatic Hydrocarbonsbenzene and its derivatives

    C

    CC

    C

    CC H

    H

    H

    H

    H

    H

    or C6H6

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    3-4

    2. Compounds containing Oxygen

    a. Alcohols R-OH

    Functional Group OH hydroxyl group

    CH3OH methyl alcohol HOCH2CH2OH ethylene glycol (antifreeze)

    b. Ethers R-O-R

    CH3CH2-O-CH2CH3 Diethylether

    c. Aldehydes and Ketones

    R-C-H

    O

    R-C-R'

    O

    Functional Group C=O carbonyl group

    O

    O

    O

    H

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    d. Carboxylic Acids

    Functional Group -CO2H -COOH -COH Carboxyl Group

    R-C-OH

    O

    O

    CH3-C-OH

    O

    OH2

    H3O+ CH

    3CO-

    O

    + +

    Acetic Acid

    e. Derivatives of Carboxylic Acids

    R-C-OR'

    O

    R-C-Cl

    O

    R-C-NH2

    O

    Ester Acid Chloride Amide

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    3-6

    3. Nitrogen-Containing Molecules

    a. Amines R-NH2

    Functional Group -NH2 amino group

    CH3NH

    2

    NH

    N

    Amines are Lewis and Bronsted basesbecause of the nonbonded pair of electrons

    NH2

    ClH NH3+ Cl+..

    b. Amides (see above)

    c. NitrilesR C N

    Functional Group Cyano GroupC N

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    3-7

    Use of Wedges and Dashed Lines

    CH

    H

    H

    HSolid Wedge indicates coming toward you

    Dashed Line indicates going awayNarrow Line indicates in the plane of paper

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    3-8

    Single versus Double Bonds

    C C

    H

    H

    HH

    H

    H

    Ethane

    The carbon-carbon single bond in ethane freely rotates at room temperature.

    CC

    HH

    HH

    Ethylene

    The carbon-carbon double bond in ethylenedoes not freely rotate at room temperature.

    Why not?

    CC

    HH

    HH

    C C

    H H

    H

    H H

    H

    Answer: The Pi bond would have to be broken. It will not break at room temperature

    Pi bond broken

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    3-9

    Isomersdifferent compounds with the same formula

    a. Constitutional (Structural) Isomersisomers that differ in their bonding sequence

    CH3CHCH

    2CH

    3\

    CH3

    CH3CH

    2CH

    2CH

    2CH

    3vs

    C5H12 C5H12

    C=C

    Cl

    H H

    Br

    C=CH

    H Cl

    Br

    C2H2BrCl C2H2BrCl

    b. Stereoisomersisomers that differ in their spatial orientation

    C=CCl

    H H

    Br

    C=CCl

    H Br

    H

    C2H2BrCl C2H2BrCl

    Cis isomer Trans isomer

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    3-10

    Alkyl Groups

    Ris the general symbol for an alkyl group.

    For example R-OH represents an alcohol where R is an alkyl group.R-Cl is an alkyl chloride.

    Alkyl Groupsknow the following

    -CH3

    methyl

    -CH2CH

    3ethyl

    -CH2CH

    2CH

    3propyl

    -CH2CH

    2CH

    2CH

    3butyl

    -CH2CHCH3

    CH3

    -CHCH2CH

    3

    CH3

    -C

    CH3

    CH3

    CH3

    isobutyl

    sec-butyl

    tert-butyl

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    3-11

    Carbon Substitution

    a. Primary carbon (1o

    ) - carbon attached to one other carbon.

    R-CH3 1o

    b. Secondary carbon (2o) - carbon attached to two other carbons.

    R-CH2-R

    2o

    c. Tertiary carbon (3o)carbon attached to three other carbons

    3o

    R-CH-R

    R

    d. Quaternary (4o)carbon attached to four other carbons.

    C

    R

    R

    R

    R4o

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    3-12

    Alkane Nomenclature

    1. Find the parent hydrocarbon

    a. Find the longest continuous chain of carbon atoms and name it accordingly.

    Number Carbons Name

    1 methane

    2 ethane

    3 propane

    4 butane

    5 pentane

    6 hexane

    7 heptane

    8 octane

    9 nonane

    10 decane

    Named as a hexane

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    3-13

    b. If two different chains of equal length are present, choose the one with the

    larger number of branch points.

    Named as hexane with 2 substituents not hexane with 1 substituent

    2. Number the atoms in the main chain

    a. Begin at the end nearer the first branch point.

    1

    2

    3

    4

    5

    6

    b. If there are branch points at equal distances away, begin at the end nearer the second

    branch point.

    7

    6

    5

    4

    3

    2

    1

    8

    9

    Named as a nonane with branch points

    at carbons 3, 4, 7.

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    3. Identify and number the substituents.

    7

    6

    5

    4

    3

    2

    1

    8

    9

    3-ethyl

    4-methyl

    7-methyl

    4. Write the name as a single word.

    a. Use prefixes such asmono, di, tri, tetra, etc. to indicate multiple substituents.

    b. List substituents alphabetically, ignoring prefixes.c. Use dashes to separate substitutents, use commas to separate numbers.

    The above example would have the name

    3-ethyl-4,7-dimethylnonane

    Name this alkane: Answer: 5-sec-butyldecane

    1

    2

    3

    4

    5

    6

    7

    8

    9

    10

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    3-15

    Physical Properties of Alkanes

    1. Combustion - Alkanes are inflammable, i.e. they burn.

    CH4 O2 CO2 OH2+ +2 2

    2. Boiling and melting points

    a. Both bp and mp increase with increasing carbon number for straight-chainalkanes with formula CnH2n+2

    Carbon Number Physical State

    C1- C4 gases

    C5C16 liquids

    C17C30 oils and greases

    C30C50 paraffin waxes>C50 plastics (polyethylene)

    b. Branching tends to raise the melting point and lower the boiling point.

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    b. Branching tends to lower the boiling point and raise the melting point

    BP 60oC 58oC 50oC

    MP -154oC -135oC -98oC

    Explanation:

    MP Branching reduces the flexibility of the molecule which reduces the entropy term

    S in the equation Tmp = H/S. Since S is in the denominator, Tmp increases.

    BP Branching reduces surface area (more compact structure), and therefore London

    dispersion forces which control boiling point for these molecules.

    3. Solubilityalkanes are nonpolar molecules and therefore insoluble in water, which

    is polar. Alkanes are hydrophobic.

    4. Densitiesalkanes are less dense than water, with densities near 0.7 g/mL. Therefore

    they float on water, e.g. Exxon Valdez oil spill.

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    3-17

    1. Conformation of Ethane

    CH3CH

    3

    C C

    H

    H

    H

    H

    H

    H

    Rotate 60o

    HH

    HH

    H

    H HH

    H

    H

    H

    H

    Staggered Conformation Eclipsed Conformation

    Lower Energy Higher Energy

    More Stable Less Stable

    The staggered conformation is more stable by 3.0 kcal/mol

    Sawhorse

    Newman

    projection

    C1

    C2

    H

    H

    HH

    H

    H

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    3-18

    Eclipsed Staggered Eclipsed Staggered Eclipsed Staggered Eclipsed

    0.0 kcal/mol

    3.0 kcal/mol

    Dihedral Anglethe angle defined by the C-H bond on the front carbon

    and the C-H bond on the back carbon in a Newman projection.

    HH

    H

    H

    H

    H

    600

    HH

    H

    H

    H

    H

    00

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    3-19

    Why is the staggered conformation more stable than the eclipsed conformation?

    In the eclipsed conformation, the C-H bonds are closer, resulting in arepulsion

    of the electron clouds.

    This effect is referred to torsional strain. Torsional strain exists anytime C-H

    bonds are eclipsed.

    HH

    H

    H

    H

    H

    1.0 kcal/mol

    1.0 kcal/mol

    1.0 kcal/mol

    Total Energy: 3.0 kcal/mol

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    2. Conformations of Propane

    Rotate 60

    0

    C2

    C1

    H

    H

    HH

    H

    CH3

    C1

    C2

    H

    H

    H

    H

    H

    CH3

    HH

    HH

    CH3

    HRotate 600

    More stable Less stable

    0.0 kcal/mol 3.3 kcal/mol

    1.3 kcal/mol

    1.0 kcal/mol1.0 kcal/mole The additional 0.3 kcal/mol energy is due

    to steric strain.

    Steric strainelectronic repulsion that

    occurs when two atoms or groups are

    forced together.

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    3. Conformations of Butane

    C3C2

    H

    H

    CH3 H

    H

    CH3

    C2

    C3

    CH3

    H

    H

    HH

    CH3

    Anti Conformation

    Staggered

    180o dihedral

    Gauche Conformation

    Staggered

    60o dihedral

    HH

    CH3

    H

    CH3

    H CH3H

    H

    H

    H

    CH3

    CH3

    H

    HH

    CH3

    H HH

    CH3

    H

    H

    CH3

    HCH3

    HH

    CH3

    H HCH3

    H

    H

    H

    CH3

    Anti

    60o

    60o

    Eclipsed

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    3-22

    There are two staggered conformations of

    different energy.

    There are two eclipsed conformations ofdifferent energy.

    Remember, staggered conformations are

    more stable than eclipsed conformatiions

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    Petroleum Refining

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    1. The first step in petroleum refining is fractional distillation.

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    2. Upstream processing of the distillates.

    a. Catalytic hydrocrackingproduces small alkanes from large alkanes by

    adding hydrogen.

    H2, heat

    Si-Al catalyst

    b. Catalytic crackingproduces small alkenes and alkanes by cracking in the absence

    of hydrogen.

    heat

    Si-Al catalyst

    c. Catalytic Reformingthe alkanes and cycloalkanes are upgraded to higher octane number

    by conversion into aromatic compounds.

    -3H2-H2

    catalyst, heat catalyst, heat

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    Octane Number

    Straight-chain hydrocarbons have low octane and make poor fuels.

    Octane Number = 0

    Branched Alkanes burn more slowly and reduce the knocking in the engine.

    heptane

    2,2,4-trimethylpentane

    Octane Number = 100