4/15/2013 (periods 1,3, & 5) 4/16/2013 (periods 2 & 6) Standards: 5 (Acids and Bases)Objectives: ●  Complete CST 83-90 ●  Students will be able to simplify ugly looking calculationsDO NOW: 1. After turning in HW, Get responders and sign-in 2. Review how to calculate a log using my simple estimating log chart 3. CST Problems 83-90 with responders (practice)HOMEWORK: NONE===========================================================TURNED IN:   ●  Journal 4/12 (what you learned about how to calculate

the log of a number with a power of 10) 1. Ch 19.3 Ch 19.2 p. 611-613 19 (a,b,c); 20 (a,b,c) (5 pts) Std 4 2. CST Problems 77-82 (5 pts) Std MISC (KEEP FOR

NOTEBOOK)

For 4/16, see whiteboard for 4/15

4/17/2013 Standards: 5 (Acids and Bases)Objectives: ●  Students will be able to calculate pH of solutions of STRONG acids or

bases give the concentration of the STRONG acids or bases ●  Students will be able to "file dump" for CST ●  Students will be able to do neutralization problemsDO NOW: 1. Copy the file dump page HOMEWORK: 1. Ch 19.3 p. 614 22 (a,b,c,d); p. 616 24-26; p. 621 30,31,32 (5 pts) Std 5 ===========================================================NO STAMPING:   ●  Journal 4/15 OR 4/16

(what you learned about simplifying

calculations on CST) (KEEP FOR

NOTEBOOK)

1 2 3 4 5 6 7 8 9 10

0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00

# left of10x# left of10x

log of

File dump for CST

LeChatstress LeChat

wantsLeChatdoes shift

Conversionsg <----> mol <----> atoms/molecules

chart Avo

Diatomicelements NOH on 17

↑↓

Trends

electronegativityionization energy

atom sizeion size

mass metal non-metreactivity

vertical & horiantal arrows loose

Review of calculating

pH & pOH

Multiply 2 x 2 = 4

1 x 10-2

1 x 10-3

1 x 10-4

1 x 10-5

1 x 10-6

1 x 10-7

1 x 10-8

1 x 10-1

1 x 10-9

= 0.1

= 0.01

= 0.001

= 0.0001

= 0.00001

= 0.000001

= 0.0000001

= 0.00000001

= 0.000000001

Exponent Increases # left of 10x increases

1 x 10-9 = 0.0000000012 x 10-9 = 0.0000000023 x 10-9 = 0.0000000034 x 10-9 = 0.0000000045 x 10-9 = 0.0000000056 x 10-9 = 0.0000000067 x 10-9 = 0.0000000078 x 10-9 = 0.0000000089 x 10-9 = 0.00000000910 x 10-9 = 0.000000010 = 1 x 10-8 1 x 10-8 = 0.000000012 x 10-8 = 0.000000023 x 10-8 = 0.000000034 x 10-8 = 0.000000045 x 10-8 = 0.000000056 x 10-8 = 0.000000067 x 10-8 = 0.000000078 x 10-8 = 0.000000089 x 10-8 = 0.0000000910 x 10-8 = 0.00000010 = 1 x 10-7

1 x 10-7 = 0.00000012 x 10-7 = 0.0000002

= 1.0 x 10-6

= 1.0 x 10-8

1 x 10-9 ------------> 10 x 10-9

1 2 3 4 5 6 7 8 9 10

0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00

# left of10x

# left of10xlog of

PATTERN for # left of 10x and the the log of those numbers

1 x 10-7 ------------> 10 x 10-7

1 2 3 4 5 6 7 8 9 10

0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00

# left of10x

# left of10xlog of

1 x 10-8 ------------> 10 x 10-8

= 1.0 x 10-7

1 x 10-6 ------------> 10 x 10-6

= 1.0 x 10-5

CONTINUED

1 2 3 4 5 6 7 8 9 10

0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00

# left of10x

# left of10xlog of

1 2 3 4 5 6 7 8 9 10

0.00 0.30 0.48 0.60 0.70 0.78 0.85 0.90 0.95 1.00

# left of10x

# left of10xlog of

What is the take away of this exercise?

3 x 10-6 = 10-5.52

6 - .48 = 5.52 = -log of the number

-log of 3 = .48

= ph or pOH

= ph or pOH(6 - .48 = 5.52)

STRONG ACIDS AND BASES

IONIZE 100%

IONIZE 100%

strong acids(memorized)

strong bases

(Gp 1 or Gp 2with OH1-)

HCl -----> H1+ + OH1-

ionize 100%

HClHNO3

HClO4

H2SO4

H3PO4

H Cl

gas(one piece)

ion ion

M1V1a = M2V2b

4/18/2013 Standards: Biology - NCLB practiceObjectives: ●  Students will perform well for the State NCLB Bio Test DO NOW: 1. Read the NCLB background and answer as many of the questions as

you can. Practice Quiz due end of period, you keep background notes.HOMEWORK: 1. ===========================================================TURN IN:   ●  Journal 4/17

(Calculating pH & pOH)

(KEEP FOR NOTEBOOK)