advanced heat transfer lecture1
TRANSCRIPT
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Advanced Heat Transfer - Prof. Dr.-Ing. R. Weber - Winter 2005/2006 - Lecture 1 (Governing Laws)
Lecture-1. Governing Laws for Thermal Radiation
Contents of the lecture
1.1 Heat Transfer Mechanisms
1.6 Geometrical Considerations
1.7 Governing Laws for Thermal Radiation1.8 Blackbody Radiation in a Wavelength Interval
1.11 Blackbody Emission into a Medium Other than Vacuum
1.10 Historical Note Origin of Quantum Mechanics
1.12 Summary
1.2 Electromagnetic Radiation
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What is heat transfer?
Heat transfer (or heat) is energy in transit due toa temperature difference
HEAT TRANSFER MODES
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The convention (in this lecture series) is
Heat transfer rate Q& in W (J/s)
Amount of heat (energy) Q in J
Heat flux q& in W/m2
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Radiation which is given off by a body
because of its temperature is called
thermal radiation
A body of a temperature larger than 0 K
emits thermal radiation
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RELEVANCE OF THERMAL RADIATION
4
2
4
1
21
21
TTQ
TTQ
TTQ
radiation
convection
conduction
&
&
&
When no medium is present radiation is the only
mode of heat transfer
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ELECTROMAGNETIC WAVES
Classical theory
Quantum theory
vhEphoton = sJ1063.634 = h
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SPEED, FREQUENCY and WAVELENGTH
For any wave:
=w
Determined
by the medium
Determined by
the source
For electromagnetic waves:
=cc=3108 m/s ( in vacuum)
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SPEED, FREQUENCY and WAVELENGTH
For a medium other than vacuum:
medium
mediumn
cc =
The frequency stays the same so,
medium
medium
n
=
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COMMON UNITS FOR WAVELENGTH
1 micrometer = 10-6 m
1 nanometer = 10-9 m
1 angstrom = 10-10 m
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Example 1.1 (Calculate energy of photons)
Frequency
(Hz)
Photon
energy in J
Energy inelectron
volts
Number ofphotons in a
joule of energy
Short radio
waves
=1076.6310-27 4.110-8 1.51026
Visible light
waves=1015
6.6310-19
4.1 1.51018
X-rays
=1018 6.6310-16 4.1103 1.51015
Gamma
rays
=1020
6.6310-14 4.1105 1.51013
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THERMAL RADIATION
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1.6 Geometrical Considerations
1.6.1 Normal to a Surface Element
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1.6.2 Solid Angle
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Example 1.2
Derive formula for calculating the length of an arc andthe circumference of a circle.
dRds =
( ) ==2
1
12
RdRs
Plane anglein radiance
radiansinanglePlaneRadiusarcanofLength =
2circletheofnceCircumfere =R
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Derive formula for calculating the area of a sphere
dRdA = 2
( ) ==2
1
12
22
RdRA
The solid angle
in steradians
( ) steradiansinangleSolidRadius
spheretheofpartaofArea
2
=
=
How to calculate the solid angle?
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How to calculate the solid angle?
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2R
dAd s=
( ) ( ) ddRdRdRdAs == sinsin2
How to calculate the solid angle?
ddd = sin
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Now we can complete the integration since we know
how to calculate the solid angle:
===
ddRdRA2
1
2
1
2
1
sin22
( ) ( ) ==2
1cos122 R
( ) )cos(cos 21122 =R
22 2)01(2e)(hemispherArea RR ==
Solid angle for a hemisphere is 2
Solid angle for a sphere is 4
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1.6.3 Area and Projected Area
cos=dAdAP
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1.6.4 Radiation Intensity and Irradiation
msrm
Wi
)AreaProjected(inintensityspectraltheis 2
'
indicates direction
srm
Wi
)AreaProjected(inintensitytotaltheis
2
'
=0
'' dii
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Irradiation
=directionsall
' cos),,( dig&
= =
==
2
0
2/
0
' sincos),,( ddig&
for isotropic incoming radiation
==2/
0
' )2()2sin(2
1
dig&
[ ] '2/0
' )2cos(2
1
ii ==
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1.7.1 Black Body RadiationReal surfaces (bodies)
gggg &&&& ++=
reflectivity
absorptivity
transmissivity
1.7 Governing Laws for Thermal Radiation
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BLACK BODY RADIATION
Definition of a black body
A black body is defined as an ideal body that all
incident radiation pass into it and internally absorbs
all the incident radiation.
This is true for radiation of all wavelengths and for all angles
of incidence
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BLACK BODY RADIATION
Properties:
Black body is a perfect emitterIn a black body enclosure radiation is isotropic
Black body is a perfect emitter in each direction
Black body is a perfect emitter at any wavelength
Total radiation of a black body into vacuum is a
function of temperature only
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===hemisphere
b
hemisphere
bbb ididie''' coscos &
The angular distribution of radiation intensity
emitted by a black body
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1.7.2 Plancks Radiation Law
1
1),(),(
/5
1'
2
==
TCbb e
CTiTe
&
216
1 mW107418.3 =
C
Km01438769.1 2
2
= C
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Plancks Radiation Law
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Plancks Radiation Law
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( ) 1
1),(/2
5
1
5
=TC
eT
C
T
Te b
&
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See Example 1.4 of the lecture notes to understand
the meaning of:
Frequency distribution
Cumulative frequency distribution
Relative cumulative frequency distribution
E l 1 4
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156
163
170
177
184
191
198205
4
12
18
25
33
22
115
TOTAL 130
153-159
160-166
167-173
174-180
181-187
188-194
195-201202-208
Class mark
(cm)
Number of
students-Frequency
Height per
class (cm)
Example 1.4
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Histogram and frequency polygon of heights of 130 students
Example 1.4
149 156 163 170 177 184 191 198 205 2120
5
10
15
20
25
30
35
f(x)
QP
Nu
mberofstudentsperheight
Height (cm)
Example 1 4
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=+++++++==Q
P
dxxfArea 130)51122332518124()(
classtheofwidththeis7cm=
(130)studentsofnumbertotaltheArea
Example 1.4
Example 1 4
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0
4
16
34
59
92
114125
130
Less than 153 cm
Less than 160 cm
Less than 167 cm
Less than 174 cm
Less than 181 cm
Less than 188 cm
Less than 195 cmLess than 201 cm
Less than 208 cm
Number of studentsHeight (cm)
Cumulative distribution
(less than the upper class boundary)
Example 1.4
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Example 1 4
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Cumulative distributionExample 1.4
150 160 170 180 190 200 210
0
20
40
60
80
100
120
F(x)Cu
mulativeFreq
uency(No.of
Students)
Height (cm)
0.0
0.2
0.4
0.6
0.8
1.0
F
(x)RelativeCumulativeFre
quency
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1.7.3 Wiens Displacement Law
We are looking for a wavelength that maximizesthe Plancks function for a given temperature
( )1
/51/5
1 11
1),( 22
==
TCTCb eC
eCTe &
( ) += 1/
6
1
1)5(2 TCb
e
C
d
ed
&
( ) ( ) 0)1(1)1( 22/2/5
1 22 =+
T
Cee
C TCTC
( )TC
e
CT
=
/
2
21
1
5
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( )22
/
1
( ) 5 1 C T
C
f T Te =
0.000 0.002 0.004 0.006 0.008 0.010
-0.010
-0.005
0.000
0.005
0.010
(C3-Wien's constant)
max
T = 0.0028977756 mK
T in mK
f(
T)in
mK
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Wiens Law
Km2,898C3max ==T
1.7.4 Stefan-Boltzmann Law
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1.7.4 Stefan Boltzmann Law
==0
?),( dTee bb &&
( )204 3
1 1
4/520
11b C T
C T C
e d dC ee
= = & TC
= 2
0 3
1 15d
e
=
44
4
2
1
15TT
C
Ceb ==
&
8 2 45.67 10 W/(m K ) = Stefan-Boltzmann
constant
1 8 Bl kb d R di ti i W l th I t l
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1.8 Blackbody Radiation in a Wavelength Interval
=
=
2
1
2
1
21),(
1
),(
),(
4
0
_
dTe
TdTe
dTeF TT &
&
&
21
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=
=2
1
21),(
14_
dTe
T
F bTT &
TTbb FFdTedTeT 12
2 1
_0_0
0 0
4),(),(
1
=
= &&
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2 1
1 2 2 1_ 0_ 0_5 50 0
( , ) ( , )1( ) ( )
T T
b b
T T T T
e T e T F d T d T F F
T T
= =
& &
1 9 Bl kb d E i i i M di O h h V
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1.9 Blackbody Emission into a Medium Other than Vacuum
21
21 /2 nCchC mm == nCk
chC mm /22 =
=
n
ccm = nm
=
11),(
/5
1
2 =
TCbe
CTe
&
),(),( 3 TenTe bmmb && =
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Stefan-Boltzmann Law
42Tnebm = &
Wiens Displacement Law
n
CTn
3max, =
1 10 i i O i i f Q i
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1.10 Historical Note Origin of Quantum Mechanics
1 Th h ll i
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1
1),(
/5
=Tbb e
aTe
&
The challenge was in
deriving a and b constantsfrom the first principle
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Quantification of energy (Max Planck 1990)
vhmE =
m=1,2,3,... quantum number
Ten years later Planck wrote:
My futile attempts to fit the elementary quantum of
action (h) somehow into the classical theory continued for
a number of years, and they cost me a great deal of efforts
In 1905 Albert Einstein made an assumption
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the energy of a light was concentrated into
localized bundles later called photons
=hEPlanck, the originator of the h constant, did not acceptat once Einsteins photons. In 1913 Planck wrote about
Einstein that he sometimes have missed the target in his
speculations, as for example in his theory of light quanta,
cannot really be held against him
In 1918 Planck received a Nobel prize for his discovery
of energy quanta
In 1921 Einstein received his Nobel prize for his service to
theoretical physics and specially for discovery of the law of
photoelectric effect
1 12 Summary
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1.12 Summary
Students should understand:
The concepts of radiation intensity and emissive power
The radiation laws for black-body radiation
Plancks law
Wiens law
Stefan-Boltzmann law