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TRANSCRIPT
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Introduction to Rock Mechanics
ENB371: Geotechnical Engineering 2ENB371: Geotechnical Engineering 2
Chaminda GallageChaminda Gallage
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Outline of the lecture Introduction
Rock formation and rock types
Rock Classification Engineering Classification more focused on applications
Shear strength of discontinuities
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Introduction -1Rock mechanics adopts many of the techniques developed in soilmechanics such as: Mohr Coulomb law
But, the behaviour of rocks is far more complex than the behaviour of
soils, in many cases rock mechanics uses techniques unknown to soilmechanics.
Rock mechanics deals with properties of rock and special
methodology required for design for rock related components ofengineering schemes
The rock considered in rock mechanics is in fact the rock mass, which
composes intact rock materials and rock discontinuities.Rock discontinuities dominate the mechanical and engineering
behaviours of rock. The existence of discontinuity depends on the
scale. The discontinuous nature and scale dependence feature is notcommon in other man-made materials.
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Introduction -2
Rock mechanics is applied to various engineering disciplines:
Civil
Mining
Hydropower
In civil engineering, it involves:
FoundationSlope
Tunnel.
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Intact rock and Rock mass
Intact rock: This isthe smallest elementof rock block not cut
Introduction -3
y any rac ure.
Rock mass: In-situ
rock together with itsdiscontinuities andweathering profile.
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Intact rock
Intact rock
Introduction -4
texture etc.)
Mechanical properties (eg. UCS, PointLoad Index etc.)
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Rocks are divided into three groups according totheir origin
Igneous Rocks Metamorphic Rocks
Rock types and their formation -1
ROCK CYCLEa scheme that represents the processes of
continuous changes that connect the three major groups of
rocks:
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Rock Cycle
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IGNEOUS ROCKS are formed when hot molten rock
material, called magma, solidifies
These samples represent igneousThese samples represent igneous
rocks, although each exhibitrocks, although each exhibit
different textures.different textures.
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Sedimentary Rocks
Sediments are formed by weathering (mechanical,chemical) of rocks and by organic matters (animal, trees)
Sediments are transported and deposited in layers
Sediments can harden into sedimentary rock by Pressure(weight of above layers) and cementation (mineral dissolved
in water).
Sedimentary rock covers about three-quarters of continentalareas and most of the sea floor
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Sedimentary rocks are typically layered,(although layering is not diagnostic of only
sedimentary rocks)
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Metamorphic rocks form deep in the earth where high temperature,
great pressure, and chemical reactions cause one type of rock to change
into another type of rock
Metamorphic rocks begin to form at 12-16 km beneath the earth'ssurface.
They begin changing at temperatures of 100- 800 0C for a few million
ears it can turn into a new kind of rock
Metamorphic Rocks
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Metamorphic Rocks
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Rock mass classification
During preliminary design stages of a project, when very little detailed
information on the rock mass and its stress and hydrological characteristics
is available, the rock mass classification schemes can be used to provide
initial estimate of support requirements, and to provide estimates of strengthand deformation properties of the rock mass
Why do we require rock classification?
Stability of rock slopes- civilengineering
Tunnel design
Petroleum engineering- extractionof crude oil and natural gas
Underground and open cut mining
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Rock mass classifications are based
on the following parameters:Quality of rock
Intact rock strengthFracture spacing, orientation
Fracture roughness
Fracture condition (eg. tight or loose)
Wet or dry conditionGeology
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Site investigationWe carry out site investigations
to determine the quality of rockbeneath the soil.
How to measure parameters required for rock classification?
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Rock Quality Designation Index (RQD)
How to measure parameters required for rock classification?
(After Deere, 1989)
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Correlation between RQD and RockMass Quality(after Deere, 1968)
RQD (%) Rock Quality
< 2 V r r
25 - 50 Poor
50 - 75 Fair
75 - 90 Good
90 - 100 Excellent
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Example for RQD
From a core run of 1.50 m, the total core
recovery was 1.25 m as shown in the
figure. Calculate RQD for the rock core
sample and identify the quality of therock mass.
50
250
75
100
125
50
10015
0100
50
125
100runcoretheoflengthTotal
cm10piecescoreofLength
>
=
RQD
1001500
)125150100125100250(
+++++=RQD
%57=RQD Rock quality: Fair
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Measurement of intact strength
Unconfined compressive strength (UCS or qu) Point load index test - UCS = 24 Is(50)
Correlation factor may vary for certain rock types.
How to measure parameters required for rock classification?
comparative study.
Is = P/D2
Triaxial strength tests - high pressure steel cells.
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UCS apparatus Rock specimens normally tested
under compression. No lateral confining pressure
M ximum m r iv tr t
How to measure parameters required for rock classification?
rock
failure is known as UCS
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Point Load Tester
According to Brook (1985), the formula to
convert the force reading to Is(50) value is asfollows:
I = FP / D 2
UCS = 24 Is(50)
s e
Where
F = size correction factor = (De/50)0.45
P = applied load (MN)
De = (4A/)0.5
A= minimum cross sectional area of the specimen (m2)
The units of the point load index are MPa and whereas the test is
considered to cause tensile failure
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Triaxial Test High pressure
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Rock strength Laboratory estimationStrength class
Extremely High (EH)
Very High (VH)
Unconfined CompressiveStrength (UCS), MPa
>250
100-250
High (H)Medium High (MH)
Weak (W)
Very Weak (VW)
Extremely Weak(EW)
50-10025-50
5-25
1-5
0.6*-1
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Direct shear apparatus for rock
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Rock mass classification systems
The two most widely used rock mass classifications are:
Rock Mass Rating (RMR) Bieniawski (1984), ISRM1978
Rock mass Quality (Q system) NGI (1974)
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RMR classification
RMR classification is based on the following 6
parameters: UCS of intact rock
RQD
Joint spacing Joint condition (eg. tight, rough?)
Ground water condition, and
Joint orientation (eg. dip angle)
RMR = relevant ratings
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G id li f i d f 10 k l RMR
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Guidelines for excavation and support of 10 m span rock tunnels- RMR
system
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E l f RMR
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Example for RMRA tunnel is to be driven through weathered granite rock. It has a joint set of 59degrees against
the tunnel direction. The point load index of 8MPa and RQD value of 73% were estimated.The joints are spaced at 390mm. They are slightly rough and slightly weathered with a
separation of
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Rock mass quality (Q) system
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E i l t Di i (D )
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Equivalent Dimension (De)
Oth U f l E ti
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Other Useful Equations
Permanent roof supportpressure
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Shear Strength of RockDiscontinuities
Introduction
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All rock masses contain discontinuities such as bedding planes, joints,
shear zones and faults
Rock mass failure is controlled by sliding on the discontinuities
To analyses the stability of individual rock blocks, it is necessary to
understand the shear strength of discontinuities of rock which separate
Shear Strength of Planar Surfaces
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gBedding surface is planar having no surface irregularities or undulations.
Filling material presents between two surfaces.
anglefrictionResidualstrength,shearResidual
firctionofanglesurface,ceentedofCohesioncstress,Normalstrength,shearPeak
rr
n
==
====
p
The Basic Friction Angle b
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The Basic Friction Angle b Shear strength of smooth rock surfaces without any filling materials
between them
r = n tan b
The roughness component (i) is then added to basic friction angle(b) to get effective friction angle of the discontinuities
Typical Values
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Typical b Values
Shear Strength of Rough Surfaces
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Shear Strength of Rough Surfaces
After Patton (1966)
r = n tan (b + i),
where i = slope of the asperity = tan-1
(v/h) atmaximum dilation
Bartons Equation for i
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q
i = JRC log (JCS/n)where n = mean effective normal stress acting on the joint surface
JRC = Joint roughness coefficient
JCS = Joint wall compressive strength (JCS UCS)UCS = Unconfined (uniaxial) compressive strength
Field Estimate of JRC -1
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The joint roughness coefficient (JRC) can be estimated by comparing the appearance of
discontinuity surface of rock with standard profile published by Barton & Choubey
(1977).
Field Estimate of JRC -2
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As an alternative method, the joint roughness coefficient (JRC) can be estimated by
measuring amplitude of asperity Barton (1982).
Field Estimate of JCS ( UCS)
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The joint compressive strength (JRC) can be estimated in the field by performing
Schmidt rebound hammer test ( Deere and Miller ,1966).
log JCS = 0.00088 r R + 1.01
R = Schmidt rebound hammer number
r = Unit weight of rock
Scale Effect on JRC and JCS
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J J
Barton and Bandis (1982)
JRCo, JCSo andLo (length) refer to 100 mmlaboratory scale samples andJRCn, andLn refer to in
situ block sizes.
Instantaneous Shear Strength (i, ci ) -1
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g (i , i )
Because of non-linear strength envelope, c an need to be defined fordesign purposes
** When pore water (u) is present in a rock mass, n (normal stress) will be replaced by
effective normal stress (n= n u) in all the equations presented in this topic