areas of triangles, trapezoids, and rhombi
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Areas of Triangles, Trapezoids, and Rhombi. Objective : TLW find the areas of triangles, trapezoids, and rhombi. SOL G.10. What does the area of a triangle have in common with the area of a rectangle or a parallelogram?. Let’s look at a Triangle. - PowerPoint PPT PresentationTRANSCRIPT
Areas of Triangles, Trapezoids, and
Rhombi
Objective: TLW find the areas of triangles, trapezoids, and rhombi. SOL G.10
What does the area of a triangle have in common
with the area of a rectangle or a parallelogram?
Let’s look at a Triangle Looking at the triangle
below, how can you relate this image to a rectangle?
What if we drew a line perpendicular to AC through point A? through point C? What does this do for us?
Let’s look at a Triangle
Could we follow this with an additional step? What would that step be?
How can we use this diagram and the information we now have to create the formula for area of a triangle?
The Area of a Triangle:
If a triangle has an area of A square units, a base of b units, and a corresponding height of h units, then: A = (1/2) b h Where b = base; h = height
Let’s Try One!!!!
A = (1/2) (7.3 cm)(3.4 cm) = (1/2) (24.82 cm2) = 12.41 cm2
How can we take this formula for the area of a
triangle and apply it to the formula for a trapezoid?
Let’s look at a Trapezoid
Could we create a trapezoid from triangles? If so, how?
h
b1
b2
Area of Trapezoid WXZY: = area of Δ WYX + area of Δ YZX = (1/2) (b1 )(h) + (1/2) (b2 )(h) = (1/2) (b1 + b2 ) h
= (1/2) h (b1 + b2 )
Consider a Trapezoid on the Coordinate Plane
Find the area of trapezoid MNPO:
Find b1 and b2: b1 = |-3 - 3| = 6 b2 = |-5 – 6| = 11Find h: h = |4 – (-1)| = 5
A = (1/2) h (b1 + b2) = (1/2) 5 (6 + 11) = (1/2) 5 (17) = (1/2) 85 u2
= 42.5 u2
How can we take what we have learned from our area formula for a triangle and
apply it to the formula for the area of a rhombus?
Let’s look at a Rhombus
Area of a Rhombus: = area of KFH + area of JFK + area of IFJ + area of HFI
= (1/2) ((1/2)d1)((1/2)d2) + (1/2)((1/2)d1)((1/2)d2) + (1/2)((1/2)d1)((1/2)d2) + (1/2)((1/2)d1)((1/2)d2)
= 4 [ (1/2) ((1/2)d1) ((1/2)d2) ]
=4 [ (1/2) ((1/2)d1) ((1/2)d2) ]
= (d1) ((1/2)d2)
A = (1/2) (d1) (d2)