c09–c–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. the side slopes are...

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* * * C09–C–404 3425 BOARD DIPLOMA EXAMINATION, (C–09) OCT/NOV—2017 DCE—FOURTH SEMESTER EXAMINATION QUANTITY SURVEYING Time : 3 hours ] [ Total Marks : 80 PART—A 3×10=30 Instructions : (1) Answer all questions. (2) Each question carries three marks. (3) Answers should be brief and straight to the point and shall not exceed five simple sentences. 1. List any four duties of quantity surveyor. 2. Prepare an approximate estimate of a hospital building for 50 beds. The cost of the construction altogether for each bed is R 60,000. Determine the total cost of the hospital building. 3. The plan of compound wall is shown in the figure below. Calculate its centre line length : /3425 1 [ Contd... * 3425 * www.ManaResults.co.in

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Page 1: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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C09–C–404

3425BOARD DIPLOMA EXAMINATION, (C–09)

OCT/NOV—2017

DCE—FOURTH SEMESTER EXAMINATION

QUANTITY SURVEYING

Time : 3 hours ] [ Total Marks : 80

PART—A 3×10=30

Instructions : (1) Answer all questions.

(2) Each question carries three marks.

(3) Answers should be brief and straight to the point and

shall not exceed five simple sentences.

1. List any four duties of quantity surveyor.

2. Prepare an approximate estimate of a hospital building for 50 beds.

The cost of the construction altogether for each bed is R 60,000.

Determine the total cost of the hospital building.

3. The plan of compound wall is shown in the figure below. Calculate

its centre line length :

/3425 1 [ Contd...

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Page 2: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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4. Calculate the length of common rafter and number of common

rafters spaces at 0·5 m c/c of the hipped roof shown below :

Room size = 6·0 m×4·0 m

Wall thickness = 300 mm

Slope of roof = 13 of span

Eaves projection = 500 mm

5. Find the cost of materials at site for the following :

Sl.

No.

Materials Rate at source

(in R)

Leads

(in km)

Conveyance

charges (in R)

1 20 mm size HBG metal

450·00/m3 30 9·0 per cum/km

2 Cement 3400/1 tonne 8 80/1 tonne/km

6. From the following figure calculate the quantity of distribution steel

6 mm f @ 190 mm c/c required for bottom mat :

Top cover (clear) = 25 mm

Side clear cover = 25 mm

Bottom cover (clear) = 15 mm

6 mm dia bars 0·22 kg/m

/3425 2 [ Contd...

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Page 3: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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7. Find the volume of the earthwork in an embankment of length

100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are

1(1/2) : 1.

8. The cross-section of a circular dispersion trench 1·5 m dia is

shown in the figure below. Calculate the quantity of—

(a) brick bats;

(b) RCC cover.

9. Write a short note on book value.

10. The cost of a building including cost of land is R 1,00,000. The

owner expects 10% return. If the expenditure on all outgoings

including sinking fund is R 5,000. Find the gross rent of property

per month.

/3425 3 [ Contd...

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Page 4: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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PART—B 10×5=50

Instructions : (1) Answer any five questions.

(2) Each question carries ten marks.

(3) Answers should be comprehensive and the criterion

for valuation is the content but not the length of the

answer.

11. Prepare the detailed estimate for the following items of work for the

residential building shown in the figure below :

(1) CC (1 : 5 : 10) for foundation bed

(2) Brick masonry for super structure walls without deduction

(3) RCC 1 2 4: : for roof slab

/3425 4 [ Contd...

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Page 5: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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12. From the following drawing, calculate the quantities for the

following items of the work :

(a) Earthwork excavation for foundation

(b) Brick masonry in CM ( : )1 6 for superstructure wall without

deductions

(c) Plastering to ceiling with CM ( : )1 3

13. Prepare the data sheet and find the cost of the following items of

works :

(1) Cement concrete 1 4 8: : of foundation using 40 mm broken

stone, unit—1 m3

(2) Plastering with CM 1 4: —12 mm, thick unit—10 2m

(a) Quantities for CC 1 4 8: : for 1 3m

0·92 m3 40 mm size broken stone0·46 cum Sand

0·115 m3 Cement

0·2 Nos. Mason

1·80 Nos. Man mazdoor

1·40 Nos. Women mazdoor

LS Sundries

/3425 5 [ Contd...

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Page 6: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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(b) Quantities for plastering with CM ( : )1 4—12 mm, thick—10 m2

0·15 cum CM ( : )1 4

1·1 Nos. Brick layer

0·5 Nos. Man mazdoor

1·1 Nos. Women mazdoor

LS Sundries

Lead statement :

Sl.

No.

Materials Rate at source

(in R)

Leads

(in km)

Conveyance

charges (in R)

1 40 mm size broken stone

400·0 one 1 3m 12 km

MT3·00/1 3m /km

2 Sand 95·00 per 1 3m 35 km

MT3·00/1 3m /km

3 Cement 2400·00 per

10 kN or 1 tonne

At site

Labour charges :

Mason or brick layer R 300/day Men and women mazdoors R 180/day Mixing charges R 27·50/cum

14. Prepare the data sheet and calculate the cost of the items given

below, using the lead statement of materials.

(a) Cement concrete 1 3 6: : using 40 mm HBG metal, unit—1 cum

0·92 m3 40 mm HBG metal— Sand— Cement0·06 Nos. Mason 1st class0·14 Nos. Mason 2nd class1·80 Nos. Men mazdoor1·40 Nos. Women mazdoorLS Sundries

(b) RR Masonry in CM ( : )1 6 unit—1 cum

1·10 cum Rough stone0·34 cum CM ( : )1 60·54 Nos. Masons 1st class1·26 Nos. Masons 2nd class1·40 Nos. Man mazdoors1·40 Nos. Women mazdoorsLS Sundries

/3425 6 [ Contd...

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Page 7: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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Lead statement of materials :

Sl.

No.

Materials Rate at source

(in R)

Leads

(in km)

Conveyance

charges (in R)

1 40 mm HBGmetal

300 per m3 10 km 15/m3

2 Sand 75 per m3 20 km 10/m3

3 Cement 1800 per tonne — At site

4 Rough stone 250 per m3 8 km 12/m3

Labour :

(a) Mason 1st class R 250/each/day

(b) Mason 2nd class R 240/each/day

(c) Men mazdoors R 230/each/day

(d) Women mazdoors R 225/each/day

(e) Mixing charges of CM R 40/cum

15. For an embankment 60 m long having uniform gradient with the

height of bank 3·0 m at one end and 1·8 m at the other end. The

width of embankment at top is 6 m and its side slopes are 2 1: .

Estimate the quantity of earthwork by—

(a) prismoidal rule;

(b) mid sectional method;

(c) mean sectional method.

The longitudinal and transverse gradient of the ground is nil.

16. Calculate the quantities for the following items of work for an open

well shown in the figure below :

(a) Refilling with excavated earth around the well staining

/3425 7 [ Contd...

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Page 8: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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(b) Laterite rough stone dry packing for well staining.

17. Calculate the quantities for the following item of a work for a slab

culvert shown in the figure below.

(a) CC ( : : )1 4 8 for abutment and wing walls

(b) Brick masonry in CM ( : )1 4 for abutment and wing walls up to

bottom deck slab

/3425 8 [ Contd...

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Page 9: C09–C–404 * 3425 * 3425 · 100·0 m, top width 7·0 m and depth 3·5 m. The side slopes are 1(1/2) : 1. 8. The cross-section of a circular dispersion trench 1·5 m dia is shown

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(c) RCC for deck slab

18. Residential building constructed 12 years ago is situated on a plot

whose total area is 400 m2. The plinth area of the building is

240 m2. The present cost of construction of the building is

R 1,30,000 and the cost of the land is R180/m2. The rate of

depreciation for the value of the building is 1%. Calculate the total

value of the property.

H H H

/3425 9 AA7(A)—PDF

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