lab report 3
Post on 01-Nov-2014
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Diagrams used:
Formulas used:
Observations:
Measurement of Active Power:
Serial No. V (Volts)
I (Amps)
W1 (Watts)
W2 (Watts)
Total Power (W1+W2) Watts
Part-1 231 0.9 180 160 360 Part-2 224 2.15 420 420 640
Part-3 226 0.9 -60 120 60
Measurement of Reactive Power:
V (Volts)
I (Amps)
Reactive Power (VAr)
231 0.9 0
224 2.15 0
226 0.92 311.76
Calculations:
Part 1: Star connected load
W1 = 180 Watt W2 = 180 Watt
Experimental Total Power = W1+ W2
= 360 Watt
Ө = Tan-1[ {(W1- W2)√3} / (W1 +W2)]
= 00
Power Factor (Cos Ө) = 1
Phase Current (I) = 0.9 Amp
Line Voltage (VL) = 231 V
Theoretically, Active Power = √3 * VR * I *Cos Ө
= √3*231*0.9*1
= 360.1 W
Active Power Theoretical = Active Power Experimental
Also total reactive power = √3 * (W2-W1) =0
=
Part 2: -Delta Connected Loads
W1 = 420 W W2 = 420 W
Experimental Total Active Power = W1+W2
= 840 W
Experimental Total Reactive Power = √3 * (W2-W1)
= 0 VAr
Now Ө = Tan-1* {√3*(W2-W1)} / (W1+W2) ]
= 00
Power Factor (Cos Ө) = 1
Line Current (IL) = 2.15 Amp Line Voltage (VL) = 224 V
Theoretically, Total Active Power = √3 * VL * IL
= 834 W
Power Dissipated Theoretically = Active Power Experimental
Part 3:- Delta connected load of Lamp & Capacitor combination
a) W1 = -60W W2 = 120 W
Experimental, Total Active Power = W1+W2
= 60 W
Experimental, Total Reactive Power = √3 * (W2-W1)
= 311.76 VAr
Ө = Tan-1 * {√3(W2-W1)} / (W1+W2) ]
= 79.110
Power Factor (Cos Ө) = 0.189
Total Active Power theoretical = √3 * VL * IL * Cos Ө
Here, Line Voltage (VL) = 226 V Line Current (IL) = 0.92 Amp
Active Power theoretical = √3 * 226 * 0.92 * 0.189
= 68.06 W
Active Power Theoretical = Active Power Experimental
b) Total Reactive Power = √3 * Wattmeter Reading
= 311.76 VAr
Reactive Power (In part (a)) = Reactive Power (In part (b))
Results:
1) In case of Star connected load with no Inductor/Capacitor
a) Power Factor = 1
b) Total Active Power = 360 W
c) Total Reactive Power = o VAr
2) In case of a Delta connected load with no Capacitor/ Inductor
a) Power Factor = 1
b) Total Active Power = 840 W
c) Total Reactive Power = 0 VAr
3) In case of a Delta connected load with Capacitor
a) Power Factor = 0.189
b) Total Active Power = 60 W
c) Total Reactive Power = 311.76 VAr
Conclusions:
1) In case of a Star connected load without any capacitor or inductor,
Power Factor (P.F.) =
2) In case of balanced load, Total Active and Reactive Power can be given by
only two wattmeter, where
Total Active Power = √3 * Difference of two Wattmeter reading
3) In case of balance load, Total Reactive Power can be given by only one
Wattmeter,
Total Reactive Power = √3 * Wattmeter Reading
Precaution:
1) We must wear shoes while doing experiment.
2) No loose connections should be there in the circuit.
3) Circuit should be checked before taking the reading.
4) Voltmeter reading should be taken carefully.
5) Multiplying factor should be taken into account, whenever necessary.
6) Wattmeter reading should be added or subtracted with their sign taken
into account.
ESO210 Lab Report by:
AKSHAY AJMERA
Y8055
LAB PARTNERS : KAMAL SAHNI, SANDEEP SINGH ADHIKARI
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