div class=ts-pagebuttonPage 1button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page1jpg target=_blank amp-img class=ts-thumb alt=Page 1: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails1jpg width=142 height=106 layout=responsive amp-imga divpCLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9p pEX 95 SOLUTIONSp pANS :pdivdiv class=ts-pagebuttonPage 2button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page2jpg target=_blank amp-img class=ts-thumb alt=Page 2: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails2jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 3button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page3jpg target=_blank amp-img class=ts-thumb alt=Page 3: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails3jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 4button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page4jpg target=_blank amp-img class=ts-thumb alt=Page 4: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails4jpg width=142 height=106 layout=responsive amp-imga divdivdiv class=ts-pagebuttonPage 5button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page5jpg target=_blank amp-img class=ts-thumb alt=Page 5: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails5jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 6button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page6jpg target=_blank amp-img class=ts-thumb alt=Page 6: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails6jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 7button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page7jpg target=_blank amp-img class=ts-thumb alt=Page 7: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails7jpg width=142 height=106 layout=responsive amp-imga divdivdiv class=ts-pagebuttonPage 8button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page8jpg target=_blank amp-img class=ts-thumb alt=Page 8: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails8jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 9button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page9jpg target=_blank amp-img class=ts-thumb alt=Page 9: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails9jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 10button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page10jpg target=_blank amp-img class=ts-thumb alt=Page 10: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails10jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 11button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page11jpg target=_blank amp-img class=ts-thumb alt=Page 11: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails11jpg width=142 height=106 layout=responsive amp-imga divdivdiv class=ts-pagebuttonPage 12button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page12jpg target=_blank amp-img class=ts-thumb alt=Page 12: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails12jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 13button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page13jpg target=_blank amp-img class=ts-thumb alt=Page 13: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails13jpg width=142 height=106 layout=responsive amp-imga divdivdiv class=ts-pagebuttonPage 14button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page14jpg target=_blank amp-img class=ts-thumb alt=Page 14: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails14jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 15button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page15jpg target=_blank amp-img class=ts-thumb alt=Page 15: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails15jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 16button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page16jpg target=_blank amp-img class=ts-thumb alt=Page 16: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails16jpg width=142 height=106 layout=responsive amp-imga divdivdiv class=ts-pagebuttonPage 17button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page17jpg target=_blank amp-img class=ts-thumb alt=Page 17: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails17jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 18button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page18jpg target=_blank amp-img class=ts-thumb alt=Page 18: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails18jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 19button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page19jpg target=_blank amp-img class=ts-thumb alt=Page 19: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails19jpg width=142 height=106 layout=responsive amp-imga divdivdiv class=ts-pagebuttonPage 20button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page20jpg target=_blank amp-img class=ts-thumb alt=Page 20: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails20jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 21button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page21jpg target=_blank amp-img class=ts-thumb alt=Page 21: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore src=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5thumbnails21jpg width=142 height=106 layout=responsive amp-imga divpANS :pdivdiv class=ts-pagebuttonPage 22button div class=ts-image a href=https:reader042vdocumentsusreader042viewer20220307095af703a97f8b9a8d1c8faa02html5page22jpg target=_blank amp-img class=ts-thumb alt=Page 22: CLASS XII DIFFERENTIAL EQUATIONS CHAPTER 9 EX 95 … · Now Substituting C = e in equation 2 we get This is the required solution of the given differential equatiorL Therefore 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