w1 example 4 answers

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4a 1ml of water occupies a volume of 1cm3. How many

litres will 5cm3 of water occupy?

4a • Convert 1ml into litres:

4a • Convert 1ml into litres:

1ml = 0.001L

4a • Convert 1ml into litres:

1ml = 0.001L

• Multiply this by the size of the sample:

4a • Convert 1ml into litres:

1ml = 0.001L

• Multiply this by the size of the sample:

5cm3 = 5ml = 0.001L x 5 = 𝟓 𝐱 𝟏𝟎−𝟑𝐋

4b There are 1.4 x 1021L of water in the ocean. What is

this in cubic metres?

4b • Work out the conversion between cm3 and m3:

4b • Work out the conversion between cm3 and m3:

1cm = 0.01m

4b • Work out the conversion between cm3 and m3:

1cm = 0.01m

1cm3 = cm x cm x cm = 0.01 x 0.01 x 0.01 m3 = 1 x 10−6m3

4b • Work out the conversion between cm3 and m3:

1cm = 0.01m

1cm3 = cm x cm x cm = 0.01 x 0.01 x 0.01 m3 = 1 x 10−6m3

• Work out the conversion between 1L and 1m3:

4b • Work out the conversion between cm3 and m3:

1cm = 0.01m

1cm3 = cm x cm x cm = 0.01 x 0.01 x 0.01 m3 = 1 x 10−6m3

• Work out the conversion between 1L and 1m3:

1ml = 1cm3

4b • Work out the conversion between cm3 and m3:

1cm = 0.01m

1cm3 = cm x cm x cm = 0.01 x 0.01 x 0.01 m3 = 1 x 10−6m3

• Work out the conversion between 1L and 1m3:

1ml = 1cm3

1 x 10−3L = 1 x 10−6m3

4b • Work out the conversion between cm3 and m3:

1cm = 0.01m

1cm3 = cm x cm x cm = 0.01 x 0.01 x 0.01 m3 = 1 x 10−6m3

• Work out the conversion between 1L and 1m3:

1ml = 1cm3

1 x 10−3L = 1 x 10−6m3

1L = 1 x 10−3m3

4b • Work out the conversion between cm3 and m3:

1cm = 0.01m

1cm3 = cm x cm x cm = 0.01 x 0.01 x 0.01 m3 = 1 x 10−6m3

• Work out the conversion between 1L and 1m3:

1ml = 1cm3

1 x 10−3L = 1 x 10−6m3

1L = 1 x 10−3m3

• Multiply by the volume of the ocean:

4b • Work out the conversion between cm3 and m3:

1cm = 0.01m

1cm3 = cm x cm x cm = 0.01 x 0.01 x 0.01 m3 = 1 x 10−6m3

• Work out the conversion between 1L and 1m3:

1ml = 1cm3

1 x 10−3L = 1 x 10−6m3

1L = 1 x 10−3m3

• Multiply by the volume of the ocean:

1.4 x 1021L = 1.4 x 1021 x 10−3 m3 = 𝟏. 𝟒 𝐱 𝟏𝟎𝟏𝟖𝐦𝟑

4c Seawater contains about 142mgL-1of bicarbonate.

How many grams of bicarbonate will there be in a 2m3

sample of seawater?

4c • Convert 142 mgL-1 into 142 mgm-3:

4c • Convert 142 mgL-1 into 142 mgm-3:

1𝐿 = 1 𝑥 10−3𝑚3

4c • Convert 142 mgL-1 into 142 mgm-3:

1𝐿 = 1 𝑥 10−3𝑚3

1

1𝐿−1 =

1

10−3𝑚−3

4c • Convert 142 mgL-1 into 142 mgm-3:

1𝐿 = 1 𝑥 10−3𝑚3

1

1𝐿−1 =

1

10−3𝑚−3

1𝐿−1 = 103𝑚−3

4c • Convert 142 mgL-1 into 142 mgm-3:

1𝐿 = 1 𝑥 10−3𝑚3

1

1𝐿−1 =

1

10−3𝑚−3

1𝐿−1 = 103𝑚−3

142𝑚𝑔𝐿−1 = 142 𝑥 103𝑚𝑔𝑚−3 = 1.42 𝑥 105𝑚𝑔𝑚−3

4c • Convert 142 mgL-1 into 142 mgm-3:

1𝐿 = 1 𝑥 10−3𝑚3

1

1𝐿−1 =

1

10−3𝑚−3

1𝐿−1 = 103𝑚−3

142𝑚𝑔𝐿−1 = 142 𝑥 103𝑚𝑔𝑚−3 = 1.42 𝑥 105𝑚𝑔𝑚−3

• Multiply by the sample size and convert mg to g:

4c • Convert 142 mgL-1 into 142 mgm-3:

1𝐿 = 1 𝑥 10−3𝑚3

1

1𝐿−1 =

1

10−3𝑚−3

1𝐿−1 = 103𝑚−3

142𝑚𝑔𝐿−1 = 142 𝑥 103𝑚𝑔𝑚−3 = 1.42 𝑥 105𝑚𝑔𝑚−3

• Multiply by the sample size and convert mg to g:

1.42 𝑥 105𝑚𝑔𝑚−3 𝑥 2𝑚3 = 2.84 𝑥 105𝑚𝑔

4c • Convert 142 mgL-1 into 142 mgm-3:

1𝐿 = 1 𝑥 10−3𝑚3

1

1𝐿−1 =

1

10−3𝑚−3

1𝐿−1 = 103𝑚−3

142𝑚𝑔𝐿−1 = 142 𝑥 103𝑚𝑔𝑚−3 = 1.42 𝑥 105𝑚𝑔𝑚−3

• Multiply by the sample size and convert mg to g:

1.42 𝑥 105𝑚𝑔𝑚−3 𝑥 2𝑚3 = 2.84 𝑥 105𝑚𝑔

2.84 𝑥 105 𝑥 10−3 = 𝟐𝟖𝟒𝒈

4d There is approximately 1.81 x 1021g of magnesium in

the entire ocean. For any sample of seawater,

calculate the magnesium content in molL-1.

4d • Calculate the number of moles of Mg in the ocean:

4d • Calculate the number of moles of Mg in the ocean:

1 mole Mg = 24.305g

4d • Calculate the number of moles of Mg in the ocean:

1 mole Mg = 24.305g

1.81 x 1021

24.305= 7.45 x 1019mol Mg

4d • Calculate the number of moles of Mg in the ocean:

1 mole Mg = 24.305g

1.81 x 1021

24.305= 7.45 x 1019mol Mg

• Use the volume of the ocean to work out the overall

concentration of Mg in seawater:

4d • Calculate the number of moles of Mg in the ocean:

1 mole Mg = 24.305g

1.81 x 1021

24.305= 7.45 x 1019mol Mg

• Use the volume of the ocean to work out the overall

concentration of Mg in seawater:

7.45 x 1019mol Mg

1.4 x 1021L= 𝟎. 𝟎𝟓𝟑𝐦𝐨𝐥𝐋−𝟏

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