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Background. The Physics Knowledge Expected for this Course: Newton’s Laws of Motion the “ Theme of the Course ” Energy & momentum conservation Elementary E&M The Math Knowledge Expected for this Course: Differential & integral calculus Differential equations - PowerPoint PPT PresentationTRANSCRIPT
Background• The Physics Knowledge Expected for this Course:
Newton’s Laws of Motion the “Theme of the Course”
– Energy & momentum conservation– Elementary E&M
• The Math Knowledge Expected for this Course:– Differential & integral calculus– Differential equations– Vector calculus– See the Math Review in Chapter 1!!
Math ReviewCh. 1: Matrices, Vectors, & Vector Calculus
• Definition of a Scalar: Consider an array of particles in 2 dimensions, as in Figure a. The particle masses are labeled by their x & y coordinates as
M(x,y)
• If we rotate the coordinate axes, as in Figure b, we find
M(x,y) M(x,y) That is, the masses are obviously unchanged by a rotation of
coordinate axes. So, the masses are Scalars!• Scalar Any quantity which is invariant under a
coordinate transformation.
Coordinate TransformationsSect. 1.3
• Arbitrary point P in 3d space, labeled with Cartesian coordinates (x1,x2,x3). Rotate axes to (x1,x2,x3). Figure has 2d Illustration
• Easy to show that (2d): x1 = x1cosθ + x2sin θ x2 = -x1sin θ + x2cos θ = x1cos(θ + π/2) + x2cosθ
Direction Cosines• Notation: Angle between xi axis & xj axis (xi,xj)• Define the Direction Cosine of the xi axis with respect to the xj axis:
λij cos(xi,xj)• For 2d case (figure):
x1 = x1cosθ + x2sinθx2 = -x1sinθ + x2cosθ = x1cos(θ +π/2) + x2cosθ
λ11 cos(x1,x1) = cosθ λ12 cos(x1,x2) = cos(θ - π/2) = sinθ
λ21 cos(x2,x1) = cos(θ + π/2) = -sinθλ22 cos(x2,x2) = cosθ
• So: Rewrite 2d coordinate rotation relations in terms of direction cosines as:x1 = λ11 x1 + λ12 x2 x2 = λ21 x1 + λ22 x2 Or: xi = ∑j λij xj (i,j = 1,2)
• Generalize to general rotation of axes in 3d: • Angle between the xi axis & the xj axis (xi,xj).
Direction Cosine of xi axis with respect to xj axis: λij cos(xi,xj) Gives:
x1 = λ11x1 + λ12x2 + λ13x3 ; x2 = λ21x1+ λ22x2 + λ23x3 x3 = λ31x1 + λ32x2 + λ33x3
• Or: xi = ∑j λijxj (i,j = 1,2,3)
• Arrange direction cosines into a square matrix: λ11 λ12 λ13
λ = λ21 λ22 λ23
λ31 λ32 λ33
• Coordinate axes as column vectors: x1 x1
x = x2 x = x2 x3 x2
• Coordinate transformation relation: x = λ xλ Transformation matrix or rotation matrix
Example 1.1
Work this example
in detail!
Rotation Matrices Sect. 1.4• Consider a line segment, as in Fig. Angles between line & x1, x2, x3 α,β,γ
• Direction cosines of line cosα, cosβ, cosγ• Trig manipulation (See Prob. 1-2) gives:
cos2α + cos2β + cos2γ = 1 (a)
• Also, consider 2 line segments
direction cosines: cosα, cosβ, cosγ, & cosα, cosβ, cosγ• Angle θ between
the lines:
• Trig manipulation (Prob. 1-2) gives:cosθ = cosα cosα +cosβcosβ +cosγcosγ (b)
Arbitrary Rotations• Consider an arbitrary rotation from axes
(x1,x2,x3) to (x1,x2,x3). • Describe by giving the direction cosines of all angles between
original axes (x1,x2,x3) & final axes (x1,x2,x3). 9 direction cosines: λij cos(xi,xj)
• Not all 9 are independent! Can show: 6 relations exist between various λij:
Giving only 3 independent ones.• Find 6 relations using Eqs. (a) & (b) for each primed axis in
unprimed system. • See text for details & proofs!
• Combined results show:∑j λij λkj = δik (c)
δik Kronecker delta: δik 1, (i = k); = 0 (i k). (c) Orthogonality condition.
Transformations (rotations) which satisfy (c)are called ORTHOGONAL TRANSFORMATIONS.
• If consider unprimed axes in primed system, can also show: ∑i λij λik = δjk (d)
(c) &(d) are equivalent!
• Up to now, we’ve considered P as a fixed point & rotated the
axes (Fig. a shows for 2d)
• Could also choose the axes fixed & allow P to rotate
(Fig. b shows for 2d) • Can show (see text) that: Get the
same transformation whether rotation acts on the frame of reference (Fig. a) or the on point (Fig. b)!