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Written Math: 1) 2 men and 5 women can do 1/4th of a job in 3 days. After 3 days 1 man joined the team and they completed another 1/4th of the job in 2 days. How many men can complete the job in 4 days? ...... 2) a, b, c, d, and e are five consecutive integers arranged in increasing order. If one of the numbers is deleted from the sum of these five numbers, their sum reduces by 20%. Find the number which was deleted. 3) Two types of rice costing Tk. 5 and Tk. 6 per kg respectively are mixed together and the mixture is sold for Tk. 7 to make a 20% profit. Find the ratio of the mixture. 2/m + 5/w = 1/(4x3) = 1/12 ----------- < i > 3/m + 5/w = 1/(4x2) = 1/8 ------------- < ii > < ii > - < i > = 1/m = 1/24 m = 24. 24 day is taken by 1 man 4 day is taken by 24/4 = 6 men 1. ans. 2 men & 5 women in 3 days can do ¼ portion 2 men & 5 women in 1 days can do 1/12 portion (a) 3 men & 5 women in 2 days can do ¼ portion 3 men & 5 women in 1 days can do 1/8 portion (b) So, 1 men in 1 days can do 1/8-1/12 =1/24 portion (b-a) and 1 men in 4 days can do 4/24=1/6 portion Hence, in 4 days 1/6 portion can do by 1 men So, in 4 days 1 (full) portion can do by 6 men. Ans.6 men.

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Page 1: Written Math

Written Math:

1) 2 men and 5 women can do 1/4th of a job in 3 days. After 3 days 1 man joined the team and they completed another 1/4th of the job in 2 days. How many men can complete the job in 4 days? ......2) a, b, c, d, and e are five consecutive integers arranged in increasing order. If one of the numbers is deleted from the sum of these five numbers, their sum reduces by 20%. Find the number which was deleted.

3) Two types of rice costing Tk. 5 and Tk. 6 per kg respectively are mixed together and the mixture is sold for Tk. 7 to make a 20% profit. Find the ratio of the mixture.

2/m + 5/w = 1/(4x3) = 1/12 ----------- < i >3/m + 5/w = 1/(4x2) = 1/8 ------------- < ii >

< ii > - < i > = 1/m = 1/24m = 24.

24 day is taken by 1 man4 day is taken by 24/4 = 6 men

1. ans. 2 men & 5 women in 3 days can do ¼ portion2 men & 5 women in 1 days can do 1/12 portion (a)3 men & 5 women in 2 days can do ¼ portion3 men & 5 women in 1 days can do 1/8 portion (b)So, 1 men in 1 days can do 1/8-1/12 =1/24 portion (b-a)and 1 men in 4 days can do 4/24=1/6 portionHence, in 4 days 1/6 portion can do by 1 menSo, in 4 days 1 (full) portion can do by 6 men.Ans.6 men.

1. a,b,c,d,e are consecutive number. Suppose, a=xtherefore b= x+1, c= x+2, d= x+3 and e= x+4So, sum of them = 5x+10According to qs, if one of a,b,c,d,e deleted 20% of the sum decreased. So the deleted number must contribute 20% of the sum.

Page 2: Written Math

Now, 20% of the sum = (20/100) (5x+10) = x+2=ctherefore c was deleted. Ans.

3. Ans. let,Rahim mixed x kg @Tk 5.y kg @ Tk 6,As per ques,1.2(5x+6y)=(x+y)7>6x+7.2y=7x+7y>x=0.2ySo x:y = 1:5