6.3 tests for parallelograms

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Page 1: 6.3 Tests for Parallelograms

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Five-Minute Check (over Lesson 6–2)

CCSS

Then/Now

Theorems: Conditions or !"r"##e#o$r"ms

!roo: Theorem 6%&

'"m#e *: +denti, !"r"##e#o$r"ms

'"m#e 2: e"#-.or#d '"m#e: se !"r"##e#o$r"ms to !rovee#"tionshis

'"m#e 0: se !"r"##e#o$r"ms "nd 1#$er" to Find 3"#uesConcet Summ"r,: !rove th"t " 4u"dri#"ter"# +s " !"r"##e#o$r"m

'"m#e 5: !"r"##e#o$r"ms "nd Coordin"te eometr,

'"m#e 7: !"r"##e#o$r"ms "nd Coordin"te !roos

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8ver Lesson 6–2

1%

9%

C%

 ____ ?

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8ver Lesson 6–2

1%

9%

C%

?

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8ver Lesson 6–2

1%   A

9% 

B

C%  C 

?

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8ver Lesson 6–2

1n e"nd"#e $"te is m"de o "r"##e#o$r"ms th"th"ve "n$#es th"t ch"n$eme"sure "s the $"te is"dusted% .hich o the

o##owin$ st"tements is"#w",s true;

1%   ∠ A ≅ ∠C  and ∠B ≅ ∠D

9%   ∠ A ≅ ∠B and ∠C  ≅ ∠D

C%

<%

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Content St"nd"rds

G.CO.11 Prove theorems about

parallelograms.G.GPE.4 Use coordinates to prove simplegeometric theorems algebraically.

M"them"tic"# !r"ctices

Construct viable arguments and criti!uethe reasoning o" others.

# $eason abstractly and !uantitatively.

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%ou recogni&ed and applied properties o"parallelograms.

' $ecogni&e the conditions that ensure a

!uadrilateral is a parallelogram.' Prove that a set o" points "orms a

parallelogram in the coordinate plane.

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+denti, !"r"##e#o$r"ms

<etermine whether the =u"dri#"ter"# is ""r"##e#o$r"m% >usti, ,our "nswer%

1nswer:Each pair o" opposite sides has the samemeasure. (here"ore) they are congruent.*" both pairs o" opposite sides o" a!uadrilateral are congruent) the !uadrilateralis a parallelogram.

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1% 9oth "irs o o% sides ??%

9% 9oth "irs o o% sides %

C% 9oth "irs o o% s %

<% 8ne "ir o o% sides oth?? "nd %

.hich method wou#d rove the=u"dri#"ter"# is " "r"##e#o$r"m;

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se !"r"##e#o$r"ms to !rove

e#"tionshis

M'C@1N+CS  Scissor #itsA #ikethe #"torm #it shownA "recommon#, "#ied to too#sintended to #it he"v, items% +n the

di"$r"mA  A  C  "nd B  D%'#"in wh, the consecutive"n$#es wi## "#w",s esu#ement"r,A re$"rd#ess o thehei$ht o the #"torm%

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se !"r"##e#o$r"ms to !rove

e#"tionshis

1nswer: +ince both pairs o" opposite angles o"!uadrilateral ABCD are congruent) ABCD isa parallelogram by (heorem ,.1-. (heorem,. states that consecutive angles o"

parallelograms are supplementary.(here"ore) m∠ A / m∠B 0 1- andm∠C  / m∠D 0 1-. 2y substitution)m∠ A / m∠D 0 1- and m∠C  / m∠B 0 1-.

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The di"$r"m shows " c"r "ck used to r"ise " c"rrom the $round% +n the di"$r"mA  AD  BC  "nd AB  DC % 9"sed on this inorm"tionA whichst"tement wi## e trueA re$"rd#ess o the hei$ht o

the c"r "ck%1%   A  B

9%   A  C 

C%   AB  BC 

<%   m  A B m C   *DE

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se !"r"##e#o$r"ms "nd 1#$er" to Find 3"#ues

Find  x  "nd y  so th"t the =u"dri#"ter"# is ""r"##e#o$r"m%

Opposite sides o" a parallelogram are congruent.

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se !"r"##e#o$r"ms "nd 1#$er" to Find 3"#ues

+ubstitution

3istributive Property

 dd 1 to each side.

+ubtract  x  "rom each side.

 AB = DC 

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se !"r"##e#o$r"ms "nd 1#$er" to Find 3"#ues

1nswer: +o) 5hen x  0 6 and y  0 ) !uadrilateral ABCD is a parallelogram.

+ubstitution

3istributive Property

 dd # to each side.

+ubtract y  "rom each side.

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1%   m  2

9%   m  0

C%   m  6

<%   m  D

Find m so th"t the =u"dri#"ter"# is " "r"##e#o$r"m%

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!"r"##e#o$r"ms "nd Coordin"te eometr,

C88<+N1T' '8M'T 4u"dri#"ter"# QRST  h"s verticesQ (–*A 0)A R (0A *)A S (2A –0)A "ndT (–2A –*)% <etermine whether the=u"dri#"ter"# is " "r"##e#o$r"m%>usti, ,our "nswer , usin$ theS#oe Formu#"%

*" the opposite sides o" a !uadrilateral are parallel)

then it is a parallelogram.

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!"r"##e#o$r"ms "nd Coordin"te eometr,

1nswer: +ince opposite sides have the same slope)QR 7ST  and RS7TQ. (here"ore) QRST  is aparallelogram by de"inition.

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1% ,es

9% no

r"h =u"dri#"ter"# EFGH  with vertices E (–2A 2)AF (2A E)A G (*A –7)A "nd H (–0A –2)% <etermine whetherthe =u"dri#"ter"# is " "r"##e#o$r"m%

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!"r"##e#o$r"ms "nd Coordin"te !roos

.rite " coordin"te roo or the o##owin$st"tement%

*" both pairs o" opposite sides o" a !uadrilateral arecongruent) then the !uadrilateral is a parallelogram.

8 2egin by placing the verte9 A at the origin.

Ste * Position !uadrilateral ABCD on the coordinateplane such that AB ≅ DC  and AD ≅ BC .

8 :et AB have a length o" a units. (hen B hascoordinates ;a) -<.

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!"r"##e#o$r"ms "nd Coordin"te !roos

8 +o that the distance "rom D to C  is also a units) letthe x =coordinate o" D be b and o" C  be b / a.

8 +ince AD ≅ BC, position the endpoints o" DC  so thatthey have the same y =coordinate) c .

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!"r"##e#o$r"ms "nd Coordin"te !roos

Ste 2 Use your "igure to 5rite a proo".

iven: !uadrilateral ABCD) AB ≅ DC ) AD ≅ BC 

!rove:   ABCD is a parallelogram.

Coordin"te !roo:

2y de"inition) a !uadrilateral is a parallelogram i"opposite sides are parallel.

Use the +lope >ormula.

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!"r"##e#o$r"ms "nd Coordin"te !roos

1nswer: +o) !uadrilateral ABCD is a parallelogrambecause opposite sides are parallel.

+ince AB and CD have the same slope and AD and BC  have the same slope) AB7CD and AD7BC .

(he slope o" CD is -.

(he slope o" AB is -.

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.hich o the o##owin$ c"n e used to rove thest"tement e#ow;*" a !uadrilateral is aparallelogram) then one pair o"opposite sides is both parallel and

congruent.1%   AB 0 a units and DC  0 a units

slope o" AB 0 - and slope o"DC  0 -

9%   AD 0 c  units and BC  0 c  units

slope o" and slope o" 

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