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Part 1 (iii)

Frontal Length = 50 m = Pad foundationBuilding depth = 25 m

Therefore, use grid spacing of 5 m

= Typical pad foundColumn spacing = 5 m

Beam Span = 5 m = Area of influence p

Floor loading = 3 kN/m2

Area of influence = 6.25 m2 (2.5m x 2.5m)

Load of column / floor = 18.75 kN

No. of floors = 4

Load on foundation = 75 kN

* Note that I am only taking into consideration a basic floor load of 3kN/m2 here, whereas in reality other loads such as slab weight and s

25 m

Part 2 (i) (this is a brief overview of the load path - you should perhaps include a visual sketch of this load path and a short descriptio

Wind

Roof cladding

Purlins / Rafters

Roof truss structure

Columns / Beams of ste

Bracing / Gable posts

Wind Cladding / Brickwork

(walls)

Part 2(ii)

Calculation of Basic wind pressure

kb = 1

Eaves Height = 12

Roof Height = 4.55 m

Total height = 16.5 m

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Cr = 0.02

vb = 23.8 m/s

Sa = 1 (assumed topography is not significant)

Sd = 1 (orientation unkown)

Ss = 1

Sp = 1

vs = 23.8 m/s

Hr = 16.5 m (max. height as a conservative value)

Sb = 1.82

Ve = 43.3 m/s

DYNAMIC PRESSURE, qs = 1150 Pa

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tion loading

er floor on pad foundation

ad weight of steel alongside live loads would come into play

50 m

n - I just dont have the time lad)

el frame

Foundation