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8/18/2019 Brace Sb4 Best
1/2
Designer :Project Name :
Best & effective Solution of Structural Technology. BeST Ver 2.6
BeST MEMBER :Date : Page :
http://www.BestUser.com
BRACE-SB4
Kwai Vii Cee 75
150
1 5 0
1 5
15x
y
Unit : cm
As = 42.74
Ix = 888 Iy = 888
Zx = 153 Zy = 153
J = 32 Cw = 543
Design Conditions
Design Code : AISC-2005(LRFD)Section Size : ㄴ-150x15
Steel Material Fy = 248 N/mm2 (A36)
Unbraced Lengths Lx = 3.13, Ly = 3.13 m
Lb = 3.13 m
EffectiveLengthFact. Kx = 1.00, Ky = 1.00
Modification Factor Cb = 1.00
Design Force and Moment
Pu = 21.7 kN
Mux = 0.4, Muy = 0.4 kN·m
Vux = 0.0, Vuy = 0.1 kN
Check Axial Strength
Check Slenderness Ratio -. L/rx = 68.60
-. KL/r = 72 + 0.75L/rx = 123.45
-. KL/r = 123.45 < 200.00 ---> O.K.
Check Width-Thickness Ratio -. bf/tf = 10.00 < 0.45 E/Fy = 12.77 ---> Non-Slender Section
Flexural Buckling Stress
-. Fe =π2E
(KL/r)2 = 129.53 N/mm2
-. Fcr,FBS = [0.658FyFe ]Fy = 111.30 N/mm2
-. Fcr,TBS = Not Apply
Compute Axial Compressive Strength -. Fcr = Min[Fcr,FBS, Fcr,TBS] = 111.30 N/mm2
-. ΦPn = Φ*As*Fcr = 428.13 kN
Check Thickness Ratios for Flexure
Check Legs of Angle -. λ
p = 0.54 E/F
y = 15.33
-. λr = 0.91 E/Fy = 25.83
-. b/t = 10.00 < λp ---> Compact Section
Check Flexural Strength of Angle
-. My = 0.8*Fy*Sx = 16.40 kN·m
-. Mn,Y = 1.5*My = 24.60 kN·m
Compute Lateral-Torsional Buckling
-. Me =0.66Eb4tCb L2
( 1+0.78(Lt/b2)2 -1) = 112.25 kN·m
-. Mn,LTB = (1.92-1.17MyMe )My = 24.16 kN·m
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8/18/2019 Brace Sb4 Best
2/2
Designer :Project Name :
Best & effective Solution of Structural Technology. BeST Ver 2.6
BeST MEMBER :Date : Page :
http://www.BestUser.com
BRACE-SB4
Kwai Vii Cee 75
Compute Leg Local Buckling -. Mn,FLB = Not Apply
-. ΦMnx,ΦMny = Φ*Mn = 21.74 kN·m
Check Interaction of Combined Strength
-. Ratio =Pu
ΦPn+ MuxΦMnx
+ MuyΦMny
= 0.087 < 1.000 ---> O.K.
Check Shear Strength
Check Shear Strength in Local-y Direction -. Cv = 1.00
-. Vn = 0.6*Fy*Aw*Cv = 335.09 kN
-. ΦVny = Φ*Vn = 301.58 kN
-. Vuy/ΦVny = 0.000 < 1.000 ---> O.K.