balancing chemical equations

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Balancing Chemical Equations

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Balancing Chemical Equations

Chemical Equations

• The chemical reactions are represented by Chemical Equations.

• It has two parts :

1. Reactants (Left hand side)

2. Products (Right hand side)

Balancing Chemical Equations

• A chemical equation needs to be balanced in order to obey the “Law of Conservation of Energy”.

• Law of Conservation of Energy states that matter can never be created, nor destroyed.

• Hence, we balance equations by adding coeffiecients in front of reactants and products.

How to Balance Chemical Equation?

Step 1 : Write the Formula for the equation.

Step 2 : Compare the number of atoms in left side with the right side.

Step 3 : Analyse where to place the coefficients, so as to make left and right side equal.

Step 4 : Verify finally, if all the atoms in left and right side are equal.

Rules

• Only the coefficients should be changed.

• Subscripts should not be changed. Changing it will change the compound.

• The coefficients should be whole numbers

• The lowest possible whole number should be used as coefficients.

Example 1

Consider an equation,

H2

+ O2 = H

2O

LHS H = 2, O = 2,

RHS H = 2, O = 1

H

H

O

O

H H

O

HH

BalancingIn order to balance, we now add 2 to the RHS, making it as 2H2O, Now, equatin becomes as

H2

+ O2 = 2H

2O

LHS, H = 2, O =2

RHS, H= 4, O= 2

H

H

O

O

OH H

O

H H

O

BalancingH is not equal , hence add 2 to the H of LHS, forming

2H2

+ O2 = 2H

2O

HH

O

O

OH H

O

H H

OH H

Example 2 Ba3N2 + H2O → Ba(OH)2 + NH3

LHS RHS

B a = 3 Ba = 1

N = 2 N = 1

H = 2 H = 5

O = 1 O = 2

Step 1 : Adding 3 to Ba in RHS, we have

Ba3N

2 + H

2O → 3Ba(OH)

2 + NH

3

LHS RHS

Ba = 3 Ba = 3

N = 2 N = 1

H = 2 H = 9

O = 1 O = 6

Step 2 : Adding 2 to N in RHS, we have

Ba3N

2 + H

2O → 3Ba(OH)

2 + 2NH

3

LHS RHS

Ba = 3 Ba = 3

N = 2 N = 2

H = 2 H = 12

O = 1 O = 6

Step 3 : Adding 6 to H2O in RHS, we have

Ba3N

2 + 6H

2O → 3Ba(OH)

2 + 2NH

3

LHS RHS

Ba = 3 Ba = 3

N = 2 N = 2

H = 12 H = 12

O = 6 O = 6

Hence, it is balanced.

Click the compounds you want from the

table and click calclate, you will yield the

balanced equation from the

chemicalequation balancer. https://www.easycalculation.com/chemistry/balancing-equations.php