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  • 8/18/2019 Brace Sb4 Best

    1/2

    Designer :Project Name :

    Best & effective Solution of Structural Technology. BeST Ver 2.6

    BeST MEMBER :Date : Page :

    http://www.BestUser.com

    BRACE-SB4

    Kwai Vii Cee  75

    150

            1        5        0

            1        5

    15x

    y

      Unit : cm

    As  = 42.74

    Ix  = 888 Iy  = 888

    Zx  = 153 Zy  = 153

    J = 32 Cw  = 543

    Design Conditions

    Design Code : AISC-2005(LRFD)Section Size : ㄴ-150x15

    Steel Material Fy = 248 N/mm2 (A36)

    Unbraced Lengths Lx = 3.13, Ly = 3.13 m

      Lb = 3.13 m

    EffectiveLengthFact. Kx = 1.00, Ky = 1.00

    Modification Factor Cb = 1.00

     Design Force and Moment

     Pu  = 21.7 kN

     Mux  = 0.4, Muy  = 0.4 kN·m

     Vux  = 0.0, Vuy  = 0.1 kN

    Check Axial Strength

    Check Slenderness Ratio  -. L/rx = 68.60

      -. KL/r = 72 + 0.75L/rx  = 123.45

      -. KL/r = 123.45 < 200.00 ---> O.K.

    Check Width-Thickness Ratio  -. bf/tf  = 10.00 < 0.45 E/Fy   = 12.77 ---> Non-Slender Section

    Flexural Buckling Stress

      -. Fe  =π2E

    (KL/r)2  = 129.53 N/mm2

      -. Fcr,FBS  = [0.658FyFe ]Fy  = 111.30 N/mm2

      -. Fcr,TBS  = Not Apply

    Compute Axial Compressive Strength  -. Fcr  = Min[Fcr,FBS, Fcr,TBS] = 111.30 N/mm2

      -. ΦPn  = Φ*As*Fcr  = 428.13 kN

    Check Thickness Ratios for Flexure

    Check Legs of Angle  -. λ

    p  = 0.54 E/F

    y  = 15.33

      -. λr  = 0.91 E/Fy   = 25.83

      -. b/t = 10.00 < λp  ---> Compact Section

    Check Flexural Strength of Angle

      -. My  = 0.8*Fy*Sx  = 16.40 kN·m

      -. Mn,Y  = 1.5*My  = 24.60 kN·m

    Compute Lateral-Torsional Buckling

      -. Me  =0.66Eb4tCb  L2

    ( 1+0.78(Lt/b2)2 -1) = 112.25 kN·m

      -. Mn,LTB  = (1.92-1.17MyMe   )My  = 24.16 kN·m

  • 8/18/2019 Brace Sb4 Best

    2/2

    Designer :Project Name :

    Best & effective Solution of Structural Technology. BeST Ver 2.6

    BeST MEMBER :Date : Page :

    http://www.BestUser.com

    BRACE-SB4

    Kwai Vii Cee  75

    Compute Leg Local Buckling  -. Mn,FLB  = Not Apply

      -. ΦMnx,ΦMny  = Φ*Mn  = 21.74 kN·m

    Check Interaction of Combined Strength

      -. Ratio =Pu

    ΦPn+ MuxΦMnx

    + MuyΦMny

      = 0.087 < 1.000 ---> O.K.

    Check Shear Strength

    Check Shear Strength in Local-y Direction  -. Cv  = 1.00

    -. Vn  = 0.6*Fy*Aw*Cv  = 335.09 kN

      -. ΦVny  = Φ*Vn  = 301.58 kN

      -. Vuy/ΦVny  = 0.000 < 1.000 ---> O.K.