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Case study: analysis of 138/13.8 kV transformer differential misoperation points to faulty CT Morgan Smith –Enmax, Calgary, Canada JC Theron – Grid Solutions, Canada 2019 Texas A&MProtective Relaying Conference

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Page 1: Case study: analysis of 138/13.8 kV transformer …prorelay.tamu.edu/wp-content/uploads/sites/3/2019/03/...Case study: analysis of 138/13.8 kV transformer differential misoperationpoints

Case study: analysis of 138/13.8 kV transformer differential

misoperation points to faulty CT

Morgan Smith – Enmax, Calgary, Canada

JC Theron – Grid Solutions, Canada

2019 Texas A&M Protective Relaying Conference

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Agenda

• Introduction

• History of Transformer Percentage Differentia l

• Enhancements to Percentage Differentia l

• Harmonic Restra int (Blocking) of Percentage Differentia l

• Securing Percentage Differentia l using Directionality Check and CT Saturation

Detection

• Settings of Percentage Differentia l

• Analysis of 138/13.8 kV Transformer Differentia l Incorrect Operation

• Conclusion

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Introduction

• Transformer Protection Original fuses, la ter Overcurrent• Not very selective; Current/Time used for Coordination – Internal Faults NOT Instantaneous

• Transformer Protection Evolved, Schemes can include:

1. Percentage Differentia l2. Instantaneous/Unrestra int Differentia l3. Restricted Ground Fault4. Sudden Pressure (Buchholz)5. Oil/Winding Temperature6. Phase/Neutral/Ground/Neg Seq Inst &

Timed OC7. Phase/Neutral/Ground/Neg Seq Dir OC8. Breaker Fail

9. Phase and Ground Distance10. Volts per Hertz (Over Fluxing)11. Phase Under/Over Voltage12. Neutral/Neg Seq Overvoltage13. Tank Ground Fault14. Dissolved Gas in Oil (DGA)

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History of Transformer Percentage Differential

• First Transformer Differentia l was Overcurrent only

• External Faults • Internal Faults

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History of Transformer Percentage Differential

• First Transformer Differentia l with Restra int:

• Coils Connected

• Operating Characteristic

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Enhancements to Percentage Differential

• Percentage Differentia l Enhanced in IEDs for added Sensitivity:

• Two Regions of Percentage Differentia l

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Harmonic Restraint of Percentage Differential

• Percentage Differentia l still challenged during Transformer Energization

• Multiple event types can cause Inrush/Harmonics:1. External Fault 2. Voltage Recover after Ext Fault3. Fault Change eg. PG to PPG 4. Out-of-phase Gen Synch5. CT Saturation during Inrush 6. Inrush during Fault Removal7. Sympathetic Inrush

• Electromechanicals & early IEDs used fixed 20% of 2nd/fundamental magnitude to restra in (block) percentage differentia l

• Modern Transformers much lower 2nd harmonics (7-10%) – due to improvements

• Improvements to Harmonic Restra int:1. Adjustable levels of 2nd Harm 2. Account for 2nd Harm Phase Angle3. 1-of-3, 2-of-3, 3-of-3 Inhibit 4. 5th Harm Restra int added

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Securing Percentage Differential With Dir Chec

• Directionality Check of Current Phase Angles: (No Voltages Used)

BLOCK

OPERATE

BLOCK

− pD

p

III

real

− pD

p

III

imag

Ip

ID - Ip

External Fault Conditions

OPERATE

BLOCK

BLOCK

− pD

p

III

real

− pD

p

III

imag

Ip

ID - Ip

Internal Fault Conditions

OPERATE

OPERATE

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Securing Percentage Differential With CT Satur

• CTs provide typically 2-4 ms unsaturated current

• Fault starts a t t0, CT starts to saturate a t t1, fully saturated at t2

diffe

rent

ial

restrainingt0

t1

t2

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Settings of Percentage Differential• Electromechanical relays needed secondary currents to be same phase and

magnitude, hence Wye-winding CTs connected in Delta and Aux CTs needed

• All CTs on IEDs Wye-connected; magnitude and phase angle compensated numerically

• Compensated currents calculated based on Magnitude and Phase, eg. for 30deg lag:

• Differentia l current calculated as:

• Restraint can be: Sum of, scaled sum of, geometrical average, maximum of

• Most commonly used: “Max Of”

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Settings of Percentage Differential (2)• The Following Setting must be calculated:

• Minimum Pickup1. Defines Minimum Differentia l Pickup a t 0 Restra int2. Compensates for CT Errors a t low currents3. Must be above leakage current not zoned

• Low Slope1. Defines Percent Bias for Restra int A 0 to Low Breakpt2. Determines Sensitivity a t Low-current Int Faults3. Must be above CT errors in Linear Operating Mode4. Include errors due to Tap Changers5. Based on CT performance in Linear Operating mode:

• Maximum Differentia l Current can be calculated based on CT Performance using IEEE PSRC CT Saturation Calculator

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Settings of Percentage Differential (3)• Low Breakpoint

1. Defines Upper Limit of Diff/Restra int of Low Slope2. Must be above Max Load and a ll CTs still Linear

(including Remanence Flux)3. CTs Must be Linear with up to 80% Remanence Flux

up to Low Breakpoint

• High Breakpoint1. Defines Min Limit of Diff/Restra int of High Slope2. Must be Minimum A where weakest CT Saturates with

no Remanence Flux

• High Slope1. Defines Percent Bias for Restra int A above High

Breakpoint2. Determines Stability of Diff a t High External Faults3. Must be high to tolera te Spurious Diff CT Sat on Ext F4. Can be relaxed if Dir Check and CT Sat Detect used

• Maximum Differentia l Current can be calculated based on CT Performance using IEEE PSRC CT Saturation Calculator

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Settings of Percentage Differential (4)• CT Saturation Calculator

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Analysis of 138/13.8kV Trfr Diff Incorrect Operation

• Percentage differentia l operated incorrectly during an external AG fault on the 13.8kV side of the 30MVA, 138kV/13.8kV Dy-1 transformer.

• Differentia l operation happened in phase C, 140ms into the fault when external fault was cleared and restra int became smaller than differentia l.

• Other transformer protection relays (OC and B-Protection) did not operate.

• Both windings waveforms looked perfect , however differentia l current built very rapidly.

• No CT saturation observed

• Directional Check and CT Saturation Detection NOT used

• Why did it happened and what may be wrong?

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Introduction

138kV

13.8kV

Iad=Ibd=0, Icd=0.472pu ???

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Introduction

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Investigation• Setting error?

Doesn’t look like…

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Investigation• Relay algorithm error?

Phase Pre-fault FaultDelta 138kV Wye 13.8kV Delta 138kV Wye 13.8kV

A 0.600A∠-241.9° 1.222A∠-91.8° 3.309A∠-306.6° 12.045A∠-133.6°B 0.603A∠0° 1.157A∠-212.1° 0.769A∠-0° 1.445A∠-192.6°C 0.572A∠-116.5° 1.234A∠-332.7° 3.866A∠-118.9° 1.265A∠-347.8°

We can verify relay response to these phasors. For given transformer group D/Yg-1, compensation currents are calculated:

Delta Wye-grounded

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Investigation• Relay algorithm error?

𝐼𝐼𝑑𝑑 = 𝑚𝑚1 �𝐼𝐼𝐼𝐼1𝑐𝑐𝐼𝐼𝐼𝐼1𝑐𝑐𝐼𝐼𝐼𝐼1𝑐𝑐

+ 𝑚𝑚2 �𝐼𝐼𝐼𝐼2𝑐𝑐𝐼𝐼𝐼𝐼2𝑐𝑐𝐼𝐼𝐼𝐼2𝑐𝑐

𝑚𝑚1 = 2 and 𝑚𝑚2 = 1 are magnitude compensation factors for each winding

For phase C, where high differentia l current was observed. Pre-fault:

𝐼𝐼𝐼𝐼𝑑𝑑 = 2 � 𝐼𝐼𝐼𝐼1 + 1 � 𝐼𝐼𝐼𝐼2−1

3+ 𝐼𝐼𝐼𝐼2

13

= 2 � 0.572𝑒𝑒−𝑗𝑗11𝑗.5° + 1 � 1.222𝑒𝑒−𝑗𝑗𝑗1.8° �−1

3+ 1.234𝑒𝑒−𝑗𝑗𝑗𝑗2.7° �

13

= 0.14𝐼𝐼 𝑜𝑜𝑜𝑜 0.029𝑝𝑝𝑝𝑝

𝐼𝐼𝐼𝐼𝑑𝑑 = 2 � 𝐼𝐼𝐼𝐼1 + 1 � 𝐼𝐼𝐼𝐼2−1

3+ 𝐼𝐼𝐼𝐼2

13

= 2 � 3.866𝑒𝑒−𝑗𝑗118.𝑗° + 1 � 12.045𝑒𝑒−𝑗𝑗1𝑗𝑗.𝑗° �−1

3+ 1.265𝑒𝑒−𝑗𝑗𝑗𝑗7.8° �

13

= 2.374𝐼𝐼 𝑜𝑜𝑜𝑜 0.476𝑝𝑝𝑝𝑝

Fault:

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Investigation• Time out! Time to think where we are…

𝐼𝐼𝑑𝑑 = 𝑚𝑚1 �1 0 00 1 00 0 1

�𝐼𝐼𝐼𝐼1𝐼𝐼𝐼𝐼1𝐼𝐼𝐼𝐼1

+ 𝑚𝑚2 �

1𝑗

−1𝑗

0

0 1𝑗

−1𝑗

−1𝑗

0 1𝑗

�𝐼𝐼𝐼𝐼2𝐼𝐼𝐼𝐼2𝐼𝐼𝐼𝐼2

= 0.02𝑝𝑝𝑝𝑝

0.006𝑝𝑝𝑝𝑝0.475𝑝𝑝𝑝𝑝

• Settings seems correct

• Waveforms look credible (No CT saturation)

• Differentia l current relay calculated from waveforms and settings seems correct as well.

• Let’s dig in… something must be wrong!

• Only Differentia l phase C is high, out of 6 currents, incorrect 𝐼𝐼𝐼𝐼1 only from deltaside can cause high phase C differentia l without affecting other phases.

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Investigation• Can we prove that delta side 𝐼𝐼𝐼𝐼1 is erroneous?

• We know that for unloaded transformer (ignoring magnetizing current), delta currents should be 180° apart for P-G fault on Wye.

• If we remove load current and rotate delta side phase A current by 180°, we should get “correct” phase C current .

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Investigation

𝐼𝐼𝐼𝐼1′ = (𝐼𝐼𝐼𝐼1𝐹𝐹 − 𝐼𝐼𝐼𝐼1𝐿𝐿) � 1𝑒𝑒𝑗𝑗180° + 𝐼𝐼𝐼𝐼1𝐿𝐿= (3.309𝑒𝑒−𝑗𝑗𝑗0𝑗.𝑗° − 0.6𝑒𝑒−𝑗𝑗2𝑗1.𝑗°) � 1𝑒𝑒𝑗𝑗180° +0.572𝑒𝑒−𝑗𝑗11𝑗.5°=3.643𝑒𝑒−𝑗𝑗1𝑗𝑗.𝑗°

𝐼𝐼𝐼𝐼1𝐿𝐿 is highlighted because as we suspect CT or CT wiring problem, we cannot 100% trust even pre-fault value.

𝐼𝐼𝐼𝐼𝑑𝑑 = 2 � 𝐼𝐼𝐼𝐼1 + 1 � 𝐼𝐼𝐼𝐼2−1

3+ 𝐼𝐼𝐼𝐼2

13

= 2 � 3.643𝑒𝑒−𝑗𝑗1𝑗𝑗.𝑗° + 1 � 12.045𝑒𝑒−𝑗𝑗1𝑗𝑗.𝑗° �−1

3+ 1.265𝑒𝑒−𝑗𝑗𝑗𝑗7.8° �

13

= 0.496𝐼𝐼 𝑜𝑜𝑜𝑜 0.099𝑝𝑝𝑝𝑝

Again differentia l calculation with assumed delta phase C current fault value

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Investigation• We proved that differentia l reduced from 0.476pu to 0.099pu by using assumed

IC current derived from healthy IA current .

• Differentia l is not reduced to zero, because we still use untrusted IC pre-fault value and ignore magnetizing current .

• Now we have reasonable confidence that CT or CT wiring of the C phase is faulty

• CT Testing will reveal will reveal the truth!!!

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Testing

Phase A testPhase B testPhase C test

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Conclusions• Percentage Differentia l is fast , dependable and secure; forms important part of

Transformer Protection Scheme

• This function was enhanced with added sensitivity (changes to characteristic) and security (CT saturation detection and Directionality check)

• When investigating suspicious relay operation, don’t take anything for granted; consider settings errors, wiring errors, instrument transformers errors and relay h/w or s/w issues.

• Use analytical skills, literature, s/w analytical programs to identify possible causes and prove these possible causes right or wrong.

• Consult with colleagues, equipment manufacturers and Industry Experts.

• Don’t rush to blame the relay h/w or s/w, as we learnt from this case, even unlikely, but CT failure can happen as well.

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Thank You

Questions?