216 s11-e2 page 2 name key - university of michiganchem216/216 s11 e2-key.pdf · 216 s11-e2 page 2...
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216 S11-E2 Page 2 Name ________Key______________ I. (9 points) Answer in the boxes below the following questions for the Grignard reagent CH3-MgBr. (1) (2 points) Is the carbon atom associated with magnesium electrophilic or nucleophilic?
electrophilic nucleophilic
[circle one] (2) (3 points) Explain why the Grignard reaction has to be carried out in an anhydrous solvent.
The Grignard reagent produced would be destroyed by the reaction with water present in a non-anhydrous solvent.
(3) (4 points) Write the conjugate carbon acid (i.e., C-H) of the CH3– MgBr and explain why Grignard reagents are strong bases.
structure: explanation:The pKa of CH4 is ca. 50. Therefore, its conjugate base is highly basic.
H C HH
H II. (6 points) Ethyl alcohol (C2H5OH) quite often is present in technical-grade diethyl ether. If this grade of diethyl ether were used, what effect, if any, would the ethyl alcohol have on a Grignard reagent used? Explain using a chemical equation using methylmagnesium bromide as an example.
explanation based upon the reaction mechansim:
A Grignard reagent formed would deprotonate H of the ethyl alcohol OH.
R MgBr
H OCH2CH3R H BrMg OCH2CH3+
III. (8 points) For each of the reactions below, draw in the boxes provided the structure of the expected major organic product.
4
Br
CH3
O
Mg (1.1 mol equiv) ether
aq NH4Cl(acidic workup)
4
Br
H3CCH3
O
aq NH4Cl(acidic workup)
+ enantiomer
+ enantiomer
2.
1. Mg (1.1 mol equiv) ether
(1.1 mol equiv)
(1)
(2)
OH
OH
MgBr
O
216 S11-E2 Page 3 Name _______Key_______________ IV. (16 points) For the following reaction sequence, draw the correct structures in the boxes provided.
Ph3P: Br CH3
O+
note: Ph = C6H5
benzene, reflux
"salt"
4
NaOC2H5 /C2H5OH
+ NaBr + C2H5OH
O
H
H
H
dichloromethaneroom temperature
4major isomer: C12H12O
4minor isomer: C12H12O
+
+
(C18H15P)
C21H19PO (ylide)
Ph3P=O
4
Ph3P CH3
OBr
Ph3PCH3
O
H
H
H
CH3
O
H
H
H
HH
O CH3
trans
cis
V (12 points) Show how many peaks you would expect to observe in the proton-decoupled 13C NMR spectrum of each of the following compounds. Indicate your answers in the boxes provided.
HO
CH3
COOH
COOH
(2) (3)
(4) (5)
-OOC S
S
NH3+
(1)
(6)O
OO
CH3
CH3
H3C
H3CCOOH
COOH
CH3H3C
O
O
7
55
6 7
6
180° rotation
chiral center!
CO2HCO2Hcis
216 S11-E2 Page 4 Name ________Key_____________ VI. (5 points) The proton NMR spectrum of a mixture of acetonitrile (CH3C≡N), methylene chloride, (CH2Cl2) and benzene (C6H6) is integrated and results in step heights of 15, 6, and 18 mm for the signals at δ 2.10, 5.30, and 7.26 ppm, respectively. In what mole ratio are the three substances present? No explanation required. No partial credit will be given to this problem.
acetonitrile : methylene chloride : benzene = : :153
62
186
: :5 3 3
VII. (8 points) For each of the reactions given below, draw in the box the structure of the expected product. Make sure to indicate the stereochemistry of the product whenever applicable.
4
OCH3
endo product
+ enantiomerO
O
O
+CH2Cl2
(solvent)room temperature
(1)
4endo product
+ enantiomer+CH2Cl2
(solvent)room temperature
(2)
H
H3C
O
O
O
O
CH3OHH
H
H
CH3O
H
H H
H OHCH3
or
VIII. (10 points) Provide in the box below a step-by-step, curved-arrow mechanism for the formation of hydroxy acid 2 from diketone 1. Make sure to include the mechanism for the acidic workup as well.
O
O
OH
OH
O
mixture of stereoisomers here
1 2
KOH ( 4 mol equiv)H2O
reflux
H3O+
to pH = 1.0
O
O1 OH
O
OHO
OO H
O
OH
OO
O H OH
H
OO
OH
HOH
H
2
O
O1
OHThis is fine, too.
mech arrows: 1 ptmech arrows: 2 pts
mech arrows: 1 pt
mech arrows: 1 pt
mech arrows: 1 pt
interm str: 1 pt each
216 S11-E2 Page 6. Name __________________________ IX. (continued)
O
O
O
O
O
O
Br O
OO
O
A B C D
E F G H
X. (15 points) On the basis of its spectroscopic information provided below, propose the structure for the compound, C5H12O. Draw the proposed structure in the box on page 7 and give a brief explanation as to how the structure is deduced from the spectroscopic information provided.
10
Explanation (just assign the IR peak at 3368 cm-1 and all H-1 peaks right next to thecorresponding functional group/H-1 nuclei):
5
Structure:
H3C
C
H3C
C
CH3
OHH
H
chiral center!diastereotopic
methyls
0 unit of unsaturation
H3C
C
H3C
C
CH3
O
H
H
1.92 ppm
1.3 ppm (doublet)
1.6 ppm (octet)
3.55 ppm(multiplet)
0.88 ppm(doublet)
0.92 ppm(doublet)
H
3368 cm-1
216 S11-E2 Page 8 Name ________Key_____________ XI. (15 points) On the basis of its spectroscopic information provided below, propose the structure of the compound, C10H16O4. Draw the proposed structure in the box on page 9 and give a brief explanation as to how the structure is deduced from the spectroscopic information provided. Make sure to assign all proton and C-13 NMR peaks.
216 S11-E2 Page 9 Name ________Key_____________ XI. (continued)
10
Explanation (just assign the strongest IR peak and all H-1 and C-13 peaks right next to thecorresponding functional group/H-1, C-13 nuclei):
5
Structure:
H3C
H3C
OCH2CH3
OCH2CH3
O
O
CH3H3C
O OOCH2CH3CH3CH2O
CH3
H3CO
OCH2CH3
OCH3CH2O
These should show only one sp2
alkene C-13 peak. => -1 point
H3C
H3C
OCH2CH3
OCH2CH3
O
O
1725 cm-1
Units of unsaturation: 3; only 6 C-13 peaks!
125 ppm156 ppm
22 ppm
167 ppm
14 ppm
60 ppm
1725 cm-1
1.2 ppm
14 ppm2.0 ppm
2.0 ppm
4.2ppm
4.2 ppm