4 fuel calculations basics
DESCRIPTION
RICKMERS FUEL CALCULATIONSTRANSCRIPT
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Fuel oil calculation Basics-SFOC-Speed - consumption
Energy efficiency training 2012
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How much is one gram?
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If SFOC of a single MPC vessel is increased by 1g/kWh, how much does the annual fuel consumption increase?
1. A) The effect is negligible
2. B) 10t
3. C) 25t
4. D) 45t
How much is one gram?
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How much is one gram / kWh?
> Annual energy production MPC Class:
> Main engines ~ 40,000 MWh
> Auxiliary engines ~ 5,000 MWh
Total ~ 45,000 MWh
> 45,000,000 kWh/a * 1 g/kWh = 45,000 kg/a
> 45 t/a * 750$/t = 33,750 $/a
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Value of 1 g/kWh is about 35,000 $/a
(per each MCC7S60 ME)
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Worst case scenario
The diesels could be +25..30 g/kWh from optimum
25 g/kWh * 45 000 000 kWh/a = 1125 t/a
1125 t/a * 750 $/t = 843 750 $/a
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Calculation Example
Consider a Superflex Heavy MPC vessel is to travel a distance of2160nm on design load on normal sea conditions.
Which option is more fuel efficient?
A) 18kn for 5 days and then wait 2 days.
B) Constant speed for 7 days.
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Calculation Exercise, source data
SFOC ME 175g/kWh
15% sea margin
AE fuel consumption 3t/d
Speed-Power curve ->
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Calculation Exercise, solution – Step 1
Required ME power in case A (including sea-margin):
6750 * 1,15 = 7762,5kW
Required kWh in case A:
7762,5kW * 24h * 5 = 931 500 kWh
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Calculation Exercise, solution – Step 2
In case all 7 days would be used for sailing, the required speed would be:
2160nm / (24h * 7) = 12,9 kn
Required ME power in case B (including sea-margin):
2400 * 1,15 = 2760kW
Required kWh in case B:
2760kW * 24h * 7 = 463 680 kWh
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Calculation Exercise, solution – Step 3
Consumed fuel in case A:931 500 kWh * 190g/kWh / 1 000 000 = 177 t
Consumed fuel in case B:463 680 kWh * 200g/kWh / 1 000 000 = 93 t
Difference: 84t (or 47%, or $ 59 000)
Auxiliary Engine consumption similar in both cases
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The end