# 11 calibration graphfall06

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    A Calibration Graph

    Experiment 11

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    Introduction

    Purpose: To build a calibration graph and

    use it to determine concentration.

    Calibration graph Used to determine

    concentration of an unknown solution bymeasuring the absorption of a solution with

    a known concentration.

    the solution we will be using today isCuSO4

    .5H20

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    Absorption

    Absorption is directly proportional toconcentration.

    Absorption Light is passed through a

    solution, at a particular wavelength. The instrument used to measure

    absorption is a spectrophotometer. The

    device measures the intensity of lightafter it has been projected through a

    sample.

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    Review

    Solute Vs. Solvent

    Molarity Concentration

    M = moles/L of Solution moles= grams/mw

    1L = 1000ml

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    Review # 2

    What would be the concentration if we

    placed that .60 mol of NaCl into 1L of

    water? M=mol/L = .60moles/1L thus .6M NaCl

    Note: does not always have to be 1 L

    # moles in 35 grams of NaCl ?

    NaClmoles60.NaCl58g

    NaCl1mole

    1

    NaCl35g

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    Obtain and crush a small amount of CuSO4.5H20

    Measure accurately 0.04grams of CuSO4.5H20

    Obtain, clean, and label 4 small beakers A-D

    Obtain 1 small graduated cylinder

    In beaker A add your CuSO4 and 20 ml of Di. water

    Under the hood add 8 drops of NH4OH

    Mix Carefully

    Making our calibration graph

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    In B add 10 ml of cylinder A + 10ml of Di

    water plus 8 drops of NH4OH In Cylinder C add 10 ml of cylinder B +

    10 ml of water plus 8 drops of NH4OH

    In Cylinder D add 10 ml of cylinder C + 10ml of water plus 8 drops of NH4OH

    Each cylinder is the concentration of the

    previous cylinder. Each cylinder will be a lighter shade of blue.

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    Set wavelength to 610nm and follow the

    directions on the spec 20.

    Transfer a portion of your sample to test

    tube one for each cylinder.

    Determine the absorbance for each sample.

    How to determine absorbance

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    My Trial

    I Used 0.040g of CuSO4.5H20

    so grams / 20 mL = 0.040g

    and grams /20 mL X10+2 = 4.0

    my second sample is of the CuSO4 from sample #1

    thus 0.020 g

    my third sample of the CuSO4 from sample # 2 thus1.00X10- 2 g

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    Chart on pg 152

    G/20 mL. Is asking for how many

    grams you used. For my trial 0.040g

    G/20 mL.X 10 +2 = 4.0g

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    Chart on pg 152 Continued

    = 8.0 X10 -3 moles CuSO4/ 1L

    For M convert to G/20 mL M/L

    249.60g

    0.04g CuSO4.5H2O

    20 mL 1L

    1000mL 1mol CuSO4.5H 2O

    = M

    M X 103 = 8.0

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    1. Type in Data X data first

    2. Highlight data

    3. Click on Chart Wizard

    4. Use X-Y scatter5. Pick type of graph you want to use

    6. Click next

    7. Add Title and Units for X and Y

    8. Add trend line if required.9. Add your name date and section to

    the worksheet.

    How To make a Graph using Excel

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    Independent Vs. Dependent Variables

    Independent variable We can change this variable.

    Graphed on X axis.

    Dependent variable - We cannot change this variable.We measure the dependent variable as the independent

    changes. Graphed on Y axis. Title of graph should be Independent Vs. Dependent

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    How to place equation of line on graph

    1. Right click on line

    2. Click on add trend line

    3. Click on linear

    4. Click on options5. Click on Display equation on chart

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    Graph #1

    Molarity Vs. Absorbance

    y = 0.0325x + 0.0505

    0

    0.2

    0.4

    0.6

    0 5 10 15

    Molarity (mol/L)X10+2

    Absorba

    nce

    Lou Tisone

    116-30

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    Graph #2

    g/20ml Vs. Absorbance

    y = 0.0649x + 0.0516

    0

    0.2

    0.4

    0.6

    0 2 4 6 8

    g/20ml X10+2

    Absorbance

    Lou Tisone

    116-30

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    If given absorbance (y-axis)

    and need concentration solve

    for (x)

    y=mx +b

    xm

    b-y

    bmxy

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    To Determine M X 10 +3 (from graph)

    My absorbance = .448

    Y= 0.0325X + 0.0505

    Put abs in for Y and solve for X

    12.20MX

    0.0325

    0.0505.448

    This is M X 10 +3

    To determine M simply x10-3 1.22X10-2 M

    The equation of graph # 1

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    Due Next Week

    Calculate mol and M for each sample. Complete chart on page 152 and questions

    1a-d

    Question # 2 Two computerized graphs are required

    (1) Absorbance Vs. Grams/20mL X10+2

    (2) Absorbance Vs. Molarity X10+3

    Place equation of line on graph