balancing equations

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Balancing Equations

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Balancing Equations. Law of Conservation of Mass. The Law of Conservation of Mass states: that mass is neither created nor destroyed in any chemical reaction . Therefore balancing equations requires the same number of atoms on both sides of a chemical reaction. - PowerPoint PPT Presentation

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Page 1: Balancing Equations

Balancing Equations

Page 2: Balancing Equations

Law of Conservation of Mass

The Law of Conservation of Mass states: that mass is neither created nor destroyed in any chemical reaction. Therefore balancing equations requires the same number of atoms on both sides of a chemical reaction.

The number of atoms in the Reactants must equal the Number of atoms in the Products

Page 3: Balancing Equations

Balance elements in the following order:

1. Nonmetals2. Metals3. Polyatomic ions4. Hydrogen5. Oxygen

Page 4: Balancing Equations

Polyatomic Ions

When balancing polyatomic ions treat them as one unit if they appear on both sides of the equation.

Page 5: Balancing Equations

Balancing Equations

Complete an atom inventory.

N2 + H2 NH3

__N____H__

2 1

2 3

Page 6: Balancing Equations

Balancing Equations

Nothing is balanced.Balance the nitrogen first by placing a coefficient of 2 in front of the NH3.

N2 + H2 2NH3

Page 7: Balancing Equations

Balancing Equations

Hydrogen is not balanced.Place a 3 in front of H2.

N2 + 3H2 2NH3Complete a final atom inventory.

__N____H__

2 2

6 6

Page 8: Balancing Equations

Balancing Equations

Complete an atom inventory.

C3H8 + O2→ CO2+ H2O

__C____H____O__

3 1

8 2

2 3

Page 9: Balancing Equations

Balancing Equations

Nothing is balanced.Balance the carbon first by placing a coefficient of 3 in front of the CO2.

C3H8 + O2 → 3CO2+ H2O

Page 10: Balancing Equations

Balancing Equations

Now balance the hydrogen by placing a 4 in front of the water on the products side.

C3H8 + O2 → 3CO2+ 4H2O

Page 11: Balancing Equations

Balancing EquationsBalance the oxygen on the reactants side with a coefficient of 5.C3H8 + 5O2 → 3CO2+

4H2OComplete a final atom inventory.

__C____H____O__

3 38 8

10 10

Page 12: Balancing Equations

Balancing Equations

Complete an atom inventory.

BF3+ Li2SO3→ B2(SO3)3+ LiF

__B__ __F__ __Li____SO3__

1 2 3 1

2 11

3

Page 13: Balancing Equations

Balancing Equations

Nothing is balanced.Balance the fluorine first by placing a coefficient of 3 in front of the LiF.

BF3+ Li2SO3→ B2(SO3)3+ 3LiF

Page 14: Balancing Equations

Balancing Equations

Now balance the boron by placing a 2 in front of the BF3 on the reactants side.

2BF3+ Li2SO3→ B2(SO3)3+

3LiF Notice we’ve unbalanced the fluorine, and now must adjust our coefficients.

Page 15: Balancing Equations

Balancing Equations

Now balance the boron by placing a 2 in front of the BF3 on the reactants side.

2BF3+ Li2SO3→ B2(SO3)3+

6LiF Notice we’ve unbalanced the fluorine, and now must adjust our coefficients.

Page 16: Balancing Equations

Balancing EquationsBalance the lithium sulfite on the reactants side with a coefficient of 3.

Complete a final atom inventory.2BF3+ 3Li2SO3→ B2(SO3)3+ 6LiF

2 2 6 6

6 6 3

3

__B__ __F__ __Li____SO3__

Page 17: Balancing Equations

YOU ARE BALANCED!!