bdm lecture 8
TRANSCRIPT
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The formula
You may need to sit down for this!
WARNING
= { (x - ) 2/ n}
This is the symbol forthe standard deviation
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BPS - 5th Ed. Chapter 2 2
Standard eiation "ormulatypical deviation from the mean
# standard deiation $ s%uare root of thearian&e '
sn
x xi
i
n
=
=1 1
2
1( )( )
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(arian&e and Standardeiation) E*ample
+eta,oli& rates of men &al./20hr.1
342 3 362 330 307 383064
16007
200,11
7
1439186714601614136216661792
=
=
++++++=x
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(arian&e and Standardeiation
E*ample from Te*tObservations Deviations Squared deviations
1792 17921600 = 192 (192)2= 36,864
1666 1666
1600 = 66 (66)
2
= 4,3561362 1362 1600 = 238 (238)2= 56,644
1614 1614 1600 = 14 (14)2= 196
1460 1460 1600 = 140 (140)2= 19,600
1867 18671600 = 267 (267)
2
= 71,2891439 1439 1600 = 161 (161)2= 25,921
su! = 0 su! = 214,870
xxi
ix ( ) 2xx
i
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67.811,35
17
870,2142=
=s
calories24.18967.811,35 ==s
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Semi-wor9ed e*ample" :e are ;oin; to try and
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To calculate the standard deviation weconstruct a table like this one:
(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
There should be enouh s!a"e
here to fit in the number ofvalues# $% there are &'
tem!eratures so leave &' lines#
x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
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x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
To calculate the standard deviation we construct atable like this one:
(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
ext e rite the values (tem!eratures) in"olumn x (they "an be in any order)#
593279822
3
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(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
*dd them u! (x)
5932798223
+al"ulate the mean (1
50!0 = 550
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(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
5932798223
50!0 = 550
next
,,,,,,,,,
,
rite the mean tem!erature ( ) inevery ro in the se"ond "olumn#
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(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
5932798223
50!0 = 550
now
,,,,,,,,,,
.ubtra"t ea"h value (tem!erature) from the mean# tdoes not matter if you obtain a neative number#
'0-2-1201-1-1
-2
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(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
5932798223
50!0 = 550
and
then
,,,,,,,,,,
'0-2-1201-1-1
-2
.uare (2) all of the fiures you obtained in"olumn 1 to et rid of the neative numbers#
'&3040&3444
0
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(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
5932798223
50!0 = 550
then
,,,,,,,,,,
'0-2-1201-1-1-2
'&3040&34440
*dd u! all of the fiures that you"al"ulated in "olumn 0 to et (x - ) 2#
80
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(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
5932798223
50!0 = 550
and
,,,,,,,,,,
'0-2-1201-1-1-2
'&3040&34440
80
5ivide (x - ) 2by the total number ofvalues (in this "ase &' 6 eather stations)
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(x - ) 2
(x - ) 2=(x - ) 2/n =(x - ) 2/n =
(x - )x
=* $ $ =*/n $
x = temperature --- = mean temperature --- = square root = total of --- 2= squared --- n = number of values
5932798223
50!0 = 550
finally
,,,,,,,,,,
'0-2-1201-1-1-2
'&3040&34440
80
Ta7e the suare root () of the fiure to obtain thestandard deviation# (8ound your anser to the nearestde"imal !la"e)
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>nswer
2"8#$