chapter 12 solutions. chapter 12 test – review section two ap problems –pv = nrt –calculating...

106
Chapter 12 Solutions

Upload: amber-payne

Post on 25-Dec-2015

217 views

Category:

Documents


1 download

TRANSCRIPT

Page 1: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Chapter 12

Solutions

Page 2: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Chapter 12 Test – Review Section

• Two AP Problems

– PV = nRT

– Calculating an Empirical/Molecular Formula

– Graham’s Law

– Real vs. Ideal Gas

– Some other simple concepts

Page 3: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Mixtures

• When materials are mixed together the distinction between heterogeneous and homogeneous depends on the size of the dispersed/dissolved particles.

Page 4: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Suspensions•Suspensions are heterogeneous because at least two substances can be clearly identified.

15.3

Suspensions can be separated by filtering.

Page 5: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Suspensions

•Suspensions–What is the difference between a suspension and a solution?

15.3

Page 6: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Suspensions

•A suspension is a heterogeneous mixture with dispersed particles much larger than the solute particles in a solution. These dispersed particles settle out upon standing.

15.3

Page 7: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

15.3

Colloids•Gelatin is a heterogeneous mixture called a colloid.

•What distinguishes a colloid from a suspension and a solution?

Page 8: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Colloids

•Colloids are heterogeneous mixtures that have dispersed particles smaller than those in suspensions and larger than those in solutions.

•Examples include: whipped cream, marshmallows, fog, jelly.

15.3

Page 9: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Colloids–The Tyndall Effect

•The scattering of visible light by colloidal particles is called the Tyndall effect.

15.3

Page 10: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Colloids•Particles in colloids and suspensions reflect or scatter light in all directions. Solutions do not scatter light.

15.3

Page 11: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

1

Page 12: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

3.8: Solutions

• Solute: The substance that dissolves (the minor component of a solution).

KMnO4

Page 13: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

3.8: Solutions

• Solvent: The substance in which the solute dissolves (the major component of a solution).

Page 14: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

KMnO4 solution

Solution: A homogeneous mixture of the solute and solvent.

Page 15: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Solutions

• Solutions come in the form of solids, liquids and gases.

• Solutes/solvents can be a gas, liquid, or solid.

Page 16: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Solute-solvent combinations: • oxygen in nitrogen (gas-gas) = air• carbon dioxide in water (gas-liquid) = soda pop• water vapor in air (liquid-gas) = humidity• alcohol in water (liquid-liquid) = liquor• mercury in silver (liquid-solid) = dental amalgam• sugar in water (solid-liquid) = kool-aid• tin in copper (solid-solid) = bronze alloy• How many other combinations are possible?

Page 17: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Other solute – solvent combinations

• (solid-gas) = Mothballs sublime in air

• (gas-solid) = Hydrogen dissolves rather well in metals; an example is hydrogen in palladium which is used as a gas stove lighter.

Page 18: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Properties of Solutions

• In solutions (homogeneous mixtures) the macroscopic properties do not vary throughout the sample.

• This is in contrast to heterogeneous mixtures in which the macroscopic properties vary from one part of the mixture to another.

Page 19: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Heterogeneous Mixture of Copper and Zinc

Page 20: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Pennies are a Heterogeneous Mixture of Copper and Zinc

• For many years pennies were 95 percent copper and 5 percent zinc until 1982, when the composition was changed to 97.5 percent zinc and 2.5 percent copper.

Page 21: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Brass is a solution of Copper and Zinc.

Page 22: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

3.8: Solutions

Dilute Concentrated

Page 23: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Solubility

• The solubility of a solute is the quantity that will dissolve in a given amount of solvent to produce a saturated solution.

• Expressed as grams of solute in 100 grams of solvent, usually water.

g of solute

100 g water

Page 24: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Unsaturated Solutions

• Contains less than the maximum amount of solute.

• No undissolved solute present.

• Can dissolve more solute.

Dissolved solute

Page 25: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Saturated Solutions

• Contains the maximum amount of solute that can dissolve.

• Have undissolved solute at the bottom of the container.

• Solution is in equilibrium with undissolved solute

Page 26: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Saturation:

Page 27: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Factors Affecting SolubilityFactors Affecting SolubilityTemperature EffectsTemperature Effects

Page 28: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Temperature and Solubility of Solids

Temperature Solubility (g/100 g H2O)

KCl(s) NaNO3(s)

0° 27.6 74

20°C 34.0 88

50°C 42.6 114

100°C 57.6 182

Page 29: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Temperature and Solubility of Solids

Temperature Solubility (g/100 g H2O)

KCl(s) NaNO3(s)

0° 27.6 74

20°C 34.0 88

50°C 42.6 114

100°C 57.6 182

The solubility of most solids increases with an increase in the temperature.

Page 30: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Supersaturated• A supersaturated solution contains more than the maximum

amount of solute and is unstable. It returns to a saturated solution if disturbed in some way (i.e.: a seed crystal)

Page 31: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Supersaturated

Page 32: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Factors Affecting SolubilityFactors Affecting SolubilityTemperature EffectsTemperature Effects

Page 33: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Temperature and Solubility of Gases

Temperature Solubility (g/100 g H2O)

CO2(g) O2(g)

0°C 0.34 0.0070

20°C 0.17 0.0043

50°C 0.076 0.0026

Page 34: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Temperature and Solubility of Gases

Temperature Solubility (g/100 g H2O)

CO2(g) O2(g)

0°C 0.34 0.0070

20°C 0.17 0.0043

50°C 0.076 0.0026

The solubility of gases decreases with an increase in temperature.

Page 35: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Factors That Affect Solubility

• Pressure– If we increase the

pressure on a liquid/gas solution, we will increase the solubility of the gas into the liquid solvent

• Example: soda pop

Page 36: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal
Page 37: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

What conditions affect solubility?

Page 38: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

What conditions affect solubility?

• For solids in liquids as the temperature goes up the solubility goes up.

Page 39: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

What conditions affect solubility?

• For solids in liquids as the temperature goes up the solubility goes up.

• For gases in a liquid as the temperature goes up the solubility goes down.

Page 40: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

What conditions affect solubility?

• For solids in liquids as the temperature goes up the solubility goes up.

• For gases in a liquid as the temperature goes up the solubility goes down.

• For gases in a liquid- as the pressure goes up the solubility goes up.

Page 41: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

GENERAL PROPERTIES OF SOLUTIONSGENERAL PROPERTIES OF SOLUTIONS

Page 42: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

GENERAL PROPERTIES OF SOLUTIONSGENERAL PROPERTIES OF SOLUTIONS

1. A solution is a homogeneous.

Page 43: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

GENERAL PROPERTIES OF SOLUTIONSGENERAL PROPERTIES OF SOLUTIONS

1. A solution is a homogeneous.

2. The solute remains uniformly distributed throughout the solution and will not settle out over time.

Page 44: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

GENERAL PROPERTIES OF SOLUTIONSGENERAL PROPERTIES OF SOLUTIONS

1. A solution is a homogeneous.

2. The solute remains uniformly distributed throughout the solution and will not settle out over time.

3. The solute is dissolved as molecules or ions.

Page 45: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

GENERAL PROPERTIES OF SOLUTIONSGENERAL PROPERTIES OF SOLUTIONS

1. A solution is a homogeneous.

2. The solute remains uniformly distributed throughout the solution and will not settle out over time.

3. The solute is dissolved as molecules or ions.

4. It has variable composition within limits of its solubility.

Page 46: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

The solution process involves changes in energy among The solution process involves changes in energy among the attractive forces within the solute and solvent.the attractive forces within the solute and solvent.

i

Page 47: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Generally solution formation increases the amount of disorder (entropy)

• The dissolving of many salts such as NaCl in water is just one example of a change that occurs spontaneously even though it is endothermic.

• NaCl dissolves as a result of the drive towards increased entropy.

Page 48: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Strong Electrolytes

• Strong electrolytes are either strong acids, strong bases or soluble salts.

• Strong electrolytes dissociate completely into ions when they dissolve in water.

Page 49: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Strong Electrolytes• Generally when an ionic compound is dissolved in

water the ions are separated and dispersed.

Page 50: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Strong Electrolytes

• The ions in the solid are being broken apart, being pulled away from the other ions in the solid, and are being surrounded by water molecules.

• An ion-dipole attraction occurs between the polar water molecules and the dissociated ions.

Page 51: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Strong Electrolytes

• Strong electrolytes can also be molecular. These substances also dissociate completely into ions when they dissolve, no intact molecules remain.

• Strong acids are molecular strong electrolytes.

Page 52: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Strong Electrolytes

• Solutions of strong electrolytes conduct electricity well.

• This is because dissociated ions are free to move and can therefore be made to create a difference in potential. 

Page 53: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Types of solutes

Na+

Cl-

Strong Electrolyte -100% dissociation,all ions in solution

high conductivity

Page 54: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

What is another way that ions can allowed freedom of movement?

Page 55: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal
Page 56: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

.

Page 57: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Weak Electrolytes

• A weak electrolyte is a compound that when dissolved in water only partially ionizes (partially dissociates into ions).

• The compound exists in water as a mixture of individual ions and intact molecules.

• This solution conducts electricity weakly.

• Therefore the term weak electrolyte is applied to this type of compound.

Page 58: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Types of solutes

CH3COOH

CH3COO-

H+

Weak Electrolyte -partial dissociation,molecules and ions in solution

slight conductivity

Page 59: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Types of solutes

CH3COOH

CH3COO-

H+

• What is the name of CH3COOH?

• How do I know it is a “weak” acid?

slight conductivity

Page 60: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Weak Electrolytes

• Weak electrolytes include weak acids and weak bases.

• There will be dipole-dipole, or possibly even hydrogen bonding, between the solute molecules and the water.

• For the few molecules which do dissociate into ions, you will have ion-dipole attractions between the dissociated ions and water molecules.

Page 61: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Hypochlorous acid• Hypochlorous acid is a polar

molecule which dissolves in water (like dissolves like).

• It can also form hydrogen bonds with water molecules.

Page 62: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Hypochlorous acid

• A few of the hypochlorous acid molecules dissociate into ions when dissolved in water.

• Therefore, hypochlorous acid, HClO is a weak electrolyte.

• This is why hypochlorous acid is termed a “weak” acid.

Page 63: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Nonelectrolytes

• A nonelectrolyte is a compound that when dissolved in water does not ionize or dissociate into ions at all.

• In water, this compound exists entirely as intact molecules.

Page 64: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Whether a compound is an electrolyte (strong or weak), Whether a compound is an electrolyte (strong or weak), or a nonelectrolyte does not mean soluble or insoluble.or a nonelectrolyte does not mean soluble or insoluble.

Page 65: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Nonelectrolytes

• Solutions of nonelectrolytes do not conduct electricity at all.

Page 66: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Types of solutes

sugar

Non-electrolyte -No dissociation,all molecules in solution

no conductivity

Page 67: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Nonelectrolytes• Most nonelectrolytes are molecular

compounds other than the acids.• Examples: alcohol, sugar.

Page 68: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Sugar dissolved in water

Page 69: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

• Hydrogen bonding between the sugar molecules and water molecules causes sugar to dissolve.

• The negative end of water (oxygen end) is attracted to the hydrogen atoms in the “OH” groups within the sugar molecules.

• The positive end of water (hydrogen end) is attracted to the oxygen atoms in the “OH” groups within the sugar molecules.

• Sugar dissolves in water but does not dissociate into any ions. It is therefore a nonelectrolyte.

Sugar dissolved in water

Page 70: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Video: Electrolytes

Page 71: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Molarity (M)

• Moles of solute per liter of solution.

Molarity =moles of soluteliters of solution

Page 72: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

What is the molarity of a solution prepared by What is the molarity of a solution prepared by dissolving 10.0 g of NaCl in 250.0 mL of solution? dissolving 10.0 g of NaCl in 250.0 mL of solution?

0.684M

Page 73: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How would you prepare 500. ml of a 6.0M NaOH solution?

Page 74: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How would you prepare 500. ml of a 6.0M NaOH solution?

• Would it be sufficent to say that I need to use 120 g of NaOH?

• This does not answer the question.

• The question was not how much NaOH do I need prepare the solution.

Page 75: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How would you prepare 500. ml of a 6.0M NaOH solution?

• Measure out 120 g of NaOH on a balance.

120g

Page 76: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How would you prepare 500. ml of a 6.0M NaOH solution?

• Add the 120 g of NaOH to a 500. ml volumetric flask.

Page 77: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How would you prepare 500. ml of a 6.0M NaOH solution?

• Add distilled water and swirl the flask to dissolve the solid.

Page 78: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How would you prepare 500. ml of a 6.0M NaOH solution?

• Add distilled to the 500. ml line on the volumetric flask.

Page 79: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How would you prepare 500. ml of a 6.0M NaOH solution?

• Cap and then invert the flask several times to thoroughly mix the solution.

Page 80: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

I need to make 250 ml of a 0.50M NaOH solution using the 6.0M NaOH prepared in the previous

example. How do I prepare this solution?

This is a dilution problem

Page 81: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Dilution Problems

Page 82: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

I need to make 250 ml of a 0.50M NaOH solution using the 6.0M NaOH prepared in the previous

example. How do I prepare this solution?

• Measure out 21ml of the 6.0M NaOH in a graduated cylinder or pipet.

Page 83: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

I need to make 250 ml of a 0.50M NaOH solution using the 6.0M NaOH prepared in the previous

example. How do I prepare this solution?

• Transfer to a 250. ml volumetric flask and add water to the 250. ml mark.

Page 84: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

I need to make 250 ml of a 0.50M NaOH solution using the 6.0M NaOH prepared in the previous

example. How do I prepare this solution?

• Cap and then invert the flask several times to thoroughly mix the solution.

Page 85: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

0.850 ml of a 5.00M Cu(NO0.850 ml of a 5.00M Cu(NO33))22 solution is diluted solution is diluted

to a total volume of 1.80L. What is the molarity to a total volume of 1.80L. What is the molarity of the resulting diluted solution? of the resulting diluted solution?

0.00236M

Page 86: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How many milliliters of water are needed to dilute How many milliliters of water are needed to dilute 12ml of a 0.44M acetic acid solution to 0.12M? 12ml of a 0.44M acetic acid solution to 0.12M?

32 ml of water added

Page 87: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Methods of separation of the components of a solution

• Distillation

• Chromatography– Paper– Column

Page 88: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Distillation• Distillation is the vaporization by heating and

subsequent condensation of a liquid by cooling.

Page 89: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

How Could a Solution of Ethanol and Water be Separated by Distillation?

Page 90: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

• Set up a distillation apparatus and heat the water and ethanol solution until it starts to boil. The ethanol boils at a lower temperature than water and therefore vaporizes first.

• The temperature should rise initially as the solution is heated.

Page 91: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

• Cooling water is passed through a condenser and the ethanol vapor turns back into a liquid and is collected.

• The temperature should remain constant during this phase.

Page 92: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

• Stop heating the mixture and remove the beaker of ethanol.• Only water should be left in the original container at this point.

..

Page 93: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Paper Chromatography

• In paper chromatography substances are distributed between a stationary phase and a mobile phase.

• The stationary phase is usually a piece of high quality filter paper.

• The mobile phase is a solvent that travels up the stationary phase, carrying the samples with it.

Page 94: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Paper Chromatography

• Paper chromatography is based on the attractive forces between different substances.

• Substances which travel further toward the top of the paper are more attracted to the solvent (mobile phase).

• Substances that do not move very far up the paper are more attracted to the paper (stationary phase).

Page 95: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Paper Chromatography• Chromatography is the method

used to separate molecules or ions based upon their structure and their interactions with the mobile and stationary phases.

• Molecules or ions with a strong attraction with the stationary phase will tend to move more slowly through the stationary phase than those molecules or ions with weaker attractions. In this way, different types of molecules or ions can be separated from each other as they move at differing rates over the stationary phase.

Page 96: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Paper Chromatography

• A spot of pure substance may move at the same rate as the solvent front (no affinity for the stationary phase), at a slower rate than the solvent front (some affinity for both the stationary and mobile phase), or the spot may not move at all (no affinity for the mobile phase).

• The retention factor (Rf) can be calculated by measuring the distance the spot traveled and the distance the solvent traveled.

Page 97: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Retention Factor (Rf)

Page 98: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Uses of Chromatography

• Used as a qualitative method for identifying the components in a mixture.

• The separated spots on the finished and dried chromatogram can be cut out and re-dissolved to obtain a pure sample of component of the sample mixtures.

• Used in several scientific studies in identification of unknown organic and inorganic compounds from a mixture.

• In forensic studies paper chromatography is used in crime scene investigation and DNA and RNA sequencing along with other studies.

Page 99: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Some Forensic Uses of Chromatography

• Drugs from narcotics to aspirin can be identified in urine and blood by using chromatography.

• Detectives can analyze a sample of paint to find out the car it came from, including the model and year it was made.

• Ink can be separated into its components to help identify the pen used for ransom notes and forgeries, as well as the type of ink used for counterfeiting.

Page 100: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Paper Chromatography Example

• Suppose you have three blue pens and you want to find out which one was used to write a message.

Page 101: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Paper Chromatography Example

• Samples of each ink are spotted on a pencil line drawn on a sheet of chromatography paper.

• Some of the ink from the message is also spotted onto the same line.

• In the diagram, the pens are labeled 1, 2 and 3, and the message ink as M.

Page 102: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Paper Chromatography Example

• The paper is suspended in a container with a shallow layer of a “suitable” solvent or a mixture of solvents in it.

• It is important that the solvent level is below the line with the spots on it.

• The container is covered to make sure that the solvent does not completely evaporate away.

Page 103: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Paper Chromatography Example

• As the solvent slowly travels up the paper, the different components of the ink mixtures travel at different rates and the mixtures are separated into different colored spots.

• The pen that wrote the message contained the same dyes as pen 2. You can also see that pen 1 contains a mixture of two different blue dyes - one of which might be the same as the single dye in pen 3.

Page 104: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Column Chromatography

• Similar to paper chromatography however a silica gel or other appropriate solid is used as the stationary phase and the mobile phase is continually poured through it.

• Primarily used to separate the components of a mixture.

Page 105: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal
Page 106: Chapter 12 Solutions. Chapter 12 Test – Review Section Two AP Problems –PV = nRT –Calculating an Empirical/Molecular Formula –Graham’s Law –Real vs. Ideal

Column Chromatography

• The individual components of a mixture are attracted by the stationary phase differently and separate from each other while they are running at different speeds through the column with the solvent.

• At the end of the column they are separated and collected one at a time.