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8/18/2019 Ahu Sb3 Best
1/1
Designer :Project Name :
Best & effective Solution of Structural Technology. BeST Ver 2.6
BeST MEMBER :Date : Page :
http://www.BestUser.com
AHU-SB3
Kwai Vii Cee 75
200
6 0 0
1 7
11
x
y
Unit : cm
As = 134.40
Ix = 77600 Iy = 2280
Zx = 2980 Zy = 361
J = 91 Cw = 1940000
Design Conditions
Design Code : AISC-2005(LRFD)Section Size : ㅐ-600x200x11x17
Steel Material Fy = 345 N/mm2 (A992)
Unbraced Lengths Lx = 1.10, Ly = 1.10 m
Lb = 0.55 m
EffectiveLengthFact. Kx = 0.80, Ky = 0.80
Modification Factor Cb = 1.00
Design Force and Moment
Pu = 0.0 kN
Mux = 77.9, Muy = 0.0 kN·m
Vux = 0.0, Vuy = 103.1 kN
Check Thickness Ratios for Flexure
Check Flange -. λp = 0.38 E/Fy = 9.15
-. λr = 1.0 E/Fy = 24.09
-. bf/2tf = 5.88 < λp ---> Compact Section
Check Web -. λp = 3.76 E/Fy = 90.56
-. λr = 5.70 E/Fy = 137.29
-. h/tw = 47.45 < λp ---> Compact Section
Check Flexural Strength about Major Axis
Compute Yielding Strength -. Mp = Fy*Zx = 1027.34 kN·m
Compute Lateral-Torsional Buckling -. Lp = 1.76ry E/Fy = 1.75 m
-. Lr = 1.95rts E0.7Fy
JcSxho
... = 5.04 m
-. Mn,LTB = Mp = 1027.34 kN·m
Compute Flexural Strength about Major Axis -. Mnx = Min[Mp, Mn,LTB] = 1027.34 kN·m
-. ΦMnx = Φ*Mnx = 924.60 kN·m
Check Interaction of Combined Strength
-. Pu/ΦPn < 0.20
-. Ratio =Pu
2ΦPn+[
MuxΦMnx
+ MuyΦMny ] = 0.084 < 1.000 ---> O.K.
Check Shear Strength
Check Shear Strength in Local-y Direction -. λr = 2.24* E/Fy = 53.95
-. h/t = 47.45 < λr
-. Cv = 1.00
-. Vn = 0.6*Fy*Aw*Cv = 1365.19 kN
-. ΦVny = Φ*Vn = 1365.19 kN
-. Vuy/ΦVny = 0.076 < 1.000 ---> O.K.