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  • 8/18/2019 Ahu Sb3 Best

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    Designer :Project Name :

    Best & effective Solution of Structural Technology. BeST Ver 2.6

    BeST MEMBER :Date : Page :

    http://www.BestUser.com

    AHU-SB3

    Kwai Vii Cee  75

    200

            6        0        0

            1        7

    11

    x

    y

      Unit : cm

    As  = 134.40

    Ix  = 77600 Iy  = 2280

    Zx  = 2980 Zy  = 361

    J = 91 Cw  = 1940000

    Design Conditions

    Design Code : AISC-2005(LRFD)Section Size : ㅐ-600x200x11x17

    Steel Material Fy = 345 N/mm2 (A992)

    Unbraced Lengths Lx = 1.10, Ly = 1.10 m

      Lb = 0.55 m

    EffectiveLengthFact. Kx = 0.80, Ky = 0.80

    Modification Factor Cb = 1.00

     Design Force and Moment

     Pu  = 0.0 kN

     Mux  = 77.9, Muy  = 0.0 kN·m

     Vux  = 0.0, Vuy  = 103.1 kN

    Check Thickness Ratios for Flexure

    Check Flange  -. λp  = 0.38 E/Fy   = 9.15

      -. λr  = 1.0 E/Fy   = 24.09

      -. bf/2tf = 5.88 < λp  ---> Compact Section

    Check Web  -. λp  = 3.76 E/Fy   = 90.56

      -. λr  = 5.70 E/Fy   = 137.29

      -. h/tw  = 47.45 < λp  ---> Compact Section

    Check Flexural Strength about Major Axis

    Compute Yielding Strength  -. Mp  = Fy*Zx = 1027.34 kN·m

    Compute Lateral-Torsional Buckling  -. Lp  = 1.76ry E/Fy   = 1.75 m

      -. Lr  = 1.95rts  E0.7Fy

     JcSxho

    ... = 5.04 m

      -. Mn,LTB  = Mp  = 1027.34 kN·m

    Compute Flexural Strength about Major Axis  -. Mnx  = Min[Mp, Mn,LTB] = 1027.34 kN·m

      -. ΦMnx  = Φ*Mnx  = 924.60 kN·m

    Check Interaction of Combined Strength

      -. Pu/ΦPn  < 0.20

      -. Ratio =Pu

    2ΦPn+[

     MuxΦMnx

    + MuyΦMny ]  = 0.084 < 1.000 ---> O.K.

    Check Shear Strength

    Check Shear Strength in Local-y Direction  -. λr  = 2.24* E/Fy   = 53.95

      -. h/t = 47.45 < λr

      -. Cv  = 1.00

    -. Vn  = 0.6*Fy*Aw*Cv  = 1365.19 kN

      -. ΦVny  = Φ*Vn  = 1365.19 kN

      -. Vuy/ΦVny  = 0.076 < 1.000 ---> O.K.