ch 05 temperature and heat - eunil wonparticle.korea.ac.kr/class/2006/phys183-01/ch05_med.pdf ·...
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Eunil Won Dept. of Physics, Korea Univ 1
Ch 05 Temperature and Heat
Eunil Won Dept. of Physics, Korea Univ 2
TemperatureWhat is temperature?
: is a quantitative measure of hot and cold
(as physicists, we need more precise definition of the temperature but for now let’s take the above statement)
From the experience, we know that
boiling point of water : 100 oCtemperature of the universe : 3 K
Temperature is directly related to the kinetic energy of the molecules
SI unit: Kelvin (K) Ex) 0 K = -273.15 oC
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Thermal ExpansionMost materials expand when their temperature is increased
α: coefficient of linear expansion
Material α (1/oC)
Aluminum 25 x 10-6
Lead 29 x 10-6
Glass 9 x 10-6
Quartz 0.4 x 10-6
Gasoline 320 x 10-6
Water 70 x 10-6
Air 1100 x 10-6
This is the operational principle of most of thermometers
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Water has highest density at 4 oC
Specific heat?
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Example 5.1
cm 105.4C)cm)(3.0C)(3.0/10(60
4
6
−
−
×=
°°×=∆=∆ TLL α
What is the change in length of a column of mercury 3.0 cm long if its temperature increases from 37℃ to 40℃?
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Example 5.2
kg 1.05g 101.05)cm )(10g/cm (1.05
3
333
=×=
== Vm ρ
What is the mass of a liter of whole blood?
]kg/m[ 3⇒=Vmρdensity
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Specific Heat
)()( fifi TTCTTQ −=−∝
dTdQ
nCs 1
mol=≡
]KJ/kg4190Ccal/g1[ ⋅=⋅ο
dTdQC ≡
TsmQ ∆=
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Example 5.3
kcal 1cal 1000C) g)(5.0 C)(200cal/g (1.00
www
==°°⋅=
∆= TmsQ
cal 03C) g)(5.0 C)(200cal/g (0.030
PbPbPb
=°°⋅=
∆= TmsQ
(a) Heat to increase the temperature of 200 g of water 5.0oC?
(a) Heat to increase the temperature of 200 g of lead 5.0oC?
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Example 5.4
mghTsmQ
2121 PE
=∆=
C 0.78
CJ
/smkg0.78
J) C)(4186kcal/kg 2(0.030m) )(20m/s (9.8
2
22
2
°=
°⋅=
°⋅=
=∆s
ghT
Calculate the temperature increase of a lead ball dropped from a height of 20 m, assuming that half the thermal energy generated on impact goes into the ball
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Phase changes and latent heat
fmhQ = vmhQ =
Gas state
Solid state
Liquid state
Latent heat: heat needed to make phase change
(boiling water)
m: mass of object
Phase change: changes of a substance from one phase of matter to another
hf: heat of fusion hv: heat of vaporization
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Example 5.5
cal 106.40cal/g) g)(80 (800
4
f
×=== mhQ
11minhr,1
s 104.27cal/s15
cal 106.40/
34
=
×=×=
=tQ
Qt
An aluminum ice cube tray contains 800 g of water at 0oC. If heat is removed at the rate of 15 cal/sec, how long will it take for all of the water to freeze?
From table 5.4
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Example 5.7
g 93.8cal/g 80
cal 7500
f
iiww
wwfii
fiicold
wwhot
hotcold
==∆−∆=∴
∆=+∆+∆=∆
∆=∆∆=∆
hTmsTmsm
TmsmhTmsmhTmsQ
TmsQQQ
Suppose that 100 g of ice at an initial temperature of -10oC are put into 400 g of water at an initial temperature of 20oC. How many grams of ice melt? (For simplicity, ignore the effects of the container)
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Evaporation
Random motion of molecules
Small fraction of them has high kinetic energy escape from substance
relative humidity=vapor density/saturation vapor density
Saturation vapor density: maximum amount of vapor density that air can hold at a given temperature
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Example 5.6
g 427cal/g 204
C) g)(1.5 10C)(70cal/g (0.83 3v
ppalc
ppvalc
palc
=°×°⋅=
∆=
∆=
=
hTms
m
Tmshm
One method of reducing a high body temperature very quickly is to give a patient an alcohol rub. How many grams of alcohol must be evaporated from the surface of 70 kg person to reduce his temperature by 1.5oC?
From table 5.3
From table 5.4
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Conduction : contact between substances
Rate of heat transfer between two substances in contact: d
TTkAtQ CH −=
k: coefficient of thermal conductivity
d
THTC
Area A
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Thermal conductivities of common substances
Thermal Conductivity (J/sec m oC)Silver 420Copper 380Aluminum 200Steel 40Ice 2.0Glass (average) 0.84Concrete, brick 0.84Human tissue without blood 0.2Wood 0.08-0.16Air 0.023
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Example 5.8
W120J/s 120m 0.01
C)33C)(37m C)(1.5mJ/s (0.2
)(
2
21
==
°−°°⋅⋅=
−=d
TTkAtQ
Calculate the rate of heat conduction out of a human body, making the following assumptions: the interior temperature is 37oC, skin temperature is 33oC, the area of the person is 1.5 m2, and the thickness of the tissues averages 1.0 cm.
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Convection : movement of molecules
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Radiation : Electromagnetic wave
4eATPtQ σ==
)TT(eA
PPP42
41
emitabsnet
−σ=
−=
The amount of heat radiated per unit time:
σ: 5.67x10-8 J/sec m2K4
A: area of the objecte: emissivity
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Example 5.9
115W]93K)2)[(306Km 5)(0.97)(1.KmJ/s 10(5.67
)(/44248
42
41
=⋅⋅×=
−=
-()
TTeAtQ-
σ
What is the heat transfer by radiation from an unclothed person standing in a dark room of temperature 20oC? The person’s skin temperature is 33oC, and the exposed area of his skin is 1.5 m2.
Note: assume the emissivity is 0.97 for human skin
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Heat and the Human Body
What are the body’s mechanisms for getting rid of excess heat?
Circulation of blood
Evaporation of perspiration from the skin
Evaporation of water from the lungs
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Example 5.10
inout
in
PPEffP
/W400
==
W32080WW400)2.0(
=−===
outinheat
out
PPPP
cal4587)J186.4/cal1)(s60)(s/J320(tPQt/QP heatheat ===⇒=
7.9g/gcal/580cal4587/ ===⇒= vv hQmmhQ
On a day when air temperature is 34oC (normal skin temperature) a cyclist is maintaining a speed of 15 km/hr. How many grams of water must this cyclist evaporate per minute?
Note: power consumption of cycling is 400 W with efficiency 20% (80% goes to heat)
heat of evaporation of water : 580 cal/gm
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Example 5.11
C4.4g)10C)(763cal/g0min)/(0.8cal/min)(64587(
sm/QTTsmQ3o
°=×=
=∆⇒∆=
How much will the temperature of the cyclist in Ex. 5.10 increase in one hour if none of the body heat generated is lost to the surroundings? Assume the cyclist’s mass is 76 kg and specific heat is 0.83 cal/goC
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Example 5.12
kW 6.3 W6300
person) (30 W/person)(210heat
===P
kcal 105.4cal105.4
min)person)(50 person](30/min)(kcal/0.3[
3
6
×=×=
=Q
(a) Calculate the power in waste heat put into a classroom by 30 students. (b) How many calories of energy do the students put into the room during a 50-min lecture?
Note: energy consumption rate by sitting in class=210W(or 3.0 kcal/min)
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Heat: Diagnostic and Therapeutic uses
Example:
Thermography