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Algebra II Notes – Unit One: Essential Concepts and Skills Page 1 of 23 Syllabus Objective 1.1 – The student will differentiate among subsets of the real number system. Real Numbers : numbers that can be graphed on the number line Notation: Ex: 8 3, 10, 2, , 4.2, 5 Put the numbers in order and graph on the real number line. The real number system is made up of the following subsets: Whole Numbers: the set of the Natural (counting) Numbers including 0 0,1,2,3,... Integers: the whole numbers and their opposites Notation: ... 3, 2, 1,0,1,2,3,... Rational Numbers: numbers that can be written as the ratio of two integers Notation: Ex: 1 5, 2, ,0.3 6 Irrational numbers: real numbers that are not rational. Decimals that do not terminate and do not repeat. Ex: 3 3, 3.14159..., 7 Properties of Real Numbers: Let a, b, and c be real numbers. Commutative Properties o Addition: a b b a Ex: 3 5 5 3 o Multiplication: ab ba Ex: 42 24 Associative Properties o Addition: a b c a b c Ex: 3 2 8 3 2 8 o Multiplication: ab c a bc Ex: 1 1 4 9 4 9 3 3

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Algebra II Notes – Unit One: Essential Concepts and Skills

Page 1 of 23             

 

Syllabus Objective 1.1 – The student will differentiate among subsets of the real number system.

Real Numbers: numbers that can be graphed on the number line Notation:

Ex: 8

3, 10, 2, ,4.2,5

Put the numbers in order and graph on the real number line.

The real number system is made up of the following subsets:

Whole Numbers: the set of the Natural (counting) Numbers including 0

0,1,2,3,...

Integers: the whole numbers and their opposites Notation:

... 3, 2, 1,0,1,2,3,...

Rational Numbers: numbers that can be written as the ratio of two integers Notation:

Ex: 1

5, 2, ,0.36

Irrational numbers: real numbers that are not rational. Decimals that do not terminate and do not repeat.

Ex: 33, 3.14159..., 7

Properties of Real Numbers:

Let a, b, and c be real numbers.

Commutative Properties

o Addition: a b b a Ex: 3 5 5 3

o Multiplication: a b b a Ex: 4 2 2 4

Associative Properties

o Addition: a b c a b c Ex: 3 2 8 3 2 8

o Multiplication: ab c a bc Ex: 1 1

4 9 4 93 3

Algebra II Notes – Unit One: Essential Concepts and Skills

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Identity Properties

o Addition (Note: 0 is the “identity” of addition): 0a a Ex: 0 3 3

o Multiplication (Note: 1 is the “identity” of multiplication): 1 a a Ex: 1

Inverse Properties

o Addition (Note: a is called the “opposite” of a ): 0a a Ex: 0.5 0.5 0

o Multiplication (Note: 1

ais called the “reciprocal” of a ):

11a

a Ex:

3 41

4 3

Distributive Property

a b c ab ac a b c ab ac Ex: 2 3 8 2 3 2 8

Review: Operations with real numbers.

1. Find the product of 3 and 2

9 . 2. Find the sum of 8 and 4.2 .

3. Find the difference of 6 and 23 . 4. Find the quotient of 1

and 43

.

You Try: Fill in the chart using the following

subsets of numbers. Give examples in each box.

Natural

Integers

Irrational

Rational

Whole

QOD (Question of the Day): What is the difference between a rational and irrational number?

Real ( ) 

 

   

Algebra II Notes – Unit One: Essential Concepts and Skills

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Sample SAT Question(s): Taken from College Board online practice problems. 1. If P and Q are two sets of numbers, and if every number in P is also in Q, Which of the following

CANNOT be true? (A) 4 is in both P and Q. (B) 5 is in neither P nor Q. (C) 6 is in P, but not in Q. (D) 7 is in Q, but not in P. (E) if 8 is not in Q, then 8 is not in P.

2. For all numbers a and b, let a b be defined a b ab a b . For all numbers x, y, and z, which of the following must be true?

I. x y y x

II. 1 1 1x x x x

III. x y z x y x z

(A) I only (B) II only (C) III only (D) I and II only (E) I, II, and III only

Algebra II Notes – Unit One: Essential Concepts and Skills

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Syllabus Objectives 1.2 – The student will simplify numerical and algebraic expressions applying the appropriate field properties. 1.3 – The student will demonstrate proper techniques for entering data into his/her calculator. Powers:

ba c a is the base, b is the exponent, and ba is the power

A power is repeated multiplication. Ex: 5a a a a a a

Caution: Be careful with negative signs.

42 2 2 2 2 −16 and 42 2 2 2 2 16

Order of Operations:

1. Parentheses – perform any operation in parentheses or grouping symbols

2. Exponents – evaluate any powers

3. Multiplication and Division – perform these two operations from left to right as seen in the expression

4. Addition and Subtraction – perform these two operations from left to right as seen in the expression

Mnemonic device for the Order of Operations: PEMDAS or “Please Excuse My Dear Aunt Sally”

Note: Be careful when using this mnemonic device. Remember that multiplication/division and addition/subtraction are performed left to right!

Ex: Evaluate the expression 22 6 3 2 5x x y when 3x and 5y .

Substitute values for x and y: 22 3 6 3 3 5 2 5

Grouping symbols:

2

2

2 3 6 3 15 2 5

2 3 6 12 2 5

Exponents: 2 9 6 12 2 5

Mult/Div Left to Right: 18 72 2 5

18 36 5

Add/Sub Left to Right: 18 5

13

Algebra II Notes – Unit One: Essential Concepts and Skills

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Ex: Write an algebraic expression for the following real-life situation. Suppose you have $25 to spend for music on a website that charges $1.50 per song. Write an expression that shows how

much money you have left after buying n songs. Evaluate the expression for 6n .

Write an expression: 25 1.50n

Evaluate for 6n : 25 1.50 6 $16

Ex: Write an algebraic expression for the area of a triangle that has a base of 6w ft. and a

height of w ft. Find the area when 14w . Label your answer with correct units.

Area of a Triangle: 1

2A bh 1

62

A w w

Area when 14w :

2

114 6 14

21

8 142

56 ft

A

Simplifying Algebraic Expressions: To simplify an algebraic expression, eliminate parentheses using the distributive property and combine like terms. Terms are separated by (+) or (–) signs.

Term: 43x 3 is the coefficient, and 4x is the variable part

Like terms are terms with the same variable part. A constant term is a term without a variable part.

Ex: 2 3 2 24 3 2 6 1x x x y xy

Step One: Use the Distributive Property. 2 3 2 24 6 18 3 3 3x x x y xy

Step Two: Combine like terms. 3 2 26 14 3 3 3x x y xy

How many terms are in your simplified expression? 5 How many are constant terms? 1

Algebra II Notes – Unit One: Essential Concepts and Skills

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Evaluate the expression when 1 and 7x y .

Step One: Substitute the given values in for the variables (use parentheses to place the values in).

3 2 26 1 14 1 3 7 3 1 7 3

Step Two: Simplify using the order of operations.

Exponents: 6 1 14 1 3 49 3 1 7 3

Multiplication: 6 14 147 21 3

Addition/Subtraction (left to right) 8 147 21 3

139 21 3 160 3 157

Calculator Activity: Does your calculator “know” the order of operations?

Evaluate the following expression on the calculator. Write down the keystrokes necessary for the calculator to obtain the correct answer according to the order of operations.

3

2

32 25

3 1

You Try: Evaluate the expressions when 5x and 1y .

a. 5

x y

y

b. 22x y c. 13 5 4

2x y

QOD: Describe what it means for terms to be like terms and give an example.

Algebra II Notes – Unit One: Essential Concepts and Skills

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Sample CCSD Common Exam Practice Question(s):

1. To which sets of numbers does 3

5 belong?

I. integers

II. natural numbers

III. rational numbers

IV. real numbers

V. whole numbers

 

A. I, III, and IV only

B. II and IV only

C. III and IV only

D. III, IV, and V only

2. Evaluate (3 )c d when 1c and 5d .

A. 8

B. 2

C. 3

D. 8

3. Which is a simplified form of the expression 3( 2) 5(2 4)x x ?

A. 16x

B. 19x

C. 7 2x

D. 7 26x

Algebra II Notes – Unit One: Essential Concepts and Skills

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Sample SAT Question(s): Taken from College Board online practice problems. 1. On a car trip Sam drove m miles, Kara drove twice as many miles as Sam, and Darin drove 20 fewer

miles than Kara. In terms of m, how many miles did Darin drive?

(A) 2 20m

(B) 2 20m

(C) 202

m

(D) 20

2

m

(E) 202

m

2. If n is an odd integer, which of the following must be an odd integer?

(A) 1n

(B) 1n

(C) 2n

(D) 3 1n

(E) 4 1n

3. If n is an integer and if 2n is a positive integer, which of the following must also be a positive integer?

(A) 2n n

(B) 22n n

(C) 2 3n n

(D) 3n n

(E) 32n n

4. If a cake is cut into thirds and each third is cut into fourths, how many pieces of cake are there? Grid-In

Algebra II Notes – Unit One: Essential Concepts and Skills

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Syllabus Objective 1.4 – The student will solve linear equations and inequalities, and absolute value equations in one variable. Equation: an algebraic “sentence” that consists of two equal algebraic expressions

Linear Equation: an equation that can be written in the form ax b c

Note: To solve an equation, we use the properties of equality to isolate the variable on one side of the equation. When isolating the variable, we will “undo” addition/subtraction first, then multiplication/division using inverse operations. This is the order of operations in reverse!

Ex: Solve the equation 8 6 5x .

Step One: Subtract 6 from both sides. 8 1x

Step Two: Divide both sides by 8 . 1

8x

For more complicated equations, you may have to simplify both sides of the equation first using the distributive property and combining like terms.

Ex: Solve the equation 6 4 2 24x x

Step One: Use the distributive property. 6 24 2 24x x

Step Two: Combine like terms. 4 24 24x

Step Three: Add 24 to both sides. 4 48x

Step Four: Divide both sides by 4. 12x

If there are variables on both sides, you will need to simplify both sides of the equation and then bring all variables to the same side using inverse operations.

Ex: Solve the equation 3 2 4 6x x

Step One: Use the distributive property. 3 2 4 24x x

Step Two: Subtract 3x from both sides. 2 24x

Step Three: Subtract 24 from both sides. 26 x

Note: We can also write the answer in set notation. The solution set to the equation above is 26 .

Algebra II Notes – Unit One: Essential Concepts and Skills

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When solving an equation with fractions, it saves time to “wipe-out” the fractions by multiplying both sides by the LCD (lowest common denominator).

Ex: Solve the equation: 3 9 1

25 10 3

x x

The LCD of the fractions is 30. Multiply every term in the equation by 30:

3 9 130 30 30 30 2

5 10 3x x 18 27 10 60x x

Now use the steps illustrated in the previous examples to solve the equation.

37

37 4242

x x

Using Equations in Real-Life:

Ex: Ann earns $8 per hour for every 40 hours worked per week, and time-and-a-half for every hour over 40 hours. If Ann earned $380 last week, how many hours did she work?

Solution: Let h be the number of hours of overtime (over 40) Ann worked last week.

8 40 1.5 8 380h

320 12 380h

12 60h

5h Therefore, Ann worked a total of 45 hours last week.

You Try: In 2005, 176 students bought non-spiral notebooks, and this number is increasing by 24 per year. That same year, 331 students bought spiral notebooks, and that number is decreasing by 15 per year. When will the number of spiral notebooks be half of the non-spirals?

QOD: What role does the order of operations play when solving an equation?

Algebra II Notes – Unit One: Essential Concepts and Skills

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Sample CCSD Common Exam Practice Question(s):

What is the value of x when 2 1 5

3 2 6x ?

A. 2

9x

B. 1

2x

C. 5

7x

D. 3

2x

Sample SAT Question(s): Taken from College Board online practice problems.

1. If 12x k and 36p x k , what is the value of p?

(A) 3 (B) 4 (C) 6 (D) 9 (E) 12

2. If 13 is added to one-half of a certain number, the result is 37. What is the original number?

(A) 24 (B) 40 (C) 48 (D) 61 (E) 80

3. If 1

9 03

y , then y

(A) −27 (B) −9 (C) −3 (D) 3 (E) 27

Algebra II Notes – Unit One: Essential Concepts and Skills

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Syllabus Objective 1.5 – The student will solve for a given variable in an equation with more than one variable.

The equation 3 2 5x y is an example of an equation that is implicitly defined. Sometimes it is useful

to rewrite the equation so that it is explicitly defined, which means it is solved for one of the variables.

Ex: Solve the equation 3 2 5x y for y .

Step One: Subtract 3x from both sides. 2 5 3y x

Step Two: Divide both sides by 2. 5 3

2 2y x

Note: There are many ways to write the correct answer. This equation is equivalent to the following:

3 5

2 2y x and

5 3

2

xy

Sometimes it is useful to solve formulas for one of the variables.

Ex: Solve the formula for the area of a trapezoid for 1b .

1 2

1

2A h b b

Step One: Multiply both sides by 2 (LCD). 1 22A h b b

Step Two: Use the distributive property. 1 22A hb hb

Step Three: Subtract 2hb from both sides. 2 12A hb hb

Step Four: Divide both sides by h . 21

2A hbb

h

or 2 1

2Ab b

h

Note: An alternate method would be to divide both sides by h for Step Two.

You Try: Solve the temperature conversion formula for C .9

325

F C

QOD: Describe a real-life situation where you would need to be able to solve the area formula of a circle for r.

Algebra II Notes – Unit One: Essential Concepts and Skills

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Sample CCSD Common Exam Practice Question(s):

1. Which represents y in terms of x for the equation 2 5 6 10 8x y x x y ?

A. 1

22

y x

B. 3

22

y x

C. 7

22

y x

D. 9

22

y x

2. The formula for the volume of a cone is 21

3V r h . Which formula represents r in

terms of V and h?

A. 3V

rh

B. 3V

rh

C. 3

Vr

h

D. 3

Vr

h

Sample SAT Question(s): Taken from College Board online practice problems.

If h and k are positive numbers and 7h k , then 7 k

h

(A) 1 (B) 0 (C) −1 (D) h

(E) 1k

Algebra II Notes – Unit One: Essential Concepts and Skills

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Syllabus Objective 1.4 – The student will solve linear equations and inequalities, and absolute value equations in one variable.

Inequality Symbols:

Greater Than Greater Than or Equal To

Less Than Less Than or Equal To

Graphing an Inequality: Use an open circle for greater than (>) or less than (<). Use a closed circle for greater than or equal to ( ) or less than or equal to ( ).

Ex: Graph the inequality 8x

Ex: Graph the inequality 3 x

Note: It may help to rewrite as 3x

Ex: Write an inequality for the situation. Zac needed to score at least a 76% on his Algebra exam

to get a B in the class. 76s (where s is Zac’s exam score)

Solving a Linear Inequality: solving an inequality is similar to solving an equation, with one exception. *When multiplying or dividing by a negative number in an inequality, you must FLIP the inequality sign*

Ex: Solve the inequality 4x .

To isolate the variable, we need to switch sides to obtain 4 x .

Which, written with the variable on the left would read 4x .

An alternative way to solve this inequality would be to divide both sides by 1 .

4

1 1

x

Note: We needed to FLIP (reverse) the inequality symbol!

Ex: Solve the inequality 2 1 3 8x x

Step One: Distributive property 2 1 3 24x x

Step Two: Get variables to one side 5 1 24x

Step Three: Subtract 1 from both sides 5 25x

Step Four: Divide both sides by NEGATIVE 5 (FLIP the inequality) 5x

 0   1   2   3   4    5   6   7   8   9

‐8  ‐7  ‐6  ‐5  ‐4  ‐3  ‐2  ‐1  0 

Algebra II Notes – Unit One: Essential Concepts and Skills

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Compound Inequalities: two inequalities joined by “and” or “or”

Ex: 5 or 2x x

Ex: 3 and 4x x

Note: This can also be written as 3 4x

Solving a compound inequality: Isolate the variable. In an “and” statement, isolate the variable between the two inequality signs. What you do to the middle, you must do to all sides!

Ex: Solve and graph: 3 1 2 5x

Step One: Add 1 to the middle and both sides 2 2 6x

Step Two: Divide the middle and both sides by 2 1 6x Don’t forget to FLIP!

Step Three: Rewrite the inequality (smallest to largest) 6 1x

Step Four: Graph on a number line (closed circle on 6 , open circle on 1 , shade in between)

Ex: Solve and graph: 6 5 7 or 8 1 25x x

Step One: Solve both inequalities separately 6 12x 8 24x

2x 3x

Step Two: Write the solutions as a compound inequality 2 or 3x x

Step Three: Graph on a number line (open circle on 2, shade left; open circle on 3, shade right)

Ex: Application Problem – There are 8 sections of seats in an auditorium. Each section contains at least 150 seats, but not more than 200 seats. Write a compound inequality that represents the number of seats (s) that could be in the auditorium.

Solution: 8 150 8 200s 1200 1600s

Challenge: What about special cases?

4 and 0x x 1 and 1x x

Solution: 0x Solution: No solution

2 3 64 75 8 91 

‐2 ‐1 2 0 3 1 4  5 ‐3

‐2 ‐1 20 31 4 5‐3‐2  ‐1  2 0  3 1  4  5 ‐3 

Algebra II Notes – Unit One: Essential Concepts and Skills

Page 16 of 23             

 

Special cases (continued):

1 or 1x x 2 or 3x x

Solution: 1x Solution: All real numbers

You Try: Solve and graph the inequalities. Is the indicated value a solution?

a) 3 2 7 11; 9x x

b) 5 3 6 or 7 4 9; 1.9x x x

QOD: When solving an inequality, when must you flip the sign, and why?

Sample CCSD Common Exam Practice Question(s):

Which expresses all of the solutions for the compound inequality below?

2 3 5 or 3( 8) 3x x

A. 1 9x

B. x = 1 or x = 9

C. 1x or 9x

D. no solution

‐2  ‐1  2 0  3 1  4  5 ‐3  ‐2 ‐1 20 31 4 5‐3

Algebra II Notes – Unit One: Essential Concepts and Skills

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Sample SAT Question(s): Taken from College Board online practice problems.

If 3 3 6 18t , which of the following must be true? (A) 5t

(B) 5 6t

(C) 4 1 9t

(D) 12 3 24t

(E) 3 or 8t t

Algebra II Notes – Unit One: Essential Concepts and Skills

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Syllabus Objective 1.4 – The student will solve linear equations and inequalities, and absolute value equations in one variable.

Absolute Value: the distance a number is away from the origin on the number line

Algebraic Definition of Absolute Value: , 0

, 0

a aa

a a

Ex: Solve the absolute value equation: 3x

Note: This means that the distance from the origin is 3.

Solution: There are two numbers that are 3 units away from the origin: 3 and 3x x

When solving an absolute value equation in the form ax b c , you must solve the equations

ax b c and ax b c .

Ex: Solve the absolute value equation: 5 1 3 14x

Step One: Put the equation in ax b c form. 5 1 11x

Step Two: Rewrite as two equations. 5 1 11x 5 1 11x

Step Three: Solve both equations. 5 10x 5 12x

Solutions: 2x or 12

5x

Note: You can check your solutions by substituting them back into the original equation.

Absolute Value Inequalities:

Ex: 3x means that the distance x is away from the origin is less than 3.

So, 3 and 3x x . We write this as 3 3x

Ex: 3x means that the distance x is away from the origin is greater than 3.

So, 3 or 3x x .

‐2  ‐1 20 31 4 5‐3 

‐2 ‐1  2 0  3 1  4 5‐3

‐2 ‐1 20 31 4‐4 ‐3

Algebra II Notes – Unit One: Essential Concepts and Skills

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Solving Absolute Value Inequalities:

Ex: Solve and graph the solutions to the inequality: 6 8x

Note: This means that the distance 6x is away from the origin is less than 8.

Step One: Rewrite as two inequalities 6 8x 6 8x

Step Two: Solve each inequality 2x 14x

Step Three: Rewrite as a compound inequality Solution: 14 2x

Step Four: Graph on a number line (open circle on 14 and 2 , shade between)

Ex: Solve the inequality: 3 3 4 10x

Step One: Rewrite in ax b c form 3 3 6x

(Note: This means that the distance 3 3x is away from the origin is greater than or equal to 6.)

Step Two: Rewrite as two inequalities 3 3 6x 3 3 6x

Step Three: Solve each inequality 3 9

3

x

x

3 3

1

x

x

Step Four: Rewrite as a compound inequality Solution: 1 or 3x x

Application of Absolute Value Inequalities:

Ex: At a bottling company, machine A fills a bottle with spring water and machine B accepts

bottles only if the number of fluid ounces is between 8

179

and 1

189

. If machine B accepts a bottle

containing n fluid ounces, write an absolute value inequality that describes all possible values of n.

Solution: 1

189

n

Algebra II Notes – Unit One: Essential Concepts and Skills

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Challenge: Special Cases

a) 1 2 0x This has one solution: 1

2x

b) 3 7 5x This has no solution. (The absolute value cannot be negative, because it is a

distance.)

c) 3 4x This has no solution. (The absolute value less than 4 , because it would have to

be a negative number.)

d) 2 1 9x The solutions are restricted to when the absolute value is nonnegative (greater

than or equal to zero). The inequality 2 1 0x is always true, giving us a solution of ALL

REAL NUMBERS.

You Try:

1. Solve and graph: 3 6 9x

2. Solve and graph: 3 2 6 2x

3. Write an absolute value inequality for the graph:

4. Write an absolute value inequality for the graph:

QOD: How are the graphs of the solutions of absolute value inequalities with a or different from absolute value inequalities with a or ?

Sample CCSD Common Exam Practice Question(s):

What is the solution set of 4 8 20x ?

A. { 7}

B. { 7,3}

C. {3}

D. { 3,7}

‐2 ‐1  2 0  3 1  4 5‐3 

‐2  ‐1  2 0  31  4 5‐3 

Algebra II Notes – Unit One: Essential Concepts and Skills

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Sample SAT Question(s): Taken from College Board online practice problems.

1. If s, t, u, and v are the coordinates of the indication points on the number line above, which of the

following is greatest?

(A) s t

(B) s v

(C) s t

(D) s v

(E) s u

2. At a snack bar, a customer who orders a small soda gets a cup containing c ounces of soda, where

c is at least 12 but no more than 1

122

. Which of the following describes all possible values of c?

(A) 1 1

122 2

c

(B) 1

122

c

(C) 1

124

c

(D) 1 1

124 2

c

(E) 1 1

124 4

c

Algebra II Notes – Unit One: Essential Concepts and Skills

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Syllabus Objective 1.7 – The student will develop a mathematical model to solve real-world problems.

Problem Solving Plan: When solving an application problem, it is important to have a plan. We will use the following steps to solve the problems that follow.

1. Write a verbal model.

2. Assign labels.

3. Write an algebraic model.

4. Solve the algebraic model.

5. Answer the question.

Ex: A gym offers 2 membership packages: $50 initial fee and $5 each visit or $200 initial fee and $2 each visit. How many visits will it take for the two packages to have equal cost?

1. Initial Fee + Cost Per Visit Number of Visits = Initial Fee + Cost Per Visit Number of Visits

(Package One) (Package Two)

2. Package One: Initial Fee = 50 Package Two: Initial Fee = 200

Cost Per Visit = 5 Cost Per Visit = 2

Number of Visits = v Number of Visits = v

3. 50 5 200 2v v

4. 3 150

50

v

v

5. It will take 50 visits for the two packages to have equal cost.

Ex: Find three consecutive integers with a sum of 84.

1. First Integer + Second Integer + Third Integer = 84

2. First Integer = n , Second Integer = 1n , Third Integer = 2n

3. 1 2 84n n n

4.

3 3 84

3 81

27

n

n

n

5. The three consecutive integers are 27,28, and 29.

Algebra II Notes – Unit One: Essential Concepts and Skills

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You Try:

a) If 4 less than 3 times a number is 2 more than the number, what is the number?

b) Joan has a monthly base salary of $200 and earns a $10 commission for each item she sells. Jimmy has a monthly base salary of $300 and earns a $5 commission for each item he sells. How many items would each need to sell to earn the same amount?

QOD: List and describe the steps of a problem solving plan.

Sample CCSD Common Exam Practice Question(s):

The cost for parts to repair a car was $1,015. The cost for labor was $70 per hour. Which of the following is a linear model for the total cost of repairing the car where n represents the number hours of labor.?

A. 70 1015C n

B. 1015 70C n

C. 70 1015C n

D. 1015 70C n

Sample SAT Question(s): Taken from College Board online practice problems.

1. The number n is a 2-digit number. When n is divided by 10, the remainder is 9, and when n is divided by 9, the remainder is 8. What is the value of n?

Grid-In

2. Roy planted corn on 1

5 of his land. If he planted 45 acres of corn, how many acres of land does

he have? (A) 90

(B) 1

1122

(C) 135 (D) 225

(E) 1

3372