electrostatics chapter 23

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Electrostatics Chapter 23. Most classes will begin with a slide similar to the following. What’s Happening. Clicker use will start on Friday (maybe). We will use them today informally. There will NOT be a quiz this week. There WILL be a quiz a week from Friday. - PowerPoint PPT Presentation

TRANSCRIPT

Electrostatics Chapter 23

Most classes will begin with a slide similar to the following.

What’s Happening• Clicker use will start on Friday (maybe).

We will use them today informally.• There will NOTNOT be a quiz this week.• There WILLWILL be a quiz a week from

Friday.• WebAssigns should be active shortly.

Keep an eye out for it.• It might be already there !!!

Probable First Observation ElectricityElectricity

Idiot!

If lightening had actually traveled down the kite string, old Ben Franklin would have been toast!

Probably never happened, but good story!

A Quick Experiment

Experimental Procedure

PivotThe sequence of Experiments1. Identify the two rods2. Treat each rod3. Bring one rod near to the other4. PREDICT WHAT WILL HAPPEN5. VOTE ON POSSIBILITIES6. Observe what happens7. Did you learn anything? What?

Allowable Predictions(Use your clicker if you have one.)

A. Rods will attract each otherB. Rods will repel each otherC. Nothing will happenD. Something not listed above will happen

Experiment #1

Pivot

motion

Rubber rod

Rubber rod

A. Rods will attract each otherB. Rods will repel each otherC. Nothing will happenD. Something not listed above will happen

Experiment #2

PivotRubber rubbed withskin of dead rabbit

Rubber rubbed withskin of dead rabbit

A. Rods will attract each otherB. Rods will repel each otherC. Nothing will happenD. Something not listed above will happen

The charges on the two rods are ..

A. Since we treated both rods in the same way, they should be of the same type

B. ……. different typesC. I have no idea what you are asking for.D. Leave me alone … I’m napping!

If you rubbed the rods longer and/or harder, do you think the effect that you see would be

A. StrongerB. WeakerC. The same

If the two rods are brought closer together, the force acting between them will get …

A. StrongerB. WeakerC. The same

Definition of sorts

We DEFINE the “stuff” that we put on the rods by the rubbing process as CHARGE.

We will try to understand what charge is and how it behaves.

We add to the properties of materials:Mass

ChargeCharge

Experiment #3

PivotGlass rubbed with wool

A. Rods will attract each otherB. Rods will repel each otherC. Nothing will happenD. Something not listed above will happen

Glass rubbed with wool

Experiment #4

Pivot

1. Rods will attract each other2. Rods will repel each other3. Nothing will happen4. Something not listed above will happen

Glass rubbed with wool

Rubber rubbed withskin of dead rabbit

What’s Going On? All of these effects involve rubbing two surfaces

together. Or pulling two surfaces apart. Something has “happened “to each of these objects. These objects have a new PROPERTY

Other properties are mass, color We call this NEW PROPERTY .………. ………

CHARGE. There seems to be two types of charge.

We call these two types of charge

PositiveNegative

An object without either a (+) or (-) charge is referred

to as being NEUTRAL.NEUTRAL.

Example - Tape

Separation

An Example

We have also observed that there must be TWO kinds of charge. Call these two types

positive (+) negative(-)

We “define” the charge that winds up on the rubber rod when rubbed by the dead cat to be NEGATIVE.

The charge on the glass rod or the dead cat is consequently defined as POSITIVE.

Old Ben screwed up more than once!!

++++++++++-------------+++---++---+-++-

From whence this charge???

-+

Easily Removed

Materials

Two kinds of materials: Insulators

Electrons and Protons are tightly bound to their positions. Hard to move them around.

Conductors Electrons are easily removed and moved around. Electrons are said to be MOBILE charges.

There are other kinds of materials that we will not discuss: semiconductors, semi-metals

Pivot

Experiment #5

Rubber rubbed withskin of dead rabbit

Metal Rod

A. Rods will attract each otherB. Rods will repel each otherC. Nothing will happenD. Something not listed above will happen

What about a charged rod and a piece of wood??

A. Rods will attract each otherB. Rods will repel each otherC. Nothing will happenD. Something not listed above will happen

Ways to charge an object

Rubbing or bond breaking (same thing) Transfer

Direct transfer Polarization Induction

Neutral Object - POLARIZATION

Positive charge attracts negative charges.Rod becomes “polarized.Negative end is closer to positive chargeDistance effect causes attraction.

Induction

Polarize

Ground

Remove Ground

Positive !

Balloon Physics

Same as before: Polarization

What happens when two surfaces touch or rub?

Bonding!Bonding!

The Triboelectric Series

No! No!

When two of the following materials are rubbed together under ordinary circumstances, the top listed material becomes positively charged and the lower listed material becomes

negatively charged.

MORE POSITIVE rabbit's fur

glass mica nylon wool

cat's fur silk

paper cotton wood

acrylic cellophane tape

polystyrene polyethylene

rubber balloon saran wrap

MORE NEGATIVE

No! No!

So far we have found? There are TWO types of charge.

Positive Negative

Like Charges Attract Un-Like charges repel The force between charges increases as they are

brought closer together. This charge separation results from chemical bonds

which are severed.

Forces Between Charges

Q1 Q2 Attract Repel

+ + X

+ - X

- + X

- - X

Coulomb’s Law – Force between charges

The force between two charges is proportional to the product of the two charges and inversely proportional to the square of the distance between them.

The force acts along the line connecting the two charges.

0

221

221

02

21

41

41

k

rqqk

rqq

rqqF

Remember

Coulomb’s Law

229

0

221

0

/1094

14

1

CNmxk

rqq

unit

rF

The Unit of Charge is calledTHE COULOMB

Smallest Charge: e ( a positive number) 1.6 x 10-19 Coul.

electron charge = -eProton charge = +e

Three point charges are located at the corners of an equilateral triangle as shown in Figure P23.7. Calculate the resultant electric force on the 7.00-μC charge.

Two small beads having positive charges 3q and q are fixed at the opposite ends of a horizontal, insulating rod, extending from the origin to the point x = d. As shown in Figure P23.10, a third small charged bead is free to slide on the rod. At what position is the third bead in equilibrium? Can it be in stable equilibrium?

The Electric Field

Fields Imagine an object is placed at a particular point in

space. When placed there, the object experiences a force F. We may not know WHY there is a force on the object,

although we usually will. Suppose further that if we double some property of

the object (mass, charge, …) then the force is found to double as well.

Then the object is said to be in a force field. The strength of the field (field strength) is defined as

the ratio of the force to the property that we are dealing with.

Example – Gravitational Field. Property is MASS (m). Force is mg. Field strength is defined

as Force/Property

gg

gF

mm

mass

m

Force nalGravitatioProperty

ForceStrength Field nalGravitatio

The Gravitational Field That We Live In.

m Mmg

Mg

This is WAR

You are fighting the enemy on the planet Mongo. The evil emperor Ming’s forces are behind a strange

green haze. You aim your blaster and fire … but ……

Ming themerciless

this guy isMEAN!

Nothing Happens! The Green thing is a Force Field!

The Force may not be with you ….

Side View

TheFORCE FIELD

Force

Positiono

|Force| Big!

Properties of a FORCE FIELD It is a property of the position in space. There is a cause but that cause may not be

known. The force on an object is usually proportional

to some property of an object which is placed into the field.

Mysterious Force

F

Electric Field If a charge Q is in an electric field E then it

will experience a force F. The Electric Field is defined as the force per

unit charge at the point. Electric fields are caused by charges and

consequently we can use Coulombs law to calculate it.

For multiple charges, add the fields as VECTORS.

Two Charges

unitunit rrFE 220

00

1rqk

rqqk

qq

Doing itQ

r

q

A Charge

The spot where we wantto know the Electric Field

unit

unit

rQk

q

rqQk

rFE

rF

2

2

F

General-

unitjj

jjj

unit

unit

rQk

q

GeneralrQk

q

rqQk

,2

2

2

rF

EE

rFE

rF

Force Field

Two ChargesWhat is the Electric Field at Point P?

The two S’s

SuperpositionSymmetry

What is the electric field at the center of the square array?

Kinds of continuously distributed charges Line of charge

or sometimes = the charge per unit length. dq=ds (ds= differential of length along the line)

Area = charge per unit area dq=dA dA = dxdy (rectangular coordinates) dA= 2rdr for elemental ring of charge

Volume =charge per unit volume dq=dV dV=dxdydz or 4r2dr or some other expressions we will look at later.

Continuous Charge Distribution

Let’s Do it Real Time

Concept – Charge perunit length

dq= ds

The math

)sin(2)cos(2

)cos()2(

)cos()2(

0

00

02

02

0

0

0

rkd

rkE

rrdkE

rdqkE

Erdds

x

x

x

y

Why?

A Harder Problem

A line of charge=charge/length

setupsetup

dx

L

r

x

dE dEy

2/

02/322

2/

02/322

22

2

2

22

)(2

)(2

)()cos(

)()cos(

L

x

L

x

L

Lx

xrdxkrE

xrdxrkE

xr

r

xrdxkE

(standard integral)

Completing the Math

rk

Lr

kLE

Lr

L

Lrr

kLE

x

x

2

2

4

:line long VERY a oflimit In the

4

:nintegratio theDoing

22

22

1/r dependence

Dare we project this??

Point Charge goes as 1/r2

Infinite line of charge goes as 1/r1

Could it be possible that the field of an infinite plane of charge could go as 1/r0? A constant??

The Geometry

Define surface charge density=charge/unit-area

dq=dA

dA=2rdr

(z2+r2)1/2

dq= x dA = 2rdr

(z2+r2)1/2

R

z

z

rzrdrzkE

rzz

rzdrrk

rzdqkdE

02/322

2/1222222

2

2)cos(

(z2+r2)1/2

Final Result

0z

220

2E

,R

12

WhenRz

zEz

Look at the “Field Lines”

What did we learn in this chapter?? We introduced the concept of the Electric

FIELDFIELD. We may not know what causes the field. (The

evil Emperor Ming) If we know where all the charges are we can

CALCULATE E. E is a VECTOR. The equation for E is the same as for the force

on a charge from Coulomb’s Law but divided by the “q of the test charge”.

What else did we learn in this chapter? We introduced continuous distributions of

charge rather than individual discrete charges.

Instead of adding the individual charges we must INTEGRATE the (dq)s.

There are three kinds of continuously distributed charges.

Kinds of continuously distributed charges

Line of charge or sometimes = the charge per unit length. dq=ds (ds= differential of length along the line)

Area = charge per unit area dq=dA dA = dxdy (rectangular coordinates) dA= 2rdr for elemental ring of charge

Volume =charge per unit volume dq=dV dV=dxdydz or 4r2dr or some other expressions we will look at later.

The Sphere

thk=dr

dq=dV= x surface area x thickness= x 4r2 x dr

dq

Summary

222

,2

2

2

)()()(rrdsk

rrdAk

rrdVk

rQk

q

GeneralrQk

q

rqQk

unitjj

jjj

unit

unit

E

rF

EE

rFE

rF

(Note: I left off the unit vectors in the lastequation set, but be aware that they should

be there.)

To be remembered … If the ELECTRIC FIELD at a point is E, then E=F/q (This is the definition!)

Using some advanced mathematics we can derive from this equation, the fact that:

EF q

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