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of 21c program to print patterns of numbers and stars

16/09/2011http://www.programmingsimplified.com/c-program-print-stars-pyramid

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Home → C programming → Programs → c program to print patterns of numbers and stars

c program to print patterns of numbers and stars

These program prints various different patterns of numbers and stars. These codes illustrate how to create various patterns using c programming. Most of these c programs involve usage of nested loops and space. A pattern of numbers, star or characters is a way of arranging these in some logical manner or they may form a sequence. Some of these patterns are triangles which have special importance in mathematics. Some patterns are symmetrical while other are not. Please see the complete page and look at comments for many different patterns.

* *** ***** ******* *********

We have shown five rows above, in the program you will be asked to enter the numbers of rows you want to print in the pyramid of stars.

C code

#include<stdio.h> #include<conio.h> main() { int row, c, n, temp; printf("Enter the number of rows in pyramid of stars you wish to see " scanf("%d",&n); temp = n; for ( row = 1 ; row <= n ; row++ ) { for ( c = 1 ; c < temp ; c++ ) printf(" "); temp--;



for ( c = 1 ; c <= 2*row - 1 ; c++ ) printf("*"); printf("\n"); } getch(); return 0; }

Output:

Consider the pattern * ** *** **** *****

to print above pattern see the code below:

#include<stdio.h> main() { int n, c, k; printf("Enter number of rows\n"); scanf("%d",&n); for ( c = 1 ; c <= n ; c++ ) { for( k = 1 ; k <= c ; k++ ) printf("*"); printf("\n"); } return 0; }

For more patterns or shapes on numbers and characters see comments below and also see codes on following pages:



26/08/2011 - 12:35

26/08/2011 - 17:06

23/08/2011 - 22:04

Floyd triangle Pascal triangle

»

Comments

#1 Guest : i need a code for this pattern.

12345 1234 123 12 1

#2 adminPs : number pattern c code

#include<stdio.h> main() { int n, c, k, space; scanf("%d", &n); space = 0; for ( k = n ; k >= 1 ; k-- ) { for ( c = 1 ; c <= space ; c++ ) printf(" "); space++; for ( c = 1 ; c <= k ; c++) printf("%d", c); printf("\n"); } return 0; }

#3 Guest : thanks for the patterns it

thanks for the patterns it really helped me a lot.



20/08/2011 - 18:07

20/08/2011 - 21:29

20/08/2011 - 14:51

#4 Guest : i need code of this pattern

A B C D E F G H A B C D E F G A B C D E F A B C D E A B C D A B C A B A

#5 adminPs : c program for character pattern

#include<stdio.h> main() { char ch = 'A'; int n, c, k, space = 0; scanf("%d", &n); for ( k = n ; k >= 1 ; k-- ) { for ( c = 1 ; c <= space ; c++) printf(" "); space++; for ( c = 1 ; c <= k ; c++ ) { printf("%c ", ch); ch++; } printf("\n"); ch = 'A'; } return 0; }

#6 Guest : c language

diamond pattern of stars



26/08/2011 - 09:48

19/08/2011 - 17:38

20/08/2011 - 08:43

#7 adminPs : diamond pattern

Diamond pattern

#8 Guest : please help give me source code

1 01 010 1010 10101

#9 adminPs : c program to print pattern

#include<stdio.h> main() { int n, c, k, num = 1; scanf("%d", &n); for ( c = 1 ; c <= n ; c++ ) { for ( k = 1 ; k <= c ; k++ ) { printf("%d", num); if ( num == 0 ) num = 1; else num = 0; } printf("\n"); } return 0; }

#10 Guest : can you write code for this

p pr pro prog



18/08/2011 - 21:20

18/08/2011 - 21:59

18/08/2011 - 20:40

progr progra program

#11 adminPs : pattern for string

Just input the string and press enter, corresponding pattern will be printed.

#include<stdio.h> #include<string.h> main() { char string[100]; int c, k, length; printf("Enter a string\n"); gets(string); length = strlen(string); for ( c = 0 ; c < length ; c++ ) { for( k = 0 ; k <= c ; k++ ) { printf("%c", string[k]); } printf("\n"); } return 0; }

#12 Guest : c programming code

please get me the code of the c program to get the output as follows:

1 121 12321 1234321 123454321

#13 adminPs : c program to print number pattern

#include<stdio.h>



18/08/2011 - 22:10

17/08/2011 - 19:15

main() { int n, c, k, x = 1; scanf("%d", &n); for ( c = 1 ; c <= n ; c++ ) { for ( k = 1 ; k <= c ; k++ ) { printf("%d", x); x++; } x--; for ( k = 1 ; k <= c - 1 ; k++ ) { x--; printf("%d", x); } printf("\n"); x = 1; } return 0; }

#14 Guest : c++ code to print pattern

1 1 12 21 12321

#15 adminPs : c++ code to print pattern

#include<iostream> using namespace std; main() { int n, k, c, space, x, num = 1; cin >> n; x = n; for ( k = 1 ; k <= n ; k++ ) { for ( c = 1 ; c <= k ; c++ ) { cout << num;



18/08/2011 - 17:14

16/08/2011 - 21:34

num++; } num--; for ( c = 1 ; c <= 2*x - 3 ; c++ ) cout << " "; x--; if ( k != n ) { for ( c = 1 ; c <= k ; c++ ) { cout << num; num--; } } else { num--; for ( c = 1 ; c <= k - 1 ; c++ ) { cout << num; num--; } } printf("\n"); num = 1; } return 0; }

#16 Guest : may i get its source code

1 232 34543 4567654 567898765

#17 adminPs : c code for number pattern

#include<stdio.h> main() { int n, c, d, num = 1, space; scanf("%d",&n); space = n - 1;



18/08/2011 - 17:17

13/08/2011 - 17:53

for ( d = 1 ; d <= n ; d++ ) { num = d; for ( c = 1 ; c <= space ; c++ ) printf(" "); space--; for ( c = 1 ; c <= d ; c++ ) { printf("%d", num); num++; } num--; num--; for ( c = 1 ; c < d ; c++) { printf("%d", num); num--; } printf("\n"); } return 0; }

#18 Guest : how to print this pattern

******* ***S*** **SSS** *SSSSS*

where S represents Space

******* *** *** ** ** * *

#19 adminPs : c code for star pattern

#include<stdio.h> main() { int n, c, k, space, r; printf("Enter number of rows\n"); scanf("%d",&n);



13/08/2011 - 19:17

22/08/2011 - 09:47

22/08/2011 - 13:01

space = 1; r = n-1; for( c = 1 ; c <= 2*n - 1 ; c++ ) printf("*"); printf("\n"); for ( k = 2 ; k <= n ; k++ ) { for( c = 1 ; c <= r ; c++ ) printf("*"); for ( c = 1 ; c <= space ; c++ ) printf(" "); space = 2*k-1; for( c = 1 ; c <= r ; c++ ) printf("*"); r--; printf("\n"); } return 0; }

#20 Guest : Doubt

In the program, instead of the statement space=2*k-1; , can we go for the statement, space+=2; ?

#21 adminPs : sure

You can use but don't forget to initialize variable space to one.

#22 Guest : code

guys i need the code for this

* ** *** **** *****



13/08/2011 - 17:15

13/08/2011 - 17:29

12/08/2011 - 18:48

#23 adminPs : star pattern source code

#include<stdio.h> main() { int n, c, k, space; printf("Enter number of rows\n"); scanf("%d",&n); space = n; for ( k = 1 ; k <= n ; k++ ) { for ( c = 1 ; c < space ; c++ ) printf(" "); space--; for( c = 1 ; c <= k ; c++ ) printf("*"); printf("\n"); } return 0; }

#24 Guest : i need a program to draw the below patern

1 22 333 4444 55555

#25 adminPs : number pattern source code

#include<stdio.h> main() { int n, c, k; printf("Enter number of rows\n"); scanf("%d",&n);



12/08/2011 - 20:13

11/08/2011 - 20:14

12/08/2011 - 07:31

09/08/2011 - 21:46

for ( c = 1 ; c <= n ; c++ ) { for( k = 1 ; k <= c ; k++ ) printf("%d", c); printf("\n"); } return 0; }

#26 Guest : need help

i need program to print the following pattern ::

1 2 3 4 5 6 7 8 9 10

#27 adminPs : Floyd's triangle

This pattern is Floyd's triangle see Floyd's Triangle code.

#28 Guest : need a code in c to print below pattern

i want a code to print stars like below

* ** *** **** *** ** *

#29 adminPs : stars pattern using c programming

#include<stdio.h> main() {



09/08/2011 - 22:38

09/08/2011 - 17:21

int n, c, k; printf("Enter number of rows\n"); scanf("%d",&n); for ( c = 1 ; c <= n ; c++) { for ( k = 1 ; k <= c ; k++ ) printf("*"); printf("\n"); } for ( c = n - 2 ; c >= 0 ; c-- ) { for ( k = c ; k >= 0 ; k-- ) printf("*"); printf("\n"); } return 0; }

#30 Guest : GET ME THE CODE OF A PROGRAM

GET ME THE CODE OF A PROGRAM TO GET OUTPUT AS FOLLOWS:

* *A* *A*A* *A*A*A*

#31 adminPs : code to print pattern of stars and numbers

#include<stdio.h> main() { int n, c, k, space, count = 1; printf("Enter number of rows\n"); scanf("%d",&n); space = n; for ( c = 1 ; c <= n ; c++) { for( k = 1 ; k < space ; k++) printf(" "); for ( k = 1 ; k <= c ; k++) { printf("*");



09/08/2011 - 21:46

08/08/2011 - 13:18

08/08/2011 - 15:32

if ( c > 1 && count < c) { printf("A"); count++; } } printf("\n"); space--; count = 1; } return 0; }

#32 Guest : codes for pyramid of stars.

i need this pattern * * * * * * * * * * *

#33 adminPs : code for pattern

#include<stdio.h> main() { int n, c, k, temp; printf("Enter number of rows\n"); scanf("%d",&n); temp = n; for ( c = 1 ; c <= n ; c++ ) { for( k = 1 ; k <= temp ; k++ ) printf("* "); temp--; printf("\n"); } return 0; }



08/08/2011 - 13:01

08/08/2011 - 15:29

06/08/2011 - 13:59

#34 Guest : Please post the code for this

* * * * * * * * * *

Please post the code to print the following shape as soon as possible.

#35 adminPs : code

#include<stdio.h> main() { int n, c, k; printf("Enter number of rows\n"); scanf("%d",&n); for ( c = 1 ; c <= n ; c++ ) { for( k = 1 ; k <= c ; k++ ) printf("* "); printf("\n"); } return 0; }

#36 Guest : please help

i need c program to print no in this format 1 1 2 1 2 3 1 2 3 4

#37 adminPs : source code

#include<stdio.h> main() {



07/08/2011 - 11:32

08/08/2011 - 22:02

int number = 1, n, c, k; printf("Enter number of rows\n"); scanf("%d",&n); for ( c = 1 ; c <= n ; c++ ) { for( k = 1 ; k <= c ; k++ ) { printf("%d ", number); number++; } number = 1; printf("\n"); } return 0; }

#38 Guest : Thanks giving and suggestion

Thanks for the pyramid program!! Please help me in the same problem. Can't we directly print k directly instead of number(in 2nd inner for loop)?

I have tried it but output gives garbage values!!why does this happen? Please help me!

#39 adminPs : number pattern code

You are right there is no need to use variable number you can use k directly as in code below:

#include<stdio.h> main() { int n, c, k; printf("Enter number of rows\n"); scanf("%d",&n); for ( c = 1 ; c <= n ; c++ ) { for( k = 1 ; k <= c ; k++ ) printf("%d ", k); printf("\n"); }



09/08/2011 - 11:19

05/08/2011 - 11:53

08/08/2011 - 15:45

return 0; }

#40 Guest : i need a code in C to print pyramid of stars

i need a code in C to print stars like this

* * * * * * * * * *

please help?

#41 adminPs : c code to print pattern

#include<stdio.h> main() { int n, c, k = 2, j; printf("Enter number of rows\n"); scanf("%d",&n); for ( j = 1 ; j <= n ; j++ ) { for ( c = 1 ; c <= 2*n-k ; c++) printf(" "); k = k + 2; for ( c = 1 ; c <= j ; c++) printf("* "); printf("\n"); } getch(); return 0; }

#42 Guest : GET THE SOURCE CODE

GET ME THE CODE OF A PROGRAM TO GET OUTPUT AS FOLLOWS:

ABCDEFEDCBA ABCDE EDCBA



04/08/2011 - 20:46

04/08/2011 - 11:13

11/07/2011 - 00:06

11/07/2011 - 00:02

29/06/2011 - 13:52

10/07/2011 - 23:00

29/06/2011 - 13:24

ABCD DCBA ABC CBA AB BA A A

#43 Guest : thank you

i was looking for it

#44 Guest : problem

Sir i have some problem regarding loop. Sometime i cant understand how loop is working and i cant implement it right too. How can i improve my understanding skill, please help if possible.

#45 Guest : Compliment

sir your site is awesome....... i really like it and learned lot from it.:)

#46 Guest : help

can you explain the code, the loop coding.

#47 adminPs : program explanation

The first loop is for number of rows, second for printing required spaces and last one to print stars ( 2*(row number) - 1 ).

#48 Guest : thanks

i am searching same and i got



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