x2 t06 04 uniform circular motion (2012)
TRANSCRIPT
![Page 1: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/1.jpg)
Acceleration with Uniform Circular Motion
![Page 2: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/2.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
![Page 3: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/3.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity. constantbealsoocity willlinear veltheofmagnitude the
![Page 4: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/4.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
constantbealsoocity willlinear veltheofmagnitude the
![Page 5: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/5.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
constantbealsoocity willlinear veltheofmagnitude the
A particle moves from A
to P with constant angular velocity.
![Page 6: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/6.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
constantbealsoocity willlinear veltheofmagnitude the
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
![Page 7: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/7.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
![Page 8: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/8.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
![Page 9: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/9.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
v
![Page 10: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/10.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
vv’
![Page 11: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/11.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
vv’
v
![Page 12: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/12.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
vv’
v
![Page 13: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/13.jpg)
Acceleration with Uniform Circular Motion
Uniform circular motion is when a particle moves with constant angular velocity.
Or
A
P
v
constantbealsoocity willlinear veltheofmagnitude the
v’
A particle moves from A
to P with constant angular velocity.
The acceleration of the particle is the change in velocity with respect to time.
vv’
v
OAPsimilar tois
vectorsoftriangleThis
![Page 14: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/14.jpg)
vv’
v
O
rA
r
![Page 15: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/15.jpg)
vv’
v
O
rA
Pr
rv
APv
![Page 16: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/16.jpg)
vv’
v
O
rA
Pr
rv
APv
rAPvv
![Page 17: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/17.jpg)
vv’
v
O
rA
Pr
rv
APv
rAPvv
tva
![Page 18: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/18.jpg)
vv’
v
O
rA
Pr
rv
APv
rAPvv
tva
trAPva
![Page 19: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/19.jpg)
vv’
v
O
rA
Pr
rv
APv
rAPvv
tva
trAPva
arcAPAPΔt ,0asBut,
![Page 20: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/20.jpg)
vv’
v
O
rA
Pr
rv
APv
rAPvv
tva
trAPva
arcAPAPΔt ,0asBut,
trarcAPva
t
0
lim
![Page 21: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/21.jpg)
vv’
v
O
rA
Pr
rv
APv
rAPvv
tva
trAPva
arcAPAPΔt ,0asBut,
trarcAPva
t
0
lim
tvarcAP timespeeddistance
![Page 22: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/22.jpg)
vv’
v
O
rA
Pr
rv
APv
rAPvv
tva
trAPva
arcAPAPΔt ,0asBut,
trarcAPva
t
0
lim
tvarcAP timespeeddistance
rv
rv
trtvva
t
t
2
2
0
0
lim
lim
![Page 23: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/23.jpg)
vv’
v
O
rA
Pr
rv
APv
rAPvv
tva
trAPva
arcAPAPΔt ,0asBut,
trarcAPva
t
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lim
tvarcAP timespeeddistance
rv
rv
trtvva
t
t
2
2
0
0
lim
lim
centrethetowardsdirected
is and magnitude hasmotion
circular uniformin on acceleratithe2
rv
![Page 24: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/24.jpg)
rva
2
Acceleration Involved inUniform Circular Motion
![Page 25: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/25.jpg)
rva
2
2raOR
Acceleration Involved inUniform Circular Motion
![Page 26: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/26.jpg)
rva
2
2raOR
Acceleration Involved inUniform Circular Motion
Forces Involved inUniform Circular Motion
![Page 27: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/27.jpg)
rva
2
2raOR
Acceleration Involved inUniform Circular Motion
rmvF
2
Forces Involved inUniform Circular Motion
![Page 28: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/28.jpg)
rva
2
2raOR
Acceleration Involved inUniform Circular Motion
rmvF
2
2mrFOR
Forces Involved inUniform Circular Motion
![Page 29: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/29.jpg)
rva
2
2raOR
Acceleration Involved inUniform Circular Motion
rmvF
2
2mrFOR
Forces Involved inUniform Circular Motion
e.g. (i) (2003)A particle P
of mass m
moves with constant angular velocity
on a circle of radius r. Its position at time t
is given by;
tryrx
where,sincos
![Page 30: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/30.jpg)
rva
2
2raOR
Acceleration Involved inUniform Circular Motion
rmvF
2
2mrFOR
Forces Involved inUniform Circular Motion
e.g. (i) (2003)A particle P
of mass m
moves with constant angular velocity
on a circle of radius r. Its position at time t
is given by;
tryrx
where,sincos
.on acting magnitude of force radial inwardan is e that therShow a) 2
Pmr
![Page 31: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/31.jpg)
y
x
P
r
cosrx
sinry
![Page 32: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/32.jpg)
y
x
P
r
cosrx
sinry
cosrx
![Page 33: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/33.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
![Page 34: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/34.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
![Page 35: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/35.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
![Page 36: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/36.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
![Page 37: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/37.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
![Page 38: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/38.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
![Page 39: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/39.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
a
![Page 40: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/40.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
a
222 yxa
![Page 41: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/41.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
a
222 yxa
24
224
2424
ryx
yx
![Page 42: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/42.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
a
222 yxa
24
224
2424
ryx
yx
2ra
![Page 43: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/43.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
a
222 yxa
24
224
2424
ryx
yx
2ra
2mrFmaF
![Page 44: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/44.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
a
222 yxa
24
224
2424
ryx
yx
2ra
2mrFmaF
xy1tan
![Page 45: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/45.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
a
222 yxa
24
224
2424
ryx
yx
2ra
2mrFmaF
xy1tan
xy
xy
1
2
21
tan
tan
![Page 46: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/46.jpg)
y
x
P
r
cosrx
sinry
cosrx sinry
sin
sin
rdtdrx
cos
cos
rdtdry
xr
dtdrx
2
2 cos
cos
yr
dtdry
2
2 sin
sin
y
x
a
222 yxa
24
224
2424
ryx
yx
2ra
2mrFmaF
xy1tan
xy
xy
1
2
21
tan
tan
centrethes toward acting,, force a is There 2mrF
![Page 47: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/47.jpg)
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
![Page 48: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/48.jpg)
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
![Page 49: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/49.jpg)
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
2mrxm
![Page 50: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/50.jpg)
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
2mrxm 2r
Am
![Page 51: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/51.jpg)
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
22
rAmmr
2mrxm 2r
Am
![Page 52: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/52.jpg)
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
22
rAmmr
2
23
A
mAmr
2mrxm 2r
Am
![Page 53: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/53.jpg)
b) A telecommunications satellite, of mass m, orbits Earth with constant angular velocity at a distance r
from the centre of the Earth.
The gravitational force exerted by Earth on the satellite is where
A
is a constant. By considering all other forces on the satellite to be negligible, show that;
2rAm
32
Ar
22
rAmmr
2
23
A
mAmr
32
Ar
2mrxm 2r
Am
![Page 54: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/54.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
![Page 55: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/55.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
![Page 56: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/56.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm
![Page 57: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/57.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
![Page 58: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/58.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
T
![Page 59: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/59.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
T
![Page 60: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/60.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
T Tmg 0
![Page 61: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/61.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
T Tmg 0
![Page 62: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/62.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
T Tmg 0
![Page 63: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/63.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
T Tmg 0
xm
![Page 64: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/64.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
T Tmg 0
xm
T
![Page 65: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/65.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
2mrT T Tmg 0
xm
T
![Page 66: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/66.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
2mrT
25.02392 T Tmg 0
xm
T
![Page 67: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/67.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
2mrT
25.02392
rad/s982392
3922
T Tmg 0
xm
T
![Page 68: X2 t06 04 uniform circular motion (2012)](https://reader033.vdocuments.us/reader033/viewer/2022052621/55896ebcd8b42a687a8b4655/html5/thumbnails/68.jpg)
(ii) A string is 50cm long and it will break if a ,mass exceeding 40kg is hung from it.A mass of 2kg is attached to one end of the string and it is revolved in a circle.Find the greatest angular velocity which may be imparted without breaking the string.
xm mg
Tmgxm
N
T392
8.940
2mrT
25.02392
rad/s982392
3922
Exercise 9B; all
T Tmg 0
xm
T